Calculate Wall Bracing - Part 7 - Design Bracing Systems - Walls

Summary

In this segment of the Buildsum series, the focus is on determining the quantity of wall bracing units required. The video calculates the need for 4 sheets of plywood bracing for Wind Direction 1 and 2 sheets for Wind Direction 2, totaling 6 sheets. It uses Method H with Method B fixing, providing 7.2 kN resistance per sheet. Additional rules are highlighted, such as the minimum length of bracing panels and the capacity adjustments for different panel sizes, ensuring viewers understand the importance of adhering to these standards for effective wall bracing.

Takeaways

• 🏗️ The video discusses calculating the number of bracing units needed for walls in a construction project.
• 📝 The requirement for Wind Direction 1 is 26.758 kN of force resistance, and bracing method H with Method B fixing is chosen, providing 6.0 kN per meter.
• 📐 Each street is 1.2m wide, and the calculation for the number of sheets needed is 26.758 / (6.0 * 1.2) = 3.7, rounded up to 4 sheets.
• 🔢 For Wind Direction 2, 10.127 kN of resistance is needed, and using the same method, 10.127 / 7.2 = 1.4, requiring 2 sheets.
• 📚 A total of 6 sheets of ply are needed for bracing, combining both wind directions.
• 📏 The minimum length for any plywood bracing panel is 900mm, and changing the width to 900mm can reduce the bracing capacity.
• 🔄 For bracing type H with Method A fixing, the minimum width can be reduced to 600mm, but the bracing capacity is halved compared to a 900mm panel.
• ⚖️ If a panel is shorter than 900mm, the bracing capacity can be calculated incrementally based on the panel's length.
• 🔄 The video mentions that there are additional rules to adhere to, which will be covered in the next video.
• 👍 The presenter encourages viewers to subscribe to the YouTube channel or follow on Facebook for more videos.

Q & A

What is the main topic of this video?

The main topic of this video is calculating the number of bracing units required for walls based on the resistance needed against wind forces.

What is the total force of resistance needed in Wind Direction 1?

The total force of resistance needed in Wind Direction 1 is 26.758 kN.

Which bracing method and fixing method are chosen for the calculation?

The chosen bracing method is H with Method B fixing, which provides a total resistance of 6.0 kN per meter.

How wide are the streets for the bracing calculation?

Each street is considered to be 1.2 meters wide for the bracing calculation.

What is the force of resistance provided by one sheet of ply when using the chosen bracing method?

Using the chosen bracing method, one sheet of ply provides 7.2 kN of resistance.

How many sheets of ply are needed to meet the resistance requirement for Wind Direction 1?

Approximately 4 sheets of ply are needed to meet the resistance requirement for Wind Direction 1.

What is the force of resistance required in Wind Direction 2?

The force of resistance required in Wind Direction 2 is 10.127 kN.

How many sheets of ply are needed for Wind Direction 2 based on the chosen bracing method?

2 sheets of ply are needed for Wind Direction 2 based on the chosen bracing method.

What is the minimum length of any plywood bracing panel according to the rules mentioned in the video?

The minimum length of any plywood bracing panel should be 900 millimeters.

What is the exception to the minimum width rule for bracing type H?

The exception for bracing type H is that the minimum width can be reduced to 600 millimeters with Method A fixing.

How should the bracing capacity be calculated for a panel with a length of 600 millimeters?

For a panel with a length of 600 millimeters, the bracing capacity should be half that of a 900 millimeter panel.

What is the total number of sheets needed for bracing as per the video's calculation?

The total number of sheets needed for bracing is 6.