A primer to wireless power transfer
Summary
TLDRLa présentation intitulée 'A primer to wireless power transfer' explore l'idée de la transmission de puissance sans fil, une notion ancienne popularisée par Nikola Tesla en 1898. Le texte décrit le concept de base impliquant des bobines primaires et secondaires, la création de flux magnétique et le coefficient de couplage qui détermine l'efficacité de la transfert. L'auteur aborde les défis, notamment la distance, les pertes par résistances parasitaires et la question de la puissance apparente. Il insiste sur l'importance des circuits résonants pour améliorer le couplage et explique le rôle du facteur de qualité (Q) dans ces circuits. La présentation couvre également divers modèles de circuits, y compris les équivalents de résistances pour des charges non linéaires telles que des batteries. Enfin, elle examine les méthodes pour améliorer le découplage et augmenter le coefficient de couplage, comme l'utilisation d'éléments de ferrite pour canaliser les lignes de flux. L'objectif est d'offrir une vue d'ensemble intuitive du transfert de puissance sans fil, soulignant sa complexité et la nécessité d'une adaptation aux différents types de charges pour obtenir des résultats optimaux.
Takeaways
- 🕰️ L'idée de transfert d'énergie sans fil n'est pas nouvelle, remontant à Nikola Tesla en 1898.
- 🔌 Le transfert d'énergie sans fil a été exploré dans les années 1920, avec des suggestions de constructions de transformateurs sans fil dans des journaux bricoleurs.
- 🌐 L'idée de Tesla visait non seulement à une technologie, mais aussi à une foi et une idéologie pour améliorer les relations pacifiques universelles en éliminant la distance.
- 🪢 Le coefficient de couplage est un facteur clé dans le transfert d'énergie sans fil, déterminant la quantité de flux magnétique atteignant le secondaire.
- ⚙️ Le modèle de système peut être basé sur la mutualité ou sur la relation d'un transformateur, avec des notions de permeabilité et de pertes.
- 🔋 L'efficacité du transfert d'énergie sans fil est cruciale, nécessitant une gestion des pertes et une réduction de la puissance apparente.
- 🔗 L'utilisation de circuits résonnants est une approche pour améliorer le couplage entre les bobines et réduire l'impédance totale du circuit.
- 📡 Le facteur de qualité (Q) est important dans les circuits résonnants, influençant la forme de l'onde sinusoïdale et la relation entre l'énergie réactive et réelle.
- 🔧 L'efficacité du transfert peut être optimisée en réduisant les pertes dues aux résistances parasitaires et en utilisant des composants à faible résistance équivalente série (ESR).
- 🔄 La simulation de circuits peut aider à comprendre le comportement du système sous différentes conditions et à trouver les points de fonctionnement optimaux.
- 🛠️ Il existe différentes configurations pour le transfert d'énergie sans fil, y compris des résonances séries et parallèles à l'entrée et à la sortie, chacune ayant ses avantages et inconvénients.
Q & A
Quelle est la première mention de la transmission sans fil de l'énergie ?
-La première mention de la transmission sans fil de l'énergie a été publiée par Nikola Tesla en 1898.
Quel était le but initial de la transmission sans fil de l'énergie selon Tesla ?
-Selon Tesla, le but initial de la transmission sans fil de l'énergie était de contribuer à des relations pacifiques universelles par l'élimination de la distance.
Comment la capacité électronique moderne influence-t-elle la transmission sans fil de l'énergie ?
-La capacité électronique moderne rend la transmission sans fil de l'énergie beaucoup plus pratique grâce à l'amélioration de la technologie.
Quel est le facteur clé dans la transmission sans fil de l'énergie ?
-Le facteur clé dans la transmission sans fil de l'énergie est le coefficient de couplage, qui détermine la quantité de flux magnétique généré dans le bobinage primaire et qui parvient au bobinage secondaire.
Comment les circuits résonnants améliorent-ils la transmission sans fil de l'énergie ?
-Les circuits résonnants améliorent la transmission sans fil de l'énergie en augmentant le coefficient de couplage entre les bobines et en réduisant l'impédance totale du circuit.
Quelle est la définition du facteur de qualité (Q) dans un circuit résonnant ?
-Le facteur de qualité (Q) dans un circuit résonnant est défini comme le rapport entre l'énergie réactive et l'énergie réelle, ce qui indique l'efficacité énergétique du circuit.
Quels sont les défis dans la transmission sans fil de l'énergie ?
-Les défis dans la transmission sans fil de l'énergie incluent la distance, qui affecte le coefficient de couplage, les pertes dues à la résistance parasitaire, et la gestion de la puissance apparente.
