Vapor Pressure | Raoult's Law | Solution Class 12

Najam Academy
24 Jul 202324:27

Summary

TLDRThis video explains key concepts related to vapor pressure and Raoult's law, starting with the distinction between volatile and non-volatile substances. It covers evaporation, vapor pressure in closed containers, and the equilibrium between evaporation and condensation. The video delves into how temperature and intermolecular forces influence vapor pressure. It introduces Raoult's law, describing how partial vapor pressure is directly proportional to mole fractions in a solution. The video concludes with applications of Raoult's law, solving problems on total vapor pressure using Dalton's law, and includes numerical examples for clarity.

Takeaways

  • đŸŒĄïž Volatile substances, such as water, gasoline, and ethanol, evaporate at temperatures above or below room temperature, whereas non-volatile substances like salt and sugar do not.
  • 💧 Evaporation is the process where surface molecules of a liquid, which have higher kinetic energy, escape and become vapor.
  • 🔄 The difference between evaporation and boiling is that boiling occurs at a fixed temperature, while evaporation can happen at any temperature.
  • 💭 Vapor pressure is defined as the pressure exerted by vapors on the surface of a liquid in a closed container and is a result of evaporation within that container.
  • 🔆 Temperature has a direct relationship with vapor pressure; as temperature increases, so does vapor pressure.
  • 🔗 The nature of the liquid and its intermolecular forces inversely affect vapor pressure; liquids with weaker intermolecular forces have higher vapor pressures.
  • 🌀 Raoult's Law states that the partial vapor pressure of a liquid in a solution is equal to the vapor pressure of the pure liquid multiplied by its mole fraction in the solution.
  • 📉 Dalton's Law is used to calculate the total vapor pressure of a solution, which is the sum of the partial vapor pressures of each volatile component in the solution.
  • 📊 Graphically, Raoult's Law can be represented by a straight line where the vapor pressure of a liquid is directly proportional to its mole fraction.
  • đŸ§Ș Numerical problems involving Raoult's Law involve calculating the partial vapor pressure of solvents in solutions using their mole fractions and pure vapor pressures.

Q & A

  • What is a volatile substance?

    -A volatile substance is one that evaporates into a gas at room temperature or higher. Examples include water, gasoline, and ethanol.

  • What is the difference between volatile and non-volatile substances?

    -Volatile substances evaporate at room temperature or below, such as water and ethanol, while non-volatile substances, like salt and sugar, do not evaporate at these conditions.

  • What is evaporation?

    -Evaporation is the process by which a liquid transforms into vapor. It occurs when surface molecules with high kinetic energy escape from the liquid into the air.

  • How is evaporation different from boiling?

    -Boiling occurs at a fixed temperature (e.g., 100°C for water), while evaporation can occur at any temperature, even as low as 0°C.

  • What is vapor pressure?

    -Vapor pressure is the pressure exerted by the vapors of a volatile liquid on the surface of the liquid when in a closed container at a given temperature.

  • How does temperature affect vapor pressure?

    -There is a direct relationship between temperature and vapor pressure. As temperature increases, vapor pressure also increases, such as water at 60°C having a higher vapor pressure than at 40°C.

  • What are the factors affecting vapor pressure?

    -Two main factors affect vapor pressure: temperature (direct relationship) and the nature of the liquid (inverse relationship with intermolecular forces).

  • What is Raoult’s Law?

    -Raoult’s Law states that the partial vapor pressure of a liquid in a solution is directly proportional to the mole fraction of that liquid in the solution.

  • How do you calculate total vapor pressure in a solution?

    -Total vapor pressure of a solution can be found using Dalton’s Law, which states that it is the sum of the partial vapor pressures of all the volatile components in the solution.

  • What is the difference between Raoult's Law and Dalton's Law?

    -Raoult’s Law explains the partial vapor pressure of a single volatile component in a solution, while Dalton’s Law is used to find the total vapor pressure of a solution by summing all partial pressures.

