Description and Derivation of the Navier-Stokes Equations
Summary
TLDRThis educational video script delves into the Navier-Stokes equations, crucial for understanding fluid dynamics. It simplifies the complex equations by illustrating their physical meaning and mathematical derivation from Newton's second law. The script explains how these equations, which describe the motion of fluid particles, are derived from the balance of forces including gravity, pressure differences, and viscosity. It also clarifies the distinction between local and convective accelerations, and how the equations are applied to different directions. The script demystifies the intimidating equations, emphasizing their fundamental role in expressing the principle that the sum of forces equals mass times acceleration.
Takeaways
- ๐ The Navier-Stokes equations are fundamental in fluid dynamics, expressing the balance of forces acting on a fluid element in motion.
- ๐ These equations are derived from Newton's second law, which states that the sum of forces equals mass times acceleration, applied to an infinitesimal fluid element.
- ๐งฎ The equations are comprised of terms representing forces due to gravity, pressure differences, and fluid viscosity, all on a per unit volume basis.
- ๐ The script focuses on the x-direction for simplicity, but the principles extend to y and z directions, resulting in three-dimensional equations.
- ๐ The acceleration term in the equations is broken down into local acceleration (rate of change of velocity at a point) and convective acceleration (due to the motion of the fluid element).
- ๐ A physical interpretation of convective acceleration is provided through the example of fluid flow through a constriction, illustrating how velocity gradients lead to acceleration or deceleration.
- ๐ The forces on a fluid element are detailed, including gravity, normal stresses, and shear stresses, which are crucial for establishing the differential form of the equations.
- ๐ The script explains the transition from the force balance equations to the Navier-Stokes equations through algebraic manipulations and the use of constitutive relations for Newtonian fluids.
- โ๏ธ The importance of the continuity equation is highlighted, showing how it simplifies the Navier-Stokes equations, especially for incompressible fluids.
- ๐ The final form of the Navier-Stokes equations is presented, emphasizing that despite their complexity, they essentially encapsulate the principle of force balance in fluid dynamics.
Q & A
What are the Navier-Stokes equations?
-The Navier-Stokes equations are a set of nonlinear partial differential equations that describe the motion of fluid substances, including the effects of viscosity and gravity.
How are the Navier-Stokes equations derived?
-The equations are derived from applying Newton's second law to a fluid element, considering the forces due to gravity, pressure differences, and viscosity.
What does the term 'local acceleration' refer to in the context of the Navier-Stokes equations?
-The 'local acceleration' term refers to the rate of change of velocity at a specific point in the fluid, which is the time derivative of the velocity component.
What is meant by 'convective acceleration' in the script?
-Convective acceleration refers to the acceleration of a fluid element as it is carried along by the bulk motion of the fluid, which is represented by the spatial derivatives of the velocity components.
How does the script explain the physical meaning of the terms in the Navier-Stokes equations?
-The script explains that the terms in the Navier-Stokes equations represent the sum of forces (gravity, pressure, and viscosity) acting on a fluid element, equated to the mass times the acceleration of that element.
What is the significance of the differential element in the Navier-Stokes equations?
-The differential element is an infinitesimally small volume of fluid used to model the fluid's behavior. It allows the equations to be applied locally, making the analysis more general and applicable to any point in the fluid.
What role does the continuity equation play in the Navier-Stokes equations?
-The continuity equation, which states that the sum of the spatial derivatives of the velocity components is zero for incompressible fluids, simplifies the Navier-Stokes equations by eliminating certain terms.
How does the script simplify the forces acting on a differential element of fluid?
-The script simplifies the forces by considering gravity, normal stresses, and shear stresses acting on the faces of the differential element and then equating the sum of these forces to the mass times the acceleration of the fluid element.
What is the significance of the constitutive relations for a Newtonian fluid in the Navier-Stokes equations?
-The constitutive relations relate the normal and shear stresses in the fluid to its viscosity and velocity profiles. They are essential for transforming the equations of motion into the Navier-Stokes equations.
How does the script demonstrate the transition from the equations of motion to the Navier-Stokes equations?
