Function Operations

The Organic Chemistry Tutor
2 Feb 201807:10

Summary

TLDRThe video script explains the operations on two functions, f(x) = 2x + 5 and g(x) = x^2 - 4. It demonstrates how to find the sum (f + g = x^2 + 2x + 1), difference (f - g = -x^2 + 2x + 9), and product (f * g = 2x^3 + 5x^2 - 8x - 20) of the functions. It then discusses the domain of these functions, highlighting that polynomials have a domain of all real numbers, while fractions require excluding values that make the denominator zero. Examples are given to calculate specific values of f and g for certain x inputs, emphasizing the process of substitution and arithmetic operations.

Takeaways

  • πŸ”’ The function f(x) = 2x + 5 and g(x) = x^2 - 4 are given, and their sum f + g results in x^2 + 2x + 1 after combining like terms.
  • βž– The difference f - g is calculated as -x^2 + 2x + 9 by subtracting g(x) from f(x) and simplifying.
  • πŸ”— The product f * g is found by multiplying the two functions using the FOIL method, resulting in 2x^3 + 5x^2 - 8x - 20.
  • 🌐 The domain of f + g, f - g, and f * g is all real numbers since they are polynomials without restrictions.
  • 🚫 The domain of f / g is restricted because it involves a fraction; x cannot be the values that make the denominator zero (x β‰  -2, 2).
  • πŸ“ The domain for functions involving fractions is determined by setting the denominator equal to zero to find the vertical asymptotes.
  • πŸ“ Interval notation is used to express the domain of functions with restrictions, excluding the values that make the denominator zero.
  • πŸ”’ To find f(a) + g(b), substitute 'a' into f(x) and 'b' into g(x), then add the results.
  • πŸ”„ To calculate f(a) * g(b), first find the values of f(a) and g(b) separately, then multiply them together.
  • πŸ“˜ The script provides a comprehensive guide on how to perform operations on functions and determine their domains.

Q & A

  • What is the function f(x) as described in the transcript?

    -The function f(x) is described as f(x) = 2x + 5.

  • What is the function g(x) as described in the transcript?

    -The function g(x) is described as g(x) = x^2 - 4.

  • How do you find the sum of the functions f(x) and g(x)?

    -You add the two functions together, which results in (2x + 5) + (x^2 - 4), and then combine like terms to get x^2 + 2x + 1.

  • What is the result of f(x) - g(x) according to the transcript?

    -The result of f(x) - g(x) is -x^2 + 2x + 9.

  • How is the product of f(x) and g(x) calculated?

    -The product f(x) * g(x) is calculated by multiplying (2x + 5) with (x^2 - 4) using the FOIL method, resulting in 2x^3 + 5x^2 - 8x - 20.

  • What is the domain of the function f(x) + g(x)?

    -The domain of f(x) + g(x) is all real numbers, as it is a polynomial without restrictions.

  • What is the domain of the function f(x) - g(x)?

    -The domain of f(x) - g(x) is also all real numbers, as it is a polynomial without restrictions.

  • What is the domain of the function f(x) * g(x)?

    -The domain of f(x) * g(x) is all real numbers, as it is a polynomial without restrictions.

  • How do you determine the domain of f(x) / g(x)?

    -The domain of f(x) / g(x) is all real numbers except where the denominator g(x) equals zero, which is when x = -2 or x = 2.

  • What is the interval notation for the domain of f(x) / g(x)?

    -The interval notation for the domain of f(x) / g(x) is (-∞, -2) U (-2, 2) U (2, ∞).

  • What is the value of f(2) + g(3) as described in the transcript?

    -The value of f(2) + g(3) is calculated as (4*2 + 5) + (8 - 3^2) which equals 13 - 1, resulting in 12.

  • What is the value of f(-2) * g(2) according to the transcript?

    -The value of f(-2) * g(2) is calculated as (4*(-2) + 5) * (8 - 2^2) which equals (-3) * 4, resulting in -12.

Outlines

00:00

πŸ“˜ Operations and Domain of Functions

This paragraph explains the operations on two functions, f(x) = 2x + 5 and g(x) = x^2 - 4. It details how to find the sum (f + g = x^2 + 2x + 1), difference (f - g = -x^2 + 2x + 9), and product (f * g = 2x^3 + 5x^2 - 8x - 20) of the functions. It also discusses the domain of these functions, stating that since they are polynomials without radicals or fractions, their domain is all real numbers (-∞, ∞). However, for the division f/g, where f/g = (2x + 5) / (x^2 - 4), the domain is restricted to all real numbers except x = ±2, as these values make the denominator zero, leading to undefined function values. The domain is expressed in interval notation as (-∞, -2) U (-2, 2) U (2, ∞).

