Area & Perimeter in the Coordinate Plane | Geometry | Eat Pi
Summary
TLDRThis educational video script offers a clear guide on calculating the area and perimeter of shapes and polygons in the coordinate plane. The presenter explains the formula for a triangle's area as half the base times the height and demonstrates using a grid. For the perimeter, the Pythagorean theorem is applied to find the hypotenuse. The script then shifts to rectangles, introducing the distance formula to find the length and width when the grid isn't aligned, and uses it to calculate the area and perimeter. The explanation is practical, with step-by-step instructions and a friendly tone, making it accessible for viewers to grasp geometrical concepts.
Takeaways
- 📐 The area of a triangle can be found using the formula: \( \frac{1}{2} \times \text{base} \times \text{height} \).
- 📏 When shapes are aligned with the grid, it's easier to determine the base and height for calculating area.
- 📍 The base and height of a triangle in the coordinate plane can be measured directly from the grid.
- 🔢 For the given triangle example, the base is 7 units and the height is 5 units, resulting in an area of 17.5 square units.
- 🧩 To find the perimeter of a triangle, sum all its sides, including the hypotenuse found using the Pythagorean theorem.
- 📐 The Pythagorean theorem states that \( a^2 + b^2 = c^2 \), where \( c \) is the hypotenuse.
- 🔑 The hypotenuse in the triangle example is approximately 8.6 units, calculated using the Pythagorean theorem with sides 7 and 5.
- 📏 The perimeter of the triangle is the sum of its sides, which is approximately 20.6 units.
- 📐 For shapes not aligned with the grid, like a rectangle, use the distance formula to find the length and width.
- 📏 The distance formula is \( \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \) for finding the distance between two points.
- 🔢 The area of a rectangle is calculated by multiplying its length by its width, which are not necessarily aligned with the grid.
- 📐 The perimeter of a rectangle can be found by adding twice the length and twice the width.
- 📝 The video provides a step-by-step guide on using the distance formula and the Pythagorean theorem for calculating areas and perimeters in the coordinate plane.
Q & A
What is the formula to calculate the area of a triangle?
-The formula to calculate the area of a triangle is one half the base times the height (A = 1/2 * base * height).
How can you determine the base and height of a triangle on a coordinate grid?
-On a coordinate grid, the base can be determined by counting the horizontal spaces from one vertex to another, and the height is the vertical distance from the base to the opposite vertex.
What is the area of the triangle in the video if the base is 7 units and the height is 5 units?
-The area of the triangle would be 17.5 square units (A = 1/2 * 7 * 5 = 17.5 units²).
How do you find the perimeter of a polygon when you know the lengths of its sides?
-To find the perimeter, you add up the lengths of all the sides of the polygon.
What is the Pythagorean theorem used for in the context of the video?
-The Pythagorean theorem (a² + b² = c²) is used to find the length of the hypotenuse of a right-angled triangle when the lengths of the other two sides are known.
How is the distance formula applied to find the length of a side of a rectangle on a coordinate grid?
-The distance formula (√((x2 - x1)² + (y2 - y1)²)) is used to calculate the distance between two points, which can be the length or width of a rectangle if the points are its vertices.
What is the formula for the area of a rectangle?
-The formula for the area of a rectangle is the length times the width (A = length * width).
How do you calculate the perimeter of a rectangle?
-The perimeter of a rectangle is calculated by adding twice the length and twice the width (P = 2 * length + 2 * width).
What is the approximate perimeter of the rectangle in the video with a length of 12.7 units and a width of 4.2 units?
-The approximate perimeter of the rectangle is 33.8 units (P = 2 * 12.7 + 2 * 4.2 ≈ 33.8 units).
What is the distance formula and how is it used to find the area of a shape on a coordinate grid?
-The distance formula is used to calculate the distance between two points in a coordinate plane. It is used to find the lengths of sides of shapes, which can then be used to calculate the area of polygons by applying the appropriate area formula for the shape.
How can you find the area of a shape that is not aligned with the grid on a coordinate plane?
-For shapes not aligned with the grid, you can use the distance formula to find the lengths of the sides of the shape, and then apply the area formula specific to that shape (e.g., for a rectangle, use length * width).