Comment l'efficacité de la transmission sans fil de l'énergie est-elle définie ?
-L'efficacité de la transmission sans fil de l'énergie est définie comme le rapport entre la puissance de sortie et la puissance totale entrante, qui inclut les pertes dues aux résistances parasitaires.
Quels sont les avantages de l'utilisation de l'inductance mutuelle dans un modèle de transmission sans fil de l'énergie ?
-L'utilisation de l'inductance mutuelle permet de modéliser la dépendance du courant secondaire en fonction du courant primaire, ce qui simplifie l'analyse et la compréhension du transfert d'énergie.
Quels sont les éléments à prendre en compte pour optimiser la transmission sans fil de l'énergie ?
-Pour optimiser la transmission sans fil de l'énergie, il est important de réduire les pertes dues à la résistance, d'utiliser des condensateurs à faible ESR (résistance série équivalente), et d'adapter la configuration du circuit en fonction de la résistance de charge.
Comment la simulation peut-elle aider dans l'analyse de la transmission sans fil de l'énergie ?
-La simulation peut aider à comprendre le comportement du circuit sous différentes conditions, à identifier les points d'optimisation et à prédire les performances du système en fonction des différentes configurations et paramètres.
Outlines
🔌 Présentation du transfert de puissance sans fil
Sabine Yaakov introduit le concept de transfert de puissance sans fil, une idée ancienne popularisée par Nikola Tesla en 1898. Il a proposé un système de bobine primaire, de condensateur et de bobine secondaire pour créer une résonance et transférer de l'énergie. Plus tard, en 1921, un article a suggéré une expérience de transfert de puissance sans fil à l'aide d'un transformateur. Aujourd'hui, avec les avancées électroniques, le transfert de puissance sans fil est plus pratique. Tesla voyait cette technologie comme un moyen d'unifier la distance et promouvoir des relations pacifiques universelles.
🔗 Principes du transfert de puissance sans fil
Le transfert de puissance sans fil repose sur le concept de couplage entre deux bobines. L'énergie est transférée par le flux magnétique créé par une bobine primaire alimentée en AC. Le couplage efficace est déterminé par le coefficient de couplage, qui est une mesure de la quantité de flux magnétique atteignant la bobine secondaire. Les modèles de mutualité inductrice et de transformateur sont utilisés pour modéliser le système. Le but est de transférer autant de puissance que possible de manière efficace, en tenant compte des pertes dues à la résistance parasitaire et de l'importance de réduire la puissance apparente pour minimiser les pertes et les besoins en composants réactifs.
🎵 Circuits résonants et facteur de qualité (Q)
Les circuits résonants série et parallèle sont essentiels pour améliorer le couplage entre les bobines. Ils permettent de réduire l'impédance totale du circuit en résonance, permettant ainsi un transfert de puissance plus efficace. Le facteur de qualité (Q) est un indicateur de l'efficacité énergétique du circuit; un Q élevé signifie une forme sinusoïdale du courant, ce qui est souhaitable pour la commutaison de courant zéro. Cependant, un Q trop élevé peut nécessiter des éléments réactifs plus grands et augmenter les pertes. Les paramètres clés comme la fréquence de résonance, l'impédance caractéristique et le Q sont discutés, ainsi que leur importance pour le transfert de puissance sans fil.
🛠️ Simulation et efficacité du transfert de puissance sans fil
Pour comprendre le comportement du transfert de puissance sans fil, des simulations sont effectuées avec des circuits modèles. Les simulations AC et en temps réel sont utilisées pour observer les performances du système sous différentes conditions. Les résultats montrent que la fréquence de résonance et l'efficacité du transfert de puissance peuvent varier en fonction des composants et de leur configuration. L'efficacité est mesurée en comparant la puissance à la sortie avec la puissance fournie à l'entrée, en tenant compte des pertes dues à la résistance parasitaire.
🔍 Analyse et ajustement des composants pour l'optimisation
L'analyse des simulations révèle que la résonance et l'efficacité du transfert de puissance sans fil sont influencées par l'interaction entre les composants du circuit. L'ajustement des valeurs des composants, tels que les bobines et les condensateurs, est essentiel pour atteindre une résonance optimale et une efficacité maximale. Il est également important de considérer la résistance de charge et de s'assurer que la configuration du circuit est adaptée au type de charge, comme une batterie, pour obtenir les meilleurs résultats.
