Chemistry: Balancing Chemical Equations (Tagalog Explained)

Summary

In this educational video, viewers are guided through the process of balancing chemical equations, a fundamental skill in chemistry. The instructor begins by explaining the components of a chemical equation, including reactants, products, chemical symbols, subscripts, and coefficients. The video then delves into the importance of ensuring equal atom counts for each element in the equation. Through step-by-step examples, the instructor demonstrates how to balance equations by adjusting coefficients while adhering to the rules of chemistry. The video is a valuable resource for students looking to master chemical equation balancing.

Takeaways

• 🔬 The video focuses on balancing chemical equations, a fundamental skill in chemistry.
• 📚 It introduces the parts of a chemical equation, including reactants, products, and their chemical symbols.
• ✏️ The importance of subscripts in chemical formulas is highlighted, which indicate the number of atoms of each element.
• 🔢 Coefficients, which represent the number of molecules, are explained, with examples showing how they multiply with subscripts to give the total number of atoms.
• 🧪 The video walks through the process of balancing equations by ensuring equal numbers of atoms for each element on both sides of the equation.
• 📝 Rules for balancing chemical equations are outlined, emphasizing that only coefficients can be adjusted and that subscripts or parentheses should not be altered.
• 🌟 Practical examples are provided, demonstrating how to balance various types of chemical equations step by step.
• 📈 The video uses a systematic approach to balance equations, starting with the most complex molecules and working towards simpler ones.
• 📊 A table format is used to organize reactants and products, facilitating the comparison and balancing of atoms.
• 👨‍🏫 The presenter, James, is a math and language instructor who aims to make chemistry more accessible through clear explanations and examples.
• 🎓 The video concludes with a teaser for the next topic, molar mass, encouraging viewers to stay tuned for further educational content.

Q & A

What are the main components of a chemical equation?

The main components of a chemical equation include reactants, products, chemical symbols, subscripts, coefficients, and the equal sign that connects them.

What is the role of subscripts in a chemical equation?

Subscripts indicate the number of atoms of a particular element within a molecule or compound.

How do coefficients in a chemical equation relate to the number of molecules?

Coefficients represent the number of molecules or formula units of a substance involved in a chemical reaction.

Why is it important to balance the number of atoms for each element in a chemical equation?

Balancing the number of atoms ensures that the law of conservation of mass is followed, meaning the number of atoms of each element is the same before and after the reaction.

What is the first rule mentioned in the script for balancing chemical equations?

The first rule mentioned is that you may only add coefficients when balancing chemical equations.

Can you change subscripts or add parentheses to balance a chemical equation?

No, according to the script, you should never add subscripts or parentheses or anything other than coefficients to a chemical equation to balance it.

What does the law of conservation of mass mean in the context of chemical equations?

The law of conservation of mass means that in a chemical reaction, the total mass of the reactants equals the total mass of the products, and the number of atoms of each element remains constant.

How do you calculate the total number of atoms for an element in a chemical equation?

You multiply the coefficient of a substance by the subscript of the element in the chemical formula to get the total number of atoms for that element.

What is an example of a chemical equation provided in the script?

An example given is '2H2 + O2 = 2H2O', which represents the reaction of hydrogen gas with oxygen gas to form water.

What is the purpose of constructing a table of reactants and products when balancing chemical equations?

Constructing a table helps to organize and compare the number of atoms of each element on both sides of the equation to ensure they are balanced.

How does changing the coefficient of a compound affect the balance of a chemical equation?

Changing the coefficient of a compound affects the number of molecules of that compound in the reaction, which in turn affects the number of atoms of each element, requiring adjustments to balance the equation.

Outlines

00:00

🔬 Introduction to Balancing Chemical Equations

The paragraph introduces the topic of balancing chemical equations, starting with the basics of chemical equations. It explains the components of a chemical equation, including reactants and products, and the importance of chemical symbols, subscripts, and coefficients. The example given is the reaction between hydrogen (H2) and oxygen (O2) to form water (H2O), emphasizing the role of subscripts in indicating the number of atoms and coefficients in showing the number of molecules. The paragraph also discusses the need to count the number of atoms for each element to ensure the equation is balanced.

