How to answer Oscillations Questions in A Level Phyics (Simple Harmonic Motion, Resonance)
Summary
TLDRThis video tutorial focuses on tackling oscillation and simple harmonic motion questions for A-level physics exams. The instructor guides viewers through past exam questions, emphasizing the importance of understanding key equations and interpreting graphs. The video covers topics like pendulum oscillations, deriving angular frequency, and resonance, providing step-by-step explanations to solve problems efficiently. It also highlights the significance of memorizing fundamental formulas and offers tips for excelling in exam questions related to oscillations.
Takeaways
- 📚 The video focuses on answering oscillation and simple harmonic motion questions for A-level physics, aiming to simplify the complex topic by working through past exam questions.
- 🔍 The presenter uses a 2022 meijing paper to illustrate a typical simple harmonic motion question involving a pendulum, emphasizing the importance of understanding the relationship between acceleration and displacement.
- 📉 The video explains how a graph with a negative gradient indicates that the acceleration is in the opposite direction to the displacement, a key characteristic of simple harmonic motion.
- 🔢 The formula for acceleration in simple harmonic motion, a = -ω²x, is derived and used to calculate the angular frequency (ω) from the graph's gradient.
- 🔄 The video discusses how the angular frequency (ω) relates to the length of a pendulum and demonstrates how to calculate a constant (K) using the previously determined angular frequency.
- 🌀 The concept of resonance is introduced, explaining that it occurs when an object's driving frequency matches its natural frequency, leading to increased amplitude.
- 📈 The script guides viewers on how to calculate the period of oscillation using the angular frequency and provides a method to label axes correctly with time and displacement scales.
- 🕒 The video demonstrates calculating phase difference by comparing the time at which each pendulum crosses the equilibrium position, emphasizing the importance of understanding periodicity.
- 📝 The presenter advises memorizing key equations and concepts to efficiently answer questions, such as those involving resonance and simple harmonic motion.
- 🎓 The video concludes by encouraging practice and memorization of key formulas and concepts for success in answering A-level physics questions on oscillations.
Q & A
What is the main topic discussed in the video?
-The video discusses how to answer questions on oscillation and simple harmonic motion in A-level physics, focusing on understanding and applying various equations and formulas related to these concepts.
Why is simple harmonic motion considered a daunting topic for students?
-Simple harmonic motion is considered daunting because it involves many equations and formulas, and there is a substantial amount of content in the chapter that can be overwhelming to learn and apply.
What is the significance of the negative gradient in the graph shown in the video?
-The negative gradient in the graph indicates that the acceleration is in the opposite direction to the displacement, which is a key characteristic of simple harmonic motion.
How does the video suggest determining the angular frequency of an oscillation?
-The video suggests using the given formula a = -Omega^2 * x and the information from the graph to determine the angular frequency (Omega) of an oscillation.
What is the relationship between angular frequency and the length of a pendulum as explained in the video?
-The video explains that the angular frequency (Omega) is related to the length (L) of the pendulum by a constant (K), and this relationship can be used to determine the value of K using the previously calculated angular frequency.
How does the video explain the concept of resonance?
-Resonance is explained as the phenomenon where an object reaches its maximum amplitude when the driving frequency equals the natural frequency of the object.
What is the importance of understanding the units of angular frequency as discussed in the video?
-Understanding that angular frequency is a ratio and does not have units (it is dimensionless) is important for correctly interpreting and calculating the values in problems involving simple harmonic motion.
How does the video suggest calculating the period of oscillation given a displacement-time graph?
-The video suggests using the formula for displacement in simple harmonic motion, x = x_0 * sin(Omega * t), to find the angular frequency (Omega) and then calculate the period (T) as T = 2 * pi / Omega.
What is the qualitative effect on the amplitude of oscillations when the length of the string in a pendulum is increased, as discussed in the video?
-When the length of the string in a pendulum is increased while maintaining the same total energy, the amplitude of oscillations increases because the angular frequency decreases, requiring a larger displacement to maintain the same energy.
How does the video approach the calculation of phase difference between two oscillating pendulums?
-The video approaches the calculation of phase difference by determining the time difference at which the pendulums cross the equilibrium position and then converting this time difference into a phase angle in radians.