🔄 Configurations de résonance pour le transfert de puissance sans fil
Il existe différentes configurations de résonance possibles pour le transfert de puissance sans fil, notamment série et parallèle à l'entrée et à la sortie. Chaque configuration présente des avantages et inconvénients en termes de puissance apparente, de courant et de contrôle. Par exemple, une résonance série à l'entrée peut générer une forte puissance apparente et un fort courant, tandis qu'une résonance parallèle à la sortie peut réduire le courant qui passe à travers les composants. Le choix de la configuration dépend des exigences spécifiques de l'application.
🛑 Conclusion et amélioration du transfert de puissance sans fil
La présentation conclut en identifiant les défis et les opportunités associés au transfert de puissance sans fil. Il est important de sélectionner les composants et la configuration du circuit en fonction des besoins spécifiques pour obtenir une efficacité et une performance optimales. Des méthodes pour améliorer le couplage et augmenter le coefficient de couplage, tels que l'utilisation d'éléments de ferrite, sont discutées. Ces méthodes peuvent aider à optimiser le transfert de puissance et à surmonter les défis techniques associés.
Mindmap
Keywords
💡Transfert de puissance sans fil
💡Nikola Tesla
💡Boucle primaire et secondaire
💡Coefficient de couplage
💡Résonneurs
💡Fréquence de résonance
💡Impédance caractéristique
💡Facteur de qualité (Q)
💡Perte de puissance
💡Éléments réactifs
💡Topologie de circuit
Highlights
L'idée de transfert de puissance sans fil n'est pas nouvelle, et la première indication de cette idée a été publiée par Nikola Tesla en 1898.
Le concept de transfert de puissance sans fil a été exploré et publié dans un journal pratique en 1921, montrant comment construire un système de transfert de puissance sans fil.
La capacité électronique moderne rend le transfert de puissance sans fil beaucoup plus pratique aujourd'hui que par le passé.
Le couplage entre les bobines est un facteur clé dans le transfert de puissance sans fil, déterminant la quantité de flux magnétique qui atteint la bobine secondaire.
La coefficient de couplage est une mesure de l'efficacité de la transfert de puissance, et il est affecté par la distance entre les bobines.
Les pertes dues à la résistance parasite et la puissance apparente sont des défis dans le transfert de puissance sans fil.
Les circuits résonants sont utilisés pour améliorer le couplage entre les bobines dans le transfert de puissance sans fil.
Le facteur de qualité (Q) est un paramètre très important dans les circuits de transfert de puissance sans fil, déterminant le rapport entre l'énergie réactive et l'énergie réelle.
Pour améliorer l'efficacité du transfert de puissance sans fil, il est important de réduire les pertes dues à la résistance parasite et d'utiliser des composants à faible ESR (résistance série équivalente).
Les simulations montrent que la fréquence de résonance et l'efficacité du transfert de puissance sans fil varient en fonction de la valeur des composants et de la résistance de charge.
L'efficacité du transfert de puissance sans fil dépend de la capacité à fournir une grande quantité de courant à la charge, ce qui nécessite un ajustement précis des composants.
Il est crucial de sélectionner la bonne fréquence de resonance pour maximiser l'efficacité du transfert de puissance sans fil.
La conception des circuits de transfert de puissance sans fil doit tenir compte de l'interaction entre les composants et de la complexité du système.
Des méthodes pratiques pour améliorer le couplage et augmenter le coefficient de couplage incluent l'utilisation d'éléments de ferrite pour canaliser les lignes de flux.
Les configurations de circuits comme les inverters résonants en push-pull parallèles sont utiles pour générer des courants résonants élevés sans surcharger les transistors.
L'utilisation de matériaux ferrimagnétiques peut augmenter le couplage entre les bobines et améliorer l'efficacité du transfert de puissance sans fil.
La présentation conclut en soulignant l'importance de l'adaptation des configurations de circuits et des composants pour répondre aux besoins spécifiques de chaque application de transfert de puissance sans fil.