05:01

📚 Balancing Equations with Rules and Examples

This section delves into the rules for balancing chemical equations, highlighting that only coefficients can be added, and they must be placed in front of the entire molecule. It also stresses that subscripts and parentheses should not be altered. The paragraph uses examples to illustrate the process, such as the reaction between lead hydroxide and hydrochloric acid to form water and lead chloride. It demonstrates how to construct a table to compare the number of atoms on both sides of the equation and adjust coefficients to achieve balance. The examples also include reactions involving aluminum, copper chloride, and other compounds, showing step-by-step how to balance the atoms of each element.

10:02

🧪 Advanced Balancing Techniques and More Examples

The paragraph continues with advanced balancing techniques, focusing on complex chemical reactions such as those involving iron chloride and magnesium oxide. It emphasizes the importance of balancing the number of atoms for each element on both sides of the equation. The examples provided include detailed steps for balancing elements like iron, chlorine, magnesium, and oxygen. The paragraph also covers how to adjust coefficients to ensure the number of atoms for each element is equal on both sides of the equation, leading to a balanced chemical reaction.

15:11

🌟 Final Examples and Conclusion

The final paragraph presents more examples of balancing chemical equations, including reactions involving copper, silver nitrate, zinc sulfide, and iron sulfide. It reiterates the importance of balancing the number of atoms for each element and demonstrates how to adjust coefficients to achieve this. The paragraph concludes with a teaser for the next topic, which will be about molar mass, and an invitation for viewers to comment with suggestions for future videos. The instructor, James, encourages viewers to like and subscribe to the channel.

Keywords

💡Chemical Equation

A chemical equation is a representation of a chemical reaction using chemical symbols and stoichiometric coefficients. It shows the reactants on the left and the products on the right, separated by an equals sign. In the video, the script explains how to balance chemical equations, ensuring that the number of atoms for each element is the same on both sides, as seen in examples like '2H2 + O2 = 2H2O'.

💡Reactants

Reactants are the substances that are consumed in a chemical reaction. They are listed on the left side of a chemical equation. The script mentions reactants in the context of balancing chemical equations, emphasizing the need to count the number of atoms of each element present in the reactants to ensure the equation is balanced.

💡Products

Products are the substances that are formed as a result of a chemical reaction. They are listed on the right side of a chemical equation. The video script discusses products in relation to balancing chemical equations, highlighting the importance of ensuring that the number of atoms of each element in the products matches that in the reactants.

💡Subscripts

Subscripts in a chemical equation indicate the number of atoms of a particular element within a molecule. They are essential for understanding the composition of compounds. The video script uses subscripts to illustrate how the number of atoms of each element is counted in both reactants and products to balance the equation.

💡Coefficients

Coefficients are the numbers placed in front of chemical formulas in a balanced equation to indicate the number of molecules or formula units of a reactant or product. The script explains that coefficients are used to balance the number of atoms of each element between reactants and products, as in the example '2H2' indicating two molecules of hydrogen gas.

💡Balancing

Balancing a chemical equation involves adjusting the coefficients to ensure that the number of atoms of each element is the same on both sides of the equation. This is a key concept in the video, where the script provides rules and examples for balancing equations, such as '2H2 + O2 = 2H2O', where coefficients are adjusted to have equal numbers of hydrogen and oxygen atoms on both sides.

💡Molar Mass

Molar mass is the mass of one mole of a substance, measured in grams per mole (g/mol). Although not directly discussed in the script, molar mass is related to the theme of the video as it is a fundamental concept in chemistry that can be used to further analyze chemical reactions and equations.

💡Stoichiometry

Stoichiometry is the calculation of reactants and products in a chemical reaction based on their respective quantities. The video script touches on stoichiometry when discussing the balancing of chemical equations, which is a stoichiometric calculation to ensure the conservation of mass and the correct proportions of reactants and products.