Outlines
📚 Introduction to Oscillation and Simple Harmonic Motion
The script begins with an introduction to answering questions on oscillation and simple harmonic motion in A-level physics. It acknowledges the complexity of the topic due to the multitude of equations and formulas involved. The speaker suggests that practicing past papers is an effective way to streamline the learning process. The focus then shifts to a specific question from the 2022 Meijing paper, which involves a pendulum with a small metal sphere (bob) attached to a string. The pendulum's oscillation and its relationship with the string's length and the bob's displacement from the equilibrium position are discussed. The speaker emphasizes the importance of understanding the graph showing the acceleration's variation with displacement, highlighting the negative gradient and the linear relationship indicative of simple harmonic motion.
🔍 Analyzing Simple Harmonic Motion with Graphs
This section delves deeper into analyzing the pendulum's motion using a graph. The speaker explains how the graph's negative gradient and linearity demonstrate the direct proportionality between acceleration and displacement, which are key characteristics of simple harmonic motion. The discussion then transitions into a mathematical approach, using the formula for angular frequency (Omega) in simple harmonic motion. The speaker rearranges the formula to solve for Omega, using the given data from the question. The result is an angular frequency of 2.83 radians per second. The speaker also touches on the concept of radians as a ratio, clarifying that they are unitless and used to describe angular relationships.
🔗 Relating Angular Frequency to Pendulum Length
The script continues with a question that connects the angular frequency (Omega) to the length (L) of the pendulum. The speaker is tasked with determining a constant (K) from the relationship between these two variables. Using the previously calculated angular frequency and the given length of the pendulum, the speaker solves for K. The importance of unit consistency is highlighted, with a detailed explanation of why radians are dimensionless. The discussion then moves to the qualitative effect of increasing the pendulum's length on the oscillation's amplitude, explaining that to maintain constant total energy, a decrease in angular frequency must be compensated by an increase in amplitude.
🌊 Exploring Resonance in Oscillating Systems
The final paragraph shifts the focus to resonance, a phenomenon where the amplitude of an oscillating system increases significantly when driven at its natural frequency. The speaker defines resonance and connects it to the concept of maximum amplitude occurring when the driving frequency matches the natural frequency. The script presents a scenario involving two pendulums with the same natural frequency but different masses, illustrating how the heavier pendulum has a larger amplitude of oscillation. The speaker then calculates the period of oscillation for the light pendulum using the given displacement-time relationship. The axes of a graph are labeled accordingly, and the amplitude is determined from the maximum value of the sine function. Finally, the phase difference between the oscillations of the light and heavy pendulums is calculated, demonstrating the application of concepts from the oscillations chapter.
Mindmap
Keywords
💡Oscillation
💡Simple Harmonic Motion (SHM)
💡Equilibrium Position
💡Angular Frequency (Omega)
💡Restoring Force
💡Displacement
💡Resonance
💡Natural Frequency
💡Phase Difference
💡Amplitude
Highlights
Introduction to answering oscillation and simple harmonic motion questions in A-level physics.
Emphasis on the importance of past papers for streamlining learning and understanding common question types.
Analysis of a pendulum example from the 2022 Meijing paper to illustrate typical simple harmonic motion questions.
Explanation of the relationship between pendulum length, equilibrium position, and maximum displacement.
Discussion on how a linear graph with a negative gradient indicates simple harmonic motion.
The significance of the negative gradient in showing the opposition between displacement and acceleration.
Advice on memorizing key concepts to save time during exams.
Derivation of angular frequency using the formula a = -omega^2 x and its rearrangement for solving problems.
Clarification on the units of angular frequency and the concept of radians as a ratio.
Use of the derived angular frequency to determine a constant K in the equation relating to pendulum length.
Explanation of the qualitative effect of changing the length of a pendulum on its amplitude and angular frequency.
Introduction to resonance and its significance in oscillation questions.
Definition of resonance and its relation to maximum amplitude and driving frequency.
Analysis of a diagram showing the oscillations of a heavy and a light pendulum with the same natural frequency.
Calculation of the period of oscillation using the given displacement-time relationship.
Guidance on labeling axes with correct scales and additional working for pendulum oscillation graphs.