Outlines

00:00

💧 Understanding Vapor Pressure and Evaporation

This section introduces the fundamental concepts of vapor pressure and evaporation. It distinguishes between volatile and non-volatile substances, using water, gasoline, and ethanol as examples of the former, and salt, sugar, and urea as examples of the latter. The script explains evaporation as a process where surface molecules with higher kinetic energy escape from the liquid to become vapor. It contrasts evaporation with boiling, highlighting that boiling occurs at a fixed temperature, whereas evaporation can happen at any temperature. The concept of vapor pressure is then introduced as the pressure exerted by vapors on the surface of a liquid in a closed container, reaching equilibrium when the rate of evaporation equals the rate of condensation.

05:03

🔍 Factors Affecting Vapor Pressure

The second paragraph delves into the factors that influence vapor pressure. It establishes a direct relationship between temperature and vapor pressure, illustrating that water at 60 degrees Celsius has a higher vapor pressure than at 40 degrees Celsius. It also discusses the nature of the liquid and its intermolecular forces, showing an inverse relationship with vapor pressure. Using water and acetone as examples, it explains that acetone has a higher vapor pressure at 40 degrees Celsius due to its weaker intermolecular forces compared to water's strong hydrogen bonding. The paragraph reinforces the understanding that vapor pressure is also known as equilibrium vapor pressure and is independent of the shape of the container.

10:05

đŸŒĄïž Vapor Pressure of Pure and Binary Liquids

This part of the script teaches the concept of vapor pressure for pure liquids (P naught) and binary liquids. It describes how a pure liquid in a closed container will exert vapor pressure over time and how combining two liquids in one container results in a solution with each liquid exerting partial pressure. The difference between the vapor pressure of a pure liquid (P naught) and the partial pressure (P) of a liquid in a solution is clarified. The script then introduces Raoult's Law, stating that the partial vapor pressure of a liquid in a solution is directly proportional to its mole fraction in the solution. The law is applied to calculate the partial vapor pressures of both liquids in a solution.

15:06

📊 Graphical Representation of Raoult's Law

The fourth paragraph provides a graphical representation of Raoult's Law. It describes how to plot vapor pressure against mole fraction for two volatile liquids, with one being more volatile than the other. The script explains that as mole fraction decreases from left to right on the x-axis, the partial vapor pressure also decreases for the first liquid, while it increases for the second liquid. The resulting graph consists of two straight lines representing the partial vapor pressures of each liquid in the solution. The total vapor pressure of the solution is the sum of the partial vapor pressures of both liquids.

20:07

📚 Application and Numerical Problems of Raoult's Law

The final paragraph applies Raoult's Law to solve numerical problems related to vapor pressure. It presents a scenario where glucose is added to water and calculates the partial vapor pressure of water in the resulting aqueous solution. The calculation involves determining the number of moles of each component and applying Raoult's Law to find the partial vapor pressure of water. Another example involves an ideal solution of ethanol and methanol, where the total vapor pressure is calculated by summing the partial vapor pressures of each component, determined using their respective mole fractions and pure vapor pressures.

Mindmap

Keywords

💡Volatile Substances

Volatile substances are materials that evaporate easily at room temperature due to having high vapor pressure. In the video, examples such as water, gasoline, and ethanol are given, showing how they evaporate and form vapors. This concept is fundamental to understanding vapor pressure, as it is these substances that generate vapor pressure when enclosed.

💡Non-Volatile Substances

Non-volatile substances are materials that do not evaporate easily at room temperature because they have low vapor pressure. Examples like salt, sugar, and urea are provided in the video. These substances help contrast the behavior of volatile substances, as non-volatile substances do not contribute significantly to vapor pressure.

💡Evaporation

Evaporation is the process by which surface molecules of a liquid escape into the air as vapor. It occurs only in volatile substances. In the video, it is explained how molecules with higher kinetic energy escape from the surface of the liquid into vapor form. Evaporation happens even at temperatures lower than the boiling point, making it a key concept in understanding how vapor pressure develops.

💡Vapor Pressure

Vapor pressure is the pressure exerted by vapor molecules when they strike the surface of a liquid in a closed container. The video describes vapor pressure as the result of volatile liquids evaporating in an enclosed space. At equilibrium, vapor pressure is constant, and it reflects the balance between evaporation and condensation. The concept is central to the discussion of how liquids behave in different conditions.

💡Boiling Point

The boiling point is the temperature at which a liquid's vapor pressure equals the external pressure, causing it to boil. The video contrasts evaporation with boiling, emphasizing that boiling occurs at a fixed temperature, while evaporation can happen at any temperature below the boiling point. Water’s boiling point, for example, is given as 100°C.