Transcripts
hi I'm Sabine Yaakov this presentation
is entitled a primer to wireless power
transfer now the idea of wireless power
transfer is not new actually the first
indication of such an idea has been
published by Nikola Tesla in 1898 about
120 years ago and here it is if there's
a primary coil this is a capacitor for
actually creating your resonance here
this is a generator it's a secondary
coil and these are the output terminals
actually this was for it through
periodic a purpose for healing people
this has been very popular at that time
now later on this idea was actually
explored and here is a suggestion for an
experiment this is in a do-it-yourself
a journal of practical early electrics
and here they suggest how to build a
wireless power transfer this was
published in 1921
and here we have a transformer this is
the AC live this sparker generate pulses
high current pulses that go through this
resonant circuit and then we have the
secondary coil and lo and behold you
have a lamp which is connected and it'll
light when this will be in operation but
this is really not new however today of
course the electronics capabilities make
it much more practical now for Tesla the
idea of wireless power transfer was not
just a technology it was sort of faith
ideology because he was concerned about
universal peaceful relations and he
believed that this could be achieved by
an elation of distance and to achieve
this wonder alike
city is the one and only means okay well
this is a really very realistic and
unfortunately I don't think it
materialized as yet maybe in the future
now let's go back to ground this is a
very simple presentation of the wireless
power transfer we have a primary coil
which is excited by say an AC source if
the result there is a current here and
the magnetic flux is created and it's
getting all over the place now if I
teach me to put another coil close to it
then part of this flux k fraction will
enter this coil and will generate a
voltage and by this we'll get the
wireless power transfer because we have
power from here going through here to
here so okay it is really a very key
factor here this is the coupling
coefficient this is how much of the
total flux are generated in the primary
is actually reaching the secondary so if
we have a cake fraction at the secondary
and if the turns ratio is n 2 here and n
1 here we are going to get this voltage
ratio K times n2 to n1 which can be also
expressed as a square root of n 2 over L
1 obviously K is always smaller than 1
in a pro Chuan but it's really never 1
because there's always some flux which
is escaping
even if in a transformer which is wound
on a magnetic or ferrite core now they
wait to model a system like this
actually can go two ways one is use this
mutual inductance concept we have two
inductors
which are coupled here or we can use a
transformer record
diction here we have a transformer this
is a model of a transformer we have a
leakage at the primary a leakage at the
secondary this is the primary inductance
and this is now ideal transformer that
just accounts for the transfer ratio
between the voltage and the current so
there are actually two ways to go and in
fact in one occasion it would be easier
or better to use one model and in some
other applications or analysis it will
be easier to use this one so if we have
this mutual inductance between two coils
then this implies that at the primary
you have an inductor l1 is the original
inductor and then you have a dependent
voltage source which depends on the
current on the secondary this is the
current in the secondary with the mutual
inductance value here and the same thing
goes for the secondary you have any
dependent voltage source the magnitude
of which is J Omega M is the coupling
coefficient that I 1 if the current here
now am this coupling coefficient again
is a function of the coupling
coefficient this is most important
parameter in this situation and square
root of l1 times l2 now in the case of a
transformer and now I'm talking about a
one-to-one transformer because in many
application l1 and l2 are the same type
of the coil for inductors so for n equal
to 1 I can eliminate the ideal
transformer here because it's a
one-to-one and what I'm left with is the
two lesions and the inductance the
common inductance now this is reflected
to the primary then the leakage
inductance is l1 times 1 minus K change
the coupling coefficient if case 1 this
is the ideal case there is no
leakage and all that we see is this
common inductor okay we won and we see
l1 now is Cain becoming smaller and
smaller we see here larger and larger
leakage inductances and this inductor
however becomes smaller and smaller and
smaller see K times L 1 so if K is a
point 1 then we are left with a small
inductance here I in the case of a
one-to-one situation with the mutual
inductance we have similarly two
inductors which are the same in this
case and two voltage sources which again
are dependent on the current of the
other side so here it is here and here
it's a function of y1 so what's the
objective of wireless power transfer
trust before we like to transfer as much
power as we can this is of course the
purpose of the whole thing
and another one which is the key factor
in the efficiency like they do it that
it is highly efficient process as
possible now what are the problems that
are involved first of all the distance
small larger distance caused a small
coupling coefficient and therefore you
get only a fraction of the flux and
therefore you have somehow to handle the
fact that a lot of the flux is actually
being lost there is the issue of
parasitic resistances which are causing
losses and reducing the efficiency and
also there is the question of the large
apparent power this is the product of
voltage times M now you'd like this
product to be very close to the real
power because if this apparent power is
large it has many implications one of
them being the fact that you need larger
reactive element that is inductors and
capacitors because they have now to
store more energy another implication is
that you get a higher losses since
higher current will
pass through the swords so you'd like to
