Arithmetic Sequences and Arithmetic Series - Basic Introduction
Summary
TLDRThis educational video script explores arithmetic and geometric sequences, distinguishing between the two by their patterns of difference and ratio. It explains how to calculate means, both arithmetic and geometric, and introduces formulas for finding the nth term and the sum of sequences and series. The script also provides examples of identifying sequences and series, whether finite or infinite, and demonstrates how to apply formulas to find specific terms and sums in arithmetic sequences. It further illustrates the process with practice problems, reinforcing the concepts taught.
Takeaways
- 🔢 Arithmetic sequences have a common difference; for example, 3, 7, 11, 15.
- 📈 Geometric sequences have a common ratio; for example, 3, 6, 12, 24.
- ➕ In arithmetic sequences, you add a constant to get the next term.
- ✖️ In geometric sequences, you multiply by a constant to get the next term.
- 📊 The arithmetic mean of two numbers in a sequence is their average, like (3+11)/2=7.
- 🔍 The geometric mean of two numbers in a sequence is the square root of their product, like sqrt(3*12)=6.
- 🔢 The formula for the nth term of an arithmetic sequence is a_n = a_1 + (n-1)*d.
- 📈 The formula for the nth term of a geometric sequence is a_n = a_1 * r^(n-1).
- ➗ Partial sums of arithmetic and geometric sequences have specific formulas.
- 🔄 Sequences are lists of numbers; series are sums of sequences.
Q & A
What is an arithmetic sequence?
-An arithmetic sequence is a sequence of numbers with a common difference between consecutive terms. For example, the sequence 3, 7, 11, 15, 19, 23, and 27 has a common difference of 4.
What is the difference between an arithmetic sequence and a geometric sequence?
-An arithmetic sequence has a common difference between consecutive terms, while a geometric sequence has a common ratio by which each term is multiplied by to get the next term. For example, the sequence 3, 6, 12, 24, 48, 96 is geometric with a common ratio of 2.
How do you calculate the arithmetic mean of two numbers within an arithmetic sequence?
-The arithmetic mean of two numbers within an arithmetic sequence is found by adding the two numbers and dividing by two. For instance, the mean of 3 and 11 is (3 + 11) / 2 = 7.
What is the formula to find the nth term of an arithmetic sequence?
-The formula to find the nth term (a_sub_n) of an arithmetic sequence is a_sub_n = a_sub_1 + (n - 1) * d, where a_sub_1 is the first term and d is the common difference.
How do you find the sum of the first n terms of an arithmetic sequence?
-The sum of the first n terms (S_sub_n) of an arithmetic sequence is found using the formula S_sub_n = (a_sub_1 + a_sub_n) / 2 * n, where a_sub_1 is the first term and a_sub_n is the nth term.
What is the difference between a sequence and a series?
-A sequence is a list of numbers in a specific order, while a series is the sum of the numbers in a sequence. For example, the list 3, 7, 11, 15 is a sequence, and 3 + 7 + 11 + 15 is a series.
How do you determine if a sequence is finite or infinite?
-A sequence is finite if it has a definite end, and infinite if it continues indefinitely, often indicated by ellipsis (...) at the end.
What is the formula to calculate the nth term of a geometric sequence?
-The formula to find the nth term (a_sub_n) of a geometric sequence is a_sub_n = a_sub_1 * r^(n-1), where a_sub_1 is the first term and r is the common ratio.
How do you calculate the sum of the first n terms of a geometric sequence?
-The sum of the first n terms (S_sub_n) of a geometric sequence is calculated using the formula S_sub_n = a_sub_1 * (1 - r^n) / (1 - r), where a_sub_1 is the first term and r is the common ratio, provided r ≠ 1.
What is the difference between the arithmetic mean and the geometric mean of two numbers?
-The arithmetic mean of two numbers is the average found by adding the numbers and dividing by two. The geometric mean is the square root of the product of the two numbers. For example, the arithmetic mean of 3 and 12 is (3 + 12) / 2 = 7.5, while the geometric mean is √(3 * 12) = √36 = 6.
How can you identify whether a sequence is arithmetic or geometric by looking at its terms?
