Composition of Function by Ma'am Ella Barrun

Sir Sam
24 Aug 202414:59

Summary

TLDRThis video script introduces the concept of function composition, explaining it as substituting one function into another to create a new function. It demonstrates this with several examples, showing step-by-step calculations for composite functions such as F(G(x)) and G(F(x)). The script covers linear and quadratic functions, illustrating the process of finding composite functions and their simplified forms, including evaluating composite functions at specific points.

Takeaways

  • πŸ“š The concept of function composition is introduced, where one function is substituted into another to create a new function.
  • πŸ”’ The notation for function composition is explained, using f(g(x)) to represent the composition of function f with function g.
  • πŸ“ An example is provided to illustrate the process of function composition, starting with simple linear functions and moving to more complex polynomials.
  • πŸ“‰ The first example demonstrates the composition of two linear functions, resulting in a new linear function.
  • πŸ“š The second example involves composing a linear function with a quadratic function, resulting in a new quadratic function.
  • πŸ”‘ The third example shows the composition of a quadratic function with another quadratic function, leading to a new quadratic expression.
  • πŸ“Œ The fourth example introduces the concept of evaluating a composite function at a specific value, in this case, G(-4).
  • 🧩 The process of substituting the result of one function into another is shown step by step, with simplification of the resulting expression.
  • πŸ” An example of finding the square root of a composite function's result is given, highlighting the application of real-world operations on function compositions.
  • πŸ“ˆ The final example demonstrates the composition of a quadratic function with a linear function, resulting in a new quadratic expression when evaluated at a specific point.
  • πŸ€” The script concludes with an invitation for questions, indicating an interactive component to the lesson on function composition.

Q & A

  • What is the definition of function composition?

    -Function composition is the process of substituting one function into another, creating a new function. If a function 'f' is substituted into all variables of another function 'g', it is denoted as 'f composite with g' or 'f(g(x))'.

  • How is the composition of functions denoted mathematically?

    -The composition of functions is denoted as 'f ∘ g' or 'f(g(x))', where 'f' and 'g' are functions and 'x' is the variable.

  • What is the first example of function composition given in the script?

    -The first example given is G(x) = 5x + 3 and F(x) = 2x + 1. The composition of F with G, denoted as F(G(x)), is calculated as 2*(5x + 3) + 1, which simplifies to 10x + 7.

  • In the second example, what are the functions F(x) and G(x), and what is their composition?

    -In the second example, G(x) is given as 5x^2 - x + 4 and F(x) as 2x - 1. The composition F(G(x)) simplifies to 10x^2 - 2x + 7.

  • What is the third example of function composition in the script?

    -In the third example, F(x) = 2x - 15, G(x) = x^2 + 19x + 90. The composition G(F(x)) simplifies to 4x^2 - 22x + 30.

  • What is the purpose of the fourth example in the script?

    -The fourth example demonstrates how to find the composition of the function H with G at a specific value, x = -4. It shows the process of substituting the result of G(-4) into H(x) and finding the final value.

  • What is the result of the composition H(G(-4)) in the fourth example?

    -The result of the composition H(G(-4)) is 6, after simplifying the expressions and evaluating the square root of the final value.

  • What is the function F(x) in the last example of the script?

    -In the last example, the function F(x) is given as x^2 + 5x + 6.

  • How is the composition F(G(4)) calculated in the last example?

    -In the last example, after finding G(4) which equals 6, this value is substituted into F(x), resulting in F(6) which simplifies to 72.

  • What is the main takeaway from the script regarding function composition?

    -The main takeaway is understanding how to perform function composition by substituting one function into another, and simplifying the resulting expression to obtain a new function or a specific value.

Outlines

00:00

πŸ“š Introduction to Function Composition

The script begins by transitioning from the topic of operations on functions to the concept of function composition. It defines function composition as the process of substituting one function into another, resulting in a new function. The notation for this is f composed with g, denoted as f(g(x)). The first example illustrates this with f(x) = 2x + 1 and g(x) = 5x + 3, showing the step-by-step process of finding f(g(x)) which simplifies to 10x + 7.

