Nyquist Rate & Nyquist Interval

Neso Academy
19 Apr 201808:06

Summary

TLDRThis lecture delves into the concept of the Nyquist rate and interval, essential for signal processing. It begins by contrasting oversampling, where the sampling frequency exceeds twice the maximum frequency of the signal, with undersampling, which is not recommended due to signal overlap. The Nyquist rate, denoted as Fs, is defined as twice the maximum frequency component (FM) of the message signal, ensuring no overlapping in the shifted spectrums. The Nyquist interval (Ts) is calculated as the reciprocal of twice FM. An example problem illustrates how to determine the Nyquist rate and interval by first identifying the maximum frequency component of a given signal. The lecture concludes with a worked example, guiding through the calculations and reinforcing the importance of adhering to the Nyquist criteria for signal recovery.

Takeaways

  • 📚 Nyquist Rate is the minimum sampling frequency required to avoid aliasing when sampling a continuous signal.
  • 🔄 Oversampling occurs when the sampling frequency (Ωs) is greater than twice the maximum frequency component (ΩM) of the message signal.
  • 🚫 Undersampling happens when Ωs is less than twice of ΩM and is not allowed as it leads to overlapping and signal recovery becomes impossible.
  • 🔄 Nyquist rate (Fs) is defined as twice the maximum frequency (FM) of the message signal, ensuring no overlapping of shifted spectrums.
  • ⏱ The Nyquist interval (Ts) is the time period corresponding to the Nyquist rate and is calculated as the reciprocal of twice the maximum frequency.
  • 📉 To recover the message signal from the sampled signal without loss, there must be a sufficient gap between the shifted spectrums, which is ensured by oversampling.
  • 📐 The relationship between sampling frequency and the maximum frequency component is crucial for determining whether oversampling or undersampling is occurring.
  • 📊 The condition for oversampling is mathematically represented as FS > 2 * FM, ensuring no overlapping of the signal's spectrum.
  • 📚 The example problem demonstrates the process of calculating the Nyquist rate and interval by first determining the maximum frequency component of a given signal.
  • 📝 In the provided example, the message signal is composed of two frequency components, and the maximum one is identified to calculate the Nyquist rate and interval.
  • ✅ The final calculation in the example results in a Nyquist rate of 200 Hz and a Nyquist interval of 5 milliseconds for the given signal.

Q & A

  • What is the Nyquist rate?

    -The Nyquist rate, denoted as Fs, is the minimum sampling frequency required to avoid aliasing when sampling a continuous signal. It is equal to twice the maximum frequency component of the message signal, FM.

  • What is the significance of the Nyquist interval?

    -The Nyquist interval, denoted as Ts, is the time period of the Nyquist rate. It is the inverse of the Nyquist rate and represents the minimum time interval between samples to prevent overlapping and ensure signal recovery.

  • Why is oversampling preferred over undersampling?

    -Oversampling, where the sampling frequency (Omega S) is greater than twice the maximum frequency component of the message signal (Omega M), is preferred because it provides a sufficient gap between the shifted spectrums of the message signal, preventing overlapping and allowing for signal recovery.

  • What happens when undersampling occurs?

    -Undersampling occurs when the sampling frequency is less than twice the maximum frequency component of the message signal. This leads to overlapping between the shifted spectrums of the message signal, making it impossible to recover the original signal from the sampled signal.

  • What is the mathematical condition for oversampling?

    -The mathematical condition for oversampling is that the sampling frequency Fs must be greater than twice the maximum frequency component FM, which can be expressed as Fs > 2 * FM.

  • What is the relationship between the sampling frequency and the maximum frequency component in the case of the Nyquist rate?

    -In the case of the Nyquist rate, the sampling frequency Fs is equal to twice the maximum frequency component FM, which can be expressed as Fs = 2 * FM.

  • How can you calculate the Nyquist rate for a given signal?

    -To calculate the Nyquist rate for a given signal, you first need to determine the maximum frequency component (Omega M) of the message signal. Then, you multiply this value by 2 to get the Nyquist rate Fs.

  • How is the Nyquist interval related to the maximum frequency component?

    -The Nyquist interval Ts is the reciprocal of twice the maximum frequency component (2 * FM). It can be calculated using the formula Ts = 1 / (2 * FM).

  • What is the example problem presented in the script?

    -The example problem presented in the script involves finding the Nyquist rate (Fs) and the Nyquist interval (Ts) for a signal composed of two frequency components: cos(100πt) and 2 * sin(200πt).

  • How are the frequency components determined in the example problem?