-A sequence is arithmetic if there is a common difference between consecutive terms. It is geometric if there is a common ratio by which consecutive terms are multiplied to get the next term.
What is the sum of the first 300 natural numbers?
-The sum of the first 300 natural numbers can be calculated using the formula for the sum of an arithmetic series: S_sub_n = n * (a_sub_1 + a_sub_n) / 2, where n = 300, a_sub_1 = 1, and a_sub_n = 300. The sum is 300 * (1 + 300) / 2 = 45150.
Outlines
🔢 Arithmetic vs. Geometric Sequences
This paragraph introduces the concepts of arithmetic and geometric sequences, providing examples for each. It explains the difference between a common difference in arithmetic sequences and a common ratio in geometric sequences. The paragraph also discusses the calculation of arithmetic and geometric means, illustrating how to find the average of two numbers in an arithmetic sequence and the middle term in a geometric sequence.
📚 Formulas for Sequences and Series
The second paragraph delves into the formulas for finding the nth term and the partial sum of both arithmetic and geometric sequences. It demonstrates how to calculate any term in an arithmetic sequence using the first term and the common difference, and similarly for a geometric sequence using the first term and the common ratio. The paragraph also explains how to find the sum of the first n terms of each sequence type, providing formulas and examples.
📉 Summation of Sequences and Series
This paragraph continues the discussion on sequences and series, focusing on the process of summing the terms of a sequence to form a series. It differentiates between finite and infinite sequences and series, providing examples for clarity. The paragraph also emphasizes the importance of understanding the difference between a sequence (a list of numbers) and a series (the sum of those numbers in a sequence).
🔍 Identifying Sequences and Series
The fourth paragraph presents practice problems to identify whether a given list of numbers is a finite or infinite sequence or series and whether it is arithmetic, geometric, or neither. It provides a method to determine the common difference or ratio and to classify the sequence accordingly. The paragraph also summarizes the answers to the practice problems, categorizing each into the correct type of sequence or series.
✍️ Writing Terms of Defined Sequences
This paragraph involves writing the first few terms of sequences defined by specific formulas. It explains how to find the initial terms of a sequence by substituting values into the given formula and how to identify the pattern to continue the sequence. The paragraph also covers recursive formulas, showing how to derive subsequent terms based on previous ones.
📘 Explicit Formulas for Sequences
The sixth paragraph discusses how to write explicit formulas for arithmetic sequences, given the first term and the common difference. It provides a step-by-step process for creating the general formula and applies this to sequences involving fractions by separating the numerator and denominator into distinct sequences. The paragraph illustrates this with examples, ensuring the formulas accurately represent the given sequences.
📊 nth Term Formulas and Summation
This paragraph focuses on writing nth term formulas for arithmetic sequences and calculating the value of specific terms and the sum of the first n terms. It provides the general formula for an arithmetic sequence and demonstrates its application to find the tenth term and the sum of the first ten terms. The paragraph also includes examples with different sequences to illustrate the process.
🧩 Sum of Natural Numbers and Even Numbers
The eighth paragraph addresses the calculation of the sum of the first 300 natural numbers and the sum of all even numbers from 2 to 100 inclusive. It uses the formula for the sum of an arithmetic series and provides a step-by-step solution for each case. The paragraph also explains how to determine the number of terms in a sequence when the last term is known.
🎯 Summation of Odd Integers and Sequence Calculation
The ninth and final paragraph discusses the sum of odd integers from 21 to 75. It explains how to determine the number of terms in the sequence and how to calculate the sum using the arithmetic series formula. The paragraph provides a clear method for finding the sum of a specific range of numbers in a sequence, emphasizing the importance of identifying the correct number of terms.
Mindmap
Keywords
💡Arithmetic Sequence
💡Geometric Sequence
💡Common Difference
💡Common Ratio
💡Arithmetic Mean
💡Geometric Mean
💡Nth Term
💡Partial Sum
💡Sequence
💡Series
💡Recursive Formula
Highlights
Introduction to the concept of arithmetic sequences and their distinction from geometric sequences.
Explanation of the common difference in arithmetic sequences and common ratio in geometric sequences.
Demonstration of how to calculate the arithmetic mean and its significance in arithmetic sequences.