-The script demonstrates this transition through a series of algebraic manipulations, including substitutions and differentiations, that incorporate the effects of gravity, pressure, and viscosity into the equations.
What is the final form of the Navier-Stokes equations presented in the script?
-The final form of the Navier-Stokes equations presented in the script is an expression of the sum of forces (gravity, pressure, and viscosity) equal to the density of the fluid times its acceleration, including both local and convective components.
Outlines
๐ Introduction to the Navier-Stokes Equations
The video script begins with an exploration of the Navier-Stokes equations, which are fundamental in fluid dynamics. These equations are presented in a way that emphasizes their physical meaning, showing that they are essentially a statement of Newton's second law, which equates the sum of forces to mass times acceleration. The script clarifies that the equations are written for an infinitesimally small fluid element, and it explains the three forces involved: gravity, pressure differences, and fluid viscosity. The script then focuses on the x-direction for simplicity, discussing the mathematical derivation of the equations using the chain rule and the concept of acceleration, which includes both local and convective components. The physical interpretation of convective acceleration is illustrated through an example of fluid flowing through a constriction, where the fluid element's velocity changes due to the constriction.
๐ Analyzing Forces and Stresses on a Fluid Element
In the second paragraph, the script delves into a more detailed analysis of the forces acting on a differential element of fluid. It discusses the forces due to gravity, normal stresses, and shear stresses, and how these forces are represented mathematically. The forces are broken down into components acting on the faces of the fluid element, and the script uses the notation Sigma and Tau to represent these stresses. The forces are then equated to the mass times the acceleration of the fluid element in the x-direction. The script simplifies the equation by canceling out terms and eventually arrives at a differential form that represents the sum of forces due to gravity, normal forces, and shear stresses. This leads to the equations of motion for a fluid, which are a precursor to the Navier-Stokes equations.
๐งฉ Deriving the Navier-Stokes Equations
The final paragraph of the script focuses on the derivation of the Navier-Stokes equations from the equations of motion. It mentions the need for constitutive relations to relate the stresses to the fluid's viscosity and velocity profiles, which are specific to Newtonian fluids. The script outlines a series of algebraic manipulations that lead to the Navier-Stokes equations. It emphasizes that the equations are a statement of the sum of forces equal to mass times acceleration, and it simplifies the equations by incorporating the local and convective components of acceleration. The script concludes by reiterating that despite their complexity, the Navier-Stokes equations can be summarized as an expression of Newton's second law for fluid dynamics.
Mindmap
Keywords
๐กNavier-Stokes Equations
๐กNewton's Second Law
๐กDifferential Element
๐กFluid Viscosity
๐กShear Stress
๐กNormal Stress
๐กAcceleration
๐กConvective Acceleration
๐กContinuity Equation
๐กConstitutive Relations
Highlights
The Navier-Stokes equations are derived from Newton's second law, expressing the balance of forces as mass times acceleration.
The equations are written for an infinitesimally small differential element of fluid, representing fluid dynamics at a local level.
Three forces are considered in the Navier-Stokes equations: gravity, pressure differences, and fluid viscosity.
The force terms are expressed per unit volume, emphasizing the local nature of the forces acting on the fluid.
The derivation begins by focusing on the x-direction to simplify the explanation, with the understanding that similar logic applies to y and z directions.
The acceleration of the fluid is described using the time derivative of the velocity component, incorporating the chain rule for partial derivatives.
Local acceleration is the rate of change of velocity at a point, while convective acceleration accounts for the movement of fluid elements.
A physical interpretation of convective acceleration is provided through the example of fluid flowing through a constriction.
The forces due to gravity are calculated by considering the mass of the fluid element and the gravitational acceleration component.
Normal and shear stresses on the faces of the fluid element are considered, contributing to the forces acting on the fluid.
The sum of forces is equated to the mass times the acceleration, leading to an expression that includes gravity, pressure, and viscous forces.
The derivation simplifies to a differential form as the volume of the fluid element approaches zero, resulting in the Navier-Stokes equations.
The continuity equation plays a crucial role, showing that the sum of the velocity gradients in all directions is zero for incompressible fluids.
Constitutive relations for a Newtonian fluid are used to relate stresses to the viscosity and velocity profiles, although not detailed in this screencast.
