Projectile Motion (Non-Horizontally Launched) Tagalog Physics Tutorial

Summary

In this tutorial, the speaker explains the principles of projectile motion, specifically focusing on the trajectory of a long jumper. Using an initial velocity of 12 meters per second at a 28-degree angle, the tutorial demonstrates how to calculate key aspects of the jump, including time of flight, horizontal distance (range), and peak height. The speaker walks through the use of relevant physics formulas, highlighting how vertical and horizontal components of velocity, as well as gravity's influence, shape the jumper’s motion. The tutorial includes step-by-step calculations for clarity and understanding.

Takeaways

• 😀 The tutorial explains projectile motion, specifically the trajectory of an object launched at a certain angle and velocity.
• 😀 The maximum height reached by the object in projectile motion is denoted as 'dy' (vertical displacement).
• 😀 The horizontal distance traveled by the object is called 'dx' or the 'range'.
• 😀 The initial vertical velocity (Vi_y) can be calculated using the formula 'Vi_y = V * sin(θ)', where V is the initial velocity and θ is the launch angle.
• 😀 The horizontal velocity (Vi_x) is constant and can be calculated as 'Vi_x = V * cos(θ)'.
• 😀 The final vertical velocity at the highest point is zero, as the object momentarily stops before falling back down.
• 😀 Gravity affects only the vertical motion of the object, with a constant acceleration of -9.8 m/s².
• 😀 The time taken to reach the highest point of the trajectory is equal to the time taken to fall back down, meaning the total time of flight is double the time to reach the peak.
• 😀 In the example of a long jumper, with an initial velocity of 12 m/s at an angle of 28 degrees, the time of flight is 1.14 seconds.
• 😀 The horizontal distance (range) traveled by the long jumper can be calculated using the formula 'dx = Vi_x * time'.
• 😀 The peak height of the long jumper can be calculated using kinematic equations that involve initial vertical velocity, acceleration due to gravity, and time.
• 😀 The vertical displacement at the highest point (dy) can be calculated using the equation 'dy = Vi_y * time + 1/2 * a_y * t²'.

Q & A

What is the main topic of the video?

The video tutorial discusses projectile motion, particularly focusing on a long jumper's motion, including time of flight, horizontal distance, and peak height.

What does 'dy' represent in the projectile motion discussion?

'dy' represents the maximum height or the vertical displacement at the highest point of the jumper's flight.

What is the significance of the horizontal distance in projectile motion?

The horizontal distance is referred to as 'dx' and represents the range of the projectile, which is the distance the jumper travels horizontally from the starting point to the landing point.

Why is the vertical final velocity ('vf') at the peak of the motion zero?

At the peak of the projectile's motion, the vertical velocity becomes zero because the jumper momentarily stops before descending.

How is the horizontal velocity ('vi_x') related to the jumper's motion?

The horizontal velocity ('vi_x') remains constant throughout the jumper’s flight because horizontal acceleration is zero, meaning no forces act on the jumper horizontally.

What is the significance of gravity in the vertical motion of the jumper?

Gravity, with an acceleration of -9.8 m/s², acts on the jumper's vertical motion, causing a deceleration as the jumper rises and an acceleration as they fall.

How is the time of flight determined in projectile motion?

The time of flight is determined by calculating the time it takes for the object to reach the peak of its flight and then doubling it, as the time ascending equals the time descending.

How do you calculate the initial vertical velocity ('vi_y')?

The initial vertical velocity ('vi_y') can be calculated by multiplying the initial velocity ('vi') by the sine of the launch angle (θ), i.e., 'vi_y = vi * sin(θ)'.

How does the angle of launch affect the jumper's motion?

The launch angle affects both the vertical and horizontal components of the initial velocity, influencing the maximum height, range, and time of flight.

What formula is used to calculate the peak height of the jumper?

The peak height can be calculated using the equation 'dy = vi_y * t + 0.5 * ay * t²', where 'vi_y' is the initial vertical velocity, 'ay' is the acceleration due to gravity, and 't' is the time to reach the peak.