Outlines
📐 Geometry Basics: Perimeter and Area of Shapes
This paragraph introduces the concepts of finding the perimeter and area of shapes and polygons on a coordinate plane. The presenter uses a triangle as an example, explaining how to calculate its area with the formula (1/2) * base * height. They demonstrate how to measure the base and height directly from the grid and then apply the Pythagorean theorem to find the hypotenuse, which is necessary for calculating the perimeter. The process is detailed with specific numerical examples, making it easy to follow.
📏 Advanced Calculations: Area and Perimeter of a Rotated Rectangle
In this paragraph, the focus shifts to calculating the area and perimeter of a rectangle that is not aligned with the grid, requiring the use of the distance formula. The presenter explains how to find the length and width of the rectangle by applying the distance formula to the coordinates of the rectangle's vertices. They provide step-by-step instructions on how to calculate the length and width, including squaring and taking the square root of the sum of squared differences in x and y coordinates. After finding the dimensions, they calculate the area by multiplying the length by the width and the perimeter by adding twice the length and twice the width. The explanation includes rounding off to approximate values for practical purposes.
Mindmap
Keywords
💡Perimeter
💡Area
💡Triangle
💡Base
💡Height
💡Pythagorean Theorem
💡Hypotenuse
💡Rectangle
💡Distance Formula
💡Coordinate Plane
Highlights
Introduction to finding the perimeter and area of shapes and polygons in the coordinate plane.
Explanation of the formula for the area of a triangle: 1/2 * base * height.
Demonstration of calculating the area of a triangle using a grid for easy measurement.
Calculation of a triangle's area with base length of 7 units and height of 5 units.
Conversion of area calculation result to units squared.
Introduction to finding the perimeter of a triangle using the Pythagorean theorem.
Application of the Pythagorean theorem to find the hypotenuse of a triangle.
Calculation of the hypotenuse with sides of 7 and 5 units resulting in approximately 8.6 units.
Summation of all sides to find the perimeter of the triangle: 7 + 5 + 8.6 = 20.6 units.
Introduction to finding the area of a rectangle using the distance formula.
Explanation of the distance formula and its application to non-aligned shapes.
Calculation of the length of a rectangle using the distance between two points (3,8) and (-6,-1).
Finding the width of the rectangle using the distance between points (3,-8) and (6,-5).
Calculation of the rectangle's area using the formula: length * width.
Conversion of area to units squared and rounding to an approximate value.
Introduction to calculating the perimeter of a rectangle using the formula: 2 * (length + width).
Final calculation of the rectangle's perimeter as 33.8 units.
Encouragement for viewers to leave feedback and engage with the content.
Transcripts
what's up you freaking geniuses so in
this video i'm going to teach you how to
find the perimeter and area of shapes
and polygons in the coordinate plane all
right so first of all we have a triangle
right here right so the area
of a triangle of any triangle is equal
to one half the base times the height
okay now when your shapes are lined up
with the grid like this it's a little
bit easier to figure it out okay because
as you can see the base right here would
just be this horizontal side right so
the base how long is the base well it's
one two three four five six
seven so it's seven spaces long or seven
units long and then the height would be
right here right so the height would be
one two three four five okay so it's
five right there okay so if we wanted to
find
the area the area would be equal to one
half the base which is seven
times the height which is five
okay so it'd be equal to one half times
35
which is equal to
17.5
okay and whatever your units you're
using just put those there and then they
would be squared right so we'll just say
17.5 units squared
okay now in order to find the perimeter
we have to add up all the sides together
right so we already have these two and
if you notice we can actually use the
pythagorean theorem to figure out this
missing side right here the the
hypotenuse right here right this long
side so
the formula for that would be
a squared plus b squared is equal to c
squared okay where a and b right here
are your two shorter sides and then c is
your hypotenuse okay so first of all uh
we can plug in let's see we have a 7 and
a 5. those are our shorter sides right
so we can plug in a 7 here and a 5 here
okay so then we'll have
7 squared plus 5 squared is equal to c
squared okay now 7 squared is equal to
49
5 squared is 25
and that's equal to c squared okay now
49 plus 25 is equal to
well 49 plus 20 is 69 nice plus 5 is 74
okay so here we have
74 is equal to c squared
okay now to get rid of this exponent
right here the two right we have to take
the square root of that and what we do
to one side we do to the other right so
then here
these cancel out so then on this side
we're just left with c is equal to the
square root of 74 which is approximately
let me change my symbol to then
approximately
8.6
all right so this side right here is the
hypotenuse we're going to say it's about
8.6
okay now if we want to find the
perimeter now we can add up all the
sides together right so we're going to
have 7 plus 5
plus 8.6
and that's equal to
20.6 and if we have units here you know
you just write your units right there
right inches or feet miles whatever okay
so here's the perimeter
all right so here's our next example so
we have a rectangle right so the area of
a rectangle is
the length
times the width right so in order to
find the area here
since it's at an angle right it's not
lined up with the grid we can't just
count spaces like we did last time so in
this case we're going to have to use the
distance formula now if you don't
remember what that is
i'll write it right here so it's x of 2
minus x of 1
squared plus
y of 2 minus y of 1 squared okay so this
whole thing
is under a square root okay now if
you're not familiar with this i'll link
a video to that in the card above but
this is the formula you have to use in
order to find the distance between two
points okay so if we want to find this
side right here this length we have to
find the distance between these two
points right here right 3 comma 8 and
negative 6 comma negative 1.
