FISIKA Kelas 10 - Gerak Melingkar | GIA Academy

GIA Academy
16 Oct 202015:14

Summary

TLDRThis educational video from Digi Academy YouTube channel explores the physics of circular motion, focusing on amusement park rides like Ferris wheels. It explains key concepts such as period, frequency, angular velocity, linear velocity, centripetal acceleration, and centripetal force. The video also covers uniform and non-uniform circular motion, comparing their characteristics and the equations governing them. Practical applications, like gear ratios in engines and connected wheels, are discussed, followed by problem-solving examples to reinforce understanding.

Takeaways

  • 🎢 The video discusses the physics concept of circular motion, specifically centripetal motion, as it relates to amusement park rides like the Ferris wheel.
  • ⏱ The script explains the key terms in circular motion, including period (T), frequency (F), angular velocity (ω), linear velocity (V), centripetal acceleration (a_c), and centripetal force (F_c).
  • 🔗 It establishes the relationship between period and frequency, where T = 1/F and F = 1/T, highlighting that period is measured in seconds and frequency in hertz.
  • 📐 The angular velocity (ω) is defined as the rate of change of the angle per unit time, with the formula ω = 2πf or ω = 2π/T.
  • 🚀 Linear velocity (V) in circular motion is the speed at which an object travels along the circular path, calculated by V = 2πR/T or V = ωR.
  • 🌀 Centripetal acceleration (a_c) is the acceleration directed towards the center of the circle, with the formula a_c = V^2/R = ω^2R.
  • 💥 Centripetal force (F_c) is the force acting towards the center of the circular path, calculated by F_c = m * a_c = m * (V^2/R) = m * ω^2R, where m is the mass of the object.
  • 🔄 The video differentiates between uniform circular motion (UCM) and non-uniform circular motion (NCM), noting that in UCM, the speed is constant but the direction changes, while in NCM, both the speed and direction can change.
  • 🔗 It discusses the application of circular motion principles to gears, explaining the relationship between gears that are meshed, tangent, and connected by a belt.
  • 🔩 The script provides examples of how to calculate the period, frequency, angular velocity, linear velocity, centripetal acceleration, and centripetal force using the formulas introduced.
  • 🎓 The video concludes with a series of problems to help viewers understand the application of circular motion concepts, including the relationship between gears in mechanical systems.

Q & A

  • What is the principle of motion associated with the swing ride in amusement parks?

    -The principle of motion associated with the swing ride is circular motion, which is closely related to the concept of physics known as 'gerak melingkar'.

  • What are the key quantities involved in circular motion?

    -The key quantities involved in circular motion include period (T), frequency (F), angular velocity (ω), linear velocity (V), centripetal acceleration (a_c), and centripetal force (F_c).

  • How is the period of circular motion defined?

    -The period of circular motion is defined as the time required to complete one full rotation.

  • What is the relationship between frequency and period in circular motion?

    -The relationship between frequency (F) and period (T) is given by the equations T = 1/F and F = 1/T, where T is measured in seconds and F is measured in Hertz (Hz).

  • How is angular velocity calculated in circular motion?

    -Angular velocity (ω) is calculated using the formula ω = 2πf or ω = 2π/T, where f is the frequency and T is the period.

  • What is the formula to determine the linear velocity in circular motion?

    -Linear velocity (V) in circular motion is determined by the formula V = 2πr/T or V = ωr, where r is the radius of the circle and ω is the angular velocity.

  • How is centripetal acceleration calculated?

    -Centripetal acceleration (a_c) is calculated using the formula a_c = V^2/r = ω^2r, where V is the linear velocity, ω is the angular velocity, and r is the radius of the circular path.

  • What is the formula for centripetal force in circular motion?

    -Centripetal force (F_c) is determined by the formula F_c = m * a_c = m * (V^2/r) = m * ω^2r, where m is the mass of the object, V is the linear velocity, ω is the angular velocity, and r is the radius.

  • What are the characteristics of uniform circular motion (GMB)?

    -In uniform circular motion (GMB), the path is circular, the magnitude of the angular position is the same in the same time interval, the linear velocity is constant but its direction changes, the angular velocity is constant in both magnitude and direction, and the centripetal acceleration is constant in magnitude with a direction always towards the center of the circle.

  • What is the difference between uniform circular motion and non-uniform circular motion?

    -In uniform circular motion, the speed is constant but the direction changes, whereas in non-uniform circular motion, both the magnitude and direction of the speed change.