Illustration of calculating the geometric mean and its relevance to geometric sequences.
Introduction to the formulas for finding the nth term in both arithmetic and geometric sequences.
Practical application of the formula to find the fifth term in an arithmetic sequence example.
Explanation of how to calculate the sixth term in a geometric sequence using the formula.
Clarification on the difference between sequences and series, and their finite and infinite forms.
Tutorial on identifying the type of sequence or series and whether it's finite or infinite.
Method to determine if a sequence is arithmetic, geometric, or neither through pattern recognition.
Practice problems to apply the understanding of sequences and series.
How to write the first four terms of a sequence using a given formula.
Finding the next three terms of an arithmetic sequence given its first few terms.
Writing the first five terms of an arithmetic sequence given the first term and common difference.
Solving recursive formulas to determine terms in a sequence.
Developing a general formula for sequences shown, including handling sequences with fractions.
Writing a formula for the nth term of arithmetic sequences and calculating specific terms.
Calculating the sum of the first 10 terms of an arithmetic sequence using the sum formula.
Finding the sum of the first 300 natural numbers using the arithmetic series sum formula.
Summing all even numbers from 2 to 100 inclusive by identifying the sequence and using the sum formula.
Determining the sum of odd integers from 20 to 76 by calculating the value of n and applying the sum formula.
Transcripts
in this video we're going to focus
mostly on arithmetic sequences
now to understand what an arithmetic
sequence is it's helpful to distinguish
it from a geometric sequence
so here's an example of an arithmetic
sequence
the numbers 3 7 11
15
19
23 and 27 represents an arithmetic
sequence
this would be a geometric sequence 3
6
12
24
48
96 192.
do you see the difference between these
two sequences and do you see any
patterns within them
in the arithmetic sequence on the left
notice that we have a common difference
this is the first term this is the
second term this is the third fourth and
fifth term
to go from the first term to the second
term we need to add four
to go from the second to the third term
we need to add four
and that is known as the common
difference
in a geometric sequence you don't have a
common difference rather you have
something that is called the common
ratio to go from the first term to the
second term
you need to multiply by two
to go from the second term to the third
term you need to multiply by two again
so that is the r value that is the
common ratio
so in an arithmetic sequence the pattern
is based on addition and subtraction
in a geometric sequence the pattern is
based on multiplication and
division now the next thing that we need
to talk about
is
the mean
how to calculate the arithmetic mean and
the geometric mean
the arithmetic mean is basically the
average of two numbers
it's a plus b divided by two
so when taking
an arithmetic mean of two numbers within
an arithmetic sequence let's say if we
were to take
the mean of three and eleven
we would get the middle number in that
sequence in this case we would get 7.
so if you were to add 3 plus 11
and divide by 2 3 plus 11 is 14 14
divided by 2 gives you 7.
now let's say if we wanted to find the
arithmetic mean between 7
and 23 it's going to give us the middle
number
of that sequence which is 15.
so if you would add up 7
plus 23 divided by 2
7 plus 23 is 30 30 divided by 2 is 15.
so that's how you can calculate the
arithmetic mean and that's how you can
identify it within
an arithmetic sequence
the geometric mean
is the square root
of a times b
so let's say if we want to find the
geometric mean between three and six
it's going to give us the middle number
of the sequence which is
i mean if we were to find the geometric
mean between 3 and 12
we will get the middle number of that
sequence which is 6.
so in this case a is 3 b is 12. 3 times
12 is 36
the square root of 36 is 6.
now let's try another example
let's find the geometric mean
between 6 and 96
this should give us the middle number
24.
now we need to simplify this radical
96 is six times sixteen
six times six is thirty six
the square root of thirty six is six the
square root of sixteen is four
so we have six times four
which is twenty 24.
so as you can see
the geometric mean of two numbers within
the geometric sequence will give us the
middle number in between those two
numbers in that sequence
now let's clear away a few things
the formula that we need to find the nth
term
of an arithmetic sequence is a sub n
is equal to a sub 1
plus n minus 1 times the common
difference d
in a geometric sequence
its a sub n
is equal to a 1
times r
raised to the n minus 1.