Determination of the phase difference between the oscillations of the light and heavy pendulums.
Advice on practicing and memorizing key equations and concepts for oscillation and resonance questions.
Conclusion and encouragement for viewers to explore more physics A-level videos for further understanding.
Transcripts
video I want to talk about how to answer
questions on oscillation and simple
harmonic motion in a levels and it's a
very daunting topic to start answering
questions about because there are very
many equations and formulas and there's
just a lot of substance in that chapter
so hopefully by doing past papers it
really streamlines the amount of
information that you should be learning
so we're going to work through a bunch
of different questions from various
papers all pretty recent to look at what
they're actually going to ask of you
so let's start with this one this one is
in the meijing paper in 2022 It's Paper
four one and I think it's a very typical
example of what a simple harmonic motion
or an oscillation question looks like
so over here it says that a pendulum
consists of a bob which is a small metal
sphere attached to that piece the end of
a piece of a string and then the other
end is connected to a fixed spot and the
Bob oscillates with small oscillations
about its equilibrium position so this
is exactly what they're telling us and
it's fixed over here and it's
essentially just telling us it's going
to oscillate over here what we should be
paying attention to is the length so L
of the string is given over here and we
know that equilibrium is over here
maximum displacement is given by X so
you should all note that and then they
say that the length of the pendulum
measured from the fixed point to the
center of the Bob is 1.24 meters and the
acceleration a of the Bob varies with
its displacement X from the equilibrium
position as shown in figure 8.2 so we
see that the acceleration to the
distance the maximum displacement is
constant for one because it has straight
line so this is a linear graph and it's
also it has a negative gradient so this
is really important and it comes up over
and over again because in the very next
question they're going to ask you state
how figure 0.4.2 shows that the motion
of the pendulum is simple harmonic and
we know that a simple harmonic motion
has an acceleration that is directly
proportional to the displacement of the
object from the equilibrium position and
we also know that the force the
restoring force that pushes the object
back into this equilibrium position it
gets bigger the bigger the X becomes so
we know that these two are the
prerequisites of simple harmonic motion
and so we all we need to do is just use
certain keywords to analyze the graph
and that would be this
so the negative gradient shows that the
displacement is in the opposite
direction to the acceleration and this
is very
self-explanatory because we know that
the positive of something would have the
negative of other things so to really
exemplify what I mean by that if we have
a positive of X we would have a negative
of a which means that they are always
going to be in opposite directions to
each other so that's the first part
and this is the second part the straight
line shows that the acceleration is
directly proportional to the
displacement so previously I talked
about how the straight line means that
the curve the graph is linear so if
there is a linear relationship then
there is a direct proportionality
between the two constants so the higher
something is the higher the other
whatever is so that is what you should
be commenting on these two things
they're really straightforward and this
is a question that comes up super often
so I would really recommend just knowing
this by heart to save time now we have
to get into some math so they tell us to
use figure Point 4.2 to determine the
angular frequency which is given by
Omega of the oscillation so over here
you have to memorize a formula for a
simple harmonic motion and that formula
is a equals
negative Omega square and if you want to
derive this do check out this one video
where I talk about all of the equations
of oscillation simple harmonic motion
and how to derive them and it is
actually also given to you over here
so you have this equation given to you
which is very nice and it's also worth
taking a look at what is given to you in
terms of simple harmonic motion these
very like primary equations are given to
you so you wouldn't have to waste a lot
of time trying to memorize all of them
but we have this very simple equation
that you can get from the beginning of
the paper and all we have to do now is
to basically just substitute so I can do
that here
I can first of all
rearrange this
so the answer is 2.83 so it is 2
.83 radians per second so it would spin
by this much
that would be the angular frequency
so now we've done that we can go on to
this part so they tell us that the
angular frequency Omega is related to
the length L of the pendulum by this
equation
where K is a constant and they tell us
to use your answer in B1 to determine K
and give a unit with your answer so we
want to be very particular with the
units as well so it's it makes a lot of
sense to write down everything that
we're doing so we know that 2.83
radians
per second equals to K over
the length which is you know we know
that L is 1.24 from the data given to us
beforehand so 1.24 meters
so before we get any further on with
