Arithmetic Sequences and Arithmetic Series - Basic Introduction

The Organic Chemistry Tutor
13 May 202144:04

Summary

TLDRThis educational video script explores arithmetic and geometric sequences, distinguishing between the two by their patterns of difference and ratio. It explains how to calculate means, both arithmetic and geometric, and introduces formulas for finding the nth term and the sum of sequences and series. The script also provides examples of identifying sequences and series, whether finite or infinite, and demonstrates how to apply formulas to find specific terms and sums in arithmetic sequences. It further illustrates the process with practice problems, reinforcing the concepts taught.

Takeaways

  • 🔢 Arithmetic sequences have a common difference; for example, 3, 7, 11, 15.
  • 📈 Geometric sequences have a common ratio; for example, 3, 6, 12, 24.
  • ➕ In arithmetic sequences, you add a constant to get the next term.
  • ✖️ In geometric sequences, you multiply by a constant to get the next term.
  • 📊 The arithmetic mean of two numbers in a sequence is their average, like (3+11)/2=7.
  • 🔍 The geometric mean of two numbers in a sequence is the square root of their product, like sqrt(3*12)=6.
  • 🔢 The formula for the nth term of an arithmetic sequence is a_n = a_1 + (n-1)*d.
  • 📈 The formula for the nth term of a geometric sequence is a_n = a_1 * r^(n-1).
  • ➗ Partial sums of arithmetic and geometric sequences have specific formulas.
  • 🔄 Sequences are lists of numbers; series are sums of sequences.

Q & A

  • What is an arithmetic sequence?

    -An arithmetic sequence is a sequence of numbers with a common difference between consecutive terms. For example, the sequence 3, 7, 11, 15, 19, 23, and 27 has a common difference of 4.

  • What is the difference between an arithmetic sequence and a geometric sequence?

    -An arithmetic sequence has a common difference between consecutive terms, while a geometric sequence has a common ratio by which each term is multiplied by to get the next term. For example, the sequence 3, 6, 12, 24, 48, 96 is geometric with a common ratio of 2.

  • How do you calculate the arithmetic mean of two numbers within an arithmetic sequence?

    -The arithmetic mean of two numbers within an arithmetic sequence is found by adding the two numbers and dividing by two. For instance, the mean of 3 and 11 is (3 + 11) / 2 = 7.

  • What is the formula to find the nth term of an arithmetic sequence?

    -The formula to find the nth term (a_sub_n) of an arithmetic sequence is a_sub_n = a_sub_1 + (n - 1) * d, where a_sub_1 is the first term and d is the common difference.

  • How do you find the sum of the first n terms of an arithmetic sequence?

    -The sum of the first n terms (S_sub_n) of an arithmetic sequence is found using the formula S_sub_n = (a_sub_1 + a_sub_n) / 2 * n, where a_sub_1 is the first term and a_sub_n is the nth term.

  • What is the difference between a sequence and a series?

    -A sequence is a list of numbers in a specific order, while a series is the sum of the numbers in a sequence. For example, the list 3, 7, 11, 15 is a sequence, and 3 + 7 + 11 + 15 is a series.

  • How do you determine if a sequence is finite or infinite?

    -A sequence is finite if it has a definite end, and infinite if it continues indefinitely, often indicated by ellipsis (...) at the end.

  • What is the formula to calculate the nth term of a geometric sequence?

    -The formula to find the nth term (a_sub_n) of a geometric sequence is a_sub_n = a_sub_1 * r^(n-1), where a_sub_1 is the first term and r is the common ratio.

  • How do you calculate the sum of the first n terms of a geometric sequence?

    -The sum of the first n terms (S_sub_n) of a geometric sequence is calculated using the formula S_sub_n = a_sub_1 * (1 - r^n) / (1 - r), where a_sub_1 is the first term and r is the common ratio, provided r ≠ 1.

  • What is the difference between the arithmetic mean and the geometric mean of two numbers?

    -The arithmetic mean of two numbers is the average found by adding the numbers and dividing by two. The geometric mean is the square root of the product of the two numbers. For example, the arithmetic mean of 3 and 12 is (3 + 12) / 2 = 7.5, while the geometric mean is √(3 * 12) = √36 = 6.

  • How can you identify whether a sequence is arithmetic or geometric by looking at its terms?

    -A sequence is arithmetic if there is a common difference between consecutive terms. It is geometric if there is a common ratio by which consecutive terms are multiplied to get the next term.

  • What is the sum of the first 300 natural numbers?

    -The sum of the first 300 natural numbers can be calculated using the formula for the sum of an arithmetic series: S_sub_n = n * (a_sub_1 + a_sub_n) / 2, where n = 300, a_sub_1 = 1, and a_sub_n = 300. The sum is 300 * (1 + 300) / 2 = 45150.

Outlines

00:00

🔢 Arithmetic vs. Geometric Sequences

This paragraph introduces the concepts of arithmetic and geometric sequences, providing examples for each. It explains the difference between a common difference in arithmetic sequences and a common ratio in geometric sequences. The paragraph also discusses the calculation of arithmetic and geometric means, illustrating how to find the average of two numbers in an arithmetic sequence and the middle term in a geometric sequence.

05:01

📚 Formulas for Sequences and Series

The second paragraph delves into the formulas for finding the nth term and the partial sum of both arithmetic and geometric sequences. It demonstrates how to calculate any term in an arithmetic sequence using the first term and the common difference, and similarly for a geometric sequence using the first term and the common ratio. The paragraph also explains how to find the sum of the first n terms of each sequence type, providing formulas and examples.