05:01

πŸ” Examples of Function Composition

This paragraph provides further examples to demonstrate function composition. It includes the process of finding f(g(x)) and g(f(x)) for different functions, such as f(x) = 2x - 1 and g(x) = x^2 - x + 4, and another with f(x) = 2x - 15 and g(x) = x^2 + 19x + 90. Each example is worked through, applying the distributive law and simplifying the results to show the composed functions.

10:04

πŸ“˜ Applying Composition with Specific Values

The final paragraph explores the application of function composition with specific values, starting with an example where f(x) = x^2 + 5x + 6 and g(x) = x + 2. It calculates the composition of f with g evaluated at x = 4, resulting in f(g(4)) = 72. The script also includes an example involving the square root function h(x) = sqrt(x + 6), where h is composed with g at x = -4, yielding h(g(-4)) = 6.

Mindmap

Keywords

πŸ’‘Function Composition

Function composition is a mathematical process where one function is applied to the result of another. It is a fundamental concept in the study of functions and is used to create new functions from existing ones. In the video's theme, function composition is the central topic, with examples illustrating how to perform it. For instance, 'F composite with G' is used to denote the composition of function F with function G.

πŸ’‘Variable

A variable in mathematics is a symbol that represents a quantity that can change. In the context of the video, variables are used within functions to denote the input values. For example, 'x' is the variable in functions like 'G of X' and 'F of X', where it is substituted with specific values during function composition.

πŸ’‘Distributive Law

The distributive law is a basic principle in algebra that allows for the multiplication of a single term with each term inside a parenthesis. In the script, the distributive law is used to simplify expressions during function composition, such as when expanding '19 * (2x - 15)' to '38x - 285'.

πŸ’‘Simplification

Simplification in mathematics refers to the process of making a complex expression more straightforward, often by combining like terms or reducing fractions. The video script includes several instances of simplification, such as reducing '2 * 5x + 3 + 1' to '10x + 7' after performing function composition.

πŸ’‘Algebraic Expression

An algebraic expression is a combination of variables, numbers, and operation signs representing a mathematical relationship. In the video, algebraic expressions are used to represent functions and their compositions, such as '5x + 3' and '2x + 1' in the first example.

πŸ’‘Quadratic Function

A quadratic function is a polynomial function of degree two, typically written in the form 'axΒ² + bx + c'. In the video, quadratic functions are used in examples to demonstrate function composition, such as '10xΒ² - 2x + 7' resulting from composing two functions.

πŸ’‘Composite Function

A composite function is the result of applying function composition. It is denoted by 'F(G(x))', indicating that the function G is applied first, followed by F. The script provides several examples of composite functions, such as 'F composite with G of X'.

πŸ’‘Square Root

The square root operation finds a number that, when multiplied by itself, gives the original number. In the script, the square root is used in the context of a function 'h of X', where 'h of 4' is calculated as the square root of '30 + 6', resulting in 6.

πŸ’‘Polynomial

A polynomial is an expression consisting of variables and coefficients, involving only the operations of addition, subtraction, and multiplication. The video script discusses polynomials in the context of function composition, such as '4xΒ² - 22x + 30'.

πŸ’‘Binomial

A binomial is an algebraic expression with two terms, often in the form 'ax + b'. The script uses binomials in the process of function composition, such as '2x - 15', which is then used as part of a larger polynomial expression.

Highlights

Definition of function composition: substituting one function into all variables of another function to create a new function.

Notation for function composition: f composite with g, denoted as f(g(x)).

Example 1: Composition of linear functions g(x) = 5x + 3 and f(x) = 2x + 1 results in f(g(x)) = 10x + 7.

Example 2: Composition of quadratic and linear functions, resulting in a quadratic function f(g(x)) = 10x^2 - 2x + 7.