this it's time to think about the radian
what does a radian actually mean the
radian is a ratio
between so if you had a sector of a
circle it's the ratio between this and
the radius and this has a unit of meters
this also has a unit of meters so it's a
ratio of these two which means that
there are no units because the meters
would cancel out so you can also just
say that if you purely want to talk
about the units it's 2.83
second to the power of negative one
so getting the value in and of itself is
not hard what is tricky is remembering
that radians don't actually have units
they're purely ratio and so this would
be the ultimate unit that you get so I'd
write down your 9.7
meters per second squared
now we have the final part of this
question so while the pendulum is
oscillating the length of the string is
increased in such a way that the total
energy of the oscillations remains
contact so Justin explain the
qualitative effect of this change on the
amplitude of the oscillations
so what is the key word here is that the
total energy of the oscillation is
remains contact I want you to imagine in
oscillating pendulum that's going back
and forth
is lengthened
like this
at the end of the day the pendulum and
the Bob will have to be moving much
greater distances so if it continues to
do so at the same speed the angular
frequency
which is the frequency of how much it is
displaced angularly this would just
decrease If This Were to stay rather
similar so we know that there will be a
decreased Omega decreased angular
frequency now we want to make sure that
the
um
energy Remains the Same and the way that
this would happen is if the amplitude
increased so if the Omega decreases
um and the amplitude stays the same this
means that the longer
pendulum is simply going to
oscillate
in the same maximum displacement back
and fro but that's not really what
happens it's more likely to extend all
the way here and move here to here so
this is why in order to make sure that
the energy stays the same we need to
decrease the angular frequency to offset
that energy change and increase that
amplitude because we can see that the x
is going to become the maximum
displacement is going to become even
bigger than it was before so here is the
answer
[Laughter]
so this is my answer here so we can just
rub this off and this is essentially
what will be happening if you pictured
the pendulum and what would happen
um purely
intuitively we know that if the maximum
displacement was this and you lengthen
the pendulum it's not going to start
oscillating towards this much it's going
to start oscillating like this so it's
going to be slower in terms of angular
frequency in order to increase that
amount of amplitude I hope that makes
sense so this is like the first example
we have of a question it's really
typical the really the only equation
that we had to use was this equation and
this equation is very common it comes up
all the time and you can easily find it
in the front of the paper a big part of
the oscillations chapter is not simple
harmonics but resonance and this is a
question regarding resonance so it's
very likely that there will be one
question in your paper that is going to
be about oscillations and it's going to
be either on simple harmonic motion or
on resonance or it's going to be on both
of them and somehow they're going to
have like one part you know regarding
simple harmonic motion and then the
latter part regarding the resonance or
whatever so this question is mainly
about resonance so we can take a look at
um how to answer this question so first
of all it's really simple and easy they
ask us State what is meant by the
resonance and we know what is resonance
imagine something here it's already
moving by itself and then we put a hand
here at the same frequency of its
movement and we add up add on to it and
the amplitude will increase a lot so how
you would write this is this
[Applause]
so that's definition you basically have
the object being at a maximum amplitude
when the driving frequency equals the
natural frequency of the object the
keywords that you should look out for
here is you should always remember to
talk about the maximum amplitude
and then you should also include the
world driving frequency and the natural
frequency so those are the keywords that
you have to include in in the definition
here so let's continue onwards
so it says that the figure 4.1 shows a
heavy pendulum and a light pendulum and
they're both suspended from the same
piece of the string and this string is
secured at each end and fixed two points
so we have this sort of like complex
system where there are two
pendulums so there's one heavy one and a
light one now they have the same natural
frequency the heavy pendulum is set to
oscillating perpendicular to the plane
of the diagram which means it's going to
come out and go back in
um because the plane of the diagram is
what we're seeing right now on the paper
or on the screen
so this is essentially the variation
that the graph shows us of time T of the
displacements of the two pendulums for
three oscillations so we have the heavy
pendulum
it's oscillating like this so there are
three oscillations and then we have the
light pendulum it's oscillating like
this and there are three
oscillations so it looks you know like
they're
you know not in face but they actually
have the same frequency because of the
fact that they exactly contain
three oscillations so that's the first
