Energy Levels & Emission Spectra - A-level Physics
Summary
TLDRThis educational video script explores the photoelectric effect, explaining how electrons absorb photons and either become excited to higher energy levels or ionize, leaving the atom. It delves into the quantization of energy levels, where electrons can only occupy specific states and release photons when returning to lower levels, creating various colors of light. The script also covers the calculation of photon wavelengths, absorption and emission spectra, and the practical application of these principles in fluorescent tubes, providing a comprehensive understanding of electron energy levels and their interactions with light.
Takeaways
- π The photoelectric effect demonstrates that electrons can absorb energy from photons, which is quantized and equals to Planck's constant times the frequency of the photon (E=hΞ½).
- π¬ When a photon is absorbed by an electron, it can either excite the electron to a higher energy level or ionize the electron, causing it to leave the atom entirely if the photon's energy is sufficient.
- π Electrons can only occupy discrete energy levels, and the energy difference between these levels dictates the energy of the photon that can be absorbed or emitted.
- π After excitation, electrons tend to return to their ground state, releasing energy in the form of a photon during a process called de-excitation or relaxation.
- π The energy levels and the transitions between them result in the emission of photons with specific energies, which can correspond to various colors of light.
- π’ The energy of a photon is directly related to its wavelength, as shown by the equation E=hC/Ξ», where h is Planck's constant, C is the speed of light, and Ξ» is the wavelength.
- π Each element has a unique absorption and emission spectrum, which can be used to identify it based on the specific wavelengths of light that are absorbed or emitted.
- π‘ The difference between absorption and emission spectra lies in the fact that electrons can take multiple paths to return to the ground state, leading to a greater variety of emitted wavelengths.
- π‘ Fluorescent tubes operate on the principle of excitation and de-excitation, where electrons collide with mercury atoms to emit UV photons, which are then converted to visible light by the tube's coating.
- π¬ The video script provides a comprehensive explanation of electron energy levels, the photoelectric effect, and the practical application of these concepts in lighting technology.
Q & A
What is the photoelectric effect?
-The photoelectric effect is a phenomenon where electrons in a material absorb energy from photons and are ejected from the material, resulting in the emission of electrons or ionization.
How is the energy of a photon related to its frequency?
-The energy of a photon is directly proportional to its frequency, as described by the equation E = hΞ½, where E is the energy, h is Planck's constant, and Ξ½ is the frequency of the photon.
What happens when an electron absorbs a photon with more energy than needed for excitation?
-If an electron absorbs a photon with energy exceeding the energy gap to the next level, it may not just get excited but could be ionized, leaving the atom and becoming a free electron.
What is the term for when an electron returns to its ground state after being excited?
-The process where an electron returns to its ground state after being excited is called de-excitation or relaxation, during which it releases energy in the form of a photon.
Why do electrons only absorb photons of certain frequencies?
-Electrons only absorb photons of frequencies that match the energy difference between their current energy level and a higher one, as per the quantization of energy levels in atoms.
What is the significance of electron volts in measuring electron energy?
-Electron volts (eV) are used to measure the energy of electrons because they provide a convenient unit for dealing with the very small energy scales involved in electron transitions.
How does the energy of a photon relate to the color of light it represents?
-The energy of a photon, and thus the color of light it represents, is inversely related to its wavelength. Higher energy photons correspond to shorter wavelengths, which are typically in the blue/violet end of the visible spectrum, while lower energy photons correspond to longer wavelengths, in the red/infrared end.
What is an absorption spectrum and how is it different from an emission spectrum?
-An absorption spectrum shows the wavelengths of light that are absorbed by a substance, typically represented by dark lines on a bright background. An emission spectrum, conversely, shows the wavelengths of light emitted by a substance, represented by bright lines on a dark background. The two spectra are complementary, but the emission spectrum typically has more lines due to the various possible transitions electrons can make as they return to the ground state.
How does the fluorescent tube work in terms of electron energy levels?
-In a fluorescent tube, electrons are fired through a low-pressure mercury vapor, causing excitation of mercury atoms. When these excited electrons de-excite, they emit ultraviolet (UV) photons, which are then absorbed by the tube's coating, causing it to emit visible light.