05:03

πŸ”’ Evaluating Functions at Specific Points

The second paragraph demonstrates how to evaluate functions at specific points. It uses the functions f(x) = 4x + 5 and g(x) = 8 - x^2 to calculate f(2) + g(3) and f(-2) * g(2). For f(2) + g(3), it substitutes x with 2 in f(x) and x with 3 in g(x), resulting in 13 - 1 = 12. For f(-2) * g(2), it first calculates f(-2) = -3 and g(2) = 4, then multiplies these values to get -12. The process involves substituting the given x values into the function's formulas and performing the arithmetic operations to find the results.

Mindmap

Keywords

πŸ’‘Function

In the context of the video, a function refers to a mathematical relation that maps each element from one set to one element of another set. The video discusses functions such as 'f of x' and 'g of x', where 'f of x' is defined as 'two x plus five' and 'g of x' as 'x squared minus four'. Functions are fundamental to the video's theme as they are the basis for the operations performed.

πŸ’‘Polynomial

A polynomial is an expression consisting of variables and coefficients, involving only the operations of addition, subtraction, multiplication, and non-negative integer exponents of variables. The video mentions polynomials when discussing the domain of 'f plus g', which is a polynomial expression 'x squared plus two x plus one', indicating that its domain is all real numbers.

πŸ’‘Domain

The domain of a function refers to the set of all possible input values (x-values) for which the function is defined. The video explains the domain in relation to different functions, stating that for polynomials like 'f plus g', the domain is all real numbers. However, for 'f divided by g', the domain excludes values that make the denominator zero, hence x cannot be -2 or 2.

πŸ’‘Range

Although not explicitly mentioned in the script, the range of a function is the set of all possible output values (y-values) that result from the input values in the domain. The concept is implicitly discussed when the video talks about the domain of 'f divided by g', where the range would be all real numbers except for undefined values at the vertical asymptotes.

πŸ’‘Vertical Asymptote

A vertical asymptote is a vertical line that the graph of a function approaches but never reaches, typically occurring where the denominator of a rational function is zero. The video script discusses vertical asymptotes in the context of 'f divided by g', where x cannot be -2 or 2 because these values would make the denominator zero, resulting in vertical asymptotes.

πŸ’‘Factoring

Factoring is the process of breaking down a polynomial into a product of other polynomials. The video uses factoring when determining the domain of 'f divided by g', where 'x squared minus four' is factored into '(x plus two) times (x minus two)' to find the values of x that are not in the domain.

πŸ’‘Interval Notation

Interval notation is a method of describing a set of numbers on a number line using parentheses and brackets. The video script uses interval notation to express the domain of 'f divided by g', indicating that the domain is all real numbers except for -2 and 2, written as '(-∞, -2) U (-2, 2) U (2, ∞)'.

πŸ’‘Combining Like Terms

Combining like terms is a process in algebra where terms that have the same variables raised to the same power are added or subtracted. In the video, this concept is used when adding 'f of x' and 'g of x' to find 'f plus g', where the like terms 'five' and 'negative four' are combined to get 'one'.

πŸ’‘FOIL Method

The FOIL method is a mnemonic for multiplying two binomials, standing for First, Outer, Inner, Last. The video uses the FOIL method to multiply 'f of x' and 'g of x' to find 'f times g', resulting in the expression '2x cubed plus 5x squared minus 8x minus 20'.

πŸ’‘Substitution

Substitution in mathematics is the process of replacing a variable with a specific value. The video script uses substitution when calculating 'f of 2' and 'g of 3', where the value of x is replaced with 2 and 3, respectively, to find the values of the functions at those points.

Highlights

Function f(x) is defined as 2x + 5.

Function g(x) is defined as x^2 - 4.

Sum of functions f and g results in x^2 + 2x + 1 after combining like terms.

Difference of functions f and g results in -x^2 + 2x + 9 after distributing and combining constants.

Product of functions f and g is calculated using the FOIL method, resulting in 2x^3 + 5x^2 - 8x - 20.

Domain of f + g, f - g, and f * g is all real numbers since they are polynomials without restrictions.

Domain of f / g is restricted to all real numbers except x = -2 and x = 2, as these make the denominator zero.

Domain of a function with a fraction is determined by setting the denominator equal to zero to find restrictions.

Vertical asymptotes at x = -2 and x = 2 for the function f / g, indicating points of discontinuity.

Domain of f / g is expressed in interval notation as (-∞, -2) U (-2, 2) U (2, ∞).

Function f(x) = 4x + 5 is given as an example for evaluating f(2).

Function g(x) = 8 - x^2 is used to evaluate g(3).

f(2) + g(3) is calculated by substituting x values into their respective functions and summing the results.

f(-2) * g(2) is computed by finding the values of f at x = -2 and g at x = 2, then multiplying these values.

The process of evaluating functions at specific points involves substitution and arithmetic operations.

