Minority charge carriers in extrinsic semiconductors | Class 12 (India) | Physics | Khan Academy
Summary
TLDRThe script delves into the nuances of semiconductor doping, explaining how the addition of impurities like phosphorus (for n-type) or boron (for p-type) dramatically alters the material's conductive properties. It addresses questions about the band structure changes due to doping and clarifies why the intrinsic band structure remains applicable. The script also explores the math behind doping, showing how even a low concentration of dopants significantly increases free electrons and decreases holes, leading to a million-fold change in carrier concentration and emphasizing the unique properties of semiconductors that enable such manipulation.
Takeaways
- π Semiconductors can be altered by adding impurities, creating either n-type (with more electrons) or p-type (with more holes) materials.
- π¬ Phosphorus, a group 15 element, when added to a semiconductor like silicon, donates an extra electron, resulting in an n-type semiconductor.
- π¬ Boron, a group 13 element, when added, accepts electrons, creating more holes and resulting in a p-type semiconductor.
- π The band structure of a semiconductor is influenced by the material's composition, but the addition of a low concentration of impurities does not significantly change the overall band structure.
- π Even though phosphorus atoms are added, their atomic orbitals do not overlap significantly due to the low doping concentration, maintaining the discrete energy level.
- π’ The doping concentration is typically very low, with about one phosphorus atom for every million silicon atoms, often referred to as 1 ppm (parts per million).
- π The effect of doping is dramatic; a low concentration of impurities can drastically increase the number of charge carriers, such as electrons in n-type semiconductors.
- π In intrinsic semiconductors, the number of electrons and holes are equal, but in extrinsic semiconductors, the number of electrons can increase significantly while the number of holes decreases.
- 𧩠The recombination rate, which is the product of the number of electrons and holes, must balance the generation rate to maintain thermal equilibrium in semiconductors.
- π The addition of impurities like phosphorus not only increases the number of electrons but also significantly reduces the number of holes, leading to a drastic change in the semiconductor's properties.
- π The ability to manipulate semiconductor properties through doping is unique to semiconductors and is a key reason for their use in various electronic devices and technologies.
Q & A
What is an intrinsic semiconductor?
-An intrinsic semiconductor is a pure semiconductor material that is undoped, meaning it does not have any impurities added to it. It has an equal number of electrons and holes, making it a neutral conductor with limited conductivity that can be manipulated through doping.
What is the role of phosphorus in an n-type semiconductor?
-Phosphorus, being a group 15 element with five valence electrons, is added to a semiconductor like silicon to create an n-type semiconductor. It donates its extra electron, increasing the number of negatively charged conduction electrons significantly compared to holes.
How does doping with boron create a p-type semiconductor?
-Boron, a group 13 element with three valence electrons, is added to a semiconductor to create a p-type semiconductor. It can accept electrons, leading to an increase in the number of holes, which are positive charge carriers.
Why does the band structure of an extrinsic semiconductor remain similar to the pure material?
-The band structure of an extrinsic semiconductor remains similar to the pure material because the doping concentration is kept very low. This means that the impurity atoms are sparsely distributed among the semiconductor atoms, and their effect on the overall band structure is minimal.
Why don't we consider the band structure of the dopant like phosphorus in an n-type semiconductor?
-The band structure of the dopant is not considered because the dopant atoms are so far apart that their atomic orbitals hardly overlap. The effect of each dopant atom is discrete and localized, justifying the use of a single donor level rather than a band.
What is the significance of the donor level being close to the conduction band in n-type semiconductors?
-The donor level being close to the conduction band allows the extra electrons from the dopant atoms to easily jump into the conduction band, increasing the number of free electrons available for conduction and enhancing the semiconductor's conductivity.
How does the number of electrons change when a semiconductor is doped to become an n-type?
-When a semiconductor is doped to become an n-type, the number of electrons increases dramatically due to the addition of dopant atoms like phosphorus, each contributing an extra electron. Even at a low doping concentration, this results in a significant increase in the number of conduction electrons.
What happens to the number of holes in an n-type semiconductor?
-In an n-type semiconductor, the number of holes decreases significantly due to the increased number of electrons. The higher electron concentration leads to a higher recombination rate, destroying many electron-hole pairs and reducing the hole concentration.
Why is the effect of doping so dramatic even with a low concentration of dopant atoms?
-The effect of doping is dramatic even at low concentrations because the intrinsic semiconductor starts with a relatively low number of charge carriers. Adding even a small number of dopant atoms can significantly alter the balance between electrons and holes, leading to a substantial change in the semiconductor's electrical properties.