Why do different elements have different absorption and emission spectra?
-Different elements have unique atomic structures with specific energy level arrangements, leading to the absorption and emission of light at distinct wavelengths. This results in characteristic spectra that can be used to identify elements.
Outlines
π Understanding the Photoelectric Effect
The paragraph explains the photoelectric effect, where an electron can absorb a photon of energy. The energy of a photon is denoted by the equation \( E = h\nu \), where \( h \) is Planck's constant (6.63 x 10^-34 Js) and \( \nu \) is the frequency. The paragraph illustrates how electrons in atoms can absorb photons, leading to excitation or ionization. Excitation occurs when an electron absorbs energy and jumps to a higher energy level, while ionization happens when the electron absorbs so much energy that it escapes the atom entirely. The paragraph also discusses the release of energy when an electron returns to its normal energy level, known as de-excitation or relaxation, and the emission of a photon in the process.
π¬ Energy Levels and Photon Emission
This section delves into the quantized nature of electron energy levels within atoms. It explains that electrons can only exist at specific energy levels, and when they absorb a photon, they may jump to a higher level. The paragraph uses the example of an electron absorbing a photon with 7 electron volts of energy, which allows it to reach a higher energy state. The electron can then return to the ground state by emitting photons at various energy levels. The discussion also includes the calculation of photon wavelength using the equation \( \lambda = \frac{hc}{E} \), where \( c \) is the speed of light, resulting in a wavelength that corresponds to visible light. The concept of absorption and emission spectra is introduced, highlighting how atoms absorb certain wavelengths and emit light at specific frequencies, leading to the characteristic spectral lines of elements.
π‘ Applications in Fluorescent Lighting
The final paragraph discusses the practical application of electron excitation and de-excitation in fluorescent lighting. It describes how low-pressure mercury vapor in a tube is excited by electrons, leading to the emission of ultraviolet (UV) photons. These UV photons are then absorbed by a phosphor coating on the tube's interior, which in turn emits visible light photons. The paragraph explains that the initial excitation is not due to photon absorption but rather from electron collisions. The UV light is transformed into visible light through the phosphor coating, illuminating the room. The paragraph concludes with an invitation for feedback and questions, and a prompt for viewers to engage with the content.
Mindmap
Keywords
π‘Photoelectric Effect
π‘Photon
π‘Excitation
π‘Ionization
π‘Ground State
π‘De-excitation
π‘Energy Levels
π‘Planck's Constant (h)
π‘Electron Volt (eV)
π‘Emission Spectrum
Highlights
The photoelectric effect demonstrates that electrons can absorb energy from photons.
Photon energy is calculated using the equation E=hf, where E is energy, h is Planck's constant, and f is frequency.
Electrons can either become excited to a higher energy level or be ionized, depending on the photon's energy.
Excitation occurs when an electron absorbs a photon and jumps to a higher energy level within the atom.
Ionization happens when a photon provides enough energy for an electron to escape the atom completely.
Electrons prefer their ground state and will release energy when returning to it, a process known as de-excitation.
De-excitation can result in the emission of photons as the electron drops from an excited state to a lower one.
Electrons can only occupy specific energy levels within an atom, which are quantized.
The energy levels are typically measured in electron volts (eV) for convenience in discussing small energy values.
An electron can absorb a photon and move to a higher energy level, but it must match the level's specific energy to be absorbed.
If a photon's energy is insufficient to reach a higher energy level, the photon will pass through unabsorbed.
When an electron returns to its ground state from an excited state, it can release photons of various energies, leading to multiple colors of light.
The wavelength of a photon can be calculated using the equation Ξ» = (hc) / E, where Ξ» is wavelength, h is Planck's constant, c is the speed of light, and E is energy.
Atoms absorb specific wavelengths of light, leading to characteristic absorption spectra with dark lines representing absorbed frequencies.
Emission spectra display the wavelengths of light emitted by atoms, which can include more lines than absorption spectra due to the various possible de-excitation paths.
