Work due to the Force of Gravity on an Incline by Billy

Summary

In this educational video, Billy explains how to calculate the work done by the force of gravity as a block moves up an incline. He starts by reviewing the work equation, breaking down the force of gravity, and discussing the angle differences on both a level surface and an incline. On the level surface, the force of gravity does zero work, while on the incline, it does negative work due to the angle between the gravitational force and the displacement. The video provides step-by-step calculations, ultimately showing that the work done by gravity is -4.4 millijoules.

Takeaways

• 😀 The video is a continuation of a previous video on 'Conservation of Energy with Friction, Incline, and Spring'.
• 😀 The main focus is on calculating the work done by the force of gravity as a block moves along an incline.
• 😀 The work done by a force is given by the formula: work = force × displacement × cos(angle).
• 😀 The force of gravity is represented as mass × gravitational acceleration.
• 😀 On a level surface, the angle between the force of gravity and the displacement is 90 degrees, making the work done zero.
• 😀 On an incline, the force of gravity is still directed straight down, but the displacement of the block is up the incline.
• 😀 The angle between the force of gravity and the displacement on the incline is 115 degrees, calculated as 90 + 25 degrees.
• 😀 The work done by gravity on the incline is calculated by substituting known values into the work equation, including the angle of 115 degrees.
• 😀 The resulting work done by gravity on the incline is -0.0043618 Joules, which is equivalent to -4.4 millijoules.
• 😀 The negative sign in the work value indicates that gravity is doing negative work as the block moves upward.
• 😀 The video concludes with an expression of gratitude for learning together and emphasizes the importance of understanding the work equation.

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