Trinomials (M2 2.3 Lesson)

Jason Maresh
11 Sept 201823:07

Summary

TLDRThe script is a tutorial on factoring polynomials, emphasizing the importance of understanding the underlying principles before using shortcuts. It introduces a method for factoring trinomials by finding two numbers that multiply to the product of the leading coefficient and constant term, and add up to the linear coefficient. The process involves splitting the middle term and using factoring by grouping. The script also covers factoring when the leading and constant terms are perfect squares and extends the technique to expressions with higher powers. It concludes with a problem-solving example, illustrating how to apply the method to solve equations.

Takeaways

  • 📚 The video script is a tutorial on factoring polynomials, emphasizing the importance of understanding the underlying principles before using shortcuts.
  • 🔑 The first method discussed is factoring out the Greatest Common Factor (GCF), which involves identifying a common factor in all terms of a polynomial.
  • 🔍 The second method involves a strategic approach to factoring trinomials with three terms, where the script introduces a game-like method to find two numbers that meet specific multiplication and addition criteria.
  • 📈 The tutorial explains how to use the coefficients of the polynomial to guide the factoring process, particularly focusing on the lead coefficient, constant term, and linear coefficient.
  • 🎯 The script provides a step-by-step guide on how to split the middle term of a trinomial based on the two numbers identified, which is crucial for the factoring process.
  • 🔄 The concept of 'factoring by grouping' is introduced as a method to simplify polynomials once they are expanded to four terms through strategic splitting.
  • 📝 The tutorial emphasizes the importance of checking work by multiplying the factored form back to its original polynomial form to ensure accuracy.
  • 🧩 The script discusses strategies for dealing with larger numbers and perfect squares in polynomials, suggesting tricks like prime factorization and recognizing patterns.
  • 🔢 The video also touches on factoring polynomials that are not quadratic, such as those with terms raised to the sixth power, showing adaptability in the factoring techniques.
  • 📉 The tutorial concludes with a problem-solving example, demonstrating how to apply the learned factoring methods to solve equations using the zero product property.

Q & A

  • What is the first type of factoring mentioned in the script?

    -The first type of factoring mentioned is factoring out the Greatest Common Factor (GCF).

  • Why is it important to understand why shortcuts work before using them?

    -It's important to understand why shortcuts work to ensure you're using them correctly and to apply them effectively in more complex problems.

  • What is the second type of factoring discussed in the script?

    -The second type of factoring discussed is factoring by grouping, which is typically applied when there are an even number of terms.

  • Why can't the method of factoring by grouping be used for three terms?

    -Factoring by grouping cannot be used for three terms because it requires an even number of terms to be split into pairs.

  • How does the script suggest finding two numbers for factoring when the terms are not easily divisible?

    -The script suggests using prime factorization and grouping factors in sets of two to find two numbers that multiply to a given product and add to a given sum.

  • What is the significance of the numbers 18 and 2 in the script?

    -The numbers 18 and 2 are found to be the two numbers whose product is 36 (3 times 12) and whose sum is 20, which allows for the successful factoring of the given expression.

  • How does the script recommend checking the factoring work?

    -The script recommends checking the factoring work by multiplying the factored terms and comparing them to the original expression.

  • What is the strategy for factoring when the numbers are large or not easily factorable?

    -The strategy is to look for patterns, such as perfect squares, and use prime factorization to break down the numbers into manageable parts.

  • Why is it important to match the terms when splitting up the middle term during factoring?

    -It's important to match the terms to ensure that the factoring process is mathematically correct and that the terms can be grouped properly for further factoring.

  • What does the script suggest for factoring expressions that are not quadratic?

    -The script suggests that the same factoring techniques can be applied to non-quadratic expressions by making necessary adjustments, such as ensuring the terms match when splitting.

  • How does the script demonstrate solving a problem using factoring?

    -The script demonstrates solving a problem by first setting the equation to zero, then factoring, and finally using the zero product property to find the solutions.

Outlines

00:00

📚 Introduction to Factoring Techniques

The speaker introduces the concept of factoring in mathematics, emphasizing the importance of understanding the underlying principles before resorting to shortcuts. They differentiate their teaching method from traditional approaches and focus on explaining why certain factoring methods work. The first method discussed is factoring out the greatest common factor (GCF), which involves identifying a common factor among all terms in a polynomial. The speaker provides a step-by-step guide on how to factor out the GCF, starting with a three-term polynomial and explaining the process of identifying the GCF and factoring it out.