💡Equilibrium

Equilibrium in this context refers to the point at which the rate of evaporation equals the rate of condensation in a closed system. The video explains that at equilibrium, the number of molecules evaporating is the same as the number condensing, resulting in a stable vapor pressure. This balance is a critical part of understanding how vapor pressure is maintained in a system.

💡Intermolecular Forces

Intermolecular forces are the forces of attraction or repulsion between molecules. In the video, these forces are discussed as a factor influencing vapor pressure, with weaker intermolecular forces (like those in acetone) leading to higher vapor pressure, while stronger forces (like hydrogen bonding in water) result in lower vapor pressure. Understanding these forces helps explain why different substances have different vapor pressures.

💡Raoult’s Law

Raoult’s Law describes how the partial vapor pressure of a liquid in a solution is proportional to its mole fraction. In the video, Raoult’s Law is used to calculate the partial vapor pressures of different volatile liquids in a solution. This law is essential for understanding how the vapor pressures of individual components contribute to the overall vapor pressure of a mixture.

💡Partial Vapor Pressure

Partial vapor pressure refers to the pressure exerted by a single component of a mixture in a solution. The video explains that in a solution of two volatile liquids, each liquid exerts its own partial vapor pressure, which can be calculated using Raoult’s Law. This concept helps in determining how each liquid contributes to the total vapor pressure of the system.

💡Dalton’s Law

Dalton’s Law states that the total vapor pressure of a solution is the sum of the partial pressures of all volatile components. The video contrasts Raoult’s Law with Dalton’s Law, showing that while Raoult’s Law explains partial vapor pressure, Dalton’s Law is used to calculate the total vapor pressure in a solution with multiple volatile liquids.

Highlights

Definition of volatile substances that evaporate at room temperature or below.

Definition of non-volatile substances that do not evaporate at room temperature or below.

Explanation of evaporation as a process occurring in volatile substances like water.

Description of the kinetic energy difference between surface and bulk molecules in a liquid.

Evaporation defined as the transformation of a liquid into vapors due to high kinetic energy of surface molecules.

Difference between evaporation and boiling point clarified, with boiling occurring at a fixed temperature.

Introduction to vapor pressure as evaporation within a closed container.

Vapor pressure defined as the pressure exerted by vapors on the surface of a liquid at a given temperature.

Factors affecting vapor pressure include temperature and the nature of the liquid or intermolecular forces.

Vapor pressure does not depend on the shape of the container.

Concept of vapor pressure of pure liquids (P naught) explained.

Introduction to partial vapor pressure in solutions containing more than one volatile liquid.

Definition of partial vapor pressure as the pressure exerted by one liquid in a solution.

Explanation of Raoult's Law stating that the partial vapor pressure of a liquid in a solution is directly proportional to its mole fraction.

Graphical representation of Raoult's Law showing the relationship between vapor pressure and mole fraction.

Application of Raoult's Law in calculating the partial vapor pressure of liquids in a solution.

Difference between Raoult's Law and Dalton's Law in calculating total vapor pressure of a solution.

Numerical problem-solving using Raoult's Law to find the vapor pressure of aqueous solutions.

Numerical problem-solving using Raoult's Law to calculate the total vapor pressure of a solution containing ethanol and methanol.

Transcripts

play00:00

vapor pressure and routes law firstly we

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will learn some basic concepts like

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volatile substances and non-volatile

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substances a volatile substance is one

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that evaporates into a gaze through

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temperature or below for example water

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gasoline ethanol Etc are all volatile

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substances

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while non-volatile substances is the one

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that doesn't evaporate into a gaze at

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room temperature or below for example

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salt sugar

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urea Etc are all non-volatile substances

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the second concept is evaporation

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remember that evaporation only occurs in

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volatile substances like water now

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consider this open object which contains

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water we know that the molecules at the

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surface are called surface molecules and

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the molecule inside are at the bottom

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are called bulk molecules the bulk

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molecules have low kinetic energy due to

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which they move slowly

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while the surface molecules have high

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kinetic energy due to which they move

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fast now listen carefully after some

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time the surface molecules would leave

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the liquid and would Escape into the

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vapors

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let me repeat it after some time the

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surface molecules would leave the liquid

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and would Escape into the vapories this

