Kirchhoff's Voltage Law (KVL)

Neso Academy
30 Jun 201815:41

Summary

TLDRIn this lecture, the speaker explains Kirchhoff's Voltage Law (KVL), stating that the algebraic sum of voltages in a closed loop is zero. Using an example circuit with a voltage source and two resistors, the speaker walks through applying KVL to find the voltage drops across each component. They also introduce two different sign conventions for writing KVL equations, discussing the relationship between voltage, current, and resistance. Lastly, the speaker emphasizes the importance of understanding the concept behind KVL, based on energy conservation, to solve circuits effectively.

Takeaways

  • 📏 The lecture begins with a discussion of KVL (Kirchhoff’s Voltage Law), stating that the algebraic sum of all voltages in a closed loop is zero.
  • 🔋 In a closed loop with a voltage source (V), a resistor (R1), and another resistor (R2), the sum of voltage drops equals the total voltage supplied.
  • 💡 KVL can be applied by adding up the voltage drops across each element in the loop, where voltage drops across resistors are calculated using Ohm’s law (V = IR).
  • 🔄 The potential drop across a resistor is determined by multiplying the current (I) by the resistance (R).
  • 🔍 Two conventions for writing KVL equations: the first considers a rise in potential as positive, while the second considers a rise as negative.
  • 📝 Both conventions lead to the same result, with V = I * (R1 + R2), showing that the total voltage drop equals the source voltage.
  • 🌍 KVL is based on the law of conservation of energy, as opposed to KCL (Kirchhoff's Current Law), which is based on the conservation of charge.
  • ⚡ Voltage represents potential energy difference, meaning the energy to move a unit charge between two points is independent of the path taken.
  • 🎯 KVL equations should include only potential differences (voltages) between points, not individual point potentials.
  • 🔁 The lecture emphasizes that regardless of the chosen path in a circuit, following proper rules will always yield consistent results.

Q & A

  • What is KVL?

    -KVL stands for Kirchhoff's Voltage Law, which states that the algebraic sum of all the voltages in any closed loop of a network is zero.

  • How do you apply KVL?

    -To apply KVL, you calculate the sum of all voltages in a closed loop, considering their signs, and set this sum equal to zero.

  • What is the significance of the voltage source in the KVL equation?

    -The voltage source in the KVL equation is represented by 'V' and is considered as a rise in potential, which is typically given a positive sign in the KVL equation.

  • What is the role of resistors in the KVL equation?

    -Resistors in the KVL equation represent voltage drops across them, calculated as the product of current (I) and resistance (R), and are typically given a negative sign due to the drop in potential.

  • How does the direction of current flow affect the KVL equation?

    -The direction of current flow determines whether the potential rises or drops. A rise in potential is associated with a positive sign, while a drop is associated with a negative sign in the KVL equation.

  • What are the conventions for writing KVL equations?

    -There are two main conventions: one where a rise in potential is positive and a drop is negative, and another where the signs are reversed. The choice of convention depends on the direction chosen to traverse the loop.

  • Why is KVL based on the law of conservation of energy?

    -KVL is based on the law of conservation of energy because voltage represents the potential energy difference across an element, and the energy required to move a unit charge between two points is independent of the path taken.

  • How do you calculate the potential difference between two points using KVL?

    -To calculate the potential difference between two points using KVL, you choose a path between those points, apply KVL up to the second point, and equate the result to the potential at the second point.

  • Why can't you include the potential at a point directly in the KVL equation?

    -You can't include the potential at a point directly in the KVL equation because KVL deals with potential differences (voltages), not absolute potentials.

  • What happens if you apply KVL starting from different points in the circuit?

    -Applying KVL from different starting points should yield the same result for the potential difference between any two points, as long as the rules are followed correctly.

  • How does the choice of path affect the KVL equation?

    -The choice of path affects the order in which voltages are added to the KVL equation, but the final result for the potential difference between any two points should be the same regardless of the path chosen.