now
let's use that equation to get the fifth
term in the arithmetic sequence
so that's going to be a sub 5
a sub 1 is the first term which is three
n is five since we're looking for the
fifth term the common difference
is four in this problem
five minus one is four
4 times 4 is 16 3 plus 16 is 19.
so this formula
gives you any term in the sequence you
could find the fifth term the seventh
term the 100th term and so forth
now in a geometric sequence
we could use this formula
so let's calculate the six term
of the geometric sequence it's going to
be a sub six
which equals a sub one the first term is
three the common ratio is two
and this is going to be raised to the
six minus one
six minus one is five
and then two to the fifth power if you
multiply two five times two times two
times two times two times two
so we can write it out
so this here that's four
three twos make eight four times eight
is thirty two
so this is three
times thirty two
three times thirty is ninety three times
two is six
so this will give you
ninety six
so that's how you could find the f term
in a geometric sequence
by the way
make sure you have a sheet of paper to
write down these formulas
so that when we work on some practice
problems
you know what to do
now the next thing we need to do is
be able to calculate the partial sum of
a sequence
s sub n is the partial sum of
a series of a few terms
and it's equal to the first term plus
the last term
divided by two times n
for geometric sequence the partial sum s
of n is going to be a sub 1
times 1 minus r raised to the n
over
1 minus r
so let's find the sum
of the first seven terms in this
sequence
so that's going to be s sub 7
that's going to equal the first term
plus the seventh term
divided by 2
times n
where n is the number of terms which is
7.
now think about what this means
so basically to find the sum of an
arithmetic sequence
you're basically taking the average
of the first and the last term in that
sequence and then multiplying it by the
number of terms
in that sequence
because this is basically the average of
3
and 27.
and we know the average or the
arithmetic mean of 3 and 27 that's going
to be the middle number 15.
so let's go ahead and plug this in
so this is 3 plus 27
over 2
times 7.
3 plus 27 is 30 plus 2 i mean well 30
divided by 2 that's 15.
so the average
of the first and last term is 15 times 7
10 times 7 is 70. 5 times 7 is 35
so this is going to be 105.
that's the sum of the first seven terms
and you can confirm this with your
calculator if you add up three plus
seven
plus eleven
plus fifteen
plus 19 plus 23
and then plus 27
and that will give you s of 7 the sum of
the first seven terms
go ahead and add up those numbers
if you do you'll get 105.
so that's how you can confirm your
answer
now let's do the same thing with a
geometric sequence
so let's get the sum
of the first six terms
s sub six
so this is going to be three
plus six
plus twelve
plus twenty four
plus 48
plus 96
so we're adding the first six terms
now because it's not many terms we're
adding we can just simply plug this into
our calculator
and we'll get 189
but now let's confirm this answer using
the formula
so s sub 6 the sum of the first six
terms
is equal to the first term a sub one
which is three
times one minus r r is the common ratio
which is two
raised to the n
n is six
over one minus r or 1 minus 2.
so i'm going to work over here since
there's more space
now 2 to the 6
that's going to be 64. if you recall 2
to the fifth power was 32 if you
multiply 32 by 2 you get 64.
so this is going to be 1 minus 64.
and 1 minus 2 is negative 1.
so this is 3 times
1 minus 64.
is negative 63.
so we could cancel the two negative
signs a negative divided by a negative
will be a positive
so this is just 3 times 63.
3 times 6 is 18. so 3 times 60 has to be
180
and then 3 times 3 is 9 180 plus 9
adds up to 189
so we get the same answer
now what is the difference between
a sequence and a series
i'm sure you heard of these two terms
before but what is the difference
between them
now we've already considered what
an arithmetic sequence is
a sequence is basically a list of
numbers
so that's a sequence
a series is the sum
of the numbers in a sequence
so this here is
an arithmetic sequence
this
is an arithmetic series because it's the
sum of an arithmetic sequence
now what we have here is a sequence but
it's a geometric sequence as we've
considered earlier
this
is a geometric series it's the sum of a
geometric sequence
now there are two types of sequences and
two types of series
you have a finite sequence
and an infinite sequence and it's also a
finite series and an infinite series
this sequence is finite it has a
beginning and it has an n
this series is also finite it has a
beginning and it has an end
in contrast if i were to write 3 7
11
15 19 and then dot dot dot
this would be
an infinite sequence
the presence of these dots tells us that
the numbers keep on going to infinity
now the same is true for a series
let's say if i had
three plus seven
plus eleven plus fifteen plus nineteen
and then plus dot dot dot dot
that would also be
an infinite series
so now you know the difference between a
finite series and an infinite series
now let's work on some practice problems
describe the pattern of numbers shown
below is it a sequence or series
is it finite or infinite
is it
arithmetic geometric or neither
so let's focus on if it's a sequence or
series first
part a
so we got the numbers 4 7 10 13 16 19.