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process is known as evaporation

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if you ask me why these surface

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molecules leave the liquid the answer is

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simple it is because they have high

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kinetic energy due to which they leave

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the liquid surface and become Vapors

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therefore we Define evaporation as the

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process by which a liquid is transformed

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into Vapors is called evaporation

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here let me ask you one important

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question what is the difference between

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evaporation and boiling point

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well boiling occurs at fixed temperature

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for example the boiling point of water

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is fixed which is 100 degree Centigrade

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while evaporation can occur at any time

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pressure

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for example water can even evaporate its

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0 degree centigrade

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just remember that every volatile liquid

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evaporates at any temperature

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now let me teach you the basic concept

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of vapor pressure if I teach the

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complete concept of vapor pressure in

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one statement then I would say vapor

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pressure is evaporation in a closed

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container this statement explain the

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whole philosophy of vapor pressure now

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consider this close container which

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contain a volatile liquid

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we already know that volatile liquid

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evaporates I mean these surface

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molecules convert into vapor due to high

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kinetic energy hence I write evaporation

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occurs and which surface molecules

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evaporate into vapories

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after some time these Vapors would

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condense and would fall back into the

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liquid

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hence I write condensation occurs in

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which Vapors convert to liquid here

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inside this close container evaporation

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occurs I mean liquid converts to Vapor

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secondly condensation occurs I mean

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Vapors convert to liquid now a time will

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reach when rate of evaporation would be

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equal to the rate of condensation this

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stage is called equilibrium

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to make this concept more simple we say

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that at equilibrium if 10 molecules of

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liquid evaporates into vapories then 10

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molecules of vapor condensed into liquid

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now listen carefully here I am going to

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teach you the best part of vapor

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pressure which a lot of talented people

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are missing

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we know that these Vapors condense and

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fall back into the liquid

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when these Vapors fall back into the

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liquid surface they exert force or unit

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area of the liquid surface let me repeat

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it when these Vapors fall back into the

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liquid surface they exert force on unit

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area of the liquid surface

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we know that pressure is equal to force

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on a unit area this pressure is exerted

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by the vapors so we call it vapor

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pressure

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remember that vapor pressure is the

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pressure of vapors on the surface of

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liquid therefore we Define vapor

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pressure as the pressure exerted by

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Vapors on the surface of the liquid at a

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given temperature is called vapor

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pressure let me repeat it the pressure

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exerted by Vapors on the surface of the

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liquid at a given temperature is called

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vapor pressure remember that vapor

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pressure is also known as equilibrium

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vapor pressure

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hence notary down that the pressure of

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vapors on the surface of liquid is

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called vapor pressure

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now let me teach you factors affecting

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vapor pressure

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first Factor affecting vapor pressure is

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temperature there is direct relationship

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between temperature and vapor pressure

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for example water is 60 degree

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Centigrade has more vapor pressure than

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water at 40 degree centigrade

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the second factor is nature of liquid or

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intermolecular forces there is inverse

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relationship between intermolecular

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forces and vapor pressure

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for example consider water and acetone

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at 40 degree Centigrade the vapor

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pressure of acetone is more than water

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because acetone has weak intermolecular

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forces like London dispersion forces

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while the water has strong

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intermolecular forces like hydrogen

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bonding also remember that vapor

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pressure doesn't depend upon the shape

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of objects

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hence noted down all these important

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points

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now we will learn the most important

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concept of this lecture

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firstly we will learn the vapor pressure

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of pure liquid P naught remember that I

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take volatile liquids now consider first

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liquid in this closed container and

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secant liquid in this close container

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this container contains one type of

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molecules and this container also

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contains one type of molecules after

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some time the volatile liquid will exert

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vapor pressure on the surface of the

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liquid

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we write vapor pressure of pure liquid 1

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is equal to P1 naught

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similarly the volatile liquid in the

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second container would exert vapor

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pressure on the surface of the liquid

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we write paper pressure of pure liquid 2

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is equal to P2 naught

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hence we learned that e naught is the

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vapor pressure of pure liquid or the

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vapor pressure of only one liquid

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let me repeat this important point

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P naught is the vapor pressure of pure

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liquid or the vapor pressure of only one

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liquid

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hence noted down this very very

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important point

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now let me teach you the Weber pressure