keep the apparent power as small as
possible now let me talk a little bit
about resonant circuits because we are
going to use this approach in order to
improve the coupling between the coils
so in this case we are talking about two
possible resonant circuits one is the
serious one here's the serious month and
see an artist's load positive resistance
if there is no load and here's the
parallel one LC in vomit and this is the
current source now there are key
parameters that we need to address the
circular resonant frequency 1 over
square root of LC the resonant frequency
Omega times 2 pi the characteristic
impedance the square root of L over C
now another key factor which is very
very important in the wireless power
transfer is the cube that is the quality
factor now for the series circuit its
defined as Omega L over R now notice
this is really the ratio between the
apparent of energy or reactive energy to
real energy because if you multiply it
by I square here and I square here this
will be the energy stored in the
inductor and the real energy now you'd
like you to be large on the one hand
because you'd like the circuit to have a
sinusoidal waveform this helps zero
voltage switching and some other
features however to logic the Q means
that this energy here is very loud so
you need large reactive element so we
like to keep Q really in a reasonable
range I'll talk about it in a second now
you can express the Q the quality factor
in this ratio 1 over Omega RC or the
characteristic impedance overarm now in
the case of the parallel circuit its
bring one over it will be R over Omega L
and we are over here now in this case in
the series case when R approaches zero
then you have a very high quality factor
in the parallel case when R becomes
infinity then you have a large Q factor
so these are the basic concept of a
series and parlin a regular number now
we can use now the resonant circuit in
order to reduce the total impedance in a
circuit now if we have a branch like
this and we are at resonance that the
total impedance here zero so when we
have here resonance we are going to see
from the source only R because these two
cancel each other the impedances okay
this one plus and minus and the same
thing goes here at resonance we're going
to see only R so we are going to use
this to our advantage in the case of the
wireless power transfer by adding
capacitance here now what would you like
to do that because otherwise we have an
inductance and this is actually limiting
the current that will be passing to the
output so by putting this inductor this
capacitor here I can and when working in
the proper frequency I can reduce the
convenience of this branch and allow
more current to go to the load so you
can see it over here and you can see it
here we had here this case two capacitor
notice that the resonant circuit are not
very clear here I mean I can talk about
these two but then we have this
inductance which is also currently
playing some role we'll talk about this
a little bit late
so in a very simplistic way you can say
that if you put a capacitor in you work
at resonance then you're going to see in
in this presentation of the transformer
a inductor K times L and RL and
obviously now part of the current we see
now it here is passing through here and
you are losing some of the primary
current so as K is becoming smaller and
smaller we have problem in transferring
of power to the load okay so we need a
high current same thing goes in this
representation of the mutual inductance
obviously here we have K the larger the
smaller decay the smaller is this
dependent voltage source and less power
will be delivered to the load so what
about the efficiency efficiency is the
output power over the total power that
coming from the input and the input has
to supply the output power plus all the
losses now in this circuit in this
equivalent circuit the losses due to
parasitic resistances and this include
first twofold the driver is that the
MOSFET are the asan resistors resistors
the induct day of positive resistance of
the inductor coils ESR equivalent series
resistance of the capacitor and the same
thing goes there
so the efficiency will be the ratio
between the real power I n is a
normalized I to 2 I 1 and divided by the
total actually power which is the this
is the contribution or the loss due to
the positive resistance of primary this
is the secondary and here is the so in
order to help or get high efficiency
you'd like to reduce
our L first of all and this could be
done by using whips wire so that the RAC
as it is called that is the resistance
at high frequency will still be very
acceptable you need a low ESR capacitors
and of course the driver should have a
lower these on transistors so that RS
this equivalent resistance or below let
me just point out that this circuit
although it looks very sort of it's
simple it is really complex because
there are many interactions here there
already mentioned this inductor here
plays a role in the resonance of the
secondary in primary and therefore a
complete analytical study of the circuit
is really complicated and it leads to
rather long equations this is not the
purpose of this presentation which is a
an intuitive look at the whole issue of
wireless power transfer just to get the
feeling of what's all about here let's
consider two cases let's start with this
gift this assume that me already is very
high and that representing it by an open
circuit well here you see we have
resonance now here there's nothing here
so the resonant frequency will be C 1
and the total which is by the way the
original primary inductance because this
Plus this is L ok and if you drive the
circuit at this resonant frequency you
get a very high voltage again more than
one I mean the ratio will be much more
than one and then if you have a high
resistance here you get quite a bit of
power so this is another this is another
mode of operation having a large
resistance here if the resistance
however is very small and I'm
representing it by short notice that we
have now here e so the vane Network
- super resonant Network and plus
another network it's a rather it's not a