Outlines

00:00

🔍 Introduction to KVL and Voltage Calculation in a Closed Loop

In this paragraph, the speaker introduces Kirchhoff's Voltage Law (KVL), which states that the algebraic sum of all voltages in a closed loop is zero. The explanation involves a simple circuit with a voltage source and two resistors. The potential difference between points in the circuit is calculated, illustrating the concept of high and low potential, as well as voltage drops across resistors according to Ohm's law. The paragraph ends by formulating a basic KVL equation.

05:00

⚖ Understanding Sign Conventions in KVL

This paragraph focuses on two different conventions for writing KVL equations. The first convention assigns a positive sign to rises in potential and a negative sign to potential drops. An example is given where moving through the circuit components leads to forming the KVL equation. The second convention reverses the sign conventions—assigning a negative sign to potential rises and a positive sign to potential drops. Despite the differences in conventions, the final equation remains consistent. The speaker suggests that the second convention is more intuitive for them.

10:03

🔋 KVL and the Conservation of Energy

Here, the relationship between KVL and the law of conservation of energy is explained. KVL is derived from the principle that voltage is a measure of potential energy difference across an element, which remains independent of the path chosen between two points. The speaker provides an example of calculating potential differences between two points, VA and VB, and explains that KVL deals only with voltages or potential differences, not the potentials themselves.

15:06

🧠 Applying KVL to Solve Potential Differences

This paragraph provides a method for solving potential differences using KVL. The speaker explains how to start from a point, apply KVL by considering only potential differences (voltage sources and drops across resistors), and avoid using individual potentials at points in the circuit. An example of solving for VA - VB is presented, showing how to follow different paths in the circuit and still arrive at the same result. The speaker emphasizes the importance of understanding concepts over memorizing formulas.

Mindmap

Keywords

💡KVL (Kirchhoff's Voltage Law)

Kirchhoff's Voltage Law (KVL) states that the algebraic sum of all voltages in a closed loop is zero. This principle is based on the law of conservation of energy and ensures that the total voltage supplied in a circuit equals the total voltage drop across the components. In the script, KVL is applied to a circuit with resistors and a voltage source, where the sum of the voltages is calculated to be zero.

💡Closed loop

A closed loop in an electrical circuit is a complete path through which current flows. The concept of a closed loop is crucial for applying KVL, as the law deals with the total voltage around such loops. In the video, the closed loop consists of a voltage source and two resistors (R1 and R2), through which current I flows.

💡Voltage drop

A voltage drop occurs when electrical energy is lost as current passes through a resistor or other circuit element, following Ohm's Law (V=IR). In the video, the voltage drop across resistors R1 and R2 is discussed, and it is shown that the potential decreases by an amount proportional to the resistance and current (IR).

💡Ohm's Law

Ohm's Law defines the relationship between voltage (V), current (I), and resistance (R) in an electrical circuit, given by the formula V=IR. This principle is used in the video to calculate the voltage drop across resistors, which is critical for applying KVL to find the sum of voltages in the circuit.

💡Potential difference

Potential difference, also known as voltage, refers to the difference in electric potential between two points in a circuit. It drives the current flow in the circuit. The script explains how the potential difference between two points (e.g., A and B) is calculated using KVL, focusing on how the potential changes across resistors and a voltage source.

💡Resistor

A resistor is a component that opposes the flow of current in a circuit, causing a voltage drop as current passes through it. The script uses two resistors, R1 and R2, to demonstrate how voltage drops across them are calculated and incorporated into the KVL equation. The values of the resistances affect the magnitude of the voltage drops.

💡Series circuit

A series circuit is a type of electrical circuit where components are connected end-to-end, so the same current flows through all of them. In the script, the resistors R1 and R2 are connected in series with the voltage source, meaning the current I is the same through both resistors, and KVL can be applied to find the total voltage drop.