05:19

🔍 Factoring by Grouping and Prime Factorization

In this segment, the speaker explores the technique of factoring by grouping, particularly useful when dealing with polynomials that don't have an even number of terms. They demonstrate how to split terms to create pairs that can be factored, using the example of a polynomial with three terms. The speaker also introduces the concept of prime factorization as a strategy to find two numbers that multiply to a given product and add up to a specific sum, which is crucial for the factoring process. They guide through the process of breaking down a number into its prime factors and then grouping them to find the necessary numbers for factoring.

10:20

🔢 Factoring with Perfect Squares and Large Numbers

The speaker discusses a specific trick for factoring when the first and last coefficients of a polynomial are perfect squares. They explain how this observation can simplify the factoring process and provide a shortcut. The segment includes a detailed example where the speaker guides through the process of factoring a polynomial with large coefficients, emphasizing the importance of recognizing patterns and using prime factorization to assist in the factoring process. The speaker also highlights the need to adjust the sign of terms to ensure the correct sum and product when factoring.

15:20

🔄 Adjusting Factoring Methods for Non-Quadratic Polynomials

This paragraph delves into factoring techniques for polynomials that are not quadratic but still have three terms. The speaker explains how to adapt the factoring by grouping method for these cases, with a focus on ensuring that the terms being split are of the same kind as the middle term in the original polynomial. The segment includes an example of a polynomial with terms raised to the sixth power, demonstrating how to find the correct pair of numbers to multiply and add to the desired coefficients, and then how to split and factor the polynomial accordingly.

20:23

🧩 Solving Equations Using Factoring

The final paragraph shifts focus to solving equations using the zero product property and factoring. The speaker guides through the process of transforming an equation to set it equal to zero, which is a prerequisite for applying the zero product property. They demonstrate how to factor the resulting polynomial and then solve for the variable by setting each factor equal to zero. The speaker concludes with an interactive problem-solving example, engaging the audience to participate in the factoring process and solve the equation together.

Mindmap

Keywords

💡Factoring

Factoring is the process of breaking down a polynomial into a product of other polynomials or factors. In the video, factoring is the central theme, with the instructor demonstrating various methods to factor expressions, particularly focusing on polynomials with three terms. The video aims to teach viewers how to factor expressions by first finding the greatest common factor (GCF) and then using techniques like factoring by grouping.

💡Greatest Common Factor (GCF)

The GCF is the largest factor that two or more numbers share. In the context of the video, the GCF is the first method introduced for factoring polynomials. The instructor explains that one should look for a common factor that can be taken out from all terms of a polynomial, which simplifies the expression. For instance, in the example '3d^2 + 12d', the GCF '3d' is factored out.

💡Factor by Grouping

Factor by grouping is a technique used when a polynomial has more than three terms. The method involves grouping terms and factoring out the GCF from each group. The video demonstrates this by first transforming a three-term polynomial into a four-term polynomial by splitting the middle term, and then factoring out the common terms. This technique is showcased when the instructor works through the polynomial '3d^2 + 20d + 12'.

💡Lead Coefficient

The lead coefficient is the numerical factor that multiplies the highest power of the variable in a term. In the video, the instructor uses the lead coefficients, such as '3' in '3d^2', to help determine the two numbers that multiply to a certain product and add up to a specific sum, which is part of the factoring process.

💡Constant Coefficient

The constant coefficient is the numerical factor that stands alone in a term without being multiplied by any variable. In the video script, the constant coefficient is used in the process of finding two numbers that multiply to the product of the lead and constant coefficients and add up to the linear coefficient.

💡Linear Coefficient

The linear coefficient is the numerical factor that multiplies the variable to the first power in a term. The video uses the linear coefficient, such as '20' in '20d', to guide the process of finding the two numbers that will be used to split the middle term during factoring by grouping.

💡Perfect Squares

Perfect squares are numbers that are the product of some integer multiplied by itself. In the video, the instructor points out that if the first and last terms of a polynomial are perfect squares, a particular factoring trick can be applied. This is demonstrated when factoring a polynomial where the terms '4x^2' and '81' are both perfect squares.

💡Zero Product Property

The zero product property states that if the product of two factors is zero, then at least one of the factors must be zero. In the video, this property is used to solve equations by setting a factored expression equal to zero and then solving for the variable.