Algebraic manipulations are performed to transform the force balance equation into the familiar form of the Navier-Stokes equations.
The final form of the Navier-Stokes equations expresses the sum of forces due to gravity, pressure, and viscosity as equal to the mass times the fluid's acceleration.
The Navier-Stokes equations, despite their complexity, fundamentally describe the relationship between forces and acceleration in fluid dynamics.
Transcripts
these are the navier-stokes equations as
they're commonly written in this
screencast we examine their physical
meaning and perform a simple
mathematical derivation based on
Newton's second law while these
equations may look intimidating and
complicated to a lot of people all they
really are is a statement that the sum
of forces is equal to the mass times the
acceleration to make it a little bit
more apparent let's flip the equations
about the equal sign so what we have in
the first equation is the sum of forces
in the x-direction is equal to the mass
times the acceleration in the
x-direction in the second and third
equations of the some forces in the Y
and Z Direction equal to their
respective accelerations these equations
are written for a differential element
of fluid which is infinitesimally small
so as small as we can possibly imagine
the three forces we're concerned with of
forces due to gravity forces due to
differences in pressure and forces due
to the viscosity of the fluid keep in
mind that each of these terms is on a
per unit volume basis so typically we
would say the force due to gravity might
be the weight of something if I took the
weight and divided by the volume what
I'm left with is the density M over V
times gravity we see this occurring for
gravity most explicitly on the
right-hand side of the equation if we
have mass times acceleration if we were
to divide that by the volume of the
fluid we would be left with the density
times the acceleration so we're looking
at the sum of forces is equal to MA on a
per unit volume basis for this
screencast let's deal only with the
x-direction the same mathematics would
apply for the Y in the Z directions but
we'll leave it with two the X direction
to save time let's examine the
right-hand side of the X component the X
component of velocity for a fluid we'll
call it lower case U and strictly
speaking you could be a function of X Y
Z and time the X component of
acceleration for the fluid is equal to
the time derivative of U is a derivative
of U with respect to time but because U
is not simply a function of time it's
also a function of XY and Z we need to
use the chain rule to perform this
differentiation
so I'm going to do the partial you with
respect to time plus D u DX times DX DT
Plus D u dy dy DT Plus D u DZ times DZ
DT if I use the definition that DX DT
simply equal to u dy DT is equal to
lowercase V and DZ DT is equal to
lowercase W we're left with something
that looks an awful lot like the
right-hand side of the equation above
the first term on the right hand side is
known as a local acceleration and the
remaining three terms are known as the
convective acceleration to think about
what this means physically let's
consider some fluid that's flowing
steadily from left to right through this
two dimensional constriction and let's
consider a differential element of fluid
which will be infinitesimally small so
I'll make it a real small cube and let's
place it right here to begin with if you
think about the motion of this element
to fluid as it flows through it's
flowing steadily from left to right it's
slow in this region but then it begins
to accelerate because of the
constriction where the fluid is moving
very rapidly here and now when it
reaches the right hand side it slows
down again and it recovers to a steady
velocity as it moves towards the exit if
the flow of fluid is at steady state
then the velocity of the differential
element to fluid at points one two and
three we'd see no change over time but
let's examine the constricting region
we've got U is a positive quantity it's
moving from left to right and D U DX is
also a positive quantity so this term of
the convective acceleration is greater
than zero so we see in the highlighted
region that the fluid element is
accelerating from left to right
conversely in the expanding region
although U is positive D u DX is less
than zero it's a negative quantity the
fluid is slowing down within that region
so the convective acceleration term is
less than zero or it would be the
acceleration would be to the left in the
highlighted read
let's examine the forces acting on the
differential element to fluid a little
bit more carefully call this point XY Z
in our differential element two flew it
has length DX a height dy and a depth DZ
the first force will consider is gravity
and typically when you draw a free body
diagram gravity will be acting downward
in the Y direction but let's do an
arbitrary case where a component of
gravity could for example could act in
the X direction so the force due to
gravity is the mass of our differential
element two fluid times the X component
of gravity let's rewrite the mass is
equal to the density times the volume of