💡Conventions for potential rise and drop

These conventions help determine whether a voltage change is positive or negative in a KVL equation. The video explains two conventions: one where a potential rise (from low to high) is positive and a drop (from high to low) is negative, and another where the opposite signs are used. Both conventions lead to the same final KVL equation.

💡Law of conservation of energy

The law of conservation of energy states that energy cannot be created or destroyed, only transferred or transformed. KVL is based on this law, as it ensures that the total energy supplied to a closed loop is equal to the energy dissipated across the circuit elements. This principle underpins the video’s explanation of why the sum of voltages in a loop equals zero.

💡KCL (Kirchhoff's Current Law)

Kirchhoff's Current Law (KCL) states that the total current entering a junction in a circuit equals the total current leaving the junction. Although this video focuses on KVL, KCL is mentioned as being based on the conservation of charge, in contrast to KVL’s foundation in the conservation of energy.

Highlights

Introduction to KVL (Kirchhoff's Voltage Law)

KVL states the algebraic sum of all voltages in a closed loop is zero

Explanation of how to calculate the sum of voltages considering their signs

Example of a closed loop with a voltage source and two resistors

Concept of potential difference and how it relates to voltage

How to determine the potential at different points in a circuit

Application of Ohm's law to calculate voltage drop across resistors

Derivation of the KVL equation for the example circuit

Introduction to conventions for writing KVL equations

First convention: rise in potential is positive, drop is negative

Second convention: rise in potential is negative, drop is positive

Explanation of why KVL is based on the law of conservation of energy

How voltage is a measure of potential energy difference

The uniqueness of voltage values and their independence of path

How to apply KVL when calculating potential differences between points

Emphasis on not including point potentials in KVL equations

Demonstration of calculating VA - VB using KVL

Explanation of choosing different paths to calculate potential differences

Final statement on the consistency of results when applying KVL correctly

Encouragement to clarify concepts for easy problem-solving

Transcripts

play00:00

in the last lecture we had discussion on

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KCl and now we are going to understand

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what is KVL and how to apply KVL so

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let's move on to this statement of KVL

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the algebraic sum of all the voltages in

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any closed loop is zero so when you

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calculate there is a break sum of all

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the voltages this means you calculate

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the sum of all the voltages considering

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their signs then you will find it is

play00:34

equal to zero in closed loop for example

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here we have a closed loop having three

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elements first one is the voltage source

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providing the voltage V second one is a

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resistor having the value R one the

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third one is resistor again but having

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the value R 2 now let's say the current

play01:00

in this loop is equal to I and we know

play01:05

the potential difference or the voltage

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is equal to the high potential minus the

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low potential let's say this point is

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connected to the ground this means here

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we will have zero volt as the potential

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and therefore here also we will have

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zero volt as the potential and therefore

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this point is still low potential point

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and let's say potential here is equal to

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V Prime

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this is the high potential point so the

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high potential that is V Prime minus the

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low potential that is zero volt will be

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equal to the potential difference or the

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voltage which is V therefore we can say

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that V prime is equal to V so the

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potential here that is V prime is equal

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to V now we know the fact that when

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current I passes through resistance r1

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there will be four

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drop and the voltage drop will be equal

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to current I multiplied to r1 following

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the Ohm's law here potential is V this

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means here also potential will be V and

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this potential will get reduced by hi I

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1 because this is the potential drop due

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to resistance r1 so here we will have

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the potential equal to V minus I R 1 hi

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r1 so here also we will have the

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potential equal to V minus hi hi 1 R 1

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and R 2 are connected in series

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therefore same current I will flow

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through r2 as well and therefore the

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drop across R 2 will be equal to I

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multiplied to r2 therefore when we move

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to this point this potential will reduce

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by hi r2 so V minus I R 1 minus hi r2

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will be the potential at this point but

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this point is having the potential equal

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to zero volt this implies V minus I R 1

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minus IR to V minus I R 1 minus I R 2 is

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equal to zero and this is our KVL

play03:47

equation so I hope you now understand

play03:51

how to find the KVL equation but every

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time we are not going to analyze this

