Prereq 13: Complex Numbers
Summary
TLDRIn this final lesson of the AP pre-calculus prerequisites review, Judy introduces complex numbers, emphasizing their importance for pre-calculus. She explains the imaginary unit 'i' and its powers, then discusses complex numbers as the sum of a real and an imaginary part. Judy covers operations with complex numbers, their properties, and the concept of complex conjugates. She provides examples of addition, subtraction, and multiplication of complex numbers, as well as simplifying expressions involving complex numbers in denominators. The lesson aims to build procedural and symbolic fluency, preparing students for AP pre-calculus.
Takeaways
- π This is the final lesson in a series of 13, focusing on complex numbers, a topic important for pre-calculus students.
- π§ Complex numbers consist of a real part and an imaginary part, written in the form a + bi, where 'a' is the real part and 'bi' is the imaginary part.
- π’ The imaginary unit 'i' is defined as the square root of negative one. Powers of 'i' follow a repeating pattern: i, -1, -i, and 1.
- π To simplify powers of 'i' greater than 4, divide the exponent by 4 and use the remainder to find the corresponding value of 'i'.
- βοΈ Addition and subtraction of complex numbers involve combining the real parts and the imaginary parts separately.
- βοΈ Multiplication of complex numbers is done using the distributive property (FOIL method), and the result is simplified by substituting iΒ² with -1.
- π Complex numbers can be plotted on a coordinate plane with the horizontal axis representing real numbers and the vertical axis representing imaginary numbers.
- π A complex conjugate is formed by changing the sign of the imaginary part of a complex number. It's used to eliminate imaginary numbers from denominators.
- β Simplifying expressions involving complex numbers in the denominator requires multiplying by the complex conjugate of the denominator.
- π― The lesson emphasizes the importance of understanding complex numbers as a foundation for success in AP pre-calculus.
Q & A
What is the main topic of the 13th lesson in the AP pre-calculus prerequisites review?
-The main topic of the 13th lesson is complex numbers, which are a prerequisite for AP pre-calculus.
What is an imaginary number?
-An imaginary number is a number that can be written as the square root of a negative number, with 'i' defined as the square root of negative one.
What happens when you square the imaginary unit 'i'?
-When you square 'i', the result is negative one, since i^2 = -1.
How can you simplify higher powers of 'i'?
-You can simplify higher powers of 'i' by dividing the exponent by 4 and using the remainder as the new exponent, following the pattern of i^1 = i, i^2 = -1, i^3 = -i, and i^4 = 1.
What is a complex number and how is it represented?
-A complex number is the sum of a real number and an imaginary number, represented in the form a + bi, where 'a' is the real part and 'bi' is the imaginary part.
Do the properties of real numbers also apply to complex numbers?
-Yes, all the properties that apply to real numbers, such as commutative, associative, and distributive properties, also apply to complex numbers.
How can complex numbers be plotted?
-Complex numbers can be plotted on a real and imaginary coordinate plane, with the horizontal axis for real numbers and the vertical axis for imaginary numbers.
What is a complex conjugate and why is it important?
-A complex conjugate is the result of changing the sign of the imaginary part of a complex number, e.g., the conjugate of 3 + 4i is 3 - 4i. It is important for simplifying expressions and eliminating complex numbers from the denominator.
How do you simplify the expression (4 + 3i) + (7 - 5i)?
-You simplify by combining like terms: (4 + 7) + (3i - 5i), which results in 11 - 2i.
What is the result of multiplying complex numbers (4 + 3i) * (7 - 5i)?
-You distribute the multiplication as with polynomials, resulting in 28 - 20i + 21i - 15, which simplifies to 43 + i after combining like terms and considering i^2 = -1.
How do you simplify the expression (2 + 5i) / (4 - 2i)?
-You multiply the numerator and denominator by the complex conjugate of the denominator (4 + 2i), simplify the resulting expressions, and then reduce the fraction to get (-1 + 12i) / 10.
Outlines
π Introduction to Complex Numbers
The first paragraph introduces the topic of complex numbers in the context of AP pre-calculus prerequisites. Judy, the presenter, explains that while students are expected to be familiar with complex numbers, they do not need to be proficient. The lesson includes a review of imaginary numbers, starting with the definition of 'i' as the square root of -1. It proceeds to explain the powers of 'i', demonstrating the cyclical nature of these powers and how to simplify expressions involving 'i' raised to higher powers. The paragraph also covers the definition of a complex number as a sum of a real and an imaginary part, the properties that apply to complex numbers, and the concept of the complex conjugate, which is essential for simplifying expressions with complex numbers in the denominator.