10:03

📉 Summation of Sequences and Series

This paragraph continues the discussion on sequences and series, focusing on the process of summing the terms of a sequence to form a series. It differentiates between finite and infinite sequences and series, providing examples for clarity. The paragraph also emphasizes the importance of understanding the difference between a sequence (a list of numbers) and a series (the sum of those numbers in a sequence).

15:04

🔍 Identifying Sequences and Series

The fourth paragraph presents practice problems to identify whether a given list of numbers is a finite or infinite sequence or series and whether it is arithmetic, geometric, or neither. It provides a method to determine the common difference or ratio and to classify the sequence accordingly. The paragraph also summarizes the answers to the practice problems, categorizing each into the correct type of sequence or series.

20:04

✍️ Writing Terms of Defined Sequences

This paragraph involves writing the first few terms of sequences defined by specific formulas. It explains how to find the initial terms of a sequence by substituting values into the given formula and how to identify the pattern to continue the sequence. The paragraph also covers recursive formulas, showing how to derive subsequent terms based on previous ones.

25:04

📘 Explicit Formulas for Sequences

The sixth paragraph discusses how to write explicit formulas for arithmetic sequences, given the first term and the common difference. It provides a step-by-step process for creating the general formula and applies this to sequences involving fractions by separating the numerator and denominator into distinct sequences. The paragraph illustrates this with examples, ensuring the formulas accurately represent the given sequences.

30:05

📊 nth Term Formulas and Summation

This paragraph focuses on writing nth term formulas for arithmetic sequences and calculating the value of specific terms and the sum of the first n terms. It provides the general formula for an arithmetic sequence and demonstrates its application to find the tenth term and the sum of the first ten terms. The paragraph also includes examples with different sequences to illustrate the process.

35:06

🧩 Sum of Natural Numbers and Even Numbers

The eighth paragraph addresses the calculation of the sum of the first 300 natural numbers and the sum of all even numbers from 2 to 100 inclusive. It uses the formula for the sum of an arithmetic series and provides a step-by-step solution for each case. The paragraph also explains how to determine the number of terms in a sequence when the last term is known.

40:06

🎯 Summation of Odd Integers and Sequence Calculation

The ninth and final paragraph discusses the sum of odd integers from 21 to 75. It explains how to determine the number of terms in the sequence and how to calculate the sum using the arithmetic series formula. The paragraph provides a clear method for finding the sum of a specific range of numbers in a sequence, emphasizing the importance of identifying the correct number of terms.

Mindmap

Keywords

💡Arithmetic Sequence

An arithmetic sequence is a series of numbers in which each term after the first is obtained by adding a constant difference to the previous term. It is central to the video's theme as it demonstrates the fundamental concept of arithmetic progressions. For example, the sequence 3, 7, 11, 15, 19, 23, and 27 is used in the script to illustrate this concept, where the common difference is 4.

💡Geometric Sequence

A geometric sequence is a sequence of numbers where each term after the first is found by multiplying the previous term by a fixed, non-zero number called the common ratio. This concept is juxtaposed with arithmetic sequences in the video to highlight the difference in patterns. The script provides the example 3, 6, 12, 24, 48, 96, 192 to demonstrate a geometric sequence with a common ratio of 2.

💡Common Difference

The common difference in an arithmetic sequence is the constant amount added to each term to get the next term. It is a key element in the formation of arithmetic sequences and is used in the script to explain the pattern within the sequence 3, 7, 11, and so on, where the common difference is 4.

💡Common Ratio

The common ratio in a geometric sequence is the constant factor by which each term is multiplied to obtain the next term. The video script uses the common ratio to explain the pattern in the sequence 3, 6, 12, etc., where the common ratio is 2, indicating that each term is twice the previous one.

💡Arithmetic Mean

The arithmetic mean, often referred to as the average, is calculated by adding a set of numbers and then dividing by the count of numbers. In the context of the video, the arithmetic mean is used to find the middle number in an arithmetic sequence, such as the mean of 3 and 11, which is 7.

💡Geometric Mean

The geometric mean of two numbers is found by multiplying the numbers together and then taking the square root of the product. The script illustrates this by showing that the geometric mean between 3 and 12 is 6, as the square root of 36 (3 * 12) is 6.

💡Nth Term

The nth term of a sequence refers to the specific term in a sequence that is the nth position. The video explains how to find any term in an arithmetic or geometric sequence using formulas. For instance, the formula for the nth term of an arithmetic sequence is a_n = a_1 + (n - 1) * d, where 'd' is the common difference.

💡Partial Sum

The partial sum, denoted as S_n, is the sum of the first n terms of a sequence. The video script discusses how to calculate the partial sum of an arithmetic sequence using the formula S_n = (a_1 + a_n) / 2 * n, and for a geometric sequence, it's S_n = a_1 * (1 - r^n) / (1 - r), where 'r' is the common ratio.

💡Sequence

A sequence is an ordered list of numbers or objects. The video script distinguishes between different types of sequences, such as arithmetic and geometric, and explains the properties that define them, like common differences or ratios.

💡Series

A series is the sum of the terms in a sequence. The script clarifies the difference between a sequence and a series, with the latter being a cumulative total of the numbers in the former. For example, the sum of the arithmetic sequence 3, 7, 11, ..., up to the nth term, is referred to as an arithmetic series.

💡Recursive Formula

A recursive formula is a definition of a sequence where each term is defined in terms of the previous terms. The video script provides examples of recursive formulas and demonstrates how to use them to find subsequent terms in a sequence, such as a_(n) = a_(n-1) + 4.

Highlights

Introduction to the concept of arithmetic sequences and their distinction from geometric sequences.

Explanation of the common difference in arithmetic sequences and common ratio in geometric sequences.

Demonstration of how to calculate the arithmetic mean and its significance in arithmetic sequences.

Illustration of calculating the geometric mean and its relevance to geometric sequences.