we're not adding the numbers we're
simply making a list of it so this is
a
sequence the same is true for part b
we're simply listing the numbers so
that's a sequence
in part c we're adding a list of numbers
so since we have a sum this is going to
be a series
d is also a series
e
that's a sequence
for f we're adding numbers so that's a
series and the same is true
for g
so hopefully this example helps you to
see the difference between a sequence
and a series
now let's move on to the next topic is
it finite or is it infinite
to answer that all we need to
do is identify if we have a list of dots
at the end or not
here this ends at 19. so that's a finite
sequence
the dots here tells us it's going to go
forever so this is an infinite
sequence
this one we have the dots so this is
going to be an infinite series
this ends at 162 so it's finite so we
have a finite series
this is going to be an infinite sequence
next we have an infinite series
and the last one is a finite series
now let's determine if we're dealing
with
an arithmetic geometric
or neither sequence or series
so we're looking for a common difference
or a common ratio
so for a
notice that we have a common difference
of three four plus three is seven
seven plus three is ten
so because we have a common difference
this is going to be
an arithmetic sequence
for b going from the first number to the
second number we need to multiply by two
four times two is eight eight times two
is sixteen
so we have a common ratio
which makes this sequence geometric
for answer choice c
going from five to nine that's plus four
and from nine to thirteen that's plus
four so we have a common difference
so this is going to be not an arithmetic
sequence
but an arithmetic series
for answer choice d going from two to
six we're multiplying by three and then
six times three is eighteen
so that's a geometric
a geometric series
now for e
going from 50 to 46 that's a difference
of negative 4 and 46 to 42 that's the
difference of negative four so this
is arithmetic
for f
we have a common ratio of four three
times four is twelve
twelve times 4 is 48
and if you're wondering how to calculate
d and r
to calculate d take the second term
subtracted by the first term
7 minus 4 extreme or you could take the
third term subtracted by the second 10
minus 7 is 4.
in the case of f if you take 12 divided
by 3 you get 4.
48 divided by 12 you get 4. so that's
how you can calculate the common
difference or the common ratio
is by analyzing the second term with
respect to the first one
so since we have a common ratio
this is going to be geometric
for g if we subtract 18 by 12 we get a
common difference of positive six
24 minus 18
gives us the same common difference of
six
so this is going to be
arithmetic
so now let's put it all together let's
summarize the answers
so for part a what we have is a finite
arithmetic sequence
part b
this is an infinite geometric sequence
c
we have an infinite arithmetic series
d
is a finite geometric series
e is an infinite arithmetic sequence
f
is an infinite geometric series
g is a finite arithmetic series
so we have three columns of information
with two different possible choices
thus two to the third is eight which
means that we have eight different
possible combinations
right now i have seven out of the eight
different combinations the last one is a
finite
geometric sequence which i don't have
listed here
so now you know how to
identify whether you have a sequence or
series if it's a rhythmical geometric
and if it's finite or infinite
number two
write the first four terms of the
sequence defined by the formula a sub n
is equal to three n minus seven
so the first thing we're going to do is
find the first term
so we're going to replace n with one
so it's going to be three minus seven
which is negative 4.
and then we're going to repeat the
process we're going to find the second
term a sub 2.
so it's 3 times 2 minus 7
which is negative 1.
next we'll find a sub 3.
