TAGALOG: Division of Polynomials - Long Division and Synthetic Division #TeacherA

Teacher A
8 Oct 202119:56

Summary

TLDRIn this educational video, Teacher A introduces lesson 99 on the division of polynomials, focusing on the long division and synthetic division methods. The video provides a step-by-step guide to dividing polynomials, starting with arranging terms in descending order of powers. Example problems are solved to demonstrate each method, showing how to divide polynomials like 'x^2 - 2x - 8' by 'x - 4' using both techniques. The video concludes with a call to action for viewers to join Teacher A's community for more educational content.

Takeaways

  • πŸ“š The lesson focuses on division of polynomials, specifically using long division and synthetic division methods.
  • πŸ”’ The first example demonstrates long division of the polynomial x^2 - 2x - 8 by x - 4, resulting in the quotient x + 2.
  • πŸ“‰ In the long division process, the first step is to arrange the dividend in descending order of powers, followed by the division symbol and the divisor.
  • βž— The division of the first terms (leading coefficients) is performed, and the result is multiplied by the divisor and subtracted from the dividend.
  • πŸ”„ This process of dividing, multiplying, and subtracting is repeated until the degree of the remaining polynomial is less than the divisor.
  • πŸ“ˆ Synthetic division is introduced as an alternative method for dividing polynomials, particularly useful for finding specific roots.
  • πŸ“ For synthetic division, coefficients of the dividend are aligned, and the divisor's root is used to successively calculate new coefficients and the remainder.
  • πŸ”Ž The second example illustrates the long division of 3x^3 + 7x^2 + 3x + 2 by x + 2, yielding a quotient of 3x^2 + x + 1 and a remainder of 0.
  • πŸ”„ Similar to the first example, the synthetic division for the second polynomial also results in a quotient of 3x^2 + x + 1 with no remainder.
  • πŸ‘¨β€πŸ« The instructor, Teacher A, invites viewers to join the community for updates on more educational content.

Q & A

  • What is the main topic of the lesson presented in the transcript?

    -The main topic of the lesson is the division of polynomials, specifically focusing on the long division method and synthetic division.

  • What is the first example given in the lesson to demonstrate the long division method?

    -The first example is the division of the polynomial x^2 - 2x - 8 by x - 4.

  • How does the teacher instruct to start the long division of polynomials?

    -The teacher instructs to start by arranging the dividend in descending order of powers and then dividing the first terms of the polynomial.

  • What is the role of the divisor in the long division method as described in the transcript?

    -The divisor is used to divide the first term of the dividend, and then it is multiplied by the result to be subtracted from the next term in the dividend.

  • What is the result of the first example using the long division method?

    -The result of the first example using the long division method is x + 2.

  • How does synthetic division differ from the long division method as explained in the transcript?

    -Synthetic division is a shortcut method for dividing polynomials that involves fewer steps and is used when the divisor is of the form x - c, where c is a constant.

  • What is the significance of the divisor being x - 4 in the synthetic division example?

    -The significance is that it allows for the use of synthetic division, which is more efficient than long division when the divisor is linear and of the form x - c.

  • What is the process for performing synthetic division as described in the transcript?

    -The process involves arranging the coefficients of the dividend in descending order, using the zero of the divisor to find the remainder, and then performing a series of multiplications and additions to find the coefficients of the quotient.

  • What is the result of the first example using synthetic division?

    -The result of the first example using synthetic division is also x + 2, which matches the result obtained by the long division method.

  • What is the second example given in the lesson to demonstrate the long division method?

    -The second example is the division of the polynomial 3x^3 + 7x^2 + 3x + 2 by x + 2.

  • How does the teacher ensure that the subtraction of polynomials is correctly performed in the long division method?

    -The teacher ensures correct subtraction by emphasizing the importance of changing the sign of the terms when they are subtracted and following the rules of polynomial subtraction.

Outlines

00:00

πŸ“˜ Polynomial Long Division

The paragraph introduces a lesson on polynomial division, specifically focusing on the long division method and synthetic division. The instructor, Teacher A, begins with an example of dividing a quadratic polynomial x^2 - 2x - 8 by a linear polynomial x - 4. The process involves arranging the dividend in descending order of powers and then performing the division step by step, multiplying the divisor with the result of each division to subtract from the dividend. The instructor demonstrates how to simplify the expression and obtain a quotient of x + 2. This method is essential for solving problems in algebra and understanding polynomial division.