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of binary liquids are two liquids

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consider liquid number one and liquid

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number two enclosed container from the

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previous example we know that vapor

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pressure of pure liquid 1 is equal to P1

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naught

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and the vapor pressure of pure liquid 2

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is equal to P2 naught now I combine

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these two liquids in one closed

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container I get a solution

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this solution contains two volatile

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liquids liquid number one and liquid

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number two I mean this solution contains

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two types of different molecules

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now listen carefully and the solution

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liquid one exert partial pressure P1 and

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liquid to exert partial pressure P2 let

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me repeat it

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and the solution liquid 1 exert partial

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pressure P1 and liquid to exert partial

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pressure P2

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here let me ask you one of my favorite

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questions what is the difference between

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P1 naught and P1 can you guess the

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answer

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well it is super easy P1 naught is the

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vapor pressure of pure liquid one

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for example P1 naught is the vapor

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pressure of pure liquid and this

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container while P1 is the partial

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pressure of liquid 1 and a solution

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for example E1 is the partial pressure

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of liquid one and this container of

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solution

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similarly P2 naught is the vapor

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pressure of pure liquid 2 and P2 is the

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partial pressure of liquid number two

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and a solution

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now what is meant by partial vapor

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pressure well partial vapor pressure

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means pressure of one liquid and a

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solution for example here are two

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liquids in this solution

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P1 is the partial vapor pressure of

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liquid one and P2 is the partial vapor

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pressure of liquid number two

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hence noted down all these important

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points

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now let me ask you the most important

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question of this lecture

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how can we find the partial vapor

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pressure of P1 and partial vapor

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pressure of P2 and a solution

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well to find partial vapor pressure in a

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solution here comes the routes Baba he

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states that partial vapor pressure of

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any liquid is directly proportional to

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mole friction of that liquid and a

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solution

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so we write partial vapor pressure of P1

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in a solution is directly proportional

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to its mole fraction X1

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if you want to learn more about mole

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friction then watch our video and its

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link is given in the description

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now to eliminate the sign of

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proportionality we have to put some sort

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of constant

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let this Escape I write partial vapor

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pressure of liquid 1 is equal to K into

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its mole fraction let this is equation

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number one

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remember that mole friction of liquid 1

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x 1 is equal to number of moles of

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liquid 1 upon number of moles of liquid

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1 less number of moles of liquid two now

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we will find the value of constant k

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let's consider only liquid 1 in this

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container its mole friction X1 is equal

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to 1. now the vapor pressure of pure

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liquid is P1 naught is equal to K into

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its mole friction

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our P1 naught is equal to K N to 1 we

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get P1 naught is equal to K

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that this is equation number two now I

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plug in equation number to n equation

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number one I get P1 is equal to P 1

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naught into its mole friction it means

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that partial vapor pressure of liquid 1

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in a solution is equal to vapor pressure

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of pure liquid 1 and to its mole

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friction

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similarly partial vapor pressure of

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liquid to NS solution is equal to vapor

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pressure of pure liquid number 2 and to

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add small friction in a solution

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therefore we Define route's law as

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partial vapor pressure of a liquid or

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solvent and a solution is equal to the

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vapor pressure of pure solvent and its

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mole friction in a solution

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let me repeat it

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partial vapor pressure of a liquid are

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solvent in a solution is equal to the

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vapor pressure of pure solvent into its

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mole friction in a solution

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thus we learned that routes law explain

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the partial pressure of a volatile

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liquid in a solution

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hence noted down this important concept

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now let me teach you the application of

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routes law

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well consider the solution of liquid

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number one and liquid number two from

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the previous example we know that there

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are two types of volatile liquids in

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this solution we already learned that

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route slow helps us to find the partial

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vapor pressure of liquid number one in a

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solution which is P1 is equal to P1

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naught into its mole friction and routes

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law helps us to find the partial vapor

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pressure of liquid number 2 which is P2

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is equal to P2 not into its small

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friction

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so let me ask you can routes law find

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the total vapor pressure of a solution

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the answer is no route slope cannot

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explain or find the total vapor pressure

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of a solution it can only find or

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explain the partial vapor pressure of

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one liquid or one component in a

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solution

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now the second question is then how can

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we find the total vapor pressure of a

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solution

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well with the help of delton's law we