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circuit like this there are some

play04:00

conventions and following those

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conventions you can write down the KVL

play04:05

equation directly and there are

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different ways to write down the KVL

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equation here we have followed the

play04:13

convention in which we are considering

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the rise in potential as positive I will

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first write down the convention and then

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we will follow it in this particular

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Rickett so the convention is rise in

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potential will give you the positive

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sign and the drop in potential who will

play04:44

give you the negative sign now focus on

play04:49

this particular voltage source we are

play04:52

starting from this point and then we

play04:55

will move back to this point and the

play04:58

first element we are encountering is a

play05:00

voltage source now when you move from

play05:03

this point to the upward direction you

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can see that we first encountered the

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negative terminal this means the low

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potential point and then we encountered

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the positive terminal

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this means the high potential point so

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low to high

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this means rising potential and

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therefore we will have the positive sign

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for V so we will write plus V then we

play05:33

will keep on moving and we encountered a

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resistance r1 so here we are having the

play05:39

voltage drop by I R 1 and we know

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resistor will dissipate the power and

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therefore current will enter the

play05:50

positive terminal and it will leave the

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negative terminal we have already

play05:55

discussed at this point in great detail

play05:57

so here you can see that we first

play06:00

encountered the high potential point and

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then we encountered the low potential

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point so there is drop in potential

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hence we will have the negative sign so

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negative I r1

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I R 1 similarly here also we will have

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the drop in potential therefore we will

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write minus hi r2 and this will be equal

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to 0

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so you can see that we have the same

play06:32

equation and from here we can say that V

play06:37

is equal to AI

play06:40

r1 plus r2 now I will give you the

play06:45

second convention and according to this

play06:49

convention the rise in potential will

play06:55

give you the negative sign opposite of

play06:58

this convention and the drop in

play07:02

potential who will give you the positive

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sign this convention is reversed here

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and now we will obtain the KVL equation

play07:13

following the new convention we will

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start from this point and we will

play07:18

encounter an element that is the voltage

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source and you can see that we are

play07:25

having the rise in potential therefore

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we will have the negative sign so minus

