Physics 20: 2.3 2D Vectors

BGRS Online
27 Jan 201609:13

Summary

TLDRThis educational video script explains the process of solving vector addition in two dimensions with vectors at angles. The presenter guides viewers through the steps of determining vector components, combining them, and calculating the resultant vector. Using an example of a person walking 15 meters at 30° north of east and then 10 meters at 20° west of north, the script demonstrates how to find the horizontal and vertical components using trigonometry, add them to find the resultant displacement, and then use the Pythagorean theorem to determine the magnitude and direction of the final vector. The method is illustrated with clear examples, making it accessible for learners to understand and apply.

Takeaways

  • 📐 Today, we are solving vector problems involving two vectors in two dimensions.
  • 📊 First, break down the vectors into components to simplify the problem.
  • 📝 Example problem: A person walks 15m at East 30° North and then 10m at North 20° West.
  • 📏 Calculate the vertical and horizontal components of the first vector (15m at 30°).
  • 📐 The vertical component is 7.5m and the horizontal component is 12.99m.
  • 📏 Next, calculate the components of the second vector (10m at 20°).
  • 📐 The vertical component is 9.4m and the horizontal component is 3.42m.
  • 🔄 Combine the vertical components (7.5m + 9.4m = 16.9m) and the horizontal components (12.99m - 3.42m = 9.57m).
  • 📐 Use the Pythagorean theorem to find the resultant vector length (19m) and angle (60°).
  • ✅ Final displacement is 19m at East 60° North.

Q & A

  • What is the process for solving vector addition problems with two vectors in two dimensions?

    -The process involves breaking down the problem into steps: first, determine the vector components for each vector, then combine these components, and finally calculate the resultant vector which includes its magnitude and direction.

  • How does the example in the script illustrate the vector addition process?

    -The example demonstrates the process by showing a person walking 15 meters at 30° North of East, followed by 10 meters at 20° West of North. The script then guides through finding the horizontal and vertical components of each vector, combining them, and finally calculating the resultant vector's magnitude and direction.

  • What is the first step in solving for the vector components of a given vector?

    -The first step is to sketch the situation and determine the horizontal (x) and vertical (y) components of the vector by using trigonometric functions such as sine for the vertical component and cosine for the horizontal component.

  • How are the horizontal and vertical components of the first vector in the example calculated?

    -For the first vector, the vertical component is calculated using sin(30°) * 15 m, which equals 7.5 m. The horizontal component is calculated using cos(30°) * 15 m, which equals approximately 12.99 m.

  • What trigonometric functions are used to find the components of the second vector in the example?

    -For the second vector, sine is used to find the horizontal component (sin(20°) * 10 m), and cosine is used to find the vertical component (cos(20°) * 10 m).

  • How are the components of the second vector combined with the first to find the resultant vector?

    -The vertical components (9.4 m and 7.5 m) are added together, and the horizontal components (12.99 m to the right and 3.42 m to the left) are combined by subtracting the leftward component from the rightward component, resulting in a net horizontal component of 9.57 m to the right.

  • What mathematical theorem is used to find the magnitude of the resultant vector?

    -The Pythagorean theorem is used to find the magnitude of the resultant vector by adding the squares of the combined vertical and horizontal components and then taking the square root of the sum.

  • How is the direction of the resultant vector determined?

    -The direction of the resultant vector is determined by calculating the angle it makes with the horizontal axis, which can be found using trigonometric functions and the components of the resultant vector.

  • What is the final answer for the magnitude and direction of the resultant vector in the example?

    -The final answer for the magnitude is approximately 19.4 meters, and the direction is East 60° North.

  • Why is it important to break down the original vectors into their components before combining them?

    -Breaking down the original vectors into their components simplifies the process of vector addition, especially when the vectors are not aligned with the coordinate axes. It allows for easier calculation of the resultant vector's magnitude and direction.

  • Can the process demonstrated in the script be applied to vectors with different magnitudes or angles?

    -Yes, the process can be applied to vectors with different magnitudes or angles. The key is to calculate the horizontal and vertical components for each vector and then combine and recalculate the resultant vector accordingly.