three times three is nine minus seven
that's two
and then the fourth term a sub four
that's going to be twelve minus seven
which is five
so we have a first term of negative four
then it's negative one
two
five
and then the sequence can continue
so the common difference in this problem
is positive three
going from negative one to two if you
add three you'll get two
and then two plus three is five
but this is the answer for the problem
so
this is
those are the first four terms of the
sequence
number three
write the next three terms of the
following arithmetic sequence
in order to find the next three terms we
need to determine the common difference
a simple way to find the common
difference is to subtract the second
term by the first term
22 minus 15 is 7.
now just to confirm we need to make sure
that
the difference between the third and the
second term is the same
29 minus 22 is also
seven
so we have a common difference of seven
so we could use that to find in the next
three terms
so 36 plus 7 is 43
43 plus 7 is 50
50 plus 7 is 57
so these are the next three terms of the
arithmetic sequence
here's a similar problem but presented
differently
write the first five terms of an
arithmetic sequence
given a one and d
so we know the first term is 29 and the
common difference is negative four
so this is all we need to write the
first five terms if the common
difference is negative four
then the next term is going to be 29
plus negative four which is 25
25 plus negative four or 25 minus 4 is
21
21 minus 4 is 17
17 minus 4 is 13.
so that's all we need to do in order to
write the first five terms
of the arithmetic sequence given this
information
number five
write the first five terms of the
sequence
defined by the following recursive
formulas
so let's start with the first one part a
so we're given the first term what are
the other terms
when dealing with recursive formulas
we need to realize is that you get the
next term by plugging in the previous
term
so let's say n is 2.
when n is two this is a sub two
and that's going to equal a sub n minus
one two minus one is one so this becomes
a sub one plus four
so the second term is going to be the
first term 3
plus 4 which is 7.
so we have 3 as the first term 7 as a
second term so now let's find the next
one
so let's plug in 3 for n so this becomes
a sub 3
the next one this becomes a sub 3 minus
1 or a sub 2
plus 4.
so this is seven
plus four which is eleven
at this point we can see that we have an
arithmetic sequence with a common
difference of four so to get the next
two terms we could just add four it's
going to be 15 and 19.
so that's it for part a
so when dealing with recursive formulas
just remember you get your next term by
using the previous term
now for part b it there's going to be a
little bit more work
so plugging in n equals 2
we have the second term
it's going to be 3 times the first term
plus 2.
the first term is two
so three times two is six plus two that
gives us eight
so now let's plug in n equals three
when n is 3 we have this equation a sub
3 is equal to 3 times a sub 2 plus 2.
so we're going to take 8 and plug it in
here to get the third term
so it's 3 times 8 plus 2
3 times 8 is 24 plus 2 that's
26.
now let's focus on the fourth term when
n is 4. so this is going to be a sub 4
is equal to 3 times
a sub 3 plus 2.
so now we're going to plug in 26 for a
sub 3.
so it's 3 times 26 plus 2.
3 times 26 is 78 plus 2 that's going to
be 80.
now let's focus on the fifth term
so a sub 5 is going to be 3 times a sub
4 plus 2
so that's 3 times 80 plus 2
3 times 8 is 24 so 3 times 80 is 240
plus 2 that's going to be 200
so the first five terms are 2
8
26
80
and
242 so this is neither
an arithmetic sequence nor is it a
geometric sequence
number six
write a general formula
or explicit formula which is the same
for the sequences shown below
in order to write a general formula or
an explicit formula
all we need is the first term and the
common difference
if it's an arithmetic sequence which for
part a
it definitely is
so if we subtract 14 by 8 we get 6 and
if we subtract 20 by 14 we get 6.
so we can see that the common difference
is positive 6
and the first term
is 8.
so the general formula is a sub n is
equal to a sub 1
plus n minus 1 times d
so all we need is the first term and the
common difference
and we can write a general formula or an
explicit formula
the first term is eight
d is six
now what we're going to do is we're
going to distribute six to n minus one
so we have six times n which is six n
and then this will be negative six
next we need to combine like terms
so eight plus negative six or eight
minus six that's going to be positive
two
so the general formula is six n
plus two
so if we were to plug in one
this will give us the first term eight
six times one plus two is eight
if we were to plug in four
it should give us the fourth term twenty
six
six times four is twenty four
plus two that's twenty six
so now that we have the explicit formula
for part a what about the sequence in
part b
what should we do if we have fractions
if you have a fraction like this or a
sequence of fractions and you need to
write an explicit formula
try to separate it into two different
sequences
notice that we have an arithmetic
sequence if we focus in the numerator
that sequence is
two
three
four
five and six
for the denominator we have the sequence
three five seven
nine eleven
so for the sequence on top the first
term is two and we can see that the
common difference is one
the numbers are increasing by one
so using the formula a sub n is equal to
a sub one plus n minus one times d
we have that a sub one is 2
and d is 1.