Introduction to the formulas for finding the nth term in both arithmetic and geometric sequences.

Practical application of the formula to find the fifth term in an arithmetic sequence example.

Explanation of how to calculate the sixth term in a geometric sequence using the formula.

Clarification on the difference between sequences and series, and their finite and infinite forms.

Tutorial on identifying the type of sequence or series and whether it's finite or infinite.

Method to determine if a sequence is arithmetic, geometric, or neither through pattern recognition.

Practice problems to apply the understanding of sequences and series.

How to write the first four terms of a sequence using a given formula.

Finding the next three terms of an arithmetic sequence given its first few terms.

Writing the first five terms of an arithmetic sequence given the first term and common difference.

Solving recursive formulas to determine terms in a sequence.

Developing a general formula for sequences shown, including handling sequences with fractions.

Writing a formula for the nth term of arithmetic sequences and calculating specific terms.

Calculating the sum of the first 10 terms of an arithmetic sequence using the sum formula.

Finding the sum of the first 300 natural numbers using the arithmetic series sum formula.

Summing all even numbers from 2 to 100 inclusive by identifying the sequence and using the sum formula.

Determining the sum of odd integers from 20 to 76 by calculating the value of n and applying the sum formula.

Transcripts

play00:01

in this video we're going to focus

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mostly on arithmetic sequences

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now to understand what an arithmetic

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sequence is it's helpful to distinguish

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it from a geometric sequence

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so here's an example of an arithmetic

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sequence

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the numbers 3 7 11

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15

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19

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23 and 27 represents an arithmetic

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sequence

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this would be a geometric sequence 3

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6

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12

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24

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48

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96 192.

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do you see the difference between these

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two sequences and do you see any

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patterns within them

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in the arithmetic sequence on the left

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notice that we have a common difference

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this is the first term this is the

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second term this is the third fourth and

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fifth term

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to go from the first term to the second

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term we need to add four

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to go from the second to the third term

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we need to add four

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and that is known as the common

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difference

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in a geometric sequence you don't have a

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common difference rather you have

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something that is called the common

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ratio to go from the first term to the

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second term

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you need to multiply by two

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to go from the second term to the third

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term you need to multiply by two again

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so that is the r value that is the

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common ratio

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so in an arithmetic sequence the pattern

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is based on addition and subtraction

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in a geometric sequence the pattern is

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based on multiplication and

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division now the next thing that we need

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to talk about

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is

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the mean

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how to calculate the arithmetic mean and

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the geometric mean

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the arithmetic mean is basically the

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average of two numbers

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it's a plus b divided by two

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so when taking

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an arithmetic mean of two numbers within

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an arithmetic sequence let's say if we

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were to take

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the mean of three and eleven

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we would get the middle number in that

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sequence in this case we would get 7.

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so if you were to add 3 plus 11

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and divide by 2 3 plus 11 is 14 14

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divided by 2 gives you 7.

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now let's say if we wanted to find the

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arithmetic mean between 7

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and 23 it's going to give us the middle

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number

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of that sequence which is 15.

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so if you would add up 7

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plus 23 divided by 2

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7 plus 23 is 30 30 divided by 2 is 15.

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so that's how you can calculate the

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arithmetic mean and that's how you can

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identify it within

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an arithmetic sequence

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the geometric mean

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is the square root

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of a times b

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so let's say if we want to find the

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geometric mean between three and six

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it's going to give us the middle number

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of the sequence which is

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i mean if we were to find the geometric

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mean between 3 and 12

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we will get the middle number of that

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sequence which is 6.

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so in this case a is 3 b is 12. 3 times

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12 is 36

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the square root of 36 is 6.

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now let's try another example

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let's find the geometric mean

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between 6 and 96

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this should give us the middle number

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24.

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now we need to simplify this radical

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96 is six times sixteen

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six times six is thirty six

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the square root of thirty six is six the

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square root of sixteen is four

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so we have six times four

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which is twenty 24.

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so as you can see

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the geometric mean of two numbers within

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the geometric sequence will give us the

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middle number in between those two

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numbers in that sequence

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now let's clear away a few things

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the formula that we need to find the nth

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term

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of an arithmetic sequence is a sub n

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is equal to a sub 1

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plus n minus 1 times the common

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difference d

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in a geometric sequence

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its a sub n

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is equal to a 1

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times r

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raised to the n minus 1.

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now

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let's use that equation to get the fifth

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term in the arithmetic sequence

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so that's going to be a sub 5

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a sub 1 is the first term which is three

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n is five since we're looking for the

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fifth term the common difference

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is four in this problem

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five minus one is four

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4 times 4 is 16 3 plus 16 is 19.

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so this formula

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gives you any term in the sequence you

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could find the fifth term the seventh

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term the 100th term and so forth

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now in a geometric sequence

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we could use this formula

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so let's calculate the six term

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of the geometric sequence it's going to

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be a sub six

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which equals a sub one the first term is

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three the common ratio is two

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and this is going to be raised to the

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six minus one

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six minus one is five

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and then two to the fifth power if you

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multiply two five times two times two

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times two times two times two

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so we can write it out

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so this here that's four

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three twos make eight four times eight

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is thirty two

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so this is three

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times thirty two

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three times thirty is ninety three times

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two is six

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so this will give you

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ninety six

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so that's how you could find the f term

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in a geometric sequence

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by the way

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make sure you have a sheet of paper to

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write down these formulas

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so that when we work on some practice

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problems

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you know what to do

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now the next thing we need to do is

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be able to calculate the partial sum of

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a sequence

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s sub n is the partial sum of

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a series of a few terms

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and it's equal to the first term plus

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the last term

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divided by two times n

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for geometric sequence the partial sum s

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of n is going to be a sub 1

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times 1 minus r raised to the n

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over

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1 minus r

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so let's find the sum

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of the first seven terms in this

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sequence

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so that's going to be s sub 7

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that's going to equal the first term

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plus the seventh term

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divided by 2

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times n

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where n is the number of terms which is

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7.

