Gerak Parabola • Part 2: Contoh Soal Gerak Parabola Dimulai dari Tanah

Summary

This educational video introduces parabolic motion in physics, focusing on a projectile problem involving a bullet fired at a 37° angle with an initial velocity of 50 m/s. Viewers are guided through detailed calculations to determine the bullet's speed and position after one second, time to reach maximum height, maximum height, total flight duration, and horizontal distance traveled before hitting the ground. By breaking down the kinematic equations and applying trigonometric principles, the tutorial provides a comprehensive understanding of projectile motion, inviting viewers to engage with the content and explore further learning resources.

Takeaways

• 😀 The video focuses on understanding projectile motion, specifically parabolic motion in physics.
• 📏 An example problem involves a bullet fired from a slope at a 37° angle with an initial speed of 50 m/s.
• 🧮 The horizontal component of the bullet's velocity is calculated to be 45 m/s.
• ⬆️ After 1 second, the bullet's vertical velocity is determined to be 20 m/s.
• 📍 The position of the bullet after one second is (40 m, 25 m).
• ⏱️ The time taken to reach the highest point of the trajectory is 3 seconds.
• 🏔️ The maximum height reached by the bullet is 45 m.
• 🕒 The total time of flight until the bullet hits the ground is 6 seconds.
• 📏 The horizontal distance traveled by the bullet before hitting the ground is 240 m.
• 💡 The video encourages viewers to ask questions and engage with the material for better understanding.

Q & A

What is the primary focus of the video?

The video focuses on understanding projectile motion, specifically through an example of a bullet fired at an angle.

What is the initial velocity of the bullet in the problem?

The initial velocity of the bullet is 50 meters per second.

At what angle is the bullet fired?

The bullet is fired at an elevation angle of 37 degrees.

How is the horizontal component of the bullet's velocity calculated?

The horizontal component of velocity (Vx) is calculated using the formula Vx = V₀ * cos(α), resulting in approximately 40 m/s.

What formula is used to find the vertical component of velocity after 1 second?

The vertical component of velocity (Vy) is found using the formula Vy = V₀ * sin(α) - g * t, where g is the acceleration due to gravity.

How do you calculate the total velocity of the bullet after 1 second?

The total velocity (V) is calculated using the Pythagorean theorem: V = √(Vx² + Vy²).

What is the maximum height reached by the bullet?

The maximum height (Hmax) reached by the bullet is 45 meters.

How long does it take for the bullet to reach its maximum height?

It takes approximately 3 seconds for the bullet to reach its maximum height.

What is the total time the bullet is in the air?

The total time the bullet is in the air is 6 seconds, which is double the time to reach maximum height.

What is the horizontal distance traveled by the bullet when it hits the ground?

The horizontal distance traveled by the bullet when it hits the ground is approximately 240 meters.