our differential element two fluid DX dy
DZ so again have the mass times gravity
in the X direction let's examine forces
acting on the left and the right sides
of our differential element we could
have a normal stress acting directly to
the right on the right face and a stress
acting to the left outward from the left
face the notation we'll use for these
stresses is Sigma xx and we're going to
evaluate Sigma xx at X plus a distance
DX and on the left face we have Sigma X
X evaluated at X on the top and the
bottom faces we could have a shear
stress acting to the right on the top
face and a shear stress acting to the
left on the bottom face the notation
we'll use for these stresses is tau YX
evaluated at y plus dy for the top of
the cube and tau YX evaluated at Y for
the bottom of the cube and additionally
we could have stresses acting to the
right on the front of the cube and a
stress acting to the left at the back of
the cube for the back of the cube we'll
use the notation tau ZX evaluated at Z
and at the front of the queue we'll use
the notation tau ZX evaluated at Z plus
DZ so continue writing the sum forces in
x-direction I've got any X component of
gravity plus a normal stress Sigma X X
evaluated at X plus DX multiplied by the
surface area of the right side of the
cube which is equal to dy DZ because it
acts to the left I'll subtract Sigma X X
evaluated at X multiplied by the same
area dy DZ
then I'll add the force due to the shear
stress at the top of the cube tau YX
evaluated at y plus dy multiplied by its
area which is DX times DC I'll subtract
the shear stress acting on the bottom
face multiplied by its area then I'll
add the force due to the shear stress at
the front of the face and subtract off
the shear stress acting at the rear face
the sum of these forces will equal the
mass times the acceleration in the X
direction or I could write mass is equal
to Rho times DX dy DZ times the
acceleration in the X direction you have
cleaned up that equation divided by the
volume of the differential element and
what I immediately see is that DX dy DZ
Zwilling out and in some terms if I
simplify a dy and DZ will cancel out DX
cancels out as well as DZ in this term
and so forth as I cancel out terms as I
continue to simplify am left on the neck
with this expression and in the limit of
DX dy and DZ are approaching zero this
turns into a differential form and the
resulting equation represents the sum of
forces in the x-direction due to gravity
due to the normal forces acting on the
left and the right side of the
differential element the shear stresses
acting on the top and the bottom of the
element and the shear stresses acting in
the front in the rear faces of the
element so these are equal to the
density times the acceleration of the
differential element in the X direction
and if I expand the
raishin into its local and convective
components were left with the an
expression on the right hand side if I
did the same analysis for the Y and the
Z directions I would come up with these
three equations which are known as the
equations of motion for a fluid but to
get from these equations to the
navier-stokes equations we need a way to
relate the normal and the shear stresses
to the viscosity of the fluid and the
velocity profiles and this is done using
these equations which are the
constitutive relations for a Newtonian
fluid which we won't get into here but
if we accept them as being true for this
screencast becomes a series of algebraic
manipulations to arrive at the
navier-stokes equation the first
substitution into the left hand side
gives me the expression at the bottom if
I differentiate the three terms I'm left
with this expression and some additional
manipulations leaves me with this
expression in which I've split this term
into two parts and I've switched the
order in which I differentiate these two
terms so I'm switching dy/dx and DD and
this expression as I continue to
simplify and rearrange terms I'm left
with this expression but what's
interesting is the sum of these three
terms D u DX plus DV dy plus DW DZ is
equal to zero by way of the continuity
equation so that whole term on the right
is identically zero for an
incompressible fluid so what I'm left
with the sum is three forces the force
due to gravity force due to any pressure
differences in the fluid plus all the
forces due to viscosity the sum of these
three is equal to the density of the
fluid multiplied by the X component of
its acceleration and expanding a X out
into its local and convective components
of acceleration I've just arrived at the
first the X component for the
navier-stokes equation so we could do
the exact same thing for the Y and the Z
directions it will arrive at the
navier-stokes equations for those
directions as well if I flip the order
of the equations you're left with the
navier-stokes equations as you'll
commonly see them
and although they may look intimidating
and complicated to begin with if someone
asks you to sum up what the
navier-stokes equations are in words
just simply tell them they're an
expression of the sum of forces is equal
to the mass times the acceleration
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