π Complex Number Operations and Simplification
This paragraph delves into the practical application of complex numbers, starting with addition and subtraction. Judy illustrates how to simplify expressions by combining like terms, using the commutative property. She then moves on to multiplication, showing the process of distributing and simplifying the product of two complex numbers, including the substitution of 'i' squared with -1. The paragraph also addresses division involving complex numbers, explaining the use of the complex conjugate to eliminate complex numbers from the denominator and simplify the expression. Through examples, Judy demonstrates the process of simplifying complex fractions by multiplying the numerator and denominator by the conjugate of the denominator, resulting in a simplified form without complex numbers in the denominator.
π Conclusion and Encouragement for AP Pre-Calculus
In the final paragraph, Judy wraps up the lesson by emphasizing the importance of understanding imaginary and complex numbers for success in AP pre-calculus. She reminds students of the mathematical practices and skills they've been building throughout the series, which will aid in their pre-calculus journey. Judy expresses excitement for the students' progress and encourages them to feel confident as they begin their AP pre-calculus course, wishing them good luck and reinforcing the idea that they are well-prepared for the challenges ahead.
Mindmap
Keywords
π‘Imaginary Number
π‘Complex Numbers
π‘Square Root of Negative One
π‘Complex Conjugate
π‘Commutative Property
π‘Associative Property
π‘Distributive Property
π‘Real and Imaginary Coordinate Plane
π‘I Squared
π‘Simplification
π‘Pre-Calculus Mathematical Practices
Highlights
Introduction to imaginary numbers and their basic properties.
Definition of the imaginary number i as the square root of -1.
Explanation of the powers of i and how they repeat in a cycle of four.
Simplification of higher powers of i by dividing the exponent by 4.
Introduction to complex numbers as the sum of a real number and an imaginary number.
Properties of operations with complex numbers follow the same rules as real numbers.
Plotting complex numbers on a real and imaginary coordinate plane.
Definition and importance of complex conjugates in simplifying expressions.
Example of adding complex numbers: (4 + 3i) + (7 - 5i).
Example of subtracting complex numbers: (4 + 3i) - (7 - 5i).
Example of multiplying complex numbers: (4 + 3i) * (7 - 5i).
Explanation of distributing multiplication in complex numbers similarly to polynomials.
Using complex conjugates to simplify complex fractions.
Example of simplifying a complex fraction: (2 + 5i) / (4 - 2i).
Final review and encouragement for students preparing for AP pre-calculus.
Transcripts
hi everyone I'm Judy from the AP program
welcome back to the AP pre-calculus
prerequisites review and thanks for
tuning in lesson number 13 is the final
lesson and complex numbers is a topic
that you should be familiar with but
you're not expected to be proficient in
this topic so this should cover the
basics of what you need to know as you
enter pre-calculus
as with the previous lessons after this
instructional video you have the option
to complete a practice problem set check
your answers using our answer key and
annotated Solutions and watch a video
demonstrating the solution for the
problem or problems that you found the
most difficult that way you can decide
if you need extra support from a teacher
or a tutor or one of your peers and
you'll be able to be specific about what
you need help with
reminders for imaginary numbers are what
we're going to start out with today
and the imaginary number is a square
root of a negative number
in particular the imaginary number I is
defined as I equals the square root of
negative one
when we look at powers of I if I is the
square root of negative 1 then I squared
is the square root of negative 1 squared
the squaring and square rooting cancel
each other out and so we end up with a
value of negative one
so I is the square root of negative one
I squared is negative 1.