💡Difference of Two Perfect Cubes

This is a special factoring formula that applies to expressions that are the difference between two cubes. The video hints at this concept when discussing the factoring of 'a^6 - b^6', which can be further factored using the difference of two perfect cubes formula, although the detailed method is mentioned to be covered later.

💡Prime Factorization

Prime factorization is the process of breaking down a number into its prime factors, which are the prime numbers that multiply together to give the original number. In the video, the instructor uses prime factorization to help find the two numbers that multiply to a certain product and add up to a specific sum, which is crucial for factoring by grouping.

Highlights

Introduction to a new method of factoring that differs from traditional approaches.

Emphasis on understanding the logic behind mathematical shortcuts before applying them.

Explanation of the first type of factoring: factoring out the Greatest Common Factor (GCF).

Discussion on why the second type of factoring, factoring by grouping, is not applicable in this case due to an odd number of terms.

Introduction of a third type of factoring method suitable for trinomials.

A game-like approach to finding two numbers that multiply to a given product and add up to a given sum.

Step-by-step guide on how to split the middle term of a trinomial based on the two numbers found.

Transformation of a trinomial into a binomial through factoring by grouping.

The importance of checking factored solutions by multiplying them out to ensure accuracy.

A strategy for factoring when dealing with larger numbers by using prime factorization.

An example of how to group prime factors to find two numbers that meet specific multiplication and addition criteria.

The use of the zero product property in solving quadratic equations.

Application of the new factoring method to a problem with a negative leading coefficient.

A special trick for factoring when the first and last coefficients are perfect squares.

Adjusting the factoring method for expressions with terms raised to the sixth power.

Final thoughts on when to stop factoring and the limitations of the method being taught.

Invitation for students to choose a problem to solve together, highlighting interactive learning.

Real-time demonstration of solving a quadratic equation using the factoring method chosen by the students.

Transcripts

play00:01

okay so you guys may have had some

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experience factoring how many of that

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experience factoring remember doing in

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the past okay I must do let us don't and

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you may the way I'm teaching you today

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is going to be different than the way

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you probably learned it's going to be

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remember

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there's in math or shortcuts and

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shortcuts are good because they're

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quicker to get especially when you have

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really complicated problems and a lot of

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stuff to do you want to take shortcuts

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but before you take the shortcuts you

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want to slow down and make sure you

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understand why do they work and so right

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now we're we are doing factoring the way

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that explains why it works and

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eventually we'll get to problems where

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factorings not the focus but we'll need

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to factor and we'll probably start

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taking some shortcuts okay so I want you

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for right now even even if you know how

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to do these a different way I want you

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to use it this way okay so the first

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type of factoring is to factor out a GCF

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so you look at all three terms we're

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going to do number six together right

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now is there something that all three

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terms have in common that we can factor

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out other than one or itself yeah I know

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then second type of factoring is what we

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did yesterday if you have four terms or

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an even even a like six terms aren't

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even number where you can split it in

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half and we don't have that we got three

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terms odd number right so you can't

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factor by grouping so now we need a

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third type of factoring and so that's

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what we're looking at here so the first

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thing you do is play a little game and

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I'm going to draw an X here and I'm

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going to ask myself what two numbers

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multiply to 3 times 12 which is 36 and

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add to 20 now let me show you where

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things are coming from the 3 and the 12

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are your lead

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and your constant coefficients your

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twenty is your linear coefficient okay

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so you're using all three of those

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numbers so you want to multiply the

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first and the last number together and

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you want to just think about that second

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number so can we come up with two

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numbers whose product is 36 and whose

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sum is 2030 18 and 2 alright so 18 times

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2 is 36 18 plus 2 is 20 right does it

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work so if it works

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then that tells you that this methods

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gonna factor if this doesn't work that

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tells you it's not going to factor using

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this method okay so this is kind of once

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you get this far then you know

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everything's gonna work out fine so once

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you have the 18 and the 2 that's going

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to split up your middle term right now I

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have 20 DS I'm going to split them up to

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18 DS plus 2 DS so it still adds up to

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20 by splitting it up in a specific way

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coming from the 18 and the two that we

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found here so 3 d squared plus 12 I'm

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going to bring my first my last term

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down video gave that now what we

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created four terms instead of three

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terms not anybody have an idea what the

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deal yeah do what we did last night so

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now you can software by grouping so

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these two terms factor out a 3d what's

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left what do you get when you factor out

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turns D plus six plus factor out of two