  • How are the angular velocities of two wheels connected by an axle related?

    -For two wheels connected by an axle (wheels with the same axis), if they rotate in the same time interval, the angular velocities are the same, i.e., ω_A = ω_B.

  • What is the relationship between the angular velocities of two meshing gears?

    -For two meshing gears, the relationship between their angular velocities is ω_A * r_A = ω_B * r_B, where r_A and r_B are the radii of the gears.

Outlines

00:00

🎢 Physics of Circular Motion in Amusement Parks

This paragraph introduces the concept of circular motion in the context of amusement park rides, specifically the Ferris wheel. It explains that the motion of a Ferris wheel is closely related to the physics of circular motion, which involves an object moving along a circular path at a certain speed. The paragraph outlines key terms and concepts such as period (t), frequency (F), angular velocity (Ω), linear velocity (V), centripetal acceleration (a_c), and centripetal force (F_c). It also discusses the relationships between these variables, such as how period and frequency are inversely related (T = 1/F) and how linear velocity is related to angular velocity and the radius of the circle (V = 2πR/T).

05:00

🔄 Understanding Uniform Circular Motion (UCM) and Non-Uniform Circular Motion (NUCM)

This paragraph delves into the differences between uniform circular motion (UCM) and non-uniform circular motion (NUCM). In UCM, the path is a circle, and the speed, direction of linear velocity, and direction of angular velocity remain constant, while the direction of centripetal acceleration and tangential acceleration changes. The paragraph explains that in UCM, the linear velocity is equal to the angular velocity multiplied by the radius, and the centripetal acceleration is constant. In contrast, NUCM involves a changing speed and direction of linear velocity, angular velocity, and acceleration. The paragraph provides formulas used to describe these motions, such as the relationship between angular velocity and time for UCM (θ = ωt) and the formulas for centripetal and tangential accelerations.

10:02

🔩 Applications of Circular Motion: Gears and Pulleys

The third paragraph explores practical applications of circular motion, focusing on gears and pulleys. It discusses how gears with the same center rotate at the same angular velocity, meaning the angular displacement and velocity are equal for both gears. The paragraph also covers the relationship between gears that are in mesh, where the direction of rotation is opposite but the linear speeds are the same. Examples include the gears in an engine, where the number of teeth on each gear affects the relationship between their angular velocities. The paragraph concludes with a problem-solving approach to understanding the relationships between the angular velocities of different gears and pulleys.

15:04

🎓 Summary and Conclusion on Circular Motion

The final paragraph summarizes the key learnings from the video, which include understanding the various aspects of circular motion, the differences between UCM and NUCM, and their practical applications in gears and pulleys. It emphasizes the importance of knowing the formulas and relationships between the different variables involved in circular motion. The paragraph ends with an invitation for viewers to continue learning by watching the next video in the series.

Mindmap

Keywords

💡Circular Motion

Circular motion refers to the movement of an object along a circular path. In the video, this concept is central as it explains the physics behind various amusement park rides like the Ferris wheel. The script uses circular motion to introduce the principles of physics that govern such rides, emphasizing how objects move in a circle due to the application of centripetal force.

💡Centripetal Force

Centripetal force is the force that pulls an object towards the center of the circular path it is following. It is a key concept in the video as it is responsible for keeping objects moving in a circle, such as in the case of a Ferris wheel. The video script mentions that this force is always directed towards the center of the circle, which is essential for maintaining circular motion.

💡Frequency

Frequency, denoted by the symbol 'F', is the number of cycles or complete rotations that occur in a unit of time. The video script explains the relationship between frequency and the period of circular motion, stating that the frequency is the inverse of the period. This is crucial for understanding how fast an object completes a circular path, such as the rate at which a Ferris wheel rotates.

💡Period

The period, symbolized by 'T', is the time taken for one complete cycle of circular motion. In the context of the video, understanding the period is essential for calculating the speed and frequency of rides in an amusement park. The script provides a formula to calculate the period, which is used to determine how long it takes for an object to complete one full rotation.

💡Angular Velocity

Angular velocity, represented by the Greek letter 'Omega' (Ω), is the rate at which an object rotates around an axis. The video script discusses how angular velocity is calculated and its relationship with the period and frequency. It is used to describe the speed of rotation in circular motion, such as the spinning of a wheel in a ride.

💡Linear Velocity

Linear velocity is the speed at which an object moves along a straight line. In the video, linear velocity is related to circular motion by the formula V = 2πR, where 'V' is the linear velocity, 'R' is the radius of the circle, and 'π' is Pi. This concept is used to explain how fast an object is moving along the circular path, like the speed of a rider on a Ferris wheel at any point.