Example 3: Composition of linear functions to get a quadratic function g(f(x)) = 4x^2 - 22x + 30.

Example 4: Composition involving square root function h(g(x)) = sqrt(x + 6), demonstrating real-world applications.

Finding h(g(-4)) = 6 by substituting -4 into the composed function.

Example 5: Composition of quadratic and linear functions to find f(g(4)) = 72.

Step-by-step process of function composition illustrated through multiple examples.

Use of distributive law in simplifying the composed functions.

Importance of function composition in creating new functions from existing ones.

Practical demonstration of how to perform function composition with clear examples.

Clarification of the difference between f(g(x)) and g(f(x)) in function composition.

Emphasis on the algebraic manipulation required for simplifying composed functions.

Explanation of how to handle different types of functions in composition, including linear, quadratic, and square root functions.

Highlighting the final simplified form of each composed function as the key takeaway.

Invitation for questions or messages at the end of the discussion, promoting engagement.

Transcripts

play00:01

okay so since we are done with operation

play00:05

of function let us now proceed to

play00:07

composition of function but first let us

play00:10

Define what is composition of function

play00:13

okay so if a function is substituted to

play00:16

all variables in another function then

play00:20

you are performing a composition of

play00:23

function to create another function

play00:26

Okay so

play00:32

for compition

play00:38

function f composite with G or equals

play00:43

okay

play00:46

equivalent F of G of X so G of X is

play00:55

insert f of x to create another function

play01:02

okay so let us now have an example

play01:06

number

play01:07

one so we have here uh G of X is = 5x +

play01:13

3 and then F ofx down is 2x +

play01:18

1 okay let's just

play01:21

copy F composite with G of X or

play01:25

equivalent or equal F of G of x

play01:30

okay so let us find F composite with

play01:34

G

play01:38

okay okay

play01:41

soag

play01:44

is um

play01:47

identify g of x g of X is 5x + 3

play01:54

okay okay so mag g f time

play02:01

5x +

play02:04

3

play02:07

so FX that is 2x +

play02:13

1 G of

play02:15

xert or

play02:18

inut FX

play02:21

so 5x +

play02:26

3it xay mag 2 X or sorry 2 * 5x + 3 + 1

play02:38

okay so

play02:40

p x 5x + 3 Yun G of X and then let us

play02:50

simplify 2 * 5x that that is 10 x and

play02:55

then 2 * 3 that is 6 and then let's just

play02:59

cop

play03:08

then and then 6 + 1 that is POS 7

play03:15

so F composite with G is 10 x + 7 okay

play03:22

so now let us proceed to example number

play03:27

two so example number

play03:31

G of x = 5 x 2 - x + 4 and then F ofx

play03:40

that is 2x

play03:42

-1 okay F composite with G of X or

play03:48

equivalent F of G of X

play03:53

so F composite with G of

play03:58

X Okay so soay an value G of X that is

play04:03

5X

play04:05

2us x + 4 and

play04:10

then

play04:12

FX okay

play04:16

2x-1 so

play04:18

X

play04:21

mam 5x 2 - x + 4 okay

play04:26

so okay mag 2 * 5X x^ 2 - x + 4 - 1 and

play04:36

then s is

play04:38

simplify okay 2 * 5 x 2 that is 10

play04:43

X2 and then 2

play04:46

*

play04:48

X is -2X and then 2 * pos4 that is

play04:56

postive 8 and then let's just copy

play05:01

1 and then

play05:03

simplify okay so 10

play05:08

xΒ² and then um let's just copy

play05:16

alsox and then last

play05:22

8us POS 7

play05:26

so um f composite with G of x = 10 x^ 2

play05:33

- 2x + 7 okay so to example number three

play05:42

f of x is = 2x -

play05:45