💡Conservation of Mass

The conservation of mass is a principle stating that mass is neither created nor destroyed in a chemical reaction. This principle is fundamental to the script's discussion on balancing chemical equations, as the process of balancing ensures that the total mass of reactants equals the total mass of products.

💡Chemical Symbols

Chemical symbols are the one- or two-letter abbreviations that represent elements in the periodic table. The script uses chemical symbols to construct chemical equations, such as 'H' for hydrogen and 'O' for oxygen, and emphasizes their importance in correctly writing and balancing equations.

💡Molecules

Molecules are groups of atoms bonded together, representing the smallest fundamental unit of a chemical compound that can take part in a chemical reaction. The video script refers to molecules, particularly when discussing coefficients, to illustrate how many molecules of a reactant or product are involved in the reaction, as in '2H2O' indicating two molecules of water.

Highlights

Introduction to balancing chemical equations

Explanation of parts of a chemical equation

Chemical symbols and their representation in equations

Understanding subscripts in chemical equations

Role of coefficients in chemical equations

Calculating the number of atoms for each element or compound

Balancing the number of atoms in reactants and products

Rules for balancing chemical equations

Example of balancing a simple hydrogen and oxygen reaction

Balancing a reaction involving tetraphosphorus and oxygen gas

Constructing a table for balancing complex chemical equations

Balancing a reaction with lead hydroxide and hydrochloric acid

Example of balancing aluminum with copper chloride

Balancing a reaction involving iron chloride and magnesium oxide

Balancing copper with silver nitrate to form copper nitrate and silver

Balancing a reaction with zinc sulfide and oxygen gas

Balancing a complex reaction with iron sulfide and chlorine gas

Conclusion and预告 of the next topic on molar mass

Transcripts

all right so welcome back to my channel

math and language and we're going to

tackle

chemistry balancing chemical equations

okay so let's start with the first topic

parts of the chemical equation

so my examples 2h2 plus

o2 is equal to 2h2o

that will be the reactants

reactants nothing you may are with

that will be the products for the

products and that will be 2 h2o

next we have the chemical symbols so

letters not and it's a chemical equation

okay we have the h and o that stands for

hydrogen and oxygen

and next one we have the subscripts

subscripts a new number of atoms

known element okay so for

the reactant side for hydrogen and

oxygen they have two subscripts

so that will be two hydrogen and two

oxygen

respectively and so product sodium and

we have

two subscript parasite hydrogen so that

will be two hydrogen atoms

oxygen subscript automatic urine

one language one oxygen atom

all right next one we have the

coefficients coefficient number

of molecules so mapapancy modern

reactant side we have two so that means

two molecules long h2 or hydrogen gas

pacquiao coefficient under studio no one

lung one molecule long

for example this o2 volume coefficient

so that means

one molecule of oxygen gas and lastly

you saw product side

two h2o so that means the living

molecule non-water

right so let's go to the next topic

number of atoms for each element or

compound

now to balance the chemical equation we

need to know

the number of atoms then sabawa element

add compound for example

2h2 plus o2 is equal to 2h2o

so again antibol for the reactants and

products

achieving chemical symbol and number of

atoms

that let's start with the subscript

my coefficient so again in coefficient

times multiplying

subscript two so that will be two times

two

is equal to four next one is oxygen

oxygen atom and number of subscriptions

coefficient so understood naona two

times one language so that will be two

parent

all right let's go to the product side

vapency was a hydrogen

it has a subscript of two okay

and my coefficient shown two so that

will be two times two

is equal to four

so that will be two so again we have the

number of atoms for

each element so for the reactant sides

on hydrogen atom that will be four

and oxygen will be two and for the

product side

hydrogen that will be number four atoms

s4

atom oxygen and then that will be two

for the number of atoms then

all right next example dial what if we

have tetraphosphorus

plasmo 3 oxygen gas

is equal to diphosphorous trioxide so p

four plus three o two

is equal to delta two p two o three

substitute three

so again number of atoms that empire

nothing yet

so government ball which the reactants

are products and the chemical symbol and

the number of atoms

so first one we have the phosphorus so