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now think about what this means

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so basically to find the sum of an

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arithmetic sequence

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you're basically taking the average

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of the first and the last term in that

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sequence and then multiplying it by the

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number of terms

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in that sequence

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because this is basically the average of

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3

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and 27.

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and we know the average or the

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arithmetic mean of 3 and 27 that's going

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to be the middle number 15.

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so let's go ahead and plug this in

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so this is 3 plus 27

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over 2

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times 7.

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3 plus 27 is 30 plus 2 i mean well 30

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divided by 2 that's 15.

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so the average

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of the first and last term is 15 times 7

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10 times 7 is 70. 5 times 7 is 35

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so this is going to be 105.

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that's the sum of the first seven terms

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and you can confirm this with your

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calculator if you add up three plus

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seven

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plus eleven

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plus fifteen

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plus 19 plus 23

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and then plus 27

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and that will give you s of 7 the sum of

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the first seven terms

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go ahead and add up those numbers

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if you do you'll get 105.

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so that's how you can confirm your

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answer

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now let's do the same thing with a

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geometric sequence

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so let's get the sum

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of the first six terms

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s sub six

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so this is going to be three

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plus six

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plus twelve

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plus twenty four

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plus 48

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plus 96

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so we're adding the first six terms

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now because it's not many terms we're

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adding we can just simply plug this into

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our calculator

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and we'll get 189

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but now let's confirm this answer using

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the formula

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so s sub 6 the sum of the first six

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terms

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is equal to the first term a sub one

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which is three

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times one minus r r is the common ratio

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which is two

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raised to the n

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n is six

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over one minus r or 1 minus 2.

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so i'm going to work over here since

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there's more space

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now 2 to the 6

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that's going to be 64. if you recall 2

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to the fifth power was 32 if you

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multiply 32 by 2 you get 64.

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so this is going to be 1 minus 64.

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and 1 minus 2 is negative 1.

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so this is 3 times

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1 minus 64.

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is negative 63.

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so we could cancel the two negative

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signs a negative divided by a negative

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will be a positive

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so this is just 3 times 63.

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3 times 6 is 18. so 3 times 60 has to be

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180

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and then 3 times 3 is 9 180 plus 9

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adds up to 189

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so we get the same answer

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now what is the difference between

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a sequence and a series

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i'm sure you heard of these two terms

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before but what is the difference

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between them

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now we've already considered what

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an arithmetic sequence is

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a sequence is basically a list of

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numbers

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so that's a sequence

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a series is the sum

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of the numbers in a sequence

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so this here is

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an arithmetic sequence

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this

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is an arithmetic series because it's the

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sum of an arithmetic sequence

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now what we have here is a sequence but

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it's a geometric sequence as we've

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considered earlier

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this

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is a geometric series it's the sum of a

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geometric sequence

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now there are two types of sequences and

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two types of series

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you have a finite sequence

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and an infinite sequence and it's also a

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finite series and an infinite series

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this sequence is finite it has a

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beginning and it has an n

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this series is also finite it has a

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beginning and it has an end

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in contrast if i were to write 3 7

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11

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15 19 and then dot dot dot

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this would be

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an infinite sequence

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the presence of these dots tells us that

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the numbers keep on going to infinity

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now the same is true for a series

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let's say if i had

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three plus seven

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plus eleven plus fifteen plus nineteen

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and then plus dot dot dot dot

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that would also be

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an infinite series

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so now you know the difference between a

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finite series and an infinite series

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now let's work on some practice problems

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describe the pattern of numbers shown

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below is it a sequence or series

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is it finite or infinite

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is it

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arithmetic geometric or neither

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so let's focus on if it's a sequence or

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series first

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part a

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so we got the numbers 4 7 10 13 16 19.

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we're not adding the numbers we're

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simply making a list of it so this is

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a

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sequence the same is true for part b

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we're simply listing the numbers so

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that's a sequence

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in part c we're adding a list of numbers

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so since we have a sum this is going to

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be a series

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d is also a series

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e

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that's a sequence

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for f we're adding numbers so that's a