Fluorescent tubes operate by exciting mercury atoms with electrons, which then emit UV photons that are converted to visible light by the tube's coating.
The process of excitation and de-excitation in fluorescent tubes results in the emission of visible light, illuminating the room.
Transcripts
so the photoelectric effect proves that
one electron can absorb one Photon of
energy the energy of a photon I'm going
to put e gamma gamma is the general
symbol for a photon doesn't necessarily
mean a gamma Photon Photon energy equals
HF F being frequency and H being planked
constant that's
6.63 * 10us 34 dual seconds now in the
photo electric effect we had electrons
in metals absorbing photons but it
doesn't have to be a metal it can be any
electron so I'm going to draw an atom
here I'm going to draw the nucleus which
is
positive then I'm going to
draw just one
electron in a shell around the nucleus
now when a photon comes
in and it's absorbed by an electron one
of two things can happen if it gets more
energy then the electron becomes more
excited and it
jumps to a shell that is further away
from the nucleus we can say that it's
gone up an energy
level and we call this
excitation photon is absorbed electron
go goes up an energy level now what
we're going to find out a little bit
later on is that electrons can only be
in certain energy levels another thing
can happen as well
though if the photon has Lads of
energy so it's got a higher frequency
then the electron has way too much
energy to go to the next energy level or
an energy level above that it actually
just completely
completely moves away from the atom what
are we left with we're left with an ion
this is ionization ionization is what
happens when an electron is given enough
energy by a photon or it can be given
energy by another free electron and it
jumps out of the atom completely and
we're left with a free electron and an
ion left obviously more energy is needed
for ionization than excitation now this
electron here doesn't like being in the
energy level above where it's supposed
to be usually so after it's absorbed the
energy and gone up it will come straight
back down when this electron does go
back to its normal energy level energy
is released and we call this de
exitation sometimes also called
relaxation the electron returns to
energy level and a
photon is
emitted so with the excitation of phot
phon can come in be absorbed by an
electron it can go up an energy level
come straight back down and by doing so
it releases its own Photon so let's draw
our atom again now this is where our
electron usually is but it could also be
if it has enough energy in any of these
shells or energy
levels above but they are very specific
to an
atom what we're going to do is take a
snapshot of this which just going to
take a slice of this and we're going to
blow it up here so instead of drawing
shells we're actually just going to draw
our energy levels like this so here's
our electron in its normal shell we're
going to call this its ground state
that's when it has no energy or rather
no more energy than usual it's all
relative now we're going to measure
these in electron volts now remember
that one electron volt is equals to 1.6
6 * 10 -9
Jew it's just an easier number to deal
with because when we're talking about
individual electrons energies we're
talking very small numbers of Jews so we
deal with electron volts instead now
when a photon comes
in the electron can jump to one of these
energy levels now I can tell you that
these energy levels here are five
electron volts seven electron volts and
eight electron volts this electron volts
here though once it reaches this point
it's out of the atom so that's when it's
actually being
ionized so if this Photon and the energy
of this photon is HF PL constant times
the frequency if the photon had eight
electron volts that's eight lots of
these or more to give the electron then
the electron would jump all the way up
past this eight electron volts and it
would escape the atom the atom is now
being ionized but we're not going to
think about that for now we're just
going to think about what would happen
if it didn't go quite to that point if
the energy of the photon was equals to
three electron volts it's not enough
energy to get the electron to its next
energy level so it's not like the photon
is absorbed and the electron goes
partway to this five electron volts it
can't do that instead the photon would
just pass straight
through so that means that it's not
absorbed but but if it did have exactly
let's say seven electron volts it's
enough to get it to its third energy
level we give these by the way numbers
N1 is the ground state then N2 then N3
so here we go the electron has absorbed
the
photon and it goes up to this energy
level here hrah it's absorbed a photon
of the right amount of energy cuz it has
just the right frequency and it's gone
up to that third energy level we said
that electrons like being at their
ground state they want to come back to
here as soon as possible now on the way
back down from here the electron now has
a choice either it can go straight back
down to
here and it can release a photon because