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it was left D plus six and now both

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terms have a common factor of D plus six

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so factor out the D plus six and you're

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left with three D plus two that's our

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answer

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and we're asked to check it how we gonna

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check this yeah so I split the 22 18

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into so fine I'm well it's a common term

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what is 18 D plus 2 D is 20 so so I have

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to I have to me I have to keep the DS

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there right I'm just splitting them up

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but yes that's where they're coming from

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so for when you're checking you've got

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to take your answer D plus 6 and 3 D

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plus 2 and multiply that out and go

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ahead and multiply that out and check

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your answer

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so to work out okay so compare your your

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factoring work with your checking work

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and notice that the last line over here

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is the first line over here the second

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to the last line on your factoring is

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exactly the second line here right or

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the third line time the second line here

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is the third line they're the first

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lines last night so it's exactly reverse

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order

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okay so let's try it again a number

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eight I'm going to skip some what I skip

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is homework for you okay so eight we're

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going to start by seeing if it factors

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we're looking for two numbers that

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multiply to Wed 3 times negative 40

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what's 3 times negative 40 so it's got

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to multiply to negative 120 and it's got

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to add to negative seven let's see if

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you could figure those out

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how many found this problem a little

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harder to come up with in the last one

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okay so eventually I'll you'll you'll

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encounter a problem that's just like I

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don't know what to do things mock like

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this and add to this and it's nice to

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have a little strategy to figure out

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what two numbers multiply to 120

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obviously it's 12 and 10 because you got

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a zero at the end it's even so 2 times 2

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times 60

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good work what else what else multiplies

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to 120 and so if you're if you're just

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having trouble coming up with things on

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the top of your head it's not so obvious

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what what I do is I take to 120 I ignore

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Nate the negative right now and I break

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that number down to Prime's so 120 for

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example it was 12 times 10 12 is 4 and 3

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10 is 2 and 5 4 is 2 and 2 and so I know

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120 is 2 times 2 times 2 times 3 times 5

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those are the prime numbers that make up

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120 and also make up all the factors

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that multiply to 120 so if I group these

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factors in sets of 2 I will get all that

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I want so for example I can group that

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way if I grouped that way then what's 2

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times 2 times 2 times 3 so that's 24

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times 5 all right so that's an option 24

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times 5 isn't is 120 so I could use this

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too and you try it out is there any way

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to make 7 from 24 and 5 if I subtract

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them or add them no so then I okay let's

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try grouping in a different way I got

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three twos a three and five let's try

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this way well what's the three twos a

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and 15 well if I add those I don't get

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seven if I subtract into I get seven yes

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so eight times 15 is what we want to

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work with now now we want to think about

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what should be positive which should be

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negative right I know I want a 15 and

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eight but which one should be negative

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15 right because you have your answer is

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negative 7 when you add them so you want

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the bigger number to be negative so that

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when you add and we get to negative

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seven okay so so this this trick of

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getting your prime factorization and

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then just grouping them into two groups

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and you could rearrange them so you

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could also do something like this to put

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the two at the five and then I got two

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more twos and a three and that would

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give me what 10 times 12 and we know

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that one right but you can you don't

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have to keep them in order from lowest

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to highest you could rearrange them to

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come up with okay so that's a good thing

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to know especially when you're

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struggling coming up with the two

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numbers all right so we found them so

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then the next step is to split this up

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to negative 15 P plus 8 P and then we

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carry down the 3p squared and the

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negative 40 so we expanded it from three

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terms to four terms now we can use our

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factoring by grouping so what do we

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factor out the first two terms 3p what's

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left P minus five good and then last two

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terms we could factor out a eight and

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we're left with another P minus five and

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then both of these have the same factor

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P minus 5 so you factor that out

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oops so P minus five times 3p plus eight

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and then again

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check that and all these the checking

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for you for homework okay so let's try

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number ten now you've never ten a chance

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numbers are getting bigger I'll give you

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a 30-second head start so when when the

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numbers are really big look for one

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thing here because sometimes this isn't

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this is a trick that you want to look

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for cuz it could happen and it does

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happen quite a bit look at the first

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number in the last number and check if

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there will anybody notice what they are

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what kind of numbers they're they're

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both perfect squares so if you notice

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the first number and the last number of

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perfect squares almost always this trick

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will work not always but almost always

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and so you start the same way and saying

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look at what two numbers multiply to

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four times 81 and I'm not gonna even