💡Centripetal Acceleration

Centripetal acceleration is the rate of change of an object's velocity as it moves in a circular path, always directed towards the center of the circle. The video script includes a formula for calculating centripetal acceleration, which is essential for understanding the forces acting on an object in circular motion, such as the sensation of being pushed towards the center of a spinning ride.

💡Uniform Circular Motion (UCM)

Uniform circular motion is a type of circular motion where the speed of the object is constant, though its direction is continuously changing. The video script explains that in UCM, the angular velocity and the magnitude of the centripetal acceleration remain constant, which is important for understanding the consistent motion of objects in rides like carousels.

💡Variable Circular Motion

Variable circular motion occurs when the speed of the object in circular motion changes. The video script contrasts this with uniform circular motion, highlighting that in variable motion, the linear velocity and angular velocity can change, leading to a more dynamic and thrilling experience in amusement park rides, such as roller coasters.

💡Gears

Gears are mechanical components that transfer rotational motion from one axis to another. The video script discusses the relationship between gears, particularly in the context of meshing gears, where the angular velocities of the gears are related. This concept is crucial for understanding how different parts of a machine, like a clock or a car transmission, work in harmony.

💡Torque

Torque is the rotational equivalent of linear force and is essential for understanding how forces can cause rotation. Although not explicitly mentioned in the script, torque is implicitly related to the discussion of gears and circular motion, as it is the force that causes gears to rotate and is a fundamental concept in the physics of rotating systems.

Highlights

Introduction to the concept of circular motion and its relation to physics.

Explanation of circular motion as a movement along a circular path with a certain speed.

Examples of circular motion in everyday life, such as ceiling fans and rotating wheels.

Introduction to the key parameters in circular motion: period, frequency, angular velocity, linear velocity, centripetal acceleration, and centripetal force.

Definition and formula for the period of circular motion.

Definition and formula for frequency and its relationship with the period.

Explanation of angular velocity and its calculation.

Introduction to linear velocity in circular motion and its formula.

Description of centripetal acceleration and its formula.

Explanation of centripetal force and its formula relating to mass, velocity, and radius.

Difference between uniform circular motion (UCM) and non-uniform circular motion (NUCM).

Characteristics and formulas used in uniform circular motion.

Characteristics and formulas used in non-uniform circular motion.

Application of circular motion in gears, explaining the relationship between gears of the same size.

Explanation of the relationship between intersecting gears and their rotational speeds.

Application of circular motion in pulleys, explaining the relationship between the pulleys connected by a belt.

Solving a problem involving the calculation of period and frequency for a rotating machine.

Solving a problem to determine the centripetal force and acceleration for a given mass, velocity, and radius.

Problem-solving involving the relationship between gears with different radii and their angular velocities.

Conclusion summarizing the learnings about circular motion, its types, and applications in mechanical systems.

Transcripts

play00:00

Hai Cinta

play00:06

[Musik]

play00:12

halo halo teman-teman kembali lagi Digi

play00:21

Academy youtube channel Semoga

play00:23

teman-teman selalu sehat dan tetap

play00:25

semangat

play00:27

hai oh iya Pernahkah teman-teman bermain

play00:31

ke taman hiburan di sana teman-teman

play00:33

bakal menemukan wahana permainan yang

play00:36

beragam dan salah satu mainin populer di

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taman hiburan adalah bianglalang tahukah

play00:42

teman-teman bahwa prinsip kerja

play00:44

bianglala sangat erat hubungannya dengan

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konsep fisika yaitu gerak melingkar

play00:50

[Musik]

play00:53

gerak melingkar adalah Gerak suatu benda

play00:57

menempuh lintasan melingkar dengan

play00:59

kecepatan tertentu benda lain yang juga

play01:02

menerapkan konsep gerak melingkar adalah

play01:04

kipas angin yang sedang menyala jarum

play01:07

jam yang bergerak dan komedi putar

play01:12

sebelum kita membahas persamaan dalam

play01:15

gerak melingkar kita perlu ketahui

play01:17

besaran-besaran dalam gerak melingkar

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pertama periode dilambangkan dengan t

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berikut nya frekuensi simbolnya F

play01:26

kecepatan

play01:27

Hai lambangnya Omega posisi sudut

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ditandai dengan Teta kecepatan linier

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simbolnya V selanjutnya percepatan