Outlines

00:00

📚 Introduction to Solving Vector Addition in Two Dimensions

This paragraph introduces the concept of solving vector addition problems in two dimensions where vectors are at specific angles, making the calculations more complex. The speaker outlines the process of breaking down the problem into manageable steps: identifying vector components, combining them, and determining the resultant vector. An example is presented where a person walks 15 meters east at 30° north and then 10 meters at 20° west of north. The goal is to find the final displacement and direction. The speaker emphasizes the importance of sketching the situation and calculating the vertical and horizontal components of each vector using trigonometric functions like sine and cosine. The first vector's components are calculated as 12.99 meters east and 7.5 meters north.

05:00

🔍 Calculating Components and Resultant Vector for Two Vectors

In this paragraph, the process continues with the calculation of the second vector's components. The horizontal component is found using the sine of the angle (20°), resulting in 3.42 meters to the west, and the vertical component using the cosine of the angle (20°), resulting in 9.4 meters upward. The speaker then combines the vertical components of both vectors, summing 9.4 meters and 7.5 meters to get a total upward displacement of 16.9 meters. For the horizontal components, the eastward displacement (12.99 meters) is adjusted by subtracting the westward displacement (3.42 meters), yielding a net eastward displacement of 9.57 meters. The final step involves using the Pythagorean theorem to find the magnitude of the resultant vector, which is approximately 19.43 meters, and calculating the direction, which is found to be 60° north of east. The paragraph concludes with the final answer presented in vector notation, rounded to two decimal places.

Mindmap

Keywords

💡Vector Components

Vector components refer to the individual horizontal and vertical parts of a vector when it is decomposed in a two-dimensional space. In the video, the concept is used to break down the complex motion of a person walking at specific angles into simpler, easier-to-manage parts. For example, the person walks 15 meters at 30° North of East, which is then decomposed into a vertical component (7.5 meters North) and a horizontal component (12.99 meters East).

💡Resultant Vector

The resultant vector is the single vector that represents the combined effect of two or more vectors acting together. In the context of the video, after determining the individual components of the vectors representing the person's walk, the resultant vector is calculated by adding the vertical components and subtracting the horizontal components due to their opposite directions. This gives the final displacement and direction of the person's walk.

💡Trigonometry

Trigonometry is a branch of mathematics that deals with the relationships between the sides and angles of triangles. The video uses trigonometric functions, such as sine and cosine, to calculate the vertical and horizontal components of the vectors. For instance, the vertical component is found using sin(30°) * 15 meters, and the horizontal component is found using cos(30°) * 15 meters.

💡Pythagorean Theorem

The Pythagorean theorem is a fundamental principle in geometry that states the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. In the video, the theorem is applied to find the magnitude of the resultant vector by adding the squares of the vertical and horizontal components and then taking the square root of the sum.

💡Displacement

Displacement in physics refers to the change in position of an object. It is a vector quantity that has both magnitude and direction. In the video, the person's final displacement is calculated by determining the resultant vector after the person has walked in two different directions with specific angles and magnitudes.

💡Direction

Direction in this context refers to the orientation of the resultant vector, which indicates the angle at which the object has moved from its starting point. The video explains how to find the direction of the resultant vector by using the calculated components and applying trigonometric relationships.

💡Angles

Angles are a measure of rotation and are crucial in determining the direction of vectors. In the script, angles such as 30° North of East and 20° West of North are given to specify the direction of the person's walk. These angles are used to decompose the vectors into their components and later to find the resultant vector's direction.

💡Horizontal Component

The horizontal component of a vector is the part of the vector that acts parallel to the ground or along the x-axis in a two-dimensional coordinate system. In the video, the horizontal component is calculated for each vector to find how far the person moves east or west.

💡Vertical Component

The vertical component of a vector is the part of the vector that acts perpendicular to the ground or along the y-axis in a two-dimensional coordinate system. In the video, the vertical component is calculated to determine how far the person moves north or south.

💡Sine and Cosine Functions

Sine and cosine are trigonometric functions used to relate the angles of a right triangle to the lengths of its sides. In the video, sine is used to find the vertical component (opposite side), and cosine is used to find the horizontal component (adjacent side) of the vectors.

Highlights

Introduction to solving vector component questions with two vectors in two dimensions.

First step: figure out the vector components and then combine them.

Example problem: adding vectors 15 meters at East 30° North and 10 meters at North 20° West.

