Adding and Subtracting Radical Expressions With Square Roots and Cube Roots
Summary
TLDRThis lesson covers the addition, subtraction, and multiplication of radical expressions. It emphasizes how like terms are essential for adding or subtracting radicals and demonstrates the process of simplifying square and cube roots. The video provides several examples of combining radicals, breaking them down using perfect squares or cubes, and solving equations with distributed terms. Through various problem-solving steps, the video illustrates the importance of simplifying radicals and recognizing when terms can be combined, concluding with an advanced example involving the multiplication of conjugates and expanded expressions.
Takeaways
- đą You can add or subtract radical expressions if they have the same radicals (like terms), such as combining 4â5 + 6â5 into 10â5.
- â Expressions like 4â3 + 6â5 cannot be combined because the radicals are different.
- â When adding or subtracting radical expressions with the same radical, only the coefficients are combined, like simplifying 7â2 - 3â2 + 5â2 into 9â2.
- đą Simplifying radicals can make expressions combinable, such as breaking down â8 and â18 to form like terms â2, allowing the expressions to be combined.
- âïž Radicals like â12, â27, and â48 can be simplified into common radicals (like â3), which allows terms to be combined, yielding a result like 9â3.
- 𧟠Cube roots can be handled similarly, and simplification to like terms (such as cube root of 2) makes combining expressions possible.
- đ Distributive property applies when multiplying radical expressions, such as in (â3)(7 + â3), which simplifies through distribution.
- 𧩠Multiplying conjugates (like 4 - â6 and 4 + â6) eliminates the middle terms, simplifying the result.
- đ For expressions like (2 + â3)ÂČ, fully expanding by using FOIL helps combine the middle terms and results in simplified answers.
- đą Complex problems involving radicals raised to powers can be simplified step-by-step using FOIL and multiplication, as shown with (4â3 + 2)Âł.
Q & A
What is the sum of 4â5 and 6â5?
-Since both terms have the same radical (â5), you can add the coefficients, 4 and 6. The result is 10â5.
Why can't you add 4â3 and 6â5?
-You can't add 4â3 and 6â5 because their radicals (â3 and â5) are different. You can only combine terms with the same radical.
How would you simplify the expression 7â2 - 3â2 + 5â2?
-Since all the terms have the same radical (â2), you can combine the coefficients. 7 - 3 + 5 equals 9, so the answer is 9â2.
How do you simplify 3â8 - 5â18?
-First, simplify the radicals: â8 becomes 2â2, and â18 becomes 3â2. After that, 3(2â2) = 6â2 and 5(3â2) = 15â2. Finally, subtract: 6â2 - 15â2 = -9â2.
What is the simplified form of 4â12 + 3â27 - 2â48?
-Simplify the radicals: â12 becomes 2â3, â27 becomes 3â3, and â48 becomes 4â3. Then, the expression becomes 8â3 + 9â3 - 8â3. The result is 9â3.
How do you simplify cube roots in expressions like 16^(1/3), 54^(1/3), and 128^(1/3)?
-You break the numbers down into perfect cubes. For example, 16 = 8 * 2, 54 = 27 * 2, and 128 = 64 * 2. Simplify the cube roots, and since all terms share a common radical (Âłâ2), combine the coefficients.
What is the result of multiplying â3 by (7 + â3)?
-Distribute â3: â3 * 7 = 7â3, and â3 * â3 = 3. So, the final answer is 7â3 + 3.
How do you simplify the expression 4â5 * â7 - â3?
-First, multiply 4â5 by â7, which gives 4â35. Then multiply 4â5 by â3, which gives â15. The final expression is 4â35 - â15.
What is the result of multiplying conjugates like (4 - â6)(4 + â6)?
-The middle terms cancel, leaving only 4ÂČ - (â6)ÂČ. This simplifies to 16 - 6, which equals 10.
How do you expand and simplify (5 + â2)ÂČ?
-First, apply the distributive property: (5 + â2)(5 + â2). This results in 25 + 10â2 + 2, which simplifies to 27 + 10â2.
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