I to the third power is the same as I
squared negative 1 times I so that comes
out to negative I
so I is the square root of negative 1 I
squared is negative 1 I to the third
power is negative I
and then I to the fourth power is the
same as I squared which is negative 1
times I squared which is negative one
and when you multiply those you get one
this whole process and this whole
pattern continues to repeat over and
over and over again so I to the fifth
power would be the square root of
negative one I to the sixth power would
be negative one I to the seventh power
would be negative i i to the eighth
power would be one
I to the ninth power would be the square
root of would be I the square root of
negative 1 and it continues on and on
and on over and over in other words
any time that I is raised to a power
greater than 4 if you want to simplify
it you simply divide the exponent by 4
and the remainder becomes your
simplified expression exponent so for
example I to the 15th power 15 divided
by 4 would be 12 remainder 3 and so that
would be the same thing as I to the
third power which is negative one
and now that we know a little bit more
about imaginary numbers let's look at a
few reminders for complex numbers
first a complex number is the sum of a
real number and an imaginary number
written in the form a plus bi with the
real number is the first term and the
imaginary number is the last term so for
example 5 plus 3i 5 is a real number 3i
is an imaginary number and it's the sum
of the two
in terms of properties for operations
with real number real numbers and
complex numbers all of the properties
that apply to real numbers also apply to
complex numbers so things like the
commutative property the associative
property the distributive property all
of the properties you've been working
with for a long long time with real
numbers apply to complex numbers as well
next complex numbers can be plotted on a
real and imaginary coordinate plane
where the horizontal axis it represents
real numbers and the vertical axis
represents the imaginary numbers
and the last reminder is a complex
conjugate that's probably a term you
haven't heard in a while and maybe
you've only heard once along the way a
complex conjugate is the expression that
results from changing the sign of the
imaginary part of a complex number so
for example 3 plus 4i is the complex
conjugate of three minus 4i
this is important because simplified
Expressions don't have any imaginary
numbers in the denominator so if you see
a complex number in the denominator you
need to use the complex conjugate in
order to eliminate that complex number
in the denominator
and I'll show you an example like that
so that you can see what I'm talking
about
now that we've been reminded what
imaginary numbers are and complex
numbers are we're going to go ahead and
work through a few examples in example
one the first expression that we're
going to simplify is the quantity 4 plus
3i plus the quantity 7 minus 5i and if
you recall whenever you've got addition
between sets of parentheses you can
simply drop the parentheses and when we
do that because of the commutative
property we can rearrange the order of
things as well so we're going to Cluster
together the real numbers and we're
going to Cluster together the com the
imaginary numbers so that we can go
ahead and add like terms so 4 plus 7 is
11 and 3i minus 5i is minus 2i
and there's our simplified answer
for example B 4 plus 3i minus the
quantity 7 minus 5i let's not forget
that we need to take that minus sign and
distribute it to everything in the
second set of parentheses so it's going
to be a minus 7 and a plus 5i that we
use to go ahead and do our
simplification so 4 minus 7 is negative
3 and 3i plus 5i is positive 8i so our
simplified answer is negative 3 plus 8i
and then when we're multiplying complex
numbers for part C to this example 4
plus 3i times 7 minus 5i we're going to
go ahead and distribute multiplication
and in the same way that we did when we
were multiplying polynomials so we're
going to start by multiplying the first
terms of each set of parentheses 4 times
7 then the outside terms so 4 times
negative 5i then the inside terms so 3
times 7 and then the last terms in each
set of parentheses so 3i times negative
5i
and when we do that we get 28
minus 20 I
plus 21
minus 15 I squared
we're going to further simplify that we
know that I squared is the same thing as
negative 1.
so that's negative 15 times negative 1.
and we can also combine the negative 20i
and the 21 I to get 1 I
so 28 plus I plus 15
gives us a final simplified answer of 43
plus I
for example two we're going to simplify
the expression 2 plus 5i over 4 minus 2i
remember we can't have any complex
numbers in the denominator in a
simplified response right so we're going
to start by multiplying the top and the
bottom we're going to multiply the
numerator and denominator by the same
value which is the complex conjugate of
the denominator so we're going to
multiply top and bottom by 4 plus 2i
we're going to foil together the
Expressions on the top of the fractions
and we're going to foil together the
expressions in the denominator of the
fractions
so for the top when we foil those
together we're going to get 8 plus 4i
plus 20i plus 10i squared
and on the bottom when we foil those
expressions together we're going to end
up with 16 plus 8i minus 8i minus 4i
squared
let's not forget that I squared is
negative 1 so when we combine our like
terms on the top and put together the 4i
and the 24 and the 20i to get 24i we can
also change the I squared to a negative
1.
and then we'll do something similar on
the bottom when we combine the 8i and
the negative 8i they'll cancel each
other out and we'll go ahead and replace
that I squared with negative 1.
so the numerator becomes 8 plus 24i
minus 10 and the denominator becomes 16
plus 4. so when we combine our like
terms in the numerator we end up with
negative 2 plus 24i and when we do the
same in the denominator we end up with
20.
we're almost done
the reason that we're not done is
because all of the numbers in this can
be reduced by a value of 2. so we're
going to go ahead and reduce this
fraction by 2.
and when we do we're going to get
negative 1 plus 12i over 10.
there's our final simplified answer
so those are all of the new things that
you needed to hear about
imaginary numbers and complex numbers
and I just wanted to remind you once
again of the pre-calculus mathematical
practices and skills
so that you can understand and make ties
to what you're learning and how it's
going to play into AP pre-calculus and
once again what we've done today has
been largely in the area of procedural
and symbolic fluency so you're building
this skill deeply and that's going to
help you be more successful when you
arrive in your AP pre-calculus soon
thank you so much for joining me I'm so
excited that you've stayed with me all
through 13 lessons and I know that you
must be feeling really good about
starting AP pre-calculus knowing that
these are the topics that you should
know before you go in and good luck with
your AP pre-calculus you've got this
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