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sentripetal atau es dan terakhir gaya

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sentripetal atau FS Nah teman-teman

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sekarang kita bahas satu persatu Besaran

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dalam gerak melingkar yang pertama

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periode-periode merupakan waktu yang

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diperlukan untuk melakukan satu putaran

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penuh periode dapat ditentukan dengan

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rumus t = tpn besaran yang kedua

play02:04

frekuensi yang merupakan banyak putaran

play02:06

tiap satuan waktu frekuensi dapat

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dihitung menggunakan persamaan F = NRT

play02:13

dengan t adalah waktu yang satuannya

play02:16

sekon dan n adalah banyak putaran

play02:20

Hai Adapun hubungan antara periode dan

play02:24

frekuensi adalah T = 1 F atau F = 1/3 P

play02:31

adalah simbol periode satuannya sekon

play02:34

dan F lambang dari frekuensi satuannya

play02:37

Heart

play02:40

Hai besaran berikutnya adalah posisi

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sudut yaitu besar sudut yang ditempuh

play02:45

tiap satuan waktu rumus untuk menentukan

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besarnya posisi sudut adalah theta =

play02:51

Omega t = 2P FT = 2 pi-tpt teta

play02:58

merupakan posisi sudut dalam radian

play03:00

Omega adalah kecepatan sudut satuannya

play03:03

Radian per sekon dan t waktu satuannya

play03:06

sekon besaran selanjutnya adalah

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kecepatan sudut kecepatan sudut

play03:15

merupakan besar sudut yang ditempuh tiap

play03:17

satuan waktu kecepatan sudut dihitung

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dengan rumus Omega = 2pf atau dua

play03:25

fibertech Omega adalah kecepatan sudut

play03:28

satuannya Radian per sekon frekuensi

play03:30

dalam khas Dante periode satuannya sekon

play03:36

Hai kemudian kecepatan linier kecepatan

play03:40

linier adalah kecepatan benda untuk

play03:42

mengelilingi lingkaran arah kecepatan

play03:45

linier selalu menyinggung Sisi lingkaran

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kecepatan linear V = 2P ver atau V = 2P

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RT = Omega Mega er dengan v adalah

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kecepatan linier satuannya meter per

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sekon Omega kecepatan sudut dalam radian

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per sekon dan R adalah jari-jari

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lingkaran satuannya

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hai lalu ada besaran percepatan

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sentripetal percepatan sentripetal

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disebabkan oleh adanya gaya yang selalu

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menuju pusat lingkaran rumus percepatan

play04:22

sentripetal adalah a s = v kuadrat per R

play04:26

= Omega kuadrat er Asada lah percepatan

play04:31

sentripetal satuannya meter per sekon

play04:33

kuadrat V merupakan kecepatan linier

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satuannya meter per sekon Omega

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kecepatan sudut dalam satuan radian per

play04:41

sekon dan besaran yang terakhir adalah

play04:44

gaya sentripetal yaitu gaya yang arahnya

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selalu menuju pusat lingkaran dan tegak

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lurus dengan vektor kecepatan linier

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gaya sentripetal ditentukan dengan

play04:55

menggunakan persamaan FX = m a s = MV

play05:00

kuadrat per r = m Omega kuadrat rev1

play05:05

dalah gaya sentripetal satuannya n m

play05:08

adalah massa benda dalam kg ASP

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kecepatan sentripetal dalam meter per

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sekon kuadrat Nah itulah besaran-besaran

play05:18

dalam gerak melingkar oke Ya teman-teman

play05:22

gerak melingkar merupakan jenis gerak

play05:25

yang mirip namun tidak sama dengan gerak

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lurus perbedaannya terdapat pada jenis

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lintasannya jika pada gerak lurus

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terdapat gerak lurus berubah beraturan

play05:34

atau GLBB maka pada gerak melingkar juga

play05:38

terdapat gerak melingkar berubah

play05:39

beraturan atau GLBB besaran pada kedua

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gerak ini memiliki hubungan yaitu