play14:52

series and the same is true

play14:54

for g

play14:56

so hopefully this example helps you to

play14:57

see the difference between a sequence

play14:59

and a series

play15:01

now let's move on to the next topic is

play15:04

it finite or is it infinite

play15:10

to answer that all we need to

play15:12

do is identify if we have a list of dots

play15:14

at the end or not

play15:16

here this ends at 19. so that's a finite

play15:20

sequence

play15:22

the dots here tells us it's going to go

play15:24

forever so this is an infinite

play15:27

sequence

play15:31

this one we have the dots so this is

play15:34

going to be an infinite series

play15:39

this ends at 162 so it's finite so we

play15:41

have a finite series

play15:45

this is going to be an infinite sequence

play15:51

next we have an infinite series

play15:55

and the last one is a finite series

play16:01

now let's determine if we're dealing

play16:02

with

play16:03

an arithmetic geometric

play16:06

or neither sequence or series

play16:09

so we're looking for a common difference

play16:11

or a common ratio

play16:14

so for a

play16:15

notice that we have a common difference

play16:17

of three four plus three is seven

play16:19

seven plus three is ten

play16:21

so because we have a common difference

play16:24

this is going to be

play16:26

an arithmetic sequence

play16:32

for b going from the first number to the

play16:34

second number we need to multiply by two

play16:37

four times two is eight eight times two

play16:39

is sixteen

play16:40

so we have a common ratio

play16:43

which makes this sequence geometric

play16:50

for answer choice c

play16:51

going from five to nine that's plus four

play16:54

and from nine to thirteen that's plus

play16:56

four so we have a common difference

play17:00

so this is going to be not an arithmetic

play17:02

sequence

play17:03

but an arithmetic series

play17:08

for answer choice d going from two to

play17:10

six we're multiplying by three and then

play17:12

six times three is eighteen

play17:15

so that's a geometric

play17:18

a geometric series

play17:22

now for e

play17:24

going from 50 to 46 that's a difference

play17:26

of negative 4 and 46 to 42 that's the

play17:30

difference of negative four so this

play17:33

is arithmetic

play17:39

for f

play17:40

we have a common ratio of four three

play17:42

times four is twelve

play17:44

twelve times 4 is 48

play17:47

and if you're wondering how to calculate

play17:49

d and r

play17:50

to calculate d take the second term

play17:52

subtracted by the first term

play17:54

7 minus 4 extreme or you could take the

play17:57

third term subtracted by the second 10

play17:59

minus 7 is 4.

play18:02

in the case of f if you take 12 divided

play18:04

by 3 you get 4.

play18:05

48 divided by 12 you get 4. so that's

play18:08

how you can calculate the common

play18:10

difference or the common ratio

play18:13

is by analyzing the second term with

play18:15

respect to the first one

play18:17

so since we have a common ratio

play18:19

this is going to be geometric

play18:24

for g if we subtract 18 by 12 we get a

play18:28

common difference of positive six

play18:30

24 minus 18

play18:32

gives us the same common difference of

play18:34

six

play18:36

so this is going to be

play18:38

arithmetic

play18:40

so now let's put it all together let's

play18:42

summarize the answers

play18:45

so for part a what we have is a finite

play18:47

arithmetic sequence

play18:49

part b

play18:50

this is an infinite geometric sequence

play18:53

c

play18:54

we have an infinite arithmetic series

play18:58

d

play18:59

is a finite geometric series

play19:02

e is an infinite arithmetic sequence

play19:06

f

play19:06

is an infinite geometric series

play19:09

g is a finite arithmetic series

play19:13

so we have three columns of information

play19:16

with two different possible choices

play19:19

thus two to the third is eight which

play19:21

means that we have eight different

play19:22

possible combinations

play19:25

right now i have seven out of the eight

play19:27

different combinations the last one is a

play19:30

finite

play19:31

geometric sequence which i don't have

play19:33

listed here

play19:35

so now you know how to

play19:36

identify whether you have a sequence or

play19:39

series if it's a rhythmical geometric

play19:41

and if it's finite or infinite

play19:44

number two

play19:45

write the first four terms of the

play19:47

sequence defined by the formula a sub n

play19:50

is equal to three n minus seven

play19:55

so the first thing we're going to do is

play19:56

find the first term

play19:58

so we're going to replace n with one

play20:01

so it's going to be three minus seven

play20:04

which is negative 4.

play20:06

and then we're going to repeat the

play20:07

process we're going to find the second

play20:08

term a sub 2.

play20:11

so it's 3 times 2 minus 7

play20:14

which is negative 1.

play20:16

next we'll find a sub 3.

play20:20

three times three is nine minus seven

play20:22

that's two

play20:23

and then the fourth term a sub four

play20:26

that's going to be twelve minus seven

play20:28

which is five

play20:31

so we have a first term of negative four

play20:33

then it's negative one

play20:34

two

play20:35

five

play20:37

and then the sequence can continue

play20:40

so the common difference in this problem

play20:43

is positive three

play20:45

going from negative one to two if you

play20:47

add three you'll get two

play20:48

and then two plus three is five

play20:53

but this is the answer for the problem

play20:55

so

play20:55

this is

play20:57

those are the first four terms of the

play20:58

sequence

play21:00

number three

play21:01

write the next three terms of the

play21:03

following arithmetic sequence

play21:08

in order to find the next three terms we

play21:10

need to determine the common difference

play21:15

a simple way to find the common

play21:16

difference is to subtract the second

play21:18

term by the first term

play21:21

22 minus 15 is 7.

play21:26

now just to confirm we need to make sure

play21:27

that

play21:28

the difference between the third and the

play21:30

second term is the same

play21:32

29 minus 22 is also

play21:35

seven

play21:37

so we have a common difference of seven

play21:40

so we could use that to find in the next

play21:42

three terms

play21:43

so 36 plus 7 is 43

play21:46

43 plus 7 is 50

play21:48

50 plus 7 is 57

play21:51

so these are the next three terms of the

play21:53

arithmetic sequence

play21:56

here's a similar problem but presented

play21:58

differently

play21:59

write the first five terms of an

play22:00

arithmetic sequence

play22:03

given a one and d

play22:06

so we know the first term is 29 and the

play22:09

common difference is negative four

play22:12

so this is all we need to write the

play22:14

first five terms if the common

play22:16

difference is negative four

play22:17

then the next term is going to be 29

play22:19

plus negative four which is 25

play22:23

25 plus negative four or 25 minus 4 is

play22:26

21

play22:27

21 minus 4 is 17

play22:29

17 minus 4 is 13.

play22:32

so that's all we need to do in order to

play22:34

write the first five terms

play22:36

of the arithmetic sequence given this

play22:38

information

play22:40

number five

play22:41

write the first five terms of the

play22:43

sequence

play22:44

defined by the following recursive

play22:46

formulas

play22:49

so let's start with the first one part a

play22:52

so we're given the first term what are

play22:54

the other terms

play22:57

when dealing with recursive formulas

play23:00

we need to realize is that you get the

play23:02

next term by plugging in the previous

play23:03

term

play23:05

so let's say n is 2.

