Electrical Engineering: Ch 18: Fourier Series (13 of 35) Even Periodic Functions
Summary
TLDRThe video script discusses simplifying the process of finding Fourier series coefficients for even periodic functions. It explains that even functions, which are symmetrical about the vertical axis, can be mirrored to produce duplicates on the other side. For such functions, the Fourier series involves only cosine terms, as sine terms become zero. The coefficients are calculated by integrating over half the period, doubling the amplitude, which simplifies the process significantly.
Takeaways
- ๐ข Recognizing the type of function (even or odd) simplifies finding the Fourier series.
- ๐ Even periodic functions resemble cosine functions with symmetry about the vertical axis.
- โ๏ธ An even function remains the same if you replace the independent variable T with -T.
- ๐ Examples of even periodic functions show identical behavior on both sides of the vertical axis.
- โ๏ธ When calculating Fourier coefficients for even functions, integrate only over half the period.
- ๐งฎ The coefficient aโ is calculated as 2/T, with integration over half the period.
- ๐ก The aโ coefficients are found using a 4/T factor, only integrating over half the period.
- ๐ซ For even functions, the Bโ coefficients always equal zero, making the calculations simpler.
- โฉ No need to compute Bโ terms when working with even periodic functions, saving time.
- ๐ The symmetry of even functions helps streamline Fourier series calculations.
Q & A
What is an even function in the context of Fourier series?
-An even function in the context of Fourier series is a function that is symmetric about the vertical axis. If you take one side of the function and flip it over, it should look exactly the same on the other side.
How does the property of an even function relate to cosine functions?
-Even functions have properties similar to cosine functions because they both exhibit symmetry about the vertical axis. This means that if you replace every independent variable T with -T, you get the same function.
What is the significance of even periodic functions in Fourier series?
-Even periodic functions are significant in Fourier series because they allow for a simplification in calculating coefficients. The symmetry means that only cosine terms (a_n) need to be calculated, and sine terms (b_n) are zero.
How does the integration process differ for even functions when calculating Fourier coefficients?
-For even functions, the integration for calculating coefficients a_n only needs to be done over half the period instead of the entire period, and the amplitude is doubled. This is due to the symmetry of the function.
Why are the b_n coefficients zero for even functions?
-The b_n coefficients are zero for even functions because the function does not have any odd symmetry, which is required for sine terms in the Fourier series. Since even functions are symmetric about the vertical axis, there are no sine components.
Can you provide an example of an even periodic function?
-Yes, an example of an even periodic function could be a cosine function itself, like cos(ฯt), or any function that is symmetric about the y-axis and repeats its values over a period.
What is the formula for calculating a_n coefficients for even functions?
-The formula for calculating a_n coefficients for even functions in the Fourier series is \( a_n = \frac{2}{T} \int_{0}^{T/2} f(t) \cos(n\omega t) dt \), where T is the period of the function.
How does the script suggest simplifying the process of finding Fourier coefficients for even functions?
-The script suggests that when dealing with even functions, you can ignore the calculation of b_n coefficients altogether since they are zero, and only calculate the a_n coefficients.
What is the implication of not having to calculate b_n coefficients for even functions?
-Not having to calculate b_n coefficients for even functions simplifies the process of finding the Fourier series representation of the function, as it reduces the number of integrals that need to be computed.
How does the script explain the process of flipping a function to determine if it's even?
-The script explains that to determine if a function is even, you can visualize flipping one side of the function over the vertical axis and see if it matches the other side, or mathematically replace T with -T and check if the function remains the same.
What is the role of the vertical axis in determining the evenness of a function?
-The vertical axis plays a crucial role in determining the evenness of a function because it serves as the line of symmetry. A function is even if it is symmetric about the vertical axis.
Outlines
๐ Understanding Even and Periodic Functions in Fourier Series
This section introduces the concept of identifying whether a function is even or odd to simplify the process of finding the Fourier series. An even function, resembling a cosine function, has symmetry around the vertical axis. By flipping the function along this axis, it appears identical on both sides. In mathematical terms, substituting the independent variable \( T \) with \( -T \) results in the same function. The periodic nature of the function is emphasized, and the examples provided show how even periodic functions mirror on both sides of the axis.