Transcripts

play00:01

let's say that f of x

play00:05

is equal to two x plus five

play00:10

and g of

play00:14

x let's say g of x is

play00:18

x squared minus four

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perform the indicated operations

play00:24

so what is f plus g

play00:27

what's the sum of the two functions all

play00:30

you gotta do is add them 2x plus five

play00:33

plus x squared minus four

play00:35

and combine like terms

play00:37

so all we can combine is five and

play00:39

negative four

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which adds up to one so it's x squared

play00:42

plus two x

play00:44

plus one

play00:47

and so that's the sum of f and g

play00:51

now what about f minus g

play00:54

f is two x plus five

play00:56

and then it's gonna be minus

play00:58

x squared minus four

play01:00

so this is going to be negative x

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squared

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plus two x

play01:05

and then we have five

play01:06

minus negative four

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five minus negative four is like five

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plus four

play01:11

which is nine

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so that's equal to f minus g

play01:18

now what about f times g

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this is just going to be two x plus 5

play01:26

times x squared minus 4.

play01:29

and we can go ahead and foil it 2x times

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x squared

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that's 2x cubed

play01:34

and then 2x times negative 4 that's

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negative 8x

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and then we have 5 times

play01:41

x squared that's

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5x squared

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and then 5 times negative 4 it's

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negative 20.

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so in standard form it's 2x cubed

play01:50

plus 5x squared

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minus 8x minus 20.

play01:56

now what is the domain

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of the three functions that we found

play02:00

let's start with f plus g

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what is the domain for that

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whenever you have a polynomial be it a

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binomial trinomial or many terms where

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you don't have any fractions no radicals

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or

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logarithmic functions

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the domain will be all real numbers

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there's no restrictions on the value of

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x in this expression x can be anything

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so for these three functions f plus g f

play02:25

minus g and f times g

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we don't have any fractions or radicals

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so the domain is all real numbers it's

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negative infinity to infinity

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now what about f

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divided by g

play02:41

what's the domain for this

play02:44

f divided by g is simply two x plus five

play02:48

divided by x squared minus 4.

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now that we have a fraction

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the domain is restricted

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is not all real numbers

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to find the domain

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you want to find the x values

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that do not exist

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the values that x cannot be

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to do that

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set the denominator equal to zero

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x squared minus four cannot be zero if

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it is we're going to get a vertical

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asymptote which means it's undefined at

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that point

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now we can factor x squared minus four

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it's x plus two times x minus two

play03:25

so therefore x

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cannot equal negative two

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and it can't equal two these are the

play03:31

vertical asymptotes

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but they're also

play03:35

infinite discontinuities

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there's no we can't plug in negative two

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for x the function will be undefined

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anytime you have a zero on the bottom

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it's undefined

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so how can we write the domain using

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interval notation if x cannot equal

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negative two or two

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it's going to be from negative infinity

play03:55

to negative two

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union negative two to two

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union

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two to infinity

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so here's another example let's say

play04:06

if we have the function one over x minus

play04:08

three

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x minus three the denominator cannot be

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zero

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so x cannot be three

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therefore the domain is everything

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except three that's how you write it

play04:28

let's say if we have this

play04:32

x

play04:33

cannot equal 4

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and it can't equal

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negative 3. just change the sign

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if you set x minus four to zero x

play04:43

you'll get four facts

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now to write the domain it's gonna be

play04:48

negative infinity to negative three

play04:51

negative three comes before four

play04:53

union negative three is a four

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union 4 to infinity

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so that's the domain for this function

play05:02

so let's say that

play05:04

f of x

play05:07

is equal to 4x plus 5.

play05:11

and g of x

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let's say it's equal to 8

play05:17

minus x squared

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what is f of 2

play05:22

plus g of three

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to find f of two

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we need to replace x with two in the

play05:29

equation four x plus five

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so that's four times two plus five

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and that is a terrible looking two

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to find g of 3 we need to plug it into

play05:40

that equation so it's plus

play05:42

8 minus

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3 squared

play05:45

and then let's add 4 times 2 is 8

play05:49

and 3 squared

play05:51

is nine eight plus five is thirteen

play05:53

eight minus nine is negative one

play05:56

thirteen minus one is twelve

play05:58

so that's the value of f of two plus g

play06:00

of three

play06:01

you just find the two values

play06:03

and you add them

play06:07

let's try another example

play06:10

so what is

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f of negative 2

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multiplied

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by

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g of two

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so let's do it separately let's find f

play06:23

of negative two first

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using this formula

play06:27

so it's gonna be four times negative two

play06:29

plus five

play06:30

which is negative eight plus five

play06:33

and so that's negative three

play06:35

now let's calculate g of two

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using this equation

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so that's eight minus two squared

play06:43

two squared is four eight minus four is

play06:45

four

play06:46

so now that we have these two values

play06:48

let's replace f of negative two which

play06:51

is negative three and let's replace g of

play06:53

two with four

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so negative three times four is negative

play06:56

twelve

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so that's the value of f of negative two

play06:59

times g of negative two i mean times g

play07:01

of positive two

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so all you gotta do is simply

play07:06

find the values

play07:08

and then multiply them

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Related Tags
AlgebraFunction OperationsDomain CalculationPolynomial FunctionsEducational ContentMathematicsFOIL MethodVertical AsymptotesInterval NotationAlgebraic Examples