it has to get rid of
energy and that's going to be a photon
that has seven electron volts of energy
that makes sense but it has another
option as well so it can go from
n 3 to N1 or it can stop
halfway it can go to
here and then down to here so it's gone
from Nal
3 to n =
2 to Nal 1 so it's gone from the third
energy level to the second and then back
to the ground state there both of these
will release photons what's the energy
of this Photon going to be well it's
gone from Seven electron volts to five
electron volts so this photon is going
to have two electron volts of energy so
it's going to be 3.2 * 10- 19 Jew this
one here is going to release a photon
that has five electron volts of energy
so it's going to be 8 * 10 -9 Jew so
when an electron absorbs some energy
from a photon it only absorbs one Photon
but on its way down it has choices it
can go straight to the bottom or it can
go to energy levels in between then fall
to the bottom from there even though
we're absorbing one Photon here one type
of photon how many photons can be
emitted 1 2 3 so we're going to have
various colors of photons and light
being emitted when this electron goes
from the third energy level down to its
ground state what about if I wanted to
find out the wavelength of this Photon
here let's let's have a look we know
that the energy of a
photon is equals to
HF from the wave equation we know the V
or C is f Lambda frequency times
wavelength so that means that
frequency is equals to speed of light
divided by the wavelength pop this in
here we end up with energy equals
HC over Lambda rearrange this and we end
up with wavelength equals PL constant
times the speed of light divided the
energy of the photon give that a go if
you want pause the video if you feel
like
it this is going to be 6.63 * 10-
34 * 3 * 10 8 divided by well it's five
electron volts that's five times this
many Jews whenever we do any
calculations we always have to use
Jewels we never put electron volts
straight into into an equation that's
going to give us a wavelength of
2.5 * 10 - 7 m or about
250 nanm pretty much visible light so
that does mean the atoms only absorb
certain wavelengths of light so you
might see a diagram like
this and you'll
see all the colors in the rainbow going
from
red all the way to
Blue and because we know that electrons
can only absorb certain wavelengths and
certain frequencies of
photons we get these black lines
appearing on
here and it's going to be different for
every single atom and molecule in the
world so this is an absorption Spectrum
so in other words all of these
wavelengths pass through but these black
lines show
the ones that are
absorbed so you can deduce energy levels
from those we also have an emission
spectrum as well other way around this
time the whole thing will be black apart
from a few colored
lines that
show what
frequencies and wavelengths are emitted
from something I've drawn an absorption
spectrum and emission spectrum for two
different elements here but if we did
have an absorption spectrum and an
emission spectrum would they be exactly
the same well no they wouldn't be you
would expect more lines on the emission
spectrum why is that well it's
because all electrons when they absorb
they have to start at the ground
state and go up to a specific energy
level on the way back down though they
can take any route they want so there's
always going to be a greater number of
different wavelengths that can be
emitted that could be absorbed you take
multiple Roots back to the ground
state one place that we see excitation
and de exitation
happening is in a fluorescent tube what
we have in here is low pressure Mercury
gas and what we do is we
fire
electrons from one end to the
other the electrons collide with the
Mercury atoms and they
excite the
electrons like we saw
earlier or we could draw it like
this the electrons de exite the problem
is is that they
emit UV photons
it's a high
frequency what do these photons
do these UV photons are absorbed by the
coating on the outside of the tube so
you have this
coating it's all around the outside if
it wasn't for this coating if you scrape
off the coating off a fluorescent tube
you're just getting UV photons coming
straight out but if we have this coating
the UV photons are absorbed by the
coating and have excitation again what
do they do in turn when they de exite
they emit visible photons therefore
lighting up a room that they're
in so that's how a fluorescent tube
Works notice that the excitation that we
get to begin with isn't due to the
absorption of photons it's an electron
coming in whacking into another electron
that electron goes off CU it's still got
loads of energy but it's given some of
its energy to this electron raising it
an energy level to get rid of that
energy it releases this high frequency
UV Photon that's absorbed by the coating
that then releases visible light photons
to light up a room so that's electron
energy levels if you think I've missed
anything or have any questions please
put it in a comment down below and don't
forget to leave a like if you found this
helpful and I'll see you next
time
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