    -In the example problem, the frequency components are determined by analyzing the given signal, which is a combination of a cosine function with an angular frequency of 100π and a sine function with an angular frequency of 200π. The maximum frequency component is 200π, as it is the higher of the two frequencies.

  • What are the calculated values for the Nyquist rate and interval in the example problem?

    -In the example problem, the calculated Nyquist rate is 200 Hertz, and the calculated Nyquist interval is 5 milliseconds.

Outlines

00:00

📚 Introduction to Nyquist Rate and Interval

This paragraph introduces the concept of the Nyquist rate and interval. It explains the importance of the sampling frequency (Omega S) in relation to the maximum frequency component of the message signal (Omega M). Oversampling, where Omega S is greater than twice Omega M, is described as the preferred case, allowing for the recovery of the message signal from the sampled signal without overlapping. Undersampling, where Omega S is less than twice Omega M, is not allowed due to overlapping, which prevents signal recovery. The Nyquist rate (Fs) is defined as twice the maximum frequency (FM) of the message signal, and the Nyquist interval (TS) is calculated as the reciprocal of twice FM. An example problem is introduced to illustrate the calculation of the Nyquist rate and interval.

05:01

🧮 Calculation of Nyquist Rate and Interval with an Example

The second paragraph provides a step-by-step calculation of the Nyquist rate and interval using a given signal composed of two frequency components. The message signal is broken down into two parts, X1(T) and X2(T), with X1(T) being a cosine function with an angular frequency of 100 pi and X2(T) being twice a sine function with an angular frequency of 200 pi. The maximum frequency component (Omega M) is identified as 200 pi, from which the maximum frequency (FM) is calculated as 100 Hz. The Nyquist rate (FS) is then determined by doubling FM, resulting in 200 Hz. Finally, the Nyquist interval (TS) is calculated using the reciprocal of the Nyquist rate, yielding 5 milliseconds. The paragraph concludes with the results of the example problem and ends the lecture.

Mindmap

Keywords

💡Nyquist Rate

The Nyquist Rate, often denoted as Fs, is the minimum sampling rate required to avoid aliasing when digitizing a signal. It is defined as twice the maximum frequency component, FM, of the message signal. In the context of the video, it is crucial for understanding how to properly sample a signal without losing information, ensuring that the sampled signal can be used to perfectly reconstruct the original signal. The script mentions that 'FS is equal to twice of FM' which is the condition for the Nyquist Rate.

💡Nyquist Interval

The Nyquist Interval, symbolized as Ts, is the inverse of the Nyquist Rate and represents the time between samples when a signal is sampled at the Nyquist Rate. It is a fundamental concept in signal processing that ensures the proper temporal spacing of samples to prevent overlap in the frequency domain. In the script, it is calculated as 'TS equal to one over twice of FM', which is used to determine the time interval at which samples must be taken to avoid signal overlap and ensure accurate signal reconstruction.

💡Oversampling

Oversampling occurs when the sampling frequency, Omega S, is greater than twice the maximum frequency component, Omega M, of the message signal. This condition is preferred as it provides a sufficient gap between the shifted spectrums of the message signal, preventing overlap and allowing for the signal to be recovered from the sampled signal without loss of information. The script discusses oversampling as the ideal scenario where 'Omega S is greater than twice of Omega M'.

💡Undersampling

Undersampling is the condition where the sampling frequency is less than twice the maximum frequency component of the message signal, leading to overlapping of the shifted spectrums in the frequency domain. This overlap makes it impossible to recover the original message signal from the sampled signal, which is why undersampling is not allowed. The script states that 'under sampling is not allowed, because in this case there is overlapping between the shifted spectrums of the message signal'.

💡Aliasing

Aliasing is the phenomenon that occurs when a signal is sampled below its Nyquist Rate, leading to a loss of information and the introduction of errors in the reconstructed signal. It is the result of frequency overlap in the sampled signal, which can cause high-frequency components to appear as lower frequencies. The script touches on aliasing in the context of undersampling, where it is mentioned that 'under sampling is not allowed' due to the overlap that leads to aliasing.

💡Sampling Frequency

The sampling frequency, denoted as Omega S or FS, is the number of samples taken per second when digitizing a continuous signal. It is a key parameter in determining whether a signal can be accurately represented in the digital domain. The script relates the sampling frequency to the Nyquist Rate, stating that 'Omega S is the sampling frequency' and that it must be greater than 'twice of Omega M' to avoid aliasing.

💡Message Signal

The message signal is the original continuous signal that is to be sampled and digitized. It contains various frequency components, with the maximum frequency component, Omega M, being particularly important for determining the Nyquist Rate. In the script, the message signal is represented by 'MT' and is composed of two frequency components, with the maximum being used to calculate the Nyquist Rate and Interval.