dialogue subscription in four

so number of atoms is four at dividing

coefficient

so four next we have the oxygen

and subscript and oxygen y2 and

coefficient i3

2 times 3 is equal to 6. next again

isoproduction and io product side

phosphorus small

i my subscript not two then my

coefficient can a two that will be two

times two

is equal to four and lastly in oxygen mo

you have a subscript of three at a

coefficient on i2

asymptote for the whole molecule now

diphosphorous trioxide

so that will be three times two i six

all right so last example tile what if

we have lead hydroxide plus hydrochloric

acid

is equal to water plus molang lead

chloride

so let again let's start with the

constructing of table

reactants and products so let's start

with the reactants since bandai is a

lead

that wouldn't subscript only

automatically

coefficient so one number of atoms

escapement

oxygen and hydrogen and hapay but the

parenthesis

and we have the chlorine chlorinating

that will be one case subscript

okay so let's go to the product side so

yum let not empathy oxygen

that's one subscript is automatic one

for the hydrogen and the chlorine

bypassing me

subscript and selena too

and hydrogen will be 1 times 3 is equal

to tuna n so number of atoms

i2 alright so didn't is a balancing

chemical equations

so let's start with the rules muna rule

number one

you may only add coefficients when

balancing chemical equations

okay pedal and diamond

coefficients do not go in the middle of

a molecule

they always must go in front of the

entire molecule

so palagina rule number three

you may never ever add subscripts or

parentheses or anything other than a

coefficient to a chemical equation to

balance it

so again number one then you may only

add coefficients

number four rule number four you may

never change numbers that are already

part of a chemical formula

konin given the equation say you may

only

add coefficients so let's start

with the first example hydrogen gas

plus oxygen gas is equal to water

h2 plus o2 is equal to h2o

so go ahead and table muna for the

number of atoms triathlons and products

so chemical symbol h o so for the

reactant sides

we have number of atoms for your

hydrogen and oxygen that will be two

okay so protoxidamine hydrogen number of

atoms is

two and oxygen is number of atoms

and reactants

now to check so for the reactant side

and hydrogen number of atoms is four

oxygen is two and the fret oxidamine

that will be

hydrogen that will be number of atoms n4

and for oxygen that number of atoms need

to so balance it

all right so next example what if we

have aluminum

plus copper chloride is equal to

aluminum

chloride plus copper so again you have

to construct a t-ball with the reactants

and products

in numbers atom cell and chemical symbol

so we have the

aluminum for the reactant side that will

be one copper is

one number of atoms chlorine is two

so products either one aluminum is one

copper is one

chlorine is three so parabolas

a number of atoms in modern such

chlorine we have

number of atoms yes two cell reactants

enzo products is three

so parama i'm going to multiply

chlorine so my galaxy on a coefficient

tensor reactance then sub copper

chloride

so that will be a l plus three

c u c l two okay so every time

i like you can coefficient

that will be two times three a six in

copper mo

that will be one times three which is

three na okay

so next i'm gonna go in balancing

chlorine pyramiding

sexu chlorine dunsa products

so that will be 3 times 2 i6

so remember the length times the

glycerin coefficient

not 2 sub products aluminum chloride

so that will be one times two for the

aluminum one times two is equal to two

so we need now let's balance

reactant satin aluminum s1 product side

that is two

for the copper nomine that will be three

for the reactants and for the product

side that is one

chlorine balancing elements

so that will be two aluminium plus three

copper chloride for the reactants so

that will be one times two is equal to

two

so balancing aluminum aluminum denser

products

and 1 times three is equal to three all

right so let's move to the

next example iron chloride plus

magnesium oxide

is equal to iron oxide plus magnesium

chloride

so again let's start with the

construction of the table of the

reactants and products as well as the

chemical symbol and number of atoms

so first one we have the iron that's one

chlorine is three magnesium is one

oxygen is one

so products item one two four iron

two for chlorine one for magnesium and

three for oxygen so first step not in a

gagawin

trinity valencia try nothing imbalance

you number of atoms then ion

so megalithic efficient semi

reactant side density iron chloride so

that will be

two fecl3 okay so

reactants that will be 1 times 2 i2

atom chlorine 3 times 2 is equal to 6.