if you distribute 1 to n minus 1 you're
just going to get n minus 1.
so we can combine 2 and negative 1
which is positive 1.
so we get the formula n plus one
and you could check it when you plug in
one one plus one is two so the first
term is two
if you were to plug in
five
five plus one is six that will give you
the fifth term which is six
now let's focus on the sequence of the
denominators
the first term is three the common
difference we could see is two
five minus three is two
seven minus five is two
so using this formula again
we have a sub n is equal to a sub one a
sub one is three plus
n minus one times d d is two
so let's distribute two to n minus one
so that's gonna be two n minus two
and then let's combine like terms three
minus two is positive one
so a sub n is going to be two n
plus one
so if we want to calculate the first
term
we plug in one for n two times one is
two plus one it gives us
three
if we wanna calculate the fourth term
and it's four
two times four is eight plus one it
gives us nine
so you always want to double check your
work to make sure that you have the
right formula
so now let's put it all together
so we're going to write a sub n
and we're going to write it as a
fraction the sequence for the numerator
is n plus one
the sequence for the denominator is two
n plus one
so this right here
represents
the sequence
that corresponds to what we see in part
b
and we can test it out let's calculate
the value of the third term
so let's replace n with three it's going
to be three plus one
over two
times three plus one
three plus one is four
two times three is six plus one that's
seven so we get four over seven
if we wish to calculate the fifth term
it's going to be five plus one
over two
times five plus one
five plus one is six
two times five is ten plus one
that's 11.
and so anytime you have to write an
explicit formula given a sequence of
fractions
separate the numerator and the
denominator into two different sequences
hopefully they're both arithmetic
if it's geometric you may have to look
at another video that i'm going to make
soon on geometric sequences
but
break it up into two separate sequences
and then write the formulas that way and
then put the two formulas in a fraction
and that's how you can get the answer
number seven
write a formula for the nth term of the
arithmetic sequences shown below
so writing a formula for the f term is
basically the same as writing a general
formula for the sequence or an explicit
formula
so we need to identify the first term
which we could see as 5
and the common difference
14 minus 5 is 9
23 minus 14 is 9 as well
so once we have these two we can write
the general formula
so let's replace the first term a sub 1
with 5.
and let's replace d with nine
now let's distribute nine to n minus one
so we're gonna have nine n minus nine
next let's combine like terms
so it's going to be 9n and then 5 minus
9 is negative 4.
so this
is the formula for the nth term of the
sequence
now let's do the same for part b
so the first term is 150
the common difference is going to be 143
minus 150
which is negative seven to confirm that
if you subtract 136 by 143 you also get
negative seven
now let's plug it into this formula to
write the general equation
so a sub n is going to be 150
plus
n minus 1 times d which is negative
seven
so let's distribute negative seven to n
minus one
so it's going to be 150 minus seven n
and then negative seven times negative
one that's going to be positive 7.
so a sub n is going to be negative 7n
plus 157
or you could just write it as
157
minus 7n
so that is the formula for the nth term
of the arithmetic sequence
now let's move on to part b
calculate the value of the tenth term
of the sequence
so we're looking for a sub 10. so let's
plug in 10 into this equation
so it's gonna be nine
times ten
minus four
nine times ten is ninety
ninety minus four is eighty-six
so that is the tenth term
of the sequence in part a
for part b
the tenth term is going to be 157
minus seven times ten
seven times ten is seventy one fifty
seven
minus seventy
is going to be eighty seven
now let's move on to part c
find the sum of the first 10 terms
so in order to find the sum we need to
use this formula
s sub n is equal to the first term plus
the last term divided by 2
times the number of terms
so if we want to find the sum of the
first 10 terms we need a sub 1 which we
know it's 5.
a sub n n is 10 so that's a sub 10
the tenth term is 86
divided by 2
times the number of terms which is 10.