💡Maximum Frequency Component

The maximum frequency component, represented as Omega M or FM, is the highest frequency present in the message signal. It is a critical value used to calculate the Nyquist Rate and Interval, as the Nyquist Rate must be at least twice this value to prevent aliasing. The script identifies Omega M as '200 pi' for the given example problem, which is then used to compute the Nyquist Rate and Interval.

💡Angular Frequency

Angular frequency, symbolized by Omega (Ω), is a measure of how fast a signal oscillates and is expressed in radians per second. It is used to describe the frequency components of the message signal in the context of the script. The angular frequency of the message signal's components is used to determine the maximum frequency component, Omega M, which is essential for calculating the Nyquist Rate and Interval.

💡Signal Reconstruction

Signal reconstruction refers to the process of recreating the original continuous signal from its sampled version. It is possible without loss of information if the signal is sampled at or above the Nyquist Rate. The script emphasizes the importance of the Nyquist Rate in ensuring that the sampled signal can be used to perfectly reconstruct the original message signal without any loss or distortion.

💡Frequency Domain

The frequency domain is a representation of a signal in terms of frequency rather than time. It is where the signal's spectrum is analyzed, showing the frequency components and their amplitudes. The script discusses the frequency domain in relation to sampling, explaining how the sampling process affects the signal's spectrum and the importance of preventing overlap (aliasing) in this domain by adhering to the Nyquist Rate.

Highlights

Introduction to the concept of Nyquist rate and interval.

Explanation of oversampling where the sampling frequency is greater than twice the maximum frequency component.

Condition for oversampling allows for no overlapping of shifted spectrums, enabling signal recovery.

Formula for sampling frequency (Ωs = 2π/PS or 2π * 2FS) and its relation to maximum frequency component (2Ωm).

Undersampling is not allowed as it leads to overlapping of shifted spectrums, making signal recovery impossible.

Condition for undersampling (FS < 2 * FM) and its implications.

Special case when sampling frequency equals twice the maximum frequency component, allowing signal recovery without overlapping.

Definition of Nyquist rate (FS = 2 * FM) and its importance in signal processing.

Calculation of Nyquist interval (TS = 1 / (2 * FM)) using the relation between frequency and time period.

Guidance on how to calculate the Nyquist rate and interval for a given signal.

Example problem presented to illustrate the calculation of Nyquist rate and interval.

Method to find the maximum frequency component (ΩM) of a composite signal.

Determination of angular frequency for individual components of the message signal.

Comparison of angular frequencies to find the maximum frequency component.

Conversion of angular frequency to frequency in hertz for calculation purposes.

Calculation of the Nyquist rate (FS) based on the maximum frequency component.

Determination of the Nyquist interval (TS) using the inverse of the Nyquist rate.

Conclusion of the lecture with a summary of the key concepts discussed.

Transcripts

play00:00

in this lecture we will understand what

play00:02

is Nyquist rate and what is Nyquist

play00:05

interval and once we are done with the

play00:07

explanation part we will solve one

play00:10

example problem and now we will begin

play00:13

our discussion with the revision of the

play00:16

concepts we developed in the previous

play00:18

lecture we saw the case of over sampling

play00:22

and the case of under sampling in over

play00:26

sampling we saw Omega S which is the

play00:29

sampling frequency is greater than twice

play00:32

of Omega M Omega M is the maximum

play00:36

frequency component of the message

play00:38

signal and when this happens you will

play00:41

find the shifted spectrums of the

play00:44

message signal are having sufficient gap

play00:48

between them and there will be no

play00:51

overlapping and therefore we can recover

play00:54

the message signal from the sampled

play00:56

signal so this over sampling case is the

play01:01

preferred case this is allowed and we

play01:04

know Omega s is equal to 2pi divided by

play01:08

PS or we can write 2 pi multiplied 2 FS

play01:13

and we can write twice of Omega m equal

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to 2 multiplied to 2 pi F M and from