play23:08

when n is two this is a sub two

play23:12

and that's going to equal a sub n minus

play23:15

one two minus one is one so this becomes

play23:17

a sub one plus four

play23:21

so the second term is going to be the

play23:22

first term 3

play23:24

plus 4 which is 7.

play23:30

so we have 3 as the first term 7 as a

play23:33

second term so now let's find the next

play23:34

one

play23:36

so let's plug in 3 for n so this becomes

play23:39

a sub 3

play23:42

the next one this becomes a sub 3 minus

play23:46

1 or a sub 2

play23:48

plus 4.

play23:51

so this is seven

play23:53

plus four which is eleven

play23:55

at this point we can see that we have an

play23:57

arithmetic sequence with a common

play23:59

difference of four so to get the next

play24:01

two terms we could just add four it's

play24:03

going to be 15 and 19.

play24:10

so that's it for part a

play24:12

so when dealing with recursive formulas

play24:13

just remember you get your next term by

play24:15

using the previous term

play24:18

now for part b it there's going to be a

play24:20

little bit more work

play24:22

so plugging in n equals 2

play24:25

we have the second term

play24:27

it's going to be 3 times the first term

play24:30

plus 2.

play24:32

the first term is two

play24:34

so three times two is six plus two that

play24:36

gives us eight

play24:39

so now let's plug in n equals three

play24:45

when n is 3 we have this equation a sub

play24:48

3 is equal to 3 times a sub 2 plus 2.

play24:53

so we're going to take 8 and plug it in

play24:55

here to get the third term

play24:58

so it's 3 times 8 plus 2

play25:01

3 times 8 is 24 plus 2 that's

play25:04

26.

play25:08

now let's focus on the fourth term when

play25:10

n is 4. so this is going to be a sub 4

play25:12

is equal to 3 times

play25:14

a sub 3 plus 2.

play25:17

so now we're going to plug in 26 for a

play25:19

sub 3.

play25:21

so it's 3 times 26 plus 2.

play25:28

3 times 26 is 78 plus 2 that's going to

play25:31

be 80.

play25:36

now let's focus on the fifth term

play25:39

so a sub 5 is going to be 3 times a sub

play25:43

4 plus 2

play25:45

so that's 3 times 80 plus 2

play25:49

3 times 8 is 24 so 3 times 80 is 240

play25:53

plus 2 that's going to be 200

play26:00

so the first five terms are 2

play26:03

8

play26:04

26

play26:05

80

play26:07

and

play26:08

242 so this is neither

play26:12

an arithmetic sequence nor is it a

play26:14

geometric sequence

play26:16

number six

play26:18

write a general formula

play26:20

or explicit formula which is the same

play26:22

for the sequences shown below

play26:25

in order to write a general formula or

play26:27

an explicit formula

play26:29

all we need is the first term and the

play26:31

common difference

play26:32

if it's an arithmetic sequence which for

play26:34

part a

play26:35

it definitely is

play26:38

so if we subtract 14 by 8 we get 6 and

play26:42

if we subtract 20 by 14 we get 6.

play26:44

so we can see that the common difference

play26:48

is positive 6

play26:49

and the first term

play26:51

is 8.

play26:53

so the general formula is a sub n is

play26:55

equal to a sub 1

play26:57

plus n minus 1 times d

play27:00

so all we need is the first term and the

play27:02

common difference

play27:04

and we can write a general formula or an

play27:07

explicit formula

play27:10

the first term is eight

play27:13

d is six

play27:14

now what we're going to do is we're

play27:15

going to distribute six to n minus one

play27:20

so we have six times n which is six n

play27:23

and then this will be negative six

play27:26

next we need to combine like terms

play27:28

so eight plus negative six or eight

play27:31

minus six that's going to be positive

play27:32

two

play27:34

so the general formula is six n

play27:37

plus two

play27:41

so if we were to plug in one

play27:44

this will give us the first term eight

play27:46

six times one plus two is eight

play27:49

if we were to plug in four

play27:50

it should give us the fourth term twenty

play27:52

six

play27:53

six times four is twenty four

play27:55

plus two that's twenty six

play27:59

so now that we have the explicit formula

play28:01

for part a what about the sequence in

play28:04

part b

play28:05

what should we do if we have fractions

play28:12

if you have a fraction like this or a

play28:14

sequence of fractions and you need to

play28:16

write an explicit formula

play28:19

try to separate it into two different

play28:20

sequences

play28:22

notice that we have an arithmetic

play28:24

sequence if we focus in the numerator

play28:26

that sequence is

play28:29

two

play28:30

three

play28:31

four

play28:32

five and six

play28:34

for the denominator we have the sequence

play28:36

three five seven

play28:37

nine eleven

play28:40

so for the sequence on top the first

play28:42

term is two and we can see that the

play28:44

common difference is one

play28:46

the numbers are increasing by one

play28:49

so using the formula a sub n is equal to

play28:51

a sub one plus n minus one times d

play28:55

we have that a sub one is 2

play28:58

and d is 1.

play29:00

if you distribute 1 to n minus 1 you're

play29:02

just going to get n minus 1.

play29:05

so we can combine 2 and negative 1

play29:08

which is positive 1.