simple circuit here and of course there
are many resonant Peaks that you can
detect it various frequencies so in
order to simplify the understanding of
this circuit I'm going to do some
simulation and present some of the
results just to show the behavior of the
circuit under various conditions and the
circuit I'm going to simulate is this
circuit two inductors which are equal
they're 86 microhenry with two capacitor
which I'm going to change later on there
is the AC source and I'm going to do two
type of analysis and AC analysis for
this you need an AC source and I'm going
to do also a time domain analysis a
transient allowances for this you need a
transient source of time domain source
and I've interviewed the people just to
fill it with a square wave if you would
do with the driver in a practical
circuit if the capacitor is not twenty
nine point forty five the resonant here
is 100 kilohertz the Karthik impedance
of this circuit is 64 oh and just for
the sake of the numerical analysis
because simulation made a miracle I'm
assuming a 10 million paralytic
resistance in the primary and at a
second so I'm going to do actually two
type of simulation one assuming that K
the coupling coefficient is 0.5 so this
will be sort of the equivalent circuit
that we considered is that point one
should be L here - and this is 0.5 and
then I'm going to use two capacitor 1 C
this is the capacitor dead for 100
kilohertz as the resonance for the whole
inductor and to see because to see
half L is giving a resonant in here okay
and then I'm going also to run a
simulation for K point one and we have
then this is point one and of the
original primary or common inductor and
this is actually approaching already L
okay so this is very small and these are
very large and I'm going to run it for
the 29 nano farad capacitor
okay here's the schematics of this
circuit there we are going to run let me
zoom on it so we can see it better here
we see the two inductors which are
coupled we have here the K linear the
element that is coupling L 1 and L 2
this is L 1 and L 2 there are 86 micro
Henry coupling coefficient is 500 merely
that it's point 5 we have here two
sources one is an AC source it is before
an AC and all these small signal
analysis and then we have a pulse type
source it's a plus/minus amplitude and
with some rise time of 0.1 microsecond
and the pulse width and period are
adjusted so that the frequency will be
like in this Ferrari Qin see here it's
defined it 100 kilo Hertz we can change
it and the duty cycle will be one half
okay so the two capacitors are defined
by parameters this is just an initial
very we're going to change it and then
we have a resistor this is the load
resistor which is also defined here
before we're going to change it right
now and we have some parasitic
resistance here and here I've just
specified it to be
the milliohm so let's change this one to
say one owned to begin with and let's
see let's run the AC simulation let's
see what is actually if the setting here
a 10 kilo her to 300 kilohertz 1000
point three decades or have a good
resolution and we have a parameter
switch of C and I'm going to do a value
list and so these are two values this is
the twenty nine point four five a nanner
and sixty eight point nine and these
correspond the twenty nine is for this
resonance and the larger capacitor is
for the model in which for a coupling
coefficient of 0.5 we are going to have
the leakage it will be 0.5 of the
inductor so therefore we need a
capacitor which is twice as large okay
so let's start with this AC analysis let
me first of all have a look at the first
capacitor this is the twenty nine point
forty five nano and I have set up scales
as follows we have the inductor the
input current inductor current we had
the output voltage this is across the
load we have the power of the load to
the power and we have actually the
efficiency which is the power on the
load divided by the power that comes off
are the source okay now the now this is
for let's remember one own load and the
capacitor is a twenty nine so that the
resonant is between supposed to be
between the total inductance and
capacitor what we observe here is really
much different to begin with we see two
peaks one it this will be one a little
bit over 140 kilo Hertz and this one is
a little bit over 80 kilo Hertz there
are two pics here this is the say the
output and of course you see the current
at the input okay so we had sort of a
split phenomenon in which the supposedly
one resonance is split into two and
again this is because there is an
interaction between all the components
in the system okay and if we look at the
output we see that we have a fairly high
output remember I didn't mention it but
the excitation is one volt
okay one bull so we have a one volt
output is about one volt and the power
is a little bit less I don't know why
supposed to be one what maybe there is a
difference here between peak and RMS
values I am not so sure so then we look
here at a this is sort of an efficiency
we see the efficiency is fairly high
remember we have pathetic resistances of
50 milli ohms below this one ohm so
relatively the losses are not that high
interesting enough we have another peak
here for high efficiency and this pig
indeed is at 100 kilohertz
okay but this peak is at the point this
is virtually no output over let me say
that the output is very very small okay
and
then the input is small and the ratio
between them and is pretty good but this
is not a useful point so the conclusion
here is that for one owned with this
capacitor we have two peaks and
frequencies which are different from
this one kilo Hertz and we get a pretty
good transfer function with this 0.5
coupling coefficient let me now go back
and have a look at the situation for the
fifty eight point nine nine afraid okay
I'm selecting at this value and well the
picture is not much different except
that the old frequencies actually
shifted downward lo and behold we have
now a peak and 100 kilohertz there's a
peak here we have a a peak current at
the input we have a peak output voltage
and then we have a good efficiency but
then we have another peak at a much