How does the ratio of electrons to holes change in an extrinsic semiconductor?
-In an extrinsic semiconductor, the ratio of electrons to holes changes dramatically due to the addition of dopant atoms. For an n-type semiconductor, the number of electrons increases while the number of holes decreases, resulting in a very high ratio of electrons to holes, which can be in the order of millions or more.
Outlines
π¬ Understanding Doping in Semiconductors
This paragraph delves into the concept of doping in semiconductors, explaining how the addition of impurities like phosphorus (a group 15 element) creates an n-type semiconductor with an excess of electrons, while boron (a group 13 element) results in a p-type semiconductor with an excess of holes. The paragraph also addresses the band structure of extrinsic semiconductors, noting that the low concentration of dopants means the band structure of the original material (silicon in this case) remains largely unchanged. It emphasizes the subtle but significant impact of doping on the semiconductor's properties, setting the stage for a deeper exploration of these effects.
π Impact of Doping Concentration on Semiconductor Properties
The second paragraph explores the quantitative effects of doping on semiconductors, particularly focusing on the example of phosphorus doping to create an n-type semiconductor. It explains that even at a low doping concentration of about 1 part per million (1 ppm), the number of electrons increases dramatically from the intrinsic level, resulting in a significant excess of electrons compared to holes. The paragraph also discusses the thermal generation and recombination processes that maintain the equilibrium of electrons and holes in semiconductors, and how these processes are affected by the introduction of dopants, leading to a drastic reduction in the number of holes.
π The Dramatic Effects of Low-Level Doping
The final paragraph highlights the profound impact that even a low level of doping can have on semiconductors. It illustrates how the addition of phosphorus not only increases the number of electrons by a million times but also decreases the number of holes by the same magnitude. This results in an enormous disparity between the number of electrons and holes, demonstrating the sensitivity of semiconductor properties to doping. The paragraph concludes by emphasizing the unique ability to manipulate semiconductor properties through doping, which is not possible with conductors or insulators due to their inherent characteristics.
Mindmap
Keywords
π‘Intrinsic Semiconductor
π‘Extrinsic Semiconductor
π‘Doping
π‘Valence Electrons
π‘n-type Semiconductor
π‘p-type Semiconductor
π‘Donor Level
π‘Acceptor Level
π‘Band Structure
π‘Thermal Generation
π‘Recombination
Highlights
Introduction to the concept of doping semiconductors with impurities to create n-type and p-type semiconductors.
Explanation of how adding phosphorus, a group 15 element, creates n-type semiconductors by donating electrons.
Description of boron, a group 13 element, creating p-type semiconductors by accepting electrons and increasing hole concentration.
Discussion on the subtle questions related to the band structure changes due to doping.
Clarification on why the band structure of the doped material is considered similar to the pure semiconductor.
Insight into the low doping concentration and its impact on the overall band structure.
Explanation of how the atomic orbitals of phosphorus atoms do not significantly overlap due to their sparse distribution.
Analysis of the dramatic increase in the number of electrons in an n-type semiconductor due to doping.
Mathematical illustration of the ratio between silicon atoms and phosphorus atoms in a doped semiconductor.
Comparison of the number of electrons and holes in an intrinsic semiconductor at room temperature.
Calculation of the number of phosphorus atoms in a one-centimeter cube of n-type semiconductor.
Highlighting the significant increase in the number of conduction electrons due to doping.
Discussion on the decrease in the number of holes in an n-type semiconductor and its impact on the material's properties.
Explanation of the generation and recombination processes in semiconductors and their equilibrium state.
Analysis of how the recombination rate changes in an extrinsic semiconductor and its effect on hole concentration.
Conclusion on the drastic change in electron to hole ratio due to low-level doping and its practical implications.
Reflection on the unique properties of semiconductors that allow for such significant changes with minimal doping.