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kecepatan linier sama dengan kecepatan

play05:48

sudut kali jari-jari percepatan linier

play05:51

sama dengan percepatan sudut kali

play05:53

jari-jari dan posisi sama dengan posisi

play05:56

sudut kali jari-jari sampai di sini bisa

play06:00

dipahami ya selanjutnya kita akan

play06:05

membahas gerak melingkar beraturan atau

play06:08

GMB Adapun ciri-ciri GMB adalah

play06:11

berikut lintasannya berbentuk lingkaran

play06:14

dalam selang waktu yang sama besar

play06:17

posisi sudutnya sama besar kecepatan

play06:19

linier tetap tapi arahnya berubah besar

play06:23

dan arah kecepatan sudutnya tetap besar

play06:26

dan arah percepatan sentripetalnya tetap

play06:28

besar percepatan tangensialnya sama

play06:31

dengan nol besar percepatan sudutnya

play06:34

sama dengan nol dan yang terakhir besar

play06:36

percepatan total sama dengan percepatan

play06:39

sentripetal berikut persamaan yang

play06:44

digunakan dalam GMB Omega = Delta theta

play06:48

PT Delta theta = Omega t t t kurang T

play06:53

tanol sama dengan Omega t t t = Teta nol

play06:57

tambah Omega tt0 sama dengan posisi

play07:01

sudut awal TT posisi sudut akhir Delta

play07:04

theta perubahan posisi sudut ketiganya

play07:07

dalam radian Omega adalah kecepatan

play07:10

sudut satuannya radian

play07:12

Hai sekon dan t waktu dalam sekon

play07:17

berikutnya gerak melingkar berubah

play07:19

beraturan atau GLBB ciri-cirinya

play07:22

lintasannya berbentuk lingkaran dalam

play07:25

selang waktu yang sama besar posisi

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sudutnya berbeda besar dan arah