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can find the total vapor pressure of a

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solution the total vapor pressure of a

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solution is equal to partial vapor

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pressure of first Liquid Plus partial

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vapor pressure of second liquid this

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remember that route slow explains the

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partial vapor pressure of one liquid in

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a solution and delton's law explained

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the total vapor pressure of a solution

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hence noted down this basic difference

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between routes law and deltan's law now

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I will teach you graphical

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representation of routes law let's

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consider two volatile liquids liquid

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number one and liquid number two

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let liquid number one is more volatile

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than liquid number two according to

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routes law vapor pressure of quid number

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one P1 is directly proportional to its

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mole friction

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similarly vapor pressure of quid number

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two P2 is directly proportional to its

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mole friction

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now I will teach you the graph of routes

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law using my personal method I draw two

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vertical arrows or y-axis we take vapor

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pressure on y-axis

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secondly I draw a horizontal line or x

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axis

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we take more friction on x-axis

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that this is the left side and this is

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the right side of x-axis

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let I take more friction of first liquid

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at left side and more friction of second

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liquid at the right side

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now I will write some important points

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believe me no one can teach you these

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magic lines

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I write from left to right along x axis

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mole friction of first liquid decreases

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we know that when mole friction

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decreases partial vapor pressure P1 also

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decreases

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if more friction are first liquid X1 is

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1 here then mole friction of first

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liquid is 0 there because it is

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constantly decreasing along x axis

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now this is the vapor pressure of first

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liquid which is P1 naught we know that

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both friction of first liquid decreases

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from left to right

play16:27

here partial vapor pressure P1 also

play16:31

decreases and we get this straight line

play16:34

it is partial vapor pressure P1 of

play16:38

liquid one

play16:39

secondly from left to right mole

play16:42

friction of secant liquid increases we

play16:45

know that if more friction of second

play16:47

liquid is 0 here then its mole friction

play16:50

is 1 there

play16:52

we also know that pure vapor pressure of

play16:55

secret liquid P1 naught is here because

play16:59

it is less volatile than first liquid

play17:02

now from left to right mole friction or

play17:05

second liquid increases hence partial

play17:08

vapor pressure of second liquid also

play17:10

increases

play17:11

I draw this straight line it is the

play17:14

partial vapor pressure P2 of liquid

play17:17

number two now what about total vapor

play17:20

pressure of the solution

play17:22

well this is the total vapor pressure of

play17:25

the solution e total is equal to T1 plus

play17:29

P2

play17:30

hence rotate down this graphical

play17:32

representation of routes law

play17:35

finally let me teach you some important

play17:37

numerical problems from je main exam

play17:40

consider this question 18 gram of

play17:43

glucose is added to

play17:46

178.2 gram water find the vapor pressure

play17:49

of water and Tor for the aqueous

play17:52

solution firstly I write the given data

play17:55

the given mass of glucose is 18 gram and

play17:59

the given mass of water is

play18:01

178.2 gram here is one important fact

play18:04

which you must know and it is not given

play18:07

in the question the vapor pressure of

play18:10

pure water PW naught is equal to

play18:14

760 torr now according to routes law

play18:17

partial vapor pressure of water in this

play18:20

aqueous solution is PW is equal to its

play18:24

pure pressure and to its mole friction

play18:27

our PW is equal to PW naught N2 number

play18:33

of moles of water upon number of moles

play18:36

of water plus number of moles of glucose

play18:39

here I will calculate the molar mass of

play18:42

glucose and molar mass of water the

play18:45

molar mass of glucose is equal to 6

play18:48

carbon plus 12 hydrogen plus 6 oxygen R

play18:51

6 into 12 plus 12 into 1 plus 6 into 16.