thing that we should realize here and we
also see that the heavy pendulum is
moving with a much higher oscillation
amplitude than the light one but other
than the amplitudes
they are basically have the same
frequency so now the question finally
tells us the variation with t of the
displacement acts of the light pendulum
is given by this which is in centimeters
and T is in second so they ask us to
calculate the period T of the
oscillation
so this is essentially what of the
equation is kind of derived out of so
the velocity of particle in simple
harmonic motion and we have the
variation with t of the displacement of
X in the light pendulum which means that
essentially the only thing that we
should care about is the Omega here
this is telling us that 5.0 pi equals
the Omega so Omega equals 5.0 pi and we
know that the angular frequency is
actually the amount of time that it
takes for one full oscillation
so it's basically telling us the amount
of
the angle value in pi
um
that is basically
moved through per unit time so that's
actually two pi over period T because
whatever T is it's going to move through
2 pi in that time it's going to do a
full oscillation during that time so we
just have to do some substitution and
that's all we need so we know that 2 pi
over T equals 5.0 Pi so we know that t
equals 2 pi over 5.0 Pi which gives us
0.4 seconds so that's our answer right
here
and now they tell us to label both of
the axes with the correct scales and use
the space below for any additional
working so now that we know the the time
this becomes quite easy to do this so we
know that it makes one oscillation in
0.4 seconds so this is just very easy
for us 0.4
this is another oscillation that's 0.8
and then that would be
1.2 and you know you can also fill in
the gaps in between 0.2 0.6
1.0 stuff like that now we should talk
about the amplitude so if you go back
here
we see this right here
this is basically showing us the maximum
displacement of the
um
the particle X because
when for instance there is maximum
um amplit and when there is maximum
displacement that means that the
sine over here is going to be at a
maximum value and it's going to equal 1
right so that means maximum displacement
has to be at this time 0.25 that's the
highest it's going to get so we know
that that is the case for the light
pendulum so this is 0.25 and that makes
life a lot easier for us this is 0.5
0.75 and one and then you can also put
in the negative
value if you want to and so that's how
you would fill in everything it's pretty
straightforward if you wanted to you
could also make it as detailed as
possible just in case there are marks
given for adding extra values whenever
you can so I would also suggest just if
you have enough time
filling out all of the values
in detail
and now we have the final one the final
question asks us to determine the
magnitude of the phase difference
between the oscillations of the light
and heavy pendulums and we have to give
a unit with our answer so the phase
difference is quite easy to find we know
that over here
we can take a close look at this and we
know that this guy
goes back up and
hits the x-axis at 0.4 but this guy goes
back up and hits the x-axis at 0.3 so
the ultimate time difference that we
have here is 0.1 seconds and we know
that the uh the periods of both of these
oscillations are the same the periods
are both 0.4 so if you want to find the
phase difference all you have to do is
to find the fraction of the difference
of time
as a fraction of the total period so
what I mean by that is you should just
write 0.1 out of 0.4 and it times this
fraction by 2 pi and this if you do that
you're going to get half pi radians
and that is the answer that's a look at
how to calculate these resonance
questions what's really important here
in the oscillations chapter is to be
able to just use the equations that are
given to you in the beginning of the
paper very well so this is the velocity
of a particle a simple harmonic motion
but we didn't use it as velocity we
actually used it for displacement so x
equals x o sine
Omega T and it's in the same format and
if you want to find the acceleration you
would also find that it's in the same
format
um we have used this one for simple
harmonic motion and we can use this if
the situation arises for it as well it's
good to be able to tie in various
formulas that are often used to these
things and you would find that most of
the formulas that are required of you
you can actually kind of derive from
what you have over here instead of
having to memorize everything and
obviously they're really important very
common questions that occur in these
chapters such as Define what resonance
is and what is simple harmonic motion
what are the two things that are
required for that motion so these are
kind of the skeleton of
um what really constitutes a question in
oscillation resonance I think they're
very typical examples of what you might
get and it's a good idea to practice
things like this and hopefully be able
to memorize how to answer a lot of the
wordy parts so yeah so I do hope that
this video kind of gave you a good idea
of how to go about in these structured
questions about oscillations and I hope
it was helpful ultimately if you want
more videos such as this on physics and
a levels then do check out the other
videos I have on my channel thank you so
much for watching
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