15 p g of X = X2 + 19 x +

play05:55

90 and

play05:56

then let us find G composite with f of

play06:05

x

play06:08

so FX and then

play06:13

insert G of

play06:15

X

play06:17

okay

play06:19

so

play06:23

insert f of x

play06:25

2x - 15 so s g of x

play06:34

2x - 15 so maging 2x - 15

play06:41

2 + 19 * 2x -

play06:47

15 + 90 okay and then let

play06:52

us um

play06:54

simplify okay so for the first binomial

play07:00

let let us use distributive

play07:04

law

play07:06

4x2 -

play07:08

60x +

play07:11

225 and then next 19 * 2x that is

play07:16

positive

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38x and then next 19

play07:22

* 15 that will

play07:25

be 285 and then you uh positive 9

play07:30

copy

play07:31

Nang okay so let us simplify

play07:36

again okay so

play07:39

since 4X let us just

play07:42

copy and then NE

play07:47

60x is POS 38x

play07:54

so

play07:55

22x and then

play07:58

lastly um constant number that is or

play08:02

positive

play08:04

225 minus

play08:07

285 + 90 so that will be postive 30 so G

play08:14

of x uh sorry G of f ofx or you g

play08:21

composite with f ofx is = to 4 x^2 -

play08:27

22x + 30

play08:31

okay

play08:33

so example number

play08:36

four okay so example

play08:40

or given FX = 2x^ 2 - 15 and then G of X

play08:48

is xΒ² + 19 x + 90 and then h of X is squ

play08:58

root x +

play09:00

6 and then let us find G uh let us find

play09:05

H composite with G

play09:11

of4

play09:15

number so

play09:19

unin G of-4 Kasi po Yan

play09:27

equivalent h

play09:31

h of

play09:33

G of

play09:42

negative okay

play09:44

so G of X

play09:47

is

play09:50

xΒ² + 19 x + 90

play09:57

soitan -4 since

play10:01

X

play10:03

is

play10:05

X

play10:07

so -4 -4 2 + 19 * -4 +

play10:16

90 so let us

play10:19

simplify

play10:21

so

play10:23

um -4 * -4 that is POS POS 16

play10:30

and

play10:34

then um positive 19 * -4 that will

play10:40

be76 and then just copy positive 90 and

play10:45

then

play10:47

simplify 16 - 76 + 90 so that will be

play10:54

postive 30 okay so proceed Naman

play10:59

H

play11:00

of4

play11:03

since G

play11:06

of4 okay so h of X is s otk x +

play11:15

30 so

play11:19

since G

play11:21

of4 which is

play11:24

30

play11:27

insert X

play11:30

H

play11:34

of4 okay

play11:36

soqu < TK of 30 +

play11:40

6 okay and then 30 + 6 that is 36 or

play11:46

square root of 36 so square root of 36

play11:50

is

play11:55

6 h composite of G or composite with G

play12:00

of -4 is equal to 6

play12:07

okay so let us proceed to our last

play12:12

example so we have here f of x = X2 + 5x

play12:19

+

play12:21

6 okay and then G of x = x +

play12:27

2 so let let us

play12:30

find F composite with G of 4

play12:37

or F of G of

play12:42

4 so example number four that

play12:48

is4 X which is

play12:53

pos4 okay so

play12:57

unin G of

play13:01

4 okay so G of X is x + 2 so

play13:11

x

play13:13

a

play13:15

given so magig 4

play13:19

+

play13:20

2 so mag G of 4 is equals to 6 since

play13:30

G of 4 which is

play13:33

6 insert or

play13:36

input f of x f of x is xΒ² + 5x + 6

play13:48

so

play13:51

is variable or X okay so mag

play14:00

F ofx = 6 2 + 5 * 6 + 6 and then let us

play14:11

simplify 6 * 6 that is 36 and then plus

play14:17

5 * 6 that is 30 and then we just need

play14:20

to copy 6 and then simplify again 36 +

play14:26

30 that is 6 6 + 6 that is

play14:34

72 excuse me

play14:37

so F composite with G of 4 is equals to

play14:43

72

play14:44

okay so a

play14:47

lang if there's any question

play14:52

um um a message okay

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