play18:56

I get 180 gram per mole we know that the

play19:01

molar mass of water is 18 gram per mole

play19:04

now I will calculate the number of moles

play19:07

the number of moles of glucose is equal

play19:09

to given Mass which is 18 gram upon

play19:13

molar mass which is 180 gram per mole

play19:17

after calculation I get 0.1 mole

play19:21

secondly the number of moles of water is

play19:24

equal to

play19:26

178.2 gram upon 18 gram per mole after

play19:31

calculation I get

play19:33

9.9 moles now we know that the vapor

play19:38

pressure of pure water PW naught which

play19:41

is 760 tall

play19:44

secondly we know that the number of

play19:47

moles of water and wo which is 9.9 mole

play19:51

thirdly we know that the number of moles

play19:54

of glucose NG which is 0.1 mole

play19:58

so I will plug in all these three values

play20:01

in this equation

play20:03

after calculation I get

play20:07

752.4 tar

play20:09

hence the partial vapor pressure of

play20:11

water and this solution is

play20:15

752.4 tall

play20:17

so note it down this important numerical

play20:19

problem

play20:21

finally consider this another question

play20:23

from je main exam

play20:26

the vapor pressure of ethanol and

play20:28

methanol are 44.5 and 88.7 mmhg an ideal

play20:35

solution is formed by mixing 60 gram of

play20:38

ethanol and 40 gram of methanol at the

play20:41

same temperature calculate the total

play20:43

vapor pressure of the solution

play20:46

well I write the given data the given

play20:49

vapor pressure of pure ethanol p e

play20:52

naught is equal to

play20:54

44.5 mm he the given vapor pressure of

play20:58

pure methanol PM naught is equal to

play21:02

88.7 mm HG

play21:05

the given mass of ethanol is 60 gram and

play21:08

the given mass of methanol is 40 Gram

play21:11

now the required value is the total

play21:13

vapor pressure of solution we know that

play21:16

total vapor pressure is equal to partial

play21:20

pressure of ethanol plus partial

play21:22

pressure of methanol

play21:24

no I will find the molar mass of ethanol

play21:27

and methanol we know that the molar mass

play21:30

of ethanol is

play21:32

c2h5oh two carbon plus 5 hydrogen plus

play21:36

oxygen plus hydrogen 2 into 12 plus 5

play21:40

into 1 plus 16 plus 1 I get 46 gram per

play21:46

mole

play21:47

secondly the molar mass of methanol is

play21:50

carbon plus three hydrogen plus oxygen

play21:52

plus hydrogen are 12 plus 3 into 1 plus

play21:56

16 plus 1 which is equal to 32 gram per

play22:00

mole now I will find the number of moles

play22:03

the number of moles of ethanol is equal

play22:06

to given Mass which is 60 gram upon

play22:09

molar mass which is 46 gram per mole I

play22:13

get 1.3 mole the number of moles of

play22:16

methanol is equal to given Mass which is

play22:19

40 gram upon molar mass which is 32 gram

play22:23

per mole I get 1.25 mole now I will find

play22:28

the partial vapor pressure of ethanol PE

play22:30

which is equal to p e naught into its

play22:34

mole friction

play22:35

our PE is equal to p e naught number of

play22:39

moles of ethanol upon total number of

play22:42

moles

play22:43

we know that vapor pressure of pure

play22:45

ethanol is 44.5 mm-hg the number of

play22:50

moles of ethanol is 1.25 upon total

play22:54

number of moles

play22:56

after calculation I get partial vapor

play22:59

pressure of ethanol is equal to

play23:03

21.8 mmhg

play23:05

secondly I find the partial vapor

play23:08

pressure of methanol PM which is equal

play23:12

to PM naught and to its mole friction

play23:15

RPM is equal to PM naught and to number

play23:19

of moles of methanol upon total number

play23:21

of moles we know that the vapor pressure

play23:25

of pure methanol is 88.7 number of moles

play23:29

of methanol is 1.3 upon total number of

play23:32

moles

play23:33

after calculation I get partial vapor

play23:37

pressure of methanol is equal to

play23:41

44.35 mm HG

play23:43

finally I put partial vapor pressure of

play23:47

ethanol and partial vapor pressure of

play23:49

methanol and this equation number one I

play23:52

write total vapor pressure of the

play23:55

solution is equal to

play23:56

21.8 mm-hg plus

play24:00

44.35 mmhg after calculation I get

play24:07

66.15 mmh GE thus the total vapor

play24:11

pressure of this solution is

play24:14

66.15 mmhg hence noted down the second

play24:18

numerical problem

play24:20

I hope that you have learned all about

play24:23

vapor pressure and routes law

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Ähnliche Tags
Vapor PressureEvaporationRaoult's LawChemistry BasicsMole FractionPartial PressureLiquid SolutionsIntermolecular ForcesEquilibrium StateChemical Properties
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