Sketching the situation to visualize the problem.

Finding the resultant displacement and direction.

Breaking down the vectors into vertical and horizontal components.

Calculating the components using trigonometric functions: sine and cosine.

Summing up vertical components: 7.5 (first vector) + 9.4 (second vector) = 16.9.

Calculating the horizontal components: 12.99 (first vector) - 3.42 (second vector) = 9.57.

Using Pythagorean theorem to find the resultant vector's magnitude: 19.43.

Finding the angle of the resultant vector: 60°.

Stating the final vector in terms of magnitude and direction: 19 meters at East 60° North.

Second example problem: 25 meters/second at an angle of 40° from Northwest.

Second vector: 30 meters/second straight South.

Repeating the process of breaking into components and solving.

Transcripts

play00:00

okay today we're going to look at

play00:02

solving Vector com questions that have

play00:05

uh two vectors in two Dimensions so both

play00:07

of them are going at Angles so that

play00:09

makes things a little more complicated

play00:11

but what we have to do is we just have

play00:13

to break it down into a couple of steps

play00:14

where we do exactly what we did before

play00:17

so we're going to first of all figure

play00:19

out what the vector components are and

play00:21

then we're going to combine those and

play00:23

then figure out what the resultant would

play00:24

be so the best way to show this is just

play00:26

to start with an example so let's do

play00:28

that so let's our question is so a

play00:33

person walks 15

play00:36

M

play00:39

at so let's suppose we want to add 15

play00:42

M at uh

play00:45

East 30°

play00:48

north and then let's say they're going

play00:51

to go 10 m after

play00:54

that

play00:57

at

play00:58

North

play01:00

20° West okay so the question is what is

play01:05

the resultant what is our final

play01:07

displacement and Direction so for all

play01:09

these questions you want to find the

play01:10

length of the vector plus the

play01:13

direction okay so our first the first

play01:16

thing is let's sketch out this this

play01:19

situation so let's suppose we started at

play01:21

the bottom here so we're going to go at

play01:23

30

play01:24

Dees okay so we know it's going to be

play01:28

30° from east to North nor and this was

play01:31

15 and then afterwards the second Vector

play01:34

we're going to go from head to tail so

play01:36

we're going to start the second one and

play01:38

it's going to go something like

play01:40

that right where this is

play01:43

20° and that one's going to go 10 so the

play01:47

question then is what is the resultant

play01:49

so our resultant would be from

play01:51

start to finish okay so for us to try to

play01:55

do this with trigonometry it's a little

play01:57

bit difficult because we don't know all

play01:58

the angles we don't know whether it's a

play02:00

right angle triangle or not so the best

play02:02

bet is to first step is to figure out

play02:05

the components so if we look at just

play02:07

that first Vector the

play02:09

15 the first thing you want to do is

play02:12

figure out the vertical and horizontal

play02:15

components of of that vector by itself

play02:19

okay so we know it's 30° we know it's 15

play02:22

so we can easily solve for each of those

play02:24

so our vertical side because the Y is

play02:27

the opposite so you'd have S of 30

play02:30

equals opposite over

play02:33

15 and we can do that on our calculator

play02:36

so just go sin

play02:38

30 time 15 so that'll give us

play02:45

7.5 okay so we know that that side is

play02:48

7.5 and then we want to do the same

play02:50

thing for the bottom but the bottom this

play02:51

time is adjacent so we'd have cosine of

play02:55

30 = x over

play02:58

15 so do that one on your calculator

play03:03

go cos 30 *

play03:09

15 and that gives us

play03:12

12.99 we'll leave the decimals intact

play03:15

for now we'll round off at the end okay

play03:17

so 12.99 so we've got our two sides of

play03:21

that initial triangle let me write those

play03:23

in there so we have 12.99 to the East

play03:28

and then our vertical component was 7.5

play03:31

to the

play03:33

north okay so now what we want to do is

play03:37

basically repeat the exact same thing

play03:39

using the second triangle so our second

play03:41

triangle we're going to have a vertical

play03:43

component that goes up first and then

play03:45

our horizontal goes to the left okay so

play03:49

we want to basically do the exact same

play03:52

thing okay so we want to find the

play03:55

