The rigid bar AB, attached to two vertical rods as shown in

MECHANICAL PROBLEMS
8 Nov 202309:21

Summary

TLDRThe video script discusses a structural engineering problem involving a rigid bar AB attached to vertical rods, subjected to a force P of 50 kilonewtons. The script guides through solving for the forces on aluminum and steel components, calculating their respective deflections, and determining the total deflection at point P. It uses principles of equilibrium and material properties to find the final deflection of 1.88 mm, providing a clear explanation for structural analysis.

Takeaways

  • 📐 The problem involves a rigid bar AB attached to two vertical rods and a horizontal bar, with a force P applied to it.
  • 🔍 The script describes a scenario where the deflection of both the aluminum and steel parts is the same, which is crucial for solving the problem.
  • 📈 The force P is given as 50 kilonewtons, and the goal is to find the forces in the aluminum and steel parts.
  • 📝 A free body diagram is drawn to visualize the forces acting on the system, including the applied force P and the reaction forces.
  • ⚖ The script applies the principle of equilibrium, stating that the sum of moments (rotational forces) around a point must equal zero.
  • 📊 By setting up equations based on the moments, the force in the steel part (PST) is calculated to be 29.2 kilonewtons.
  • 📐 The deflection of the steel part is then calculated using the formula involving force, length, area, and modulus of elasticity.
  • 🔱 The deflection for the steel part is found to be 1.94 mm, and for the aluminum part, it is 1.78 mm.
  • 📐 The script discusses the need to calculate the movement of point P, which involves understanding the geometry of the setup and the forces involved.
  • 📐 The total deflection at point P (ÎŁB) is calculated by considering the deflection of the aluminum and steel parts and the angle formed by the forces.
  • 🔑 The final answer for the total deflection at point P is given as 1.88 mm, which is the sum of the individual deflections and the additional movement due to the angle.

Q & A

  • What is the problem described in the transcript about?

    -The problem described in the transcript is about calculating the deflection of a rigid bar AB attached to two vertical rods and a horizontal bar, with a force P of 50 kN applied to it.

  • What are the two unknown forces that need to be determined in the problem?

    -The two unknown forces that need to be determined are the force in the aluminium (P_al) and the force in the steel (P_st).

  • What is the method used to find the unknown forces?

    -The method used to find the unknown forces involves drawing a free body diagram and applying the principle of equilibrium, specifically summation of forces (ÎŁF) equal to zero.

  • What is the value of the force P applied to the system?

    -The value of the force P applied to the system is 50 kN.

  • What are the distances used in the equilibrium equations?

    -The distances used in the equilibrium equations are 2.5 m and 3.5 m.

  • What is the calculated force in the steel (P_st)?

    -The calculated force in the steel (P_st) is 20 kN.

  • What are the parameters used to calculate the deflection of the steel and aluminium?

    -The parameters used to calculate the deflection are the force applied (P_st and P_al), the length of the material (L), the area of cross-section (A), and the modulus of elasticity (E).

  • What is the modulus of elasticity for steel and aluminium?

    -The modulus of elasticity for steel is 200 GPa, and for aluminium, it is 70 GPa.

  • What is the calculated deflection for steel and aluminium?

    -The calculated deflection for steel is 1.94 mm, and for aluminium, it is 1.78 mm.

  • How is the total deflection of the system calculated?

    -The total deflection of the system is calculated by considering the deflection of both the steel and aluminium components and the movement caused by the force P acting on the system.

  • What is the final answer for the total deflection of the system?

    -The final answer for the total deflection of the system is 1.88 mm.

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