play29:10

so we get the formula n plus one

play29:15

and you could check it when you plug in

play29:17

one one plus one is two so the first

play29:19

term is two

play29:21

if you were to plug in

play29:23

five

play29:24

five plus one is six that will give you

play29:26

the fifth term which is six

play29:31

now let's focus on the sequence of the

play29:33

denominators

play29:35

the first term is three the common

play29:37

difference we could see is two

play29:39

five minus three is two

play29:41

seven minus five is two

play29:44

so using this formula again

play29:46

we have a sub n is equal to a sub one a

play29:49

sub one is three plus

play29:51

n minus one times d d is two

play29:56

so let's distribute two to n minus one

play30:00

so that's gonna be two n minus two

play30:03

and then let's combine like terms three

play30:05

minus two is positive one

play30:09

so a sub n is going to be two n

play30:11

plus one

play30:18

so if we want to calculate the first

play30:20

term

play30:21

we plug in one for n two times one is

play30:23

two plus one it gives us

play30:26

three

play30:26

if we wanna calculate the fourth term

play30:29

and it's four

play30:30

two times four is eight plus one it

play30:33

gives us nine

play30:35

so you always want to double check your

play30:36

work to make sure that you have the

play30:38

right formula

play30:40

so now let's put it all together

play30:48

so we're going to write a sub n

play30:51

and we're going to write it as a

play30:52

fraction the sequence for the numerator

play30:54

is n plus one

play30:56

the sequence for the denominator is two

play30:58

n plus one

play31:02

so this right here

play31:06

represents

play31:08

the sequence

play31:10

that corresponds to what we see in part

play31:12

b

play31:15

and we can test it out let's calculate

play31:17

the value of the third term

play31:20

so let's replace n with three it's going

play31:22

to be three plus one

play31:24

over two

play31:25

times three plus one

play31:27

three plus one is four

play31:28

two times three is six plus one that's

play31:30

seven so we get four over seven

play31:33

if we wish to calculate the fifth term

play31:35

it's going to be five plus one

play31:38

over two

play31:39

times five plus one

play31:41

five plus one is six

play31:42

two times five is ten plus one

play31:45

that's 11.

play31:49

and so anytime you have to write an

play31:50

explicit formula given a sequence of

play31:53

fractions

play31:55

separate the numerator and the

play31:56

denominator into two different sequences

play31:58

hopefully they're both arithmetic

play32:01

if it's geometric you may have to look

play32:02

at another video that i'm going to make

play32:03

soon on geometric sequences

play32:06

but

play32:07

break it up into two separate sequences

play32:09

and then write the formulas that way and

play32:11

then put the two formulas in a fraction

play32:13

and that's how you can get the answer

play32:15

number seven

play32:16

write a formula for the nth term of the

play32:19

arithmetic sequences shown below

play32:24

so writing a formula for the f term is

play32:26

basically the same as writing a general

play32:27

formula for the sequence or an explicit

play32:29

formula

play32:31

so we need to identify the first term

play32:33

which we could see as 5

play32:35

and the common difference

play32:38

14 minus 5 is 9

play32:40

23 minus 14 is 9 as well

play32:44

so once we have these two we can write

play32:47

the general formula

play32:52

so let's replace the first term a sub 1

play32:54

with 5.

play32:56

and let's replace d with nine

play32:59

now let's distribute nine to n minus one

play33:05

so we're gonna have nine n minus nine

play33:08

next let's combine like terms

play33:13

so it's going to be 9n and then 5 minus

play33:16

9 is negative 4.

play33:19

so this

play33:20

is the formula for the nth term of the

play33:23

sequence

play33:32

now let's do the same for part b

play33:35

so the first term is 150

play33:38

the common difference is going to be 143

play33:41

minus 150

play33:42

which is negative seven to confirm that

play33:45

if you subtract 136 by 143 you also get

play33:49

negative seven

play33:53

now let's plug it into this formula to

play33:55

write the general equation

play33:59

so a sub n is going to be 150

play34:01

plus

play34:02

n minus 1 times d which is negative

play34:05

seven

play34:06

so let's distribute negative seven to n

play34:08

minus one

play34:12

so it's going to be 150 minus seven n

play34:15

and then negative seven times negative

play34:17

one that's going to be positive 7.

play34:20

so a sub n is going to be negative 7n

play34:24

plus 157

play34:27

or you could just write it as

play34:30

157

play34:32

minus 7n

play34:36

so that is the formula for the nth term

play34:39

of the arithmetic sequence

play34:44

now let's move on to part b

play34:46

calculate the value of the tenth term

play34:49

of the sequence

play34:52

so we're looking for a sub 10. so let's

play34:54

plug in 10 into this equation

play34:56

so it's gonna be nine

play34:57

times ten

play34:59

minus four

play35:00

nine times ten is ninety

play35:02

ninety minus four is eighty-six

play35:05

so that is the tenth term

play35:08

of the sequence in part a

play35:10

for part b

play35:11

the tenth term is going to be 157

play35:15

minus seven times ten

play35:18

seven times ten is seventy one fifty

play35:20

seven

play35:22

minus seventy

play35:23

is going to be eighty seven

play35:30

now let's move on to part c

play35:31

find the sum of the first 10 terms

play35:37

so in order to find the sum we need to

play35:39

use this formula

play35:43

s sub n is equal to the first term plus

play35:45

the last term divided by 2

play35:48

times the number of terms

play35:51

so if we want to find the sum of the

play35:52

first 10 terms we need a sub 1 which we

play35:55

know it's 5.

play35:58

a sub n n is 10 so that's a sub 10

play36:02

the tenth term is 86

play36:04

divided by 2

play36:06

times the number of terms which is 10.

play36:10

5 plus 86 is 91. 91 divided by 2

play36:14

gives us an average of 45.5 of the first

play36:17

and last number

play36:19

and then times 10

play36:21

we get a total sum of 455.