05:00

πŸ”„ Synthetic Division Explained

In this segment, the instructor explains synthetic division, another method for dividing polynomials. Using the same polynomial x^2 - 2x - 8 divided by x - 4, the process starts by arranging the polynomial in descending order and then setting up the division with the divisor. The synthetic division algorithm simplifies the process by using a shortcut method that involves fewer steps than long division. The instructor walks through the steps, including bringing down the first coefficient, multiplying by the root, and adding to get the next coefficient. The final result is the same quotient of x + 2, confirming the method's accuracy.

10:04

πŸ“ Further Exploration of Polynomial Division

The third paragraph continues the exploration of polynomial division with a new example: dividing the cubic polynomial 3x^3 + 7x^2 + 3x + 2 by the linear polynomial x + 2. The instructor demonstrates the long division method, explaining each step in detail, including dividing the leading terms, multiplying the divisor by the result, and subtracting from the current polynomial. The process is repeated until the remainder is zero or the degree of the remainder is less than the divisor. The instructor concludes with the quotient 3x^2 + x + 1, showcasing the method's application to higher-degree polynomials.

15:05

πŸ”„ Synthetic Division for Cubic Polynomials

The final paragraph revisits synthetic division, this time applying it to the cubic polynomial 3x^3 + 7x^2 + 3x + 2 divided by x + 2. The instructor guides through the process, emphasizing the arrangement of coefficients and the use of the divisor's root to perform the division. The synthetic division is shown to be an efficient way to find the quotient, which matches the result obtained through long division. The instructor concludes by encouraging viewers to subscribe to the community for more educational content, highlighting the importance of understanding different methods for polynomial division.

Mindmap

Keywords

πŸ’‘Polynomials

Polynomials are algebraic expressions that consist of variables and coefficients, involving only the operations of addition, subtraction, and non-negative integer exponents. In the video, polynomials are the main objects of study, specifically focusing on their division. The script mentions dividing polynomials like 'x squared minus 2x minus 8' by 'x minus 4', illustrating the application of polynomial division in algebra.

πŸ’‘Long Division Method

The long division method is a procedural technique used to divide one polynomial by another. It is analogous to the long division process used with numbers. The video script provides a step-by-step guide on how to apply this method to polynomials, starting with arranging the dividend in descending order of powers and then dividing and multiplying terms to obtain the quotient and remainder.

πŸ’‘Synthetic Division

Synthetic division is a more efficient method for dividing polynomials, particularly when the divisor is of the form 'x - c'. It involves fewer steps than long division and is demonstrated in the script as an alternative to long division. The video explains how to set up the coefficients of the dividend and the divisor, perform the division, and arrive at the quotient polynomial.

πŸ’‘Dividend

In the context of division, the dividend is the expression or number that is being divided. In the video, the dividend is the polynomial that the teacher is demonstrating how to divide using both long division and synthetic division methods. Examples from the script include 'x squared minus 2x minus 8' and '3x cubed plus 7x squared plus 3x plus 2'.

πŸ’‘Divisor

The divisor is the expression or number by which the dividend is divided. In polynomial division, the divisor is typically a simpler polynomial, such as 'x - 4' or 'x + 2'. The script explains how to use these divisors to divide the given polynomials, demonstrating the process of finding the quotient.

πŸ’‘Quotient

The quotient is the result of a division operation. In the video, the teacher calculates the quotient when dividing the given polynomials. The script shows how the quotient is derived step by step, first by dividing the leading terms and then continuing with the rest of the polynomial terms until the division is complete.

πŸ’‘Remainder

In polynomial division, the remainder is what is left over after the division process. The script explains that if the remainder is zero, the divisor is a factor of the dividend. The teacher demonstrates how to find the remainder after performing both long division and synthetic division.

πŸ’‘Coefficients

Coefficients are the numerical factors in a polynomial that multiply the variables. The video script discusses how to handle coefficients during the division process, especially when setting up for synthetic division, where the coefficients of the dividend are used to calculate the quotient.

πŸ’‘Exponents

Exponents indicate the number of times a variable is multiplied by itself. In the video, the script mentions arranging the dividend in descending order of the exponents before performing division, which is a crucial step in ensuring the correct application of the division algorithm.

πŸ’‘Variables

Variables are symbols, often represented by letters, that represent unknown values in algebraic expressions. The video script uses variables like 'x' in polynomials to demonstrate division. The teacher explains how to treat variables and their exponents during the division process.

Highlights

Introduction to lesson 99 on division of polynomials.

Explanation of the long division method for polynomials.

Step-by-step guide to long division with the example of x^2 - 2x - 8 divided by x - 4.

Division of the first terms in the polynomial.

Multiplication step in long division to find the next term.