play01:24

here we are getting 2 pi F s is greater

play01:27

than 2 multiplied to 2 pi FM 2 pi 2 pi

play01:32

will cancel out so we are finally

play01:34

getting FS greater than twice of FM so

play01:39

this condition is allowed and in this

play01:42

condition there will be no overlapping

play01:44

now in case of under sampling we saw

play01:48

Omega s is less than twice of Omega M

play01:53

and under sampling is not allowed

play01:56

because in this case there is

play01:58

overlapping between the shifted

play02:01

spectrums of the message signal and

play02:04

therefore when we try to recover the

play02:07

message signal from the sample signal it

play02:10

won't be possible therefore this case

play02:13

is not allowed and from here we will get

play02:16

FS less than twice of FM we saw one more

play02:22

case in which Omega has was equal to

play02:26

twice of Omega M and in this case the

play02:31

shifted spectrums of message signal who

play02:34

was touching and this case is also

play02:37

allowed because in this case there is no

play02:40

overlapping and we can recover the

play02:43

message signal from the sampled signal

play02:46

and from here we can say that F s will

play02:50

be equal to twice of FM now the surface

play02:54

is known as Nyquist rate so remember

play02:59

FS is equal to twice of FM and to

play03:04

calculate the Nyquist interval we will

play03:07

simply use the relation between

play03:10

frequency and the time period we know

play03:14

time period is equal to one over

play03:18

frequency so from here we are getting TS

play03:23

equal to one over twice of FM so this is

play03:29

known as the Nyquist interval and in

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questions they will ask you to calculate

play03:34

the Nyquist rate this means you need to

play03:37

calculate FS and they will ask you to

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calculate the Nyquist interval this

play03:42

means you need to calculate TS and both

play03:46

the parameters will be calculated after

play03:48

calculating the maximum frequency

play03:51

component of the message signal which is

play03:55

Omega M to understand this in a better

play03:57

way let's solve one example problem in

play04:00

this example problem we need to find the

play04:03

Nyquist rate this means we need to find

play04:06

F s and we also need to find the Nyquist

play04:11

interval this means we need to find T s

play04:14

and we need to find them for the

play04:17

following signal in this signal here MT

play04:20

is the message signal and it is equal to

play04:23

cos 100 PI D plus sign 200

play04:27

piety so here we are having to frequency

play04:30

components and to find Omega M we need

play04:34

to find the maximum frequency component

play04:36

so let's understand how we can solve

play04:40

this problem let's see the message

play04:42

signal is composed of two signals X 1 T

play04:47

and X 2 T signal X 1 T is equal to coz

play04:52

hundred pie T signal X 1 T is equal to

play04:57

cos hundred pie T and signal X 2 T is

play05:01

equal to twice of sine two hundred pie T

play05:04

X 2 T is equal to twice of sine two

play05:10

hundred pie T and comparing it with the

play05:14

standard cosine function we can hopped

play05:17

in the value of angular frequency he

play05:21

will find angular frequency is equal to

play05:24

100 pi in this case and it is equal to

play05:27

200 pi in this case so let's say in the

play05:31

first signal the angular frequency is

play05:34

Omega 1 and it is equal to hundred pi as

play05:38

you can see and in the second signal the

play05:42

angular frequency is Omega 2 and it is

play05:45

200 pi now compare Omega 1 and Omega 2

play05:50

you will find Omega 1 is less than Omega

play05:54

2 and we are looking for the maximum

play05:57

frequency component and out of Omega 1

play06:01

and Omega 2 Omega 2 is the maximum

play06:04

frequency component therefore Omega is

play06:08

equal to Omega 2 and it is equal to 200

play06:12

pi now we have Omega M we can calculate

play06:15

Omega s or we can directly calculate FM

play06:19

we can calculate FM because we know FM

play06:23

is equal to Omega M divided by 2 pi

play06:27

Omega M is 200 pi so we will get FM

play06:31

equal to 200 pi divided by 2 pi and this

play06:36

is equal to hundred and the unit will be

play06:39

heard

play06:40

and we know the angular frequency is

play06:43

having the unit radians per second now

play06:47

it is very easy to calculate the Nyquist

play06:50

rate FS because we have calculated FM

play06:53

and the only thing required is to

play06:55

multiply to 2 FM so let's calculate

play06:59

Nyquist rate FS it is equal to 2

play07:02

multiplied to FM which is hundred Hertz

play07:05

so finally we are getting the Nyquist

play07:09

rate equal to 200 Hertz this is the

play07:15

answer and to calculate the Nyquist

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interval TS you can use this 1 over 2 FM

play07:22

or you can directly use this we have

play07:25

calculated F s so we will use 1 over F s

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TS will be equal to 1 divided by 200

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seconds when you simplify this you will

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get T s is equal to 5 milli seconds and

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this is our answer

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so this is all for this lecture and I

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will end it here soon the next one

play07:54

[Applause]

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[Music]

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Related Tags
Nyquist RateSignal SamplingOversamplingUndersamplingFrequency AnalysisSignal RecoveryLecture SeriesTechnical EducationEngineering ConceptsExample Problem