๐ง Simplifying Fourier Coefficients for Even Functions
This part explains how to calculate Fourier coefficients when dealing with even periodic functions. Due to the function's symmetry, only half the period needs to be integrated, simplifying the process. The coefficient \( A_0 \) is found using \( 2/T \) instead of the standard \( 1/T \) because of the halved period. Similarly, for \( A_n \), the integral is taken over half the period, with the amplitude doubled. It also highlights the fact that all \( B_n \) coefficients, which relate to sine terms, are automatically zero, eliminating the need to calculate them, thus saving time.
โก Efficiency in Fourier Series Calculation for Even Functions
This section emphasizes how recognizing a function as even simplifies the Fourier series calculation. Since all \( B_n \) coefficients are zero for even functions, only the \( A_0 \) and \( A_n \) coefficients need to be computed. This reduction in calculations makes the process more efficient, especially when handling even periodic functions. The takeaway message is to always check for symmetry in the function to streamline the analysis and avoid unnecessary steps in future problems.
Mindmap
Keywords
๐กFourier series
๐กEven function
๐กOdd function
๐กPeriodic function
๐กCosine function
๐กVertical axis
๐กCoefficients
๐กA_n
๐กB_n
๐กIntegration
๐กOmega (ฯ)
Highlights
The process of finding the Fourier series can be simplified by recognizing the type of function involved.
Even functions can be treated as even periodic functions similar to cosine functions.
Cosine functions are not periodic but share properties with even functions, such as symmetry about the vertical axis.
An even function can be identified by its mirror image about the vertical axis.
Replacing the independent variable T with -T in an even function yields the same function.
Periodic functions that are even can be visually identified by their symmetry when flipped.
For even periodic functions, the coefficients can be determined with specific formulas.
The coefficient A_n can be found using 2/T instead of the usual 1/T due to the function's symmetry.
Integration for A_n only needs to be performed over half the period for even functions.
The coefficient A_0 is calculated by doubling the amplitude and integrating over half the period.
For even functions, all the B_n coefficients are zero, simplifying the Fourier series calculation.
There is no need to calculate B_n coefficients for even functions as they are guaranteed to be zero.
This property of even functions saves time in Fourier series calculations.
Only the A_n coefficients need to be calculated for even periodic functions.
The method simplifies the process of finding Fourier series for even periodic functions.
This approach is practical for functions that exhibit even periodicity.
The significance of this method is its efficiency in handling even periodic functions in Fourier series.
Transcripts
welcome to electron line our job in
finding the Fourier series can be made
easier if we recognize what kind of
function we're dealing with if we're
dealing with an even or not function if
we're dealing with an even function and
we should call it an even periodic
function then it's kind of like a cosine
function of course the cosine functions
not a periodic function per se but it
has the same properties as a cosine
function but other words it has a mirror
image about the vertical axis but other
words if we take this side of the
function and we flip it over here we
have an exact duplicate on the other
side another way of thinking about an
even function is if we replace every
independent variable T by a negative T
we get the exact same function that's
what that really means and so we have
some periodic functions here that can be
considered even again if you think about
taking this and flipping it over it
looks exactly the same on both sides of
the vertical axis same over here I can
flip this over same over here we can
flip this over so therefore these are
considered even periodic functions and
when you're dealing with even periodic
functions there's something very
specific about the coefficients we can
determine the coefficients as follows
Asaph not can be found to be 2 over T
remember normally we say 1 over T but
then we integrate over the entire period
we only have to integrate over half the
period because of the symmetry on both
sides of vertical axis and therefore we
doubled the magnitude so it's 2 over T
but then integrating only over half the
period of the f of T DT when we find the
in the a sub ends again we only have to
integrate from zero to half the period
but instead of having 2 over T there we
now have a 4 over T we double the
amplitude but we only integrate over
half the period the rest is the same f
of T times the cosine of n Omega T DT
but what's nice is you can be assured
that when you deal with an even function
you do not have any beasts event terms
in other words all the B sub n factors
become equal to 0 and you don't have to
try them out you could simply not bother
with those integrals so
makes the job a lot easier you only have
to try to find the ace if not and you
only need to try to find the ace of ends
you don't even have to try to be Saban's
because now you know for sure they're
going to be equal to zero
as long as the function is an even
periodic function so remember that it'll
save you time in the future
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