5 plus 86 is 91. 91 divided by 2
gives us an average of 45.5 of the first
and last number
and then times 10
we get a total sum of 455.
so that is the sum of the first 10 terms
of this sequence
now for part b
we're going to do the same thing
calculate s sub 10
the first term a sub 1 is 150
the tenth term is eighty seven
divided by two times the number of terms
which is ten
one fifty plus eighty seven that's two
thirty seven
divided by 2 that's
118.5
times 10
we get a sum of 11.85
so now you know how to calculate the
value of the m term and you also know
how to find the sum
of
a series
number eight
find the sum of the first 300 natural
numbers
so how can we do this
the best thing we can do right now is
write a series
zero is not a natural number but one is
so if we write a list one plus two plus
three
and this is going to keep on going
all the way to 300
so to find the sum of a partial series
we need to use this equation s sub n is
equal to a sub 1
plus a sub n over 2 times n
now let's write down what we know
we know that a sub 1 the first term is
one
we know n
is 300
if this is the first term this is the
second term this is the third term this
must be the 300th term
so we know n is 300 and
a sub n or a sub 300 is 300
so we have everything that we need to
calculate the sum of the first 300 terms
so it's a sub 1 which is 1 plus a sub n
which is 300
over 2
times the number of terms which is 300
so it's going to be 301 divided by 2
times 300
and that's
45
150.
so that's how we can calculate the sum
of the first 300
natural numbers
in this series
number nine
calculate the sum of all even numbers
from two to one hundred inclusive
so let's write a series
two is even three is odd so the next
even number is four
and then six and then eight
all the way to one hundred
so we have the first term
the second term is four
the third term is sixty
one hundred is likely to be the 50th
term but let's confirm it
so what we need to do is calculate n and
make sure it's 50 and not 49 or 51.
so we're going to use this equation to
calculate the value of n
so a sub n is a hundred
let's replace that with a hundred
a sub one
is two
the common difference
we see four minus two is two six minus
four is two so the common difference
is two in this example
and our goal is to solve for n
so let's begin by subtracting both sides
by two
a hundred minus two is ninety-eight
and this is going to equal two times n
minus one
next we're going to divide both sides by
two
98 divided by two is 49
so we have 49 is equal to n minus one
and then we're going to add one to both
sides so n is 49 plus 1 which is 50.
so that means that
100 is indeed the 50th term so we know
that n
is 50.
so now we have everything that we need
in order to calculate the sum of the
first 50 terms
so let's begin by writing out the
formula first
so the sum of the first 50 of terms is
going to be the first term which is 2
plus a sub 50 the last term which is 100
divided by 2
times n
which is 50.
so 2 plus 100 that's 102 divided by 2
that's 51.
51 times 50
is 2550.
so that is the sum
of all of the even numbers from 2 to 100
inclusive
try this one determine the sum of all
odd integers from 20 to 76
20 is even but the next number 21 is odd
and then 23 25 27
all of that are odd numbers up until 75
so a sub 1
is 21 in this problem
the last number a sub n
is 75
and we know the common difference is two
because the numbers are increased by two
what we need to calculate is the value
of n
once we could find n then we could find
the sum from
21 to 75.
so what is the value of n
so we need to use
the general formula for
an arithmetic sequence
so a sub n is 75 a sub 1 is 21
and the common difference is 2.
so let's subtract both sides by 21
75 minus 21 this is going to be 54.
dividing both sides by 2.
54 divided by 2 is 27. so we get 27 is n
minus 1
and then we're going to add 1 to both
sides
so n is 28
so a sub 28 is 75
75 is the 28th term in the sequence
so now we need to find the sum of the
first 28 terms
it's going to be a sub 1 the first term
plus the last term or the 28th term
which is 75
divided by 2
times the number of terms which is
28
21 plus 75 that's 96
divided by 2 that's 48 so 48 is the
average of the first and the last term
so 48 times 28
that's 1
344.
so that is the sum of the first 28 terms
you
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