horizontal and vertical components in

play03:57

this case the horizontal is our opposite

play03:59

side

play04:00

so we'd

play04:03

have sin

play04:08

20 okay so we got the opposite side so

play04:10

sin 20 would equal x over 10 and then

play04:13

the same thing for the vertical

play04:14

component but it'll be cosine because

play04:16

it's our adjacent so cos 20 = y/ 10 so

play04:20

that's our calculations we need for the

play04:23

second triangle so let's solve for each

play04:25

of those So Co or that's to the S 21st

play04:29

so s 20 *

play04:32

10 gives us

play04:39

3.42 and then do cos 20 *

play04:43

10 gives us

play04:46

9.4 if we round it

play04:53

off okay so let's write those on our

play04:56

original triangle again so we have 3

play05:00

42 on the

play05:02

top and 9.4 on the

play05:08

side and that's it so we've got our

play05:11

triangles calculated so we figured out

play05:13

all the components for the two vectors

play05:16

so now when you look at it you can see

play05:18

basically what we do have is we have two

play05:21

vectors that go up right we have our two

play05:23

vertical vectors so if we can combine

play05:27

those two into one so let's just make

play05:28

one tall Vector that goes up and it'll

play05:31

be

play05:34

9.40 plus 7.5 cuz they're both going

play05:38

upward so we can add them together so

play05:40

that would be the same thing as

play05:42

[Music]

play05:43

16.9 and then if you look at the

play05:45

horizontal vectors we got 12.99 to the

play05:49

right but then we have

play05:51

3.42 going to the left so because those

play05:54

are in opposite directions we need to

play05:55

subtract them so

play05:57

12.99 - 3.42 2 gives us an answer of

play06:02

9.57 to the right that's the bigger

play06:05

Direction okay so what we want to do

play06:07

then let's just put the two vectors head

play06:09

to tail it doesn't matter whether I drew

play06:10

it like this or I could draw the 9.57

play06:14

starting up here and go this way it

play06:16

really doesn't make any difference I

play06:17

just picked the bottom because that's

play06:19

going to look similar to our original

play06:22

right so now the question is what is the

play06:24

resultant so we want to find out what

play06:26

that side and angle is okay so when you

play06:29

look at these two triangles you can see

play06:31

that our original resultant right there

play06:34

should be the exact same as the green

play06:36

resultant that we're going to solve for

play06:38

now okay so all we have to do for the

play06:41

green one is just like we did with the

play06:42

other questions find that length and

play06:45

that angle and we're done so the length

play06:47

is pretty easy we just use Pythagorean

play06:50

theorem so 16.9 SAR + 9.57

play06:56

squar and square root that answer

play07:07

that gives us

play07:15

[Music]

play07:24

19.429661

play07:25

[Music]

play07:27

that and we get an angle of

play07:30

60° so that's it we've done the question

play07:33

so the final step then would be just to

play07:35

State your answer so we'll just State

play07:37

our answer in final Vector notation and

play07:40

let's round it off to two digits

play07:42

everything should be in two digits so

play07:43

our final answer was 19 M right the 19.4

play07:46

we'll round it to two and our Direction

play07:49

was 60° so we went East

play07:55

60°

play07:58

North and that's it okay so you can see

play08:01

with this question we sort of did two

play08:03

steps First Step was break the original

play08:05

vectors into its two components then

play08:07

combine those into one new triangle and

play08:10

then solve that new triangle for the

play08:12

hypotenuse and the

play08:16

angle let's try one more and that'll be

play08:18

it for today so let's suppose in this

play08:21

case I've got a vector that

play08:25

goes 25 m/ second at an angle

play08:30

[Music]

play08:32

of let's suppose that angle is 40° from

play08:37

Northeast or north west and then let's

play08:40

suppose our second Vector then

play08:43

goes

play08:44

down

play08:46

at um let's say it's 30

play08:50

m/s and that one is straight South okay

play08:54

so this one is perfectly so the other

play08:55

one was at an angle of

play08:57

40° so we want to do the exact same

play08:59

thing again so let's break it into our

play09:03

horizontal and vertical

play09:08

components so that first first Vector

play09:11

we'll just do those two

Rate This

5.0 / 5 (0 votes)

Related Tags
Vector MathTrigonometryComponent AnalysisDisplacementDirectionAnglesCalculusGeometryProblem SolvingEducational Content