Transcripts
we've seen in previous videos that if
you take an intrinsic or a pure
semiconductor and you add some
impurities like say phosphorus which is
group 15 it has five valence electrons
one more than silicon and as a result it
will end up donating its electrons and
so now you will have a lot more
electrons a lot more negatively charged
conduction electrons compared to holes
and so we call that as an n-type
semiconductor and similarly if you were
to dope with if you had to add a group
13 element like boron which has only
three valence electrons then it can
accept electrons now and as a result you
will have a lot of holes so more
positive type charge carriers so we call
it as p-type semiconductor and we also
saw their band structure and we
understood that the whole thing is
possible because of the donor level
being very close to conduction band the
energy level of that extra electron
being very close as the result electrons
can easily jump and over here the
acceptor level being very close to the
valency band and so we spoke all about
this in previous videos so if you need a
refresher it would be a great idea to go
back and watch those videos and come
back over here
in this video we're not going to learn
more but we'll go deeper into these
impure extrinsic conductors we'll
explore some fantastic and very subtle
questions and eventually we'll also see
the numbers over here i mean we know
over here like there are more electrons
and and less holes but how much more how
much more are these is it 10 times more
100 times more the answer is going to be
mind-boggling all right so let's do it
here's one very subtle question we can
ask remember that the band structure
really depends on which material we're
dealing with silicon has one band
structure and germanium has another band
structure well notice this extrinsic
semiconductor is no longer silicon it's
silicon and phosphorus together so
wouldn't the band structure of that
material change why did we still use the
same band structure as that of silicons
and another question we could ask is now
that we have so many phosphorous atoms
uh aren't the ato or orbitals of the
phosphorus atoms overlapping and
shouldn't we also consider the band
structure for phosphorus i mean look
over here we said the donor level i mean
same question we can ask here let's just
concentrate on one the donor level over
here we just took one single discrete
level shouldn't that also be a band how
do we justify these
and the reason we can do all of this we
can justify all of this is because of
one simple reason we keep our doping
concentration very very low the doping
is so low that the impurities that we
add is so low that it turns out that
about usually about one phosphorus atom
for example is surrounded by about a
million silicon atoms so if you could
actually see that
then usually we would draw something
like this but if you were to zoom out
then you would see that one phosphorous
atom is surrounded by lots and lots of
silicon atoms something like this and so
you really have to travel a lot a lot of
atoms to actually find the next
phosphorus atom it's all silicon it
might be somewhere over here here's
another one here's another one
so this should answer the question if
you look at this crystal this is pretty
much silicon
and that's why we can justify and say
that hardly anything has changed by
adding these phosphorous atoms and so we
could say yeah the band structure is
going to remain the same this also helps
us understand why we don't have to
consider the band structure or
phosphorus for example the reason is two
phosphorous atoms are so far apart that
atomic orbitals are hardly going to
overlap and as a result
we can totally justify that we are using
a single discrete energy level and not
the band structure of phosphorus because
they're so far apart it wouldn't matter
and the same thing can be exp same thing
will happen over here as well
the immediate follow-up question we
could ask is since each phosphorous atom
is contributing to one under conduction
electron so one extra electron per
phosphorous atom and since the number of
phosphorous atoms is so low that's just
that's what we saw right now then is is
the number of electrons here
considerably increasing i mean what how
much is it more than the holes is it a
lot does it really matter
and the answer is yes it turns out that
even if you are using a very low amount
of impurity atoms their effect is
dramatically high incredibly high and to
understand why that works out to be that
way we have to look into the math behind
it and don't worry we're going to keep
the math very simple
now the first thing we'll do is write
down the doping concentration
doping level we just saw that
if you take phosphorus we'll take
phosphorus as an example um one
phosphorus atom is pretty much
surrounded by about a million silicon
atoms so let's write that down one
phosphorous atom
is surrounded by
surrounded by about 10 to the power 6 a
million silicon atoms and usually people
call that as one ppm one part per
million but that's what it means okay
and if we go back to our intrinsic
semiconductor intrinsic semiconductor a
pure semiconductor without any doping
then we have seen some numbers before
and let me just write that down one more
time we've seen that if you go to say
room temperature
if you look at room temperature and if
you take a tiny box of silicon
let's say one centimeter cube box of
silicon and if you look inside that
okay this is one centimeter cube let's
say then you will find roughly these
numbers can be worked out we don't have
to worry too much about them the numbers
can be the numbers will be roughly about
number of electrons
and the number of holes are equal and
they're about 10 to the power 10.
and the number of silicon atoms
themselves
the total number of silicon atoms is
roughly about
roughly about 10 to the 20 10 to the 22.