play07:31

V then we encounter another element that

play07:35

is a resistor and here we are having the

play07:38

fall or drop in potential therefore we

play07:42

will have the positive sign and then we

play07:45

have I R 1 i R 1 similarly we have plus

play07:51

I R 2 for resistor r2 plus hi r2 and the

play07:57

sum we are going to get is equal to 0

play08:01

and from this equation we can say that

play08:04

voltage V is equal to I multiplied to r1

play08:09

plus r2 the same result now please let

play08:15

me know in the comment section which

play08:17

convention do you want to follow I

play08:19

personally like to follow this

play08:22

convention because this makes more sense

play08:24

to me now

play08:26

we will move on to the last point and

play08:29

according to this point

play08:31

KVL his based on law of conservation of

play08:35

energy

play08:36

KCl was based on law of conservation of

play08:40

charge but KVL is based on law of

play08:44

conservation of energy the voltage is

play08:47

the measure of potential energy

play08:49

difference across the element we know

play08:52

this point

play08:53

and we also know that there is a single

play08:56

unique value of a voltage therefore the

play09:00

energy required to move a unit charge

play09:03

from one point to other his independent

play09:07

of the path chosen you will get the same

play09:10

voltage or potential difference between

play09:13

the two points irrespective of the path

play09:16

you have chosen for example let's say

play09:19

this point his point a and this point

play09:22

his point B and potential here is equal

play09:27

to VA and potential here is equal to VB

play09:31

and we want to calculate the potential

play09:34

difference VA minus VB that is we want

play09:39

to calculate the difference in the

play09:41

potentials of the point a and the point

play09:44

B we want to have the potential

play09:48

difference VA minus VB and due to our

play09:53

initial analysis we know the potential

play09:57

at Point a is equal to zero volt and the

play10:00

potential at point B is equal to V minus

play10:03

I R 1 so we can write VA minus VB equal

play10:09

to 0 minus V minus I R 1 or we can write

play10:16

minus V plus I R 1 so this is the

play10:21

potential difference VA minus VB the

play10:25

potential difference between the point a

play10:28

and the point B but every time you won't

play10:31

have the potentials at the two points

play10:35

and therefore you must know how to apply

play10:38

KVL when you are required to calculate

play10:41

the potential difference between the two

play10:44

random points in the circuit and we know

play10:48

KVL is the voltage law voltage means the

play10:53

potential difference and therefore in

play10:55

the KVL equation you will only have the

play10:59

voltage or potential difference all the

play11:01

three values here our voltages V is the

play11:05

voltage hi r1 is

play11:08

I r2 is also a voltage so you cannot

play11:12

include the potential at a point in KVL

play11:16

equation this means you cannot include

play11:19

VA and you cannot include VB but you can

play11:23

include VA minus VB because VA minus VB

play11:28

is the potential difference or the

play11:30

voltage so I will now explain how to

play11:33

deal with this kind of problem whenever

play11:37

you have to deal with the potentials at

play11:40

a point then pick one point for example

play11:44

pique then write down the potential at

play11:48

ay that is VA I will write here then

play11:52

simply apply KVL up to this particular

play11:56

point move in this direction you will

play11:59

have a voltage source V following this

play12:01

convention we will write plus V Plus V

play12:06

then we will move forward and have one

play12:09

resistance therefore we will have minus

play12:12

hi hi 1 now when you move at this point

play12:17

then don't write VB like this and equate

play12:21

it with zero you have to write equal to

play12:27

and then instead of equating with zero

play12:30

equate it with V B now in this scenario

play12:34

when you subtract V B from both the

play12:38

sides you have VA minus VB plus V minus

play12:43

y1 equal to zero now this is proper KVL

play12:48

equation this is one very powerful way

play12:51

and we will use it a lot to solve the

play12:54

questions in this course so from here we

play12:58

will have VA minus VB equal to minus V

play13:03

Plus hi hi 1 the same result there is

play13:08

one point I want to clear you can see

play13:11

that while applying the KVL starting

play13:14

from the point a we did not included the

play13:18

potential here which

play13:20

we so whenever you apply kvl from one

play13:23

point to another point don't include the

play13:27

other potentials at point because your

play13:30

KVL will then be in valid so simply

play13:35

start with potential at a point and then

play13:38

include only potential differences and

play13:41

then finally equate everything with the

play13:44

final points potential so I hope this

play13:48

was clear now we have chosen one path to

play13:52

calculate VA minus VB we can choose

play13:56

another path as well

play13:57

so now let's calculate VA minus VB

play14:01

following this path we will start from

play14:05

point A and we will have VA then we will

play14:09

have plus I R 2 plus i r2 and then we

play14:17

will stop at point B therefore we will

play14:20

equate with potential VB from here we

play14:25

are getting VA minus V B equal to minus

play14:30

hi r2 and VA minus VB we have calculated

play14:35

should be equal therefore minus V plus I

play14:38

R 1 should be equal to minus I R 2 this

play14:42

implies we will have minus V plus I R 1

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equal to minus I R 2 and from here we

play14:53

can say that V is equal to Y R 1 plus R

play14:58

2 the same result so whatever you do in

play15:03

the circuit following the proper rules

play15:05

you will finally have the same result

play15:08

you don't have to mug up anything you

play15:12

simply have to clear your concepts and

play15:15

if your concepts are clear you can

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easily solve any network so I hope this

play15:21

lecture was clear to you and if you have

play15:23

any doubt you may ask in the comment

play15:25

section I will hand this lecture here

play15:28

see you in the next one

play15:30

[Applause]

play15:33

you

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[Music]

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KVLKirchhoff's LawCircuit AnalysisVoltage LawElectrical EngineeringOhm's LawCurrent FlowSeries CircuitsEnergy ConservationPotential Difference
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