lower frequency this is supposed to be
the b-17 above sixty close to 60 akira
hurt there's another peak and for this
peak we get also a pretty good result
however this high efficiency is really
useless because at this point we just
don't have any output and of course
there is no input okay so this is the
situation with the capacitor which is
twice as big so that the resonant is
between the capacitor and a half the
inductor half decide the value of the
inductor let me now move to the case of
a different resistor and let me put this
month to be like
27 oh you remember that the
characteristic impedance of this circuit
calculated just by this inductor and
this capacitor which really doesn't tell
the whole story but if you use these to
calculate the characteristic impedance
it comes out to be 54 so we are now at a
value which is like half so wailing
supposedly having formerly a queue of
two okay so let's run this one now and
I'll pick the first one and wow we have
a whole different story here and you can
see the sort of q2 is causing this
circuit to look very flat this is the
efficiency it's very high here but again
one has to look at the output but
unfortunately the output as far as the
power goes is not very good indeed we do
get a fairly high output voltage about 1
that is we have actually again above the
input but since the resistor now is much
larger it's 27 as compared to 1 then
obviously this square over R which is
the power is now much lower and indeed
we having only like 50 millivolts so we
have a problem here in terms of the
amount of power that we are delivering
but not again that this flat behavior
that kind of suggests low Q circuit now
let me now go back and change the
resistance even further let's make it
let's say 100 ohm and run it again and
we'll choose again this 1929 Nana all
right well we have a different story
here we have one resonant one resident
and it is at
100 kilohertz this is because we have
now our rhythm and this is like an open
circuit at the output which are shown
earlier one of the slides so we really
have a resonant between the whole
conductor and the capacitor and we know
this should be at 100 kilohertz and
indeed it is we have a output which is
fairly high because the Q is high and
this is now like a parallel circuit
partially and we have a higher voltage
but still the amount of power that we
get out is not very much is only 120 250
a millivolt at this point however the
efficiency is furthering high because
now we have a much larger load resistor
as compared to the 50 million of the
parasitics then of course the efficiency
will be high okay that's do even larger
make a larger registered say 1 kilo ohm
and then of course we are just about a D
and this is indeed like a open circuit
the Q is much higher now like a parallel
circuit and the output voltage is much
higher see that we get a much higher
voltage we do have now a fairly high
output power this is above 1 watt and
this is because the voltage is 3 hi and
so that this 40 squared less
thirtysomething divided by 1 kilo ohm is
again 1 what now the input current in
this case is not that high it's about 1
ampere it's a little bit more than one
end
and one amp would be the power required
for one one and this is a little bit
higher so we see that the VA the
apparent power is is not that high as
far as the input source is concerned so
what really this teaches us that the
situation is really complex and you have
to look at your particular load resistor
and match it to the configuration of the
circuit to get an optimum result
let me move now to the case of the 200
mini for the coupling coefficient that
is point to a K of point two and let's
start off with say again and one ohm
here and we see pretty much similar
situation maybe the frequencies that are
a little bit different you see these two
peaks are a closer one to another again
we have this strange high efficiency
point with no output power but the
situation is not very different and just
for a check
let's have a look at say 10 10 ohms here
what is happening okay now obviously
this total apparent quality factor is
worse these two peaks are sort of
getting closer and as you see here the
minimum now is not zero it's going up
and we get the same gain just about the
same gain however since the load
resistor is much higher to ten times
higher than the power is about ten times
lower so we get good efficiency but the
power output is low so the conclusion
here again is that you really have to
tailor the load to the particular
circuit and there's no one solution for
all loads let us now look at the
a transient responded if the time domain
remember we have here a square wave or
excitation so I'm moving to a transient
setting and let's see what is the
setting here we are running it for five
millisecond collecting data after 4.95
millisecond this is the resolution and
the parametric's which is again these
two capacitors I'm now back at the AC
the result of the AC analysis and the
reason is that I like to select the
operating point so let's start with this
100 kilohertz which is right here this
doesn't seem to be the optimum point but
this let's just see what's going on here
and now running it and this is for a
frequency of 100 kilohertz
okay let's choose again the twenty nine
point forty five nano farad and here it
is and this is now the output voltage
and you can see if you see a nice
sinusoidal waveform this is the
excitation this is the current of the
input and here we have the actual power
this is the product of the current times
the voltage on the load resistor okay
and average so this is now the power
which is not very good okay so let's go
back to the AC analysis again and run
the same one this is the AC analysis
again and let's run the 100 ohm case
again and the purpose of which would be
to find the frequency okay so I'm
turning on the cursor and let's have a
look at here look at
frequency and this is 110 point 63 let's
say 111 actually 111 kilo Hertz this is
this frequency okay so I'm returning now
to the circuit running a transient
analysis but changing it to 111 K and
running okay I'll choose the game this
29 rod and here what it is so we see
that the power is now higher we have an