okay so if we're going to use the
distance formula we have to label our
points here that we're going to use okay
so this one let's label this one as
x of 1 y of 1 and this one we'll label
as x of 2
y of 2 okay so now that we labeled our
two points right here now we can find
the distance between them okay by
plugging it in right here so we're going
to have the length is equal to the
square root of
all this junk right here right so x of 2
minus x sub 1 so we're going to have x
of 2 which is 3 minus x of 1 which is
negative 6. so 3 minus negative 6.
okay so
in parentheses we're going to have 3
minus
negative 6 and that's squared and then
we're going to add that to our other set
of parentheses right here y of 2 minus y
of 1. so y of 2 is 8
y of 1 is negative 1. so we're going to
have 8 minus
negative 1 and this is also squared okay
so then this is going to be equal to the
square root of now 3 minus negative 6
that's the same thing as 3 plus 6 right
so 3 plus 6 is equal to 9.
okay so we have 9 squared and then we're
going to add that to here so 8 minus
negative 1 so this is the same thing
again as 8 plus 1. so 8 plus 1 is equal
to 9 squared also right so
9 squared also okay so then here we're
going to have the square root of well 9
squared is equal to 81 right so we have
81 plus 81 which is equal to the square
root of
162
which if you plug into your calculator
you're gonna get approximately
12.7
okay so the length right the length
right here the distance right here is
equal to approximately
12.7
okay now we just have to find the width
right so again we're going to use the
distance formula to find the width okay
and to find this side now we're going to
have to use these two points right here
right 3 comma negative 8 and 6 comma
negative 5. okay so this one since it's
already labeled i'll just leave it as x
of 2 y 2 and then this one will be
x sub 1
y of one okay so these are the two
points we're using this time okay so now
that these are labeled now we can plug
them into our formula right here okay so
we're gonna have the square root of
remember it's x of two minus x of one
right so x of two is 3
x of 1 is 6. so we're going to have 3
minus 6 in our first set of parentheses
right here right 3 minus 6 and that's
squared and then we're going to add that
to this set of parentheses right here
y of 2 minus y of 1. so 8 minus five
okay
eight minus five and this is squared
also okay so then the width is equal to
the square root of three minus six
that's equal to negative three and this
is squared plus 8 minus 5 which is equal
to 3 and that's squared also so then we
have the square root of negative 3
squared is equal to 9
and 3 squared is equal to 9 okay so here
we have the square root of 18
which if you plug that into your
calculator you're going to get about
right approximately
4.2
okay so then the width over here is
approximately
4.2
all right and let's get rid of all this
crap in three two one boom all right
cool
now in order to find the area remember
the area is just the length times the
width right so here we have 12.7 times
4.2 so
12.7
times
4.2
and that's going to be approximately
again right because we're just rounding
everything
53.3
and those are units
squared all right don't forget those
right so that's the area right here now
to find the perimeter
remember we just have to add up all the
sides right and another way we could
write that is 2 times the length plus 2
times the width okay so then the
perimeter is going to be equal to two
times the length which is again
approximately 12.7
right plus two times the width which is
about 4.2
okay and then the perimeter uh so 2
times 12.7 that's equal to
25.4
plus 2 times 4.2 so then this is equal
to 8.4 right and if you add these up
you're going to get a nice grand total
of 33.8
units in length all right so then that's
your perimeter
so if you found the video helpful
definitely leave a thumbs up down below
and if you have any other questions or
want to see any other examples just let
me know in the comment section below
also there's a couple playlists attached
that i think you'll find helpful so
definitely check those out and i'll see
you there
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