Subtraction step to simplify the polynomial.

Process of bringing down the next term in the polynomial.

Final answer of the long division example, x + 2.

Introduction to synthetic division method.

Setting up the synthetic division with the same polynomial example.

First step in synthetic division: arranging the dividend.

Second step: using the divisor to find the roots.

Synthetic division process: bringing down and multiplying.

Final result of synthetic division, confirming the quotient x + 2.

Transition to a second example with a different polynomial.

Long division of 3x^3 + 7x^2 + 3x + 2 by x + 2.

Division, multiplication, and subtraction steps in the second example.

Final quotient from the second example, 3x^2 + x + 1.

Synthetic division of the second polynomial example.

Final result of synthetic division for the second example, confirming the quotient.

Encouragement for viewers to join the community for updates.

Transcripts

play00:01

good morning guys teacher a here and

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welcome to guru penaisa america so for

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today i'm lesson 99 division of

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polynomials so pathology modules the

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learning tasks

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long division method and synthetic

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division

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let's have example number one

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so i'm given nothing i x squared minus

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2x minus 8 divided by x minus four so is

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to solve nothing step by step starting

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with long division

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so panda bayon first step

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okay lemon you're adding dividend nasa

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descending order of powershot it

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disappears

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exponents

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so we have two

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one

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and then

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variable your constant term so you're

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adding given

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okay

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so after that second step indeed divide

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the nothing sha katula divide nothing

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multi-digit numbers no elementary title

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so

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at the division symbol

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adding dividend

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na

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x squared

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minus two x

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minus eight

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and then celebration divisor

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minus four

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okay

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so subtract the dividing polynomials and

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got doing is indeed dividing first terms

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of first term okay so they divide

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so x squared

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divided by x

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so therefore

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x squared divided by x i x sanatini

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okay

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and then after that after dividing in

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multiply

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so you will multiply your quotient your

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partial quotients adding divisor so x

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times x i x squared

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katakana in the x squared

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and then x times negative four a number

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and the letter multiplied

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so we have negative four x

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and then after that after you multiply

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is to subtract so the ms natal so

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traffic

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automatically

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cancel out your first term

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okay so

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x squared minus x squared that's zero

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so negative two minus negative four

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so say negative four

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this is subtraction your rule in

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subtracting polynomials i

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young minus

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negative two plus positive 4. so

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following the rules in adding

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is to subtract so 4 minus 2i

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2

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and then x

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positive shock assemblies melaka c4 at

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positive c4 okay and then after that

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bring down you should do the term which

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is negative eight

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okay

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so repeat the process divide ou let your

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first term is a first term

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so 2x divided by x so c2x pinangasi x

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positive

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and then

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multiply

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two times x making a two x

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then two times negative four i negative

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eight

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and then after multiplication subtract

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you're negative by becoming positive

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you're positive

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negative and then you minus magicking

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2x plus negative 2x different signs ema

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minus so that's 0. 3 negative 8 plus

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positive 8 different signs minus that is

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equal to zero

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yeah

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so don't end i'm adding public divide so

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base theta starting solution

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i'm at the answer i

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x plus two okay so that's the long

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division method now each of nothing

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number

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nothing using synthetic division okay

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okay so same given dial x squared minus

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two x minus eight divided by x minus

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four

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so

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in dividing polynomials using synthetic

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division again your first step not then

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i think dividend okay

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descending order of powershot meaning

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your exponent

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so we have two an exponent

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one now exponent and then zero i'll say

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that x okay so

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done

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and then

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in second nothing

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human numerical coefficients now

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dividend

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so we have

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one

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and then you sustained a no negative two

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and then what's next negative eight so

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you're not adding dividend now

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i think divisor which is x minus four

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here

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on third step now then i solve for x

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so para mass of x

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nothing just a zero

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so we have x

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minus four

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is equal to zero solving for x

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x is equal to it transpose is negative

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force habit by giving positive four

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so therefore you divisor naga gamma t

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naught and i four

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draw a line there

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usually of course you like

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equal sign okay

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so

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on synthetic division

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i think dividend

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okay

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divide

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first step

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it bring down your first number which is

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one

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there you go

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bring down the tile

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next is emo multiply nothing human

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and then

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one times four the answer is four sun

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illa lagai salo

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okay don is the next number so we have

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here four

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now

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add

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following the rules in adding integers

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negative two plus positive four make by

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subtract four minus two is two

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and that is positive because

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foreign okay

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now repeat the process multiply again

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so two times four i

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so we have

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zero

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okay

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so two minus one is one therefore