play07:29

kecepatan linearnya berubah besar dan

play07:32

arah kecepatan sudutnya berubah besar

play07:35

percepatan sentripetalnya berubah tetapi

play07:37

arahnya tetap besar percepatan

play07:39

tangensialnya tetap tapi arahnya berubah

play07:42

besar dan arah percepatan sudutnya tetap

play07:45

dan terakhir besar percepatan total

play07:47

adalah resultan vektor percepatan

play07:49

sentripetal dengan percepatan tangensial

play07:55

Nah berikut persamaan yang digunakan

play07:57

pada gerak melingkar berubah beraturan

play08:00

Omega nol kecepatan sudut awal dan

play08:03

omega-3 kecepatan sudut akhir dalam

play08:06

radian per sekon Alpha percepatan sudut

play08:09

satuannya Radian per sekon kuadrat t

play08:12

posisi sudut dalam radian t adalah waktu

play08:14

satuannya sekon Ate percepatan

play08:17

tangensial as percepatan sentripetal

play08:20

atau tal percepatan total dalam meter

play08:23

per sekon kuadrat Sekarang kita akan

play08:28

membahas aplikasi yang terkait dengan

play08:30

gerak melingkar pada roda yang pertama

play08:33

hubungan roda roda sepusat yang dimaksud

play08:36

roda roda sepusat adalah dua roda atau

play08:38

lebih yang berporos sama dan saling

play08:40

menyatu apabila roda roda sepusat

play08:43

diputar dalam selang waktu T maka kedua

play08:46

roda menempuh sudut pusat yang sama

play08:48

sehingga kecepatan sudut pada kedua roda

play08:51

sama dalam hal ini berlaku persamaan

play08:54

Omega a = Omega B sehingga beaber ra = V

play09:00

bbrb

play09:01

Hai yang kedua hubungan roda roda

play09:06

bersinggungan pada roda-roda yang saling

play09:09

bersinggungan arah putar kedua roda

play09:11

berlawanan dan kelajuan liniernya sama

play09:14

fatsamma dengan VB sehingga Omega Ara

play09:18

sama dengan Omega BRB salah satu contoh

play09:22

roda roda bersinggungan yaitu pada roda

play09:24

gigi mesin oleh karena ukuran gigi roda

play09:27

besar dan kecil sama roda yang lebih

play09:30

besar memiliki gigi lebih banyak jika

play09:33

banyak gigi untuk tiap roda dilambangkan

play09:35

dengan n maka hubungan roda gigi yang

play09:38

bersinggungan berlaku persamaan Omega

play09:40

Ana sama dengan Omega bnb yang terakhir

play09:46

hubungan roda-roda setali roda roda yang

play09:50

dihubungkan dengan tali memiliki arah

play09:52

Putar dan laju linier yang sama Dalam

play09:54

keadaan ini berlaku persamaan V = VB

play09:58

Omega a ra = Omega

play10:01

BRB key bisa dimengerti ya teman-teman

play10:07

agar teman-teman lebih paham kita akan

play10:09

membahas beberapa contoh soal-soal

play10:12

pertama Diketahui sebuah mesin berputar

play10:15

120 kali artinya n = 120° waktu yang

play10:22

diperlukan untuk putaran mesin tersebut

play10:24

adalah satu menit waktu satuannya sekon

play10:27

jadi kita ubah terlebih dahulu satuan

play10:30

waktunya satu menit = 60-second yang

play10:34

ditanya periode dan frekuensi untuk

play10:38

menyelesaikan soal ini ingat kembali

play10:40

rumusnya periode atau t = tpn lalu

play10:44

masukkan angkanya tes = 60-second per

play10:48

120 putaran = 0,5 sekon setelah kita

play10:53

dapatkan nilai periode kita bisa

play10:55

menentukan frekuensi dengan menggunakan

play10:57

rumus hubungan periode dan frekuensi

play11:00

yaitu

play11:01

Hai F = 1/3 sehingga F = 1 pernoll koma

play11:07

5 = 2 Heart jadi jawabannya ee ee

play11:14

Hai soal selanjutnya diketahui M = 5 kg

play11:18

V2 meter per sekon dan R 0,5 M pada soal

play11:23

ini kita diminta menentukan pernyataan

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yang benar untuk menjawab soal ini kita

play11:28

bahas satu persatu pernyataan pertama

play11:31

waktu putarnya adalah 0,5 phi second

play11:35

artinya t = 0,5 phi second Kita buktikan

play11:40

dengan mencari nilai Omega terlebih

play11:42

dahulu dengan persamaan Omega = V PR =

play11:48

2005 = 4 Radian per sekon kemudian kita

play11:52

gunakan rumus Omega 2.ppt untuk

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menentukan nilai T sehingga tes = 2

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piper Omega = 2P 4 = 0,5 phi second

play12:06

artinya pernyataan pertama benar

play12:09

selanjutnya pernyataan kedua besar

play12:13

percepatan

play12:14

tanya ksama dengan delapan meter per

play12:17

sekon kuadrat percepatan sentripetal

play12:20

dapat dihitung menggunakan rumus as = p

play12:23

kuadrat per R2 kuadrat per 0,5 sama

play12:27

dengan 40 koma 5 = 8 meter per sekon

play12:32

kuadrat pernyataan yang kedua juga benar

play12:36

kemudian pernyataan ketiga gaya

play12:39

sentripetalnya FS sama dengan 40 n gaya

play12:44

sentripetal dihitung dengan menggunakan

play12:46

persamaan f = m * s lima kali 8 = 40 n

play12:53

jadi pernyataan ketiga benar yang

play12:57

terakhir Factor kecepatannya tidak tetap

play13:00

dalam gerak melingkar beraturan besar

play13:02

atau nilai kecepatannya tetap tapi

play13:05

arahnya berubah selalu tegak lurus

play13:07

dengan gaya sentripetal jadi pernyataan

play13:11

keempat juga

play13:14

di Jawa banyak a lalu soal terakhir soal

play13:20

tentang hubungan roda-roda diketahui ra

play13:23

= 20 cm kita ubah ke m menjadi 0,2 m RB

play13:29

= 8 cm = 0,008 m r c = 4 cm = 0,04 m

play13:39

kemudian Omega B = 10 Radian per sekon

play13:44

yang ditanya Omega C roda A dan roda B

play13:48

sepusat roda roda sepusat kecepatan

play13:51

sudutnya sama sehingga Omega a = Omega B

play13:55

yaitu 10 Radian per sekon Fea bisa kita

play13:59

tentukan dengan rumus ra kali Omega a =

play14:03

0,2 kali 10 = 2 meter per sekon kemudian

play14:08

perhatikan roda A dan roda c yang

play14:11

dihubungkan dengan tali sehingga VC

play14:14

sama dengan v a yaitu dua meter per

play14:17

sekon kecepatan sudut di roda C Omega C

play14:20

dapat kita hitung dengan rumus Omega c =

play14:24

v cprc 2per 0,04 sama dengan 50 Radian

play14:30

per sekon jadi jawabannya

play14:35

Hai Nah berarti di video kali ini kita

play14:38

udah belajar tentang besaran gerak

play14:40

melingkar jenis-jenis gerak melingkar

play14:43

ada gmbg MB dan aplikasi gerak melingkar

play14:47

hubungan roda roda sepusat bersinggungan

play14:50

dan sekali Oke teman-teman sampai di

play14:55

sini bisa dipahami ya jangan lupa tonton

play14:58

video berikutnya sampai jumpa

play15:04

[Musik]

play15:09

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