products mgcl2

so that will be two times three i six

such chlorine so then

my coefficient cannot reduce magnesium

so that will be one times three i three

so

parabolase

mgo so that will be 3 mg

so 1 times 3 i3 oxygen mode 1 times 3 a3

check main equation at n so the number

of atoms are react inside that will be 2

6 3 3 for iron chlorine

magnesium and oxygen respectively that's

a product segment that will be two

six three three four iron

chlorine magnesium and oxygen

respectively again at balance is stable

all right so the next example tile

example number four

copper plus silver nitrate is equal to

copper nitrate plus silver okay detail

again

go ahead and people reactants and

products chemical symbol and number of

atoms

so for the reactant side that will be

for the number of atoms that will be one

one one and three for copper

silver nitrogen and oxygen respectively

as a product seidman that will be one

one

two and six for copper silver

nitrogen and oxygen respectively again

for the product side

okay so balancing copper and silver atom

nitrogen and oxygen and misha balances

so i'll start

balancing the inside nitrogen

coefficient silver nitrate

and silver nitrogen oxygen omega times

1 times 282 for silver and 1 times 2

is equal to 2 again for nitrogen and 3

times 2 is equal to 6 for oxygen

okay now balancing oxygen fatty nitrogen

causing problema

young silver miniature

two six and same with the product side

one two two six four copper

silver nitrogen and oxygen respectively

so balancing

all right so number of atoms

inside nitrogen and oxygen i2 and six

respectively

remember this is

subscription parenthesis

that's one subscript so one number of

atom i tell my subscript

distribution that will be 1 times 2 2.

oxygen mining o3 in the soluble

parenthesis

at my subscription at 2 so that will be

2 times 3 6 chaos 6

u number of atoms and sub protoxide

all right so fifth example dial zinc

sulfide

plus monong oxygen gas is equal to

zinc oxide plus sulfur dioxide

so again ready the t balls for the

reactants and products for

the chemical equation number of atoms

for the reactant side that will be one

one and two four zinc

sulfur and oxygen respectively for the

products of mine that will be one

one three forcing sulfide and oxygen

respectively again for the product side

sink and sulfur in oxygen

technique

so that will be three halves i said two

times three is six diva

divided by three

sulfide plus mono three oxygen gas

is equal to two zinc oxide

plus monong two sulfur dioxide

so balancing tapos

one times two a two one times two two

two times three a six

atoms of products like the mine two two

and six forcing sulfur and oxygen

respectively so again

fraction

all right so last example tile what if

we have

iron sulfide plus one and chlorine gas

is equal to ferric chloride

plus monodiesel for dichloride so again

you have to construct the table for the

reactants and products chemical symbol

and number of atoms so way

one two two for the iron sulfur and

chlorine

respectively for the reactant side and

one two and five

for the iron sulfur and chlorine again

for the products like the month

okay elements now then valencia and

chlorine and amanda

okay so that will be two times five

vapes is equal to five balancing a diva

okay we're good to go again

fraction now chemical equation so what

you have to do

multiply mulat that's a denominator

and voila

for the iron sulfide

at five for chlorine gas two

ferric chloride and two disulfur

dichloride

that's already the balance equation all

right so that's the end of the video

about

balancing chemical equations next medium

atom will be about molar mass so

molar mass element

you would like to comment or suggest

another matte language video

please comment down below and comment

down below

again this is james your math and

language instructor please

like and subscribe thank you bye