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my ex

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squared my x cube my x to the fourth my

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x to the fifth and so on and so forth

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okay

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again from right to left

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you do love your remainder

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constant you should not give my x so not

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my x squared x cube x to the fourth x to

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the fifth x to the sixth etc etc okay so

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i rewrite nothing though so therefore

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we have one

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and then casamay x

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again hindi no no let's see one okay

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next this is positive two so that's plus

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two

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so therefore since zero remainder

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nothing i'm adding final answer i

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x plus two

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yes so therefore

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okay

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example number two

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number two we have three x plus three x

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cubed plus two plus seven x squared

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divided by x plus two so again

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it's a long division

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first step it arranged nothing in

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dividend

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in descending order of powers

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exponent so

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exponents are given i you my three so

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so we have three

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x

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cubed

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and then after num three two so

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plus

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seven

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x squared

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and that's also not i one you make x

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lamp

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plus three x

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and then your constant not two

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then divided by x plus two okay so

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it divide the nut and sha

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we have x plus two salabus

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dividend number three x cubed

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plus seven x squared

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plus three x

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plus two

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oh my

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indica

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so first step

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process not then e divide first terms

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the first term

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so three x cubed

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divided by x so c x cubed

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so therefore this is three x squared so

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nothing is three x squared sata s

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my x squared then so we have here three

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x

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squared okay

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and then next sub process now then

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multiply so three x squared times x so

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say three x squared the negative

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compression is upon x so name x naught n

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so three

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x cubes

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objective

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out okay

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and then

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three x squared times two so three times

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two is six

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and then copy against the x squared

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so after that after another

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multiplication subtraction so you

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subtract again sub two subtract you

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should change nothing you sign on

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six x squared the positive magnitude

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negative then

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okay

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so

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this will be cancelled out

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oh my god three x cubed plus negative

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three x cubed macheba is a trap that's

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zero next seven minus six i one

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and then x squared

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is

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next after my subtract bring down and

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the basis is not the term a union plus

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three x

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and then after that just repeat the

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process

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x cube x sub sorry x squared

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tinang

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is an x d by k x

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so plus x

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after d divide and multiply x times x is

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an x charge upon x d divided by x na

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then x times two that's two x

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and then we subtract

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so again capacitor drop change the sign

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so this will become plus this is minus

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or negative this is negative

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so x squared plus negative x squared

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much about the sine subtract that's zero

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and then after that

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three x plus negative two x marker

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banana sign is subtract three minus two

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is one and then cx

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again hindi nakailang is

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after that it bring down your last term

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which is plus two

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okay so

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so we have x plus 2

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so

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it divides

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x

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divided by x so x divided by x

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okay one any number or letter multiply

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and multiply sorry divided by itself as

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i got i one okay

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so that's one so plus one here and then

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multiply one times x i x

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1 times 2 i 2

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then you subtract x minus x is 0 2 minus

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2 is 0. so therefore

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0 and la la basna remainder well

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remainder okay

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so therefore i'm adding quotient i

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it's over there

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three x squared plus x plus one okay now

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each other using synthetic division

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so synthetic division first step the

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arrangement given in adding dividend

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into

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descending order of powers

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and then second step is

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numerical coefficients

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we have three

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followed by

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seven

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and then we have three

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and then we have two

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so he checked

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one two three

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and then after starting dividend

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prototypes out in divisor on divisor

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nothing x plus two so nothing in value

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in the x by equating this to zero so x

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plus two

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is equal to 0

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solving for x it transpose it positive

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to

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so in divisor not in a negative 2 sali

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nakahualai

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draw a line

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bring down the first number which is

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three

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again

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that's addition

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following the rules in adding

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so seven plus negative six okay we're

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gonna sign a minus seven minus six i one

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and then repeat the process multiply

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again one times negative two i negative

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two

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and then

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add following the rows in adding

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integers

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subtract three minus two i

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one

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and then after that it multiplies

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so one times negative two i negative two

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now

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let's add

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even the sign you subtract two minus two

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is zero okay

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next

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diagonal line i said that's the

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remainder

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it's a young constant so from right to

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left remainder

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constant which means relational letter

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prolonged variable

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so so now you my x

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and this is the given x squared

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that was

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less than the highest exponential

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dividend okay so looking at the answer

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here it rearranged

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so we have three

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x squared

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and then plus one x hindi

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is

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one plus x naught and then plus one okay

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so therefore

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at

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and please if ever you are not yet a

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member of my community please subscribe

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updated my

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latest

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by teacher a okay that's all for today

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see you in my next video

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