play36:25

so that is the sum of the first 10 terms

play36:28

of this sequence

play36:31

now for part b

play36:33

we're going to do the same thing

play36:34

calculate s sub 10

play36:36

the first term a sub 1 is 150

play36:40

the tenth term is eighty seven

play36:44

divided by two times the number of terms

play36:47

which is ten

play36:50

one fifty plus eighty seven that's two

play36:52

thirty seven

play36:53

divided by 2 that's

play36:55

118.5

play36:57

times 10

play36:58

we get a sum of 11.85

play37:05

so now you know how to calculate the

play37:06

value of the m term and you also know

play37:09

how to find the sum

play37:10

of

play37:11

a series

play37:14

number eight

play37:15

find the sum of the first 300 natural

play37:17

numbers

play37:20

so how can we do this

play37:22

the best thing we can do right now is

play37:23

write a series

play37:25

zero is not a natural number but one is

play37:28

so if we write a list one plus two plus

play37:31

three

play37:32

and this is going to keep on going

play37:35

all the way to 300

play37:39

so to find the sum of a partial series

play37:41

we need to use this equation s sub n is

play37:43

equal to a sub 1

play37:45

plus a sub n over 2 times n

play37:50

now let's write down what we know

play37:52

we know that a sub 1 the first term is

play37:55

one

play37:56

we know n

play37:57

is 300

play37:59

if this is the first term this is the

play38:00

second term this is the third term this

play38:03

must be the 300th term

play38:06

so we know n is 300 and

play38:08

a sub n or a sub 300 is 300

play38:12

so we have everything that we need to

play38:13

calculate the sum of the first 300 terms

play38:17

so it's a sub 1 which is 1 plus a sub n

play38:20

which is 300

play38:22

over 2

play38:23

times the number of terms which is 300

play38:27

so it's going to be 301 divided by 2

play38:30

times 300

play38:32

and that's

play38:33

45

play38:35

150.

play38:37

so that's how we can calculate the sum

play38:39

of the first 300

play38:41

natural numbers

play38:43

in this series

play38:46

number nine

play38:47

calculate the sum of all even numbers

play38:49

from two to one hundred inclusive

play38:52

so let's write a series

play38:55

two is even three is odd so the next

play38:57

even number is four

play38:59

and then six and then eight

play39:02

all the way to one hundred

play39:05

so we have the first term

play39:07

the second term is four

play39:09

the third term is sixty

play39:12

one hundred is likely to be the 50th

play39:14

term but let's confirm it

play39:16

so what we need to do is calculate n and

play39:18

make sure it's 50 and not 49 or 51.

play39:23

so we're going to use this equation to

play39:24

calculate the value of n

play39:30

so a sub n is a hundred

play39:34

let's replace that with a hundred

play39:37

a sub one

play39:38

is two

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the common difference

play39:46

we see four minus two is two six minus

play39:49

four is two so the common difference

play39:52

is two in this example

play39:54

and our goal is to solve for n

play39:57

so let's begin by subtracting both sides

play39:59

by two

play40:01

a hundred minus two is ninety-eight

play40:06

and this is going to equal two times n

play40:07

minus one

play40:09

next we're going to divide both sides by

play40:11

two

play40:14

98 divided by two is 49

play40:17

so we have 49 is equal to n minus one

play40:20

and then we're going to add one to both

play40:22

sides so n is 49 plus 1 which is 50.

play40:28

so that means that

play40:30

100 is indeed the 50th term so we know

play40:33

that n

play40:34

is 50.

play40:36

so now we have everything that we need

play40:37

in order to calculate the sum of the

play40:39

first 50 terms

play40:41

so let's begin by writing out the

play40:43

formula first

play40:48

so the sum of the first 50 of terms is

play40:50

going to be the first term which is 2

play40:53

plus a sub 50 the last term which is 100

play40:56

divided by 2

play40:58

times n

play40:59

which is 50.

play41:02

so 2 plus 100 that's 102 divided by 2

play41:05

that's 51.

play41:06

51 times 50

play41:08

is 2550.

play41:12

so that is the sum

play41:14

of all of the even numbers from 2 to 100

play41:16

inclusive

play41:17

try this one determine the sum of all

play41:20

odd integers from 20 to 76

play41:24

20 is even but the next number 21 is odd

play41:29

and then 23 25 27

play41:32

all of that are odd numbers up until 75

play41:37

so a sub 1

play41:39

is 21 in this problem

play41:44

the last number a sub n

play41:47

is 75

play41:50

and we know the common difference is two

play41:52

because the numbers are increased by two

play41:56

what we need to calculate is the value

play41:58

of n

play41:59

once we could find n then we could find

play42:01

the sum from

play42:02

21 to 75.

play42:06

so what is the value of n

play42:09

so we need to use

play42:11

the general formula for

play42:13

an arithmetic sequence

play42:15

so a sub n is 75 a sub 1 is 21

play42:20

and the common difference is 2.

play42:23

so let's subtract both sides by 21

play42:27

75 minus 21 this is going to be 54.

play42:35

dividing both sides by 2.

play42:40

54 divided by 2 is 27. so we get 27 is n

play42:44

minus 1

play42:45

and then we're going to add 1 to both

play42:47

sides

play42:49

so n is 28

play42:52

so a sub 28 is 75

play42:56

75 is the 28th term in the sequence

play43:00

so now we need to find the sum of the

play43:03

first 28 terms

play43:04

it's going to be a sub 1 the first term

play43:07

plus the last term or the 28th term

play43:09

which is 75

play43:11

divided by 2

play43:13

times the number of terms which is

play43:15

28

play43:21

21 plus 75 that's 96

play43:25

divided by 2 that's 48 so 48 is the

play43:28

average of the first and the last term

play43:31

so 48 times 28

play43:34

that's 1

play43:35

344.

play43:37

so that is the sum of the first 28 terms

play44:03

you

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Arithmetic SequenceGeometric SequenceCommon DifferenceCommon RatioMean CalculationSequence SeriesEducational VideoMathematics TutorialArithmetic MeanGeometric MeanSequence Formula
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