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multiply the madam's going to leave four

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times 81 and add to negative 36 well 4

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times 81 are both perfect squares so 4

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times 81 4 is 2 times 2 81 is 9 times 9

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and so if you pair them up you know you

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kind of split

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so I take one of the twos with one of

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the nines and not the other two with the

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other night what is that what product

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will that give us what times wet

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18:18 and just check if I add those do I

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get 36 and usually it works like that if

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you have perfect squares that's that's a

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trick that you even use and doesn't

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always work but if it does check that

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one first because it'll save you some

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time so 18 and 18 is what I want but I

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can't

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something wrong still how do I fix this

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yeah you got to make them both negative

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because the product is positive so I

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need a negative times a negative because

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when this the sums got to be negative

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but the products got to be positive so I

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know both terms are going to be negative

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so then you split them up negative 18x

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and another negative 18x bring down to

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81

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bring down the 4x squared factor by

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grouping so the first two terms I can

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pull out a 2x left with 2x minus 9 last

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two terms I could pull out a negative 9

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left with 2x minus 9 again both terms

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have a 2x minus 9 and we have

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another 2x minus 9 and so we have

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matching factors here so if you have two

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factors that match what's it what's a

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shorthand for writing that yet that's

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the same thing as 2x minus 9 quantity

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squared and that would be our answer and

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again you're going to want to check that

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and I'll let you took that for homework

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you check by doing what what which is

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what's the opposite of factoring

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multiplying good ok

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now let's scroll down to the very number

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1515 looks a bit different right it's

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something to the sixth power not to the

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2nd power so it's not quadratic it's the

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power of six

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and but our factoring techniques are not

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limited to quadratics only and so number

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14 and 15 are not quadratic but there's

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still three terms and so we could try

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our method on this we just have to

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change a couple things about the method

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so let's do fifteen see how things me

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have to be adjusted so we still start

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saying what two numbers multiply to what

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1 times negative 32 which is negative 32

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and add to what negative 4 so find those

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two

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numbers however you'd like to find them

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let me know nu heaven negative eight and

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four you agree Lindsey okay so now when

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we split this up what am I going to

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write here negative eight what R to the

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third plus four what R to the third so

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what's important here is that these two

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are always like terms with this middle

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term so this is an R to the third term

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so both of these have to match it and if

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you go back and look the two middle

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terms always match that that middle one

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in the trinomial and then we bring down

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the 32 negative 32 we bring down the art

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of the six and then factor by grouping

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and everything else is going to work out

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perfectly so it's just that that

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adjustment just so you know that when

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you split those up they have to be the

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same kind of term as the term that's

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being split up so when we factor this

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what can we factor out R to the third

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and we're left with R to the third minus

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8 plus second one we could factor out a

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4 we've got an R to the third minus 8

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and then go to factor out the arch of

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the third minus 8 and we're left with R

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to the third plus 4 and at this point

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that's where you would stop but the arts

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of the third minus 8 will factor more

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once you know how to factor a difference

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of two perfect cubes

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I don't looked at that yet this one

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won't factor anymore and a lot to learn

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why later on but this is as far as I'd

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want you to go right now and so then you

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can check that okay so those are

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some new kind of factoring it it's

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really how to split something up from

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three to four terms so that we can use

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factoring by grouping let's look let's

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do a solving problem together I'll let

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you pick one that we will do together

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sixteen seventeen or eighteen your pick

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seventeen okay I heard seventeen first

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let's do seventeen but you tell me

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seventeen what do we have to do first

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why okay we want to make the

play21:19

to zero so we're gonna have to subtract

play21:21

30 from both sides of that equation and

play21:25

we get C squared plus C minus 30 equals

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zero because we want to use the zero

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product property so it's got to be equal

play21:33

to zero okay then we factor looking for

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two numbers that multiply to one times

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negative 30 so that's negative 30 and

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adds to one what is it six and negative

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five so we split it up C squared plus

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six C minus five C minus 30 equals zero

play22:03

and then we continue what we've learned

play22:06

so we factor by grouping all right so

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now it's factored I wish I had a little

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more space but nowadays factored what

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are we do we have our

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times RB equals zero which means what

play22:38

one of them has to equal zero so you

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split your factors up get over here

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so either C plus 6 equals 0 or C minus 5

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equals 0 if C plus 6 is 0 then C is

play22:54

negative 6 if C minus 5 is 0 then C is

play22:59

positive 5 stop there

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