i just happen to remember these numbers
you don't have to remember this okay
it's definitely not needed we're just
going to work out some things with this
okay now having said this given this
we want to figure out how many
phosphorus atoms will be there in the
n-type
semiconductor all right
given this if you look at an n-type
semiconductor again take one centimeter
cube box
how many phosphorous atoms will you find
and this is math okay so i want you to
try and pause the video and and see if
you can figure this out look at this
number
look at this number and see if you can
do it
all right so we saw that 10
one phosphorous atom uh is surrounded by
a million silicon atoms so we could just
ask if you take 10 to the 22 silicon
atoms how many phosphorous atoms will be
there so let's just do it let's do that
we saw that 10 to the power 6 silicon
atoms
you will find one phosphorous atom
so if you have about 10 to the 22
because that's what you find in one
centimeter cube if there are 10 to the
22 silicon atoms
how many phosphorous atoms will you find
well if you do cross multiplication you
get 10 to the 22 divided by 10 to the 6
that is if you do that 10 to the 16
phosphorous atoms
and now get this we we saw that one
phosphorus atoms one phosphorous atom
donates one extra electron which means
that by adding this impurity the number
of electrons that we are getting
is we already had this much
plus 10 to the 16
plus 10 to the 16.
and if you add them that's not 10 to the
26 because it's an exponent but just
think about one and ten zeros one and
sixteen zeros
this number is so huge you can totally
neglect this and you could say that the
number of electrons
in the n type is roughly 10 to the 16.
look at that that is an incredible
amount of increase
and if you think about it that's a
million times higher than what we had
before but that's not it now it's time
for the climax
what do you think
happens to the number of holes
pause the video and think about this
okay now if we didn't think too much
here here's the way we could we could
answer this we could say that you see
but since we're adding phosphorus and
phosphorus only giving us electrons only
electrons would be affected and the
holes shouldn't be affected so we could
say that the number of holes should
remain 10 to the power 10
right
guess what that's wrong not just wrong
it's very wrong to understand why we
need to recall two important processes
that happen in semiconductors one
process is generation remember remember
thermal generation uh that's a process
by which electron hole pairs are
continuously being created due to
thermal energy that's happening all the
time and we've seen in previous videos
that that rate rate at which thermal
generation happens that is a function of
temperature it's only some function we
don't care what that is but some
function of temperature and we saw
another process called the recombination
where electron whole pairs meet up and
destroy each other and we saw that that
number depends on the product it's even
proportional to the product of the
number of electrons and holes and so
that number would be we could say some
constant k times this product and the
product would be about 10 to the 20.
and at thermal equilibrium these two
must be exactly the same otherwise the
total number of electrons and the holes
will keep on changing it'll keep on
increasing or decreasing arbitrarily
this is what we saw for intrinsic
now what can we write for extrinsic this
these two process are continuously
happening even in extrinsic
semiconductor even in the n-type
semiconductor so if you go up a little
bit
all right so if we write down the
generation rate over here well the
generation rate must be exactly the same
as before because the generation rate
only depends on the temperature we are
using the same temperature so the
generation rate over here for the n-type
must still be the same number it should
still be k times
k times 10 to the 20.
but what about the recombination rate
the recombination rate is the product of
these two right so if the number of
holes was 10 to the 10
look what happens to the recombination
rate this number would be a whopping 10
to the
26
and that's not equal to each other you
now see that the recombination rate
would be much higher than the generation
rate and that's not thermal equilibrium
so because the recombination rate has
skyrocketed what's going to happen now
is that a lot of electron holes will
recombine with each other and as a
reason a lot of holes will be destroyed
i mean of course electrons will also be
destroyed but the electron number is so
huge we can neglect that and so now we
can ask the question how many holes are
left well to do that
we know that the recombination rate is
the num product of number of electrons
and the number of holes
we have to make sure that the rate is
exactly the same as 10 to the 20. so to
do that let's say we don't know what
that is
it has to be equal to k times 10 to the
20.
and so now if you look carefully you see
that the number of holes
is not 10 to the 10 but it is 10 to the
20 divided by 10 to the 16 that is 10 to
the power 4.
that is 10 to the power 4 that means it
has decreased a million times
whoa so can you see the subtle effect
by adding phosphorus not only have you
increased the electrons a million times
more
but if you look carefully you've also
decreased the number of holes a million
times smaller
and that
is incredible and now if you look at the
ratio of the number of electrons and the
number of holes that's a million million
what is that i don't even know what to
call it anymore but the fascinating
thing is that we have just
done such a low level of doping and yet
the effect is so high and that is all
possible because in intrinsic in the
pure semiconductor we had this much
amount of charge carriers so guess what
this is only possible in semiconductors
and that's the main reason why we can we
can change the properties of
semiconductors and we can't do that for
conductor it's too high nothing will
work and for insulator is too low so it
only works for semiconductors isn't this
just awesome
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