ice on it so that waveform because of
the nice nicer Q so here we can examine
the actually time domain waveform of
this okay let's go back now to some real
circuits and see how we actually
implement this wireless power transfer
now this would be a very simple
realization we have here a half bridge
driven of course out with 180 degree
phase the phase shifted the pulses here
is the primary this is the secondary we
are talking about this resonant circuit
and we know that there are some
implication and questions but let's
leave these aside just look at the
circuit itself we have now a rectifier
and we have a smoothing or filter
capacitor plus RL bridge represent the
load now in the analysis we have been
using any resistor so it be useful to
replace this this is a nonlinear circuit
that you cannot use in AC analysis it
will be useful to replace it by an
equivalent and encourage our AC resistor
that is I like to replace this whole
thing by some resistor such that the
circuit will behave the same as far as
AC analysis goes now the way to do it
has been demonstrated many years ago by
professor
Steigerwald and the idea behind this for
presentation is to equate the power that
is you like to select a RAC such that
the power delivered to it'll consume
dissipated by it is equivalent to the
power dissipated by this DC current
through this RL load so here is the AC
side power this is the unknown yet
resistor this is the DC part okay now we
can now Express IDC as a function of I
RMS through the pic and the average
value 2 over pi and then from which we
get this RAC is it's about point eight
pi square is about 10 so it's point
eight correct so you can replace this
whole thing by by this and this is very
helpful when analyzing or simulating in
fact the circuit now there are some
other situations which are practical for
example if you are charging a battery
then you cannot represent this load by
airport this store it is a fixed voltage
and you may change the current so again
by equating these two power on the AC
power the DC we get this our AC
expression and in this case it is a
function well you can make it a function
of the DC current charging the battery
or the primary AC current so it's a
nonlinear resistor depending on the
operating point but for a given
operating point this is the value for a
given say charging of say if it is a
battery for point 4 volts 1 amp then
you'll get 3 point 6 ohm resistor our AC
equivalent attic when you for the
panelists another case is when you feed
the battery with the constant care
so this is a power type of shitload but
then again since you have the current
here and the battery is very similar to
what we had before so you end up with
something very similar as we had before
so this is the way to represent this
nonlinear of rectifier plus load by an
arrays looking now at the bigger picture
it turns out that this case of resonance
resonance at the input and output it's
just a private case of many other not
many but there are other possibilities
we can have a resonant search rather
than the input sir it's written on the
output we can have serious at the input
parlor at output and we have parlour the
input course should answer is it output
and of course Harlan and parlor now
what's the advantage and problem with
any of these connections now when you
have a serious resonant at the input you
have a fairly large apparent power and
you have all the current passing through
the source so the idea son of the
transistor sees all these cards it could
be high so in the output you have this
resistor in series with this resonant
circuit and obviously to get a
reasonable Q our L has to be smaller
than they characteristic impedance so
this leads to fairly low values of R
okay in this case in the second case
this would be suitable for loads which
are represented by a large arm so that
you can get a high Q at the secondary
given a certain value of characteristic
impedance of LHC and this again suffered
from the same thing here we have an
advantage in that we can generate a very
high current in the
resonant Network this here while this
current is circulating here and not seen
by the swords by the way for apartment
circuit this has to be a current source
because if it is a voltage source then
obviously you are imposing a voltage
here and the resonant doesn't take place
here at all so for a parallel resonant
primary unity current source secondary
again we have very serious and here
again we have part and pallet so this
will be helpful to eliminate the high
current through the coil from passing
through the input and here this is be
suitable for a high value of resistance
I mean high value compared to the
towards the convenience of the secondary
it can be concluded that the panel
connection at the input is really
desirable under all cases because it can
generate high current which is locked in
the parlour circuit not passing through
need and for the output it really
depends on the type of flow one way to
do it is to use this network shown here
this is the coil Primerica the input the
output coil and this is the inductor
should be very large and this is sort of
imposing current into this circuit as it
turns out that this circuit is really
not easy to control and also you cannot
very easily control the switching office
under all operating conditions so this
has not been used as far as I know it's
not been very popular another circuit
which is very interesting is a so called
push-pull parallel resonant inverter and
there are two configurations and I'll
start with this one which is the
original one and
being around for many years we have here
a parallel circuit for the resonant
circuit which is sent attempt okay and
then again we have a series resistor
these transistors are operated in 100
degree phase shift so that when this
pulse is high this is low and vice versa
when this voltage is high and this
transistor is conducting so this point
is connected to ground and since we have
the feed here
of the source then we start generating a
sinusoidal waveform of this at this
point they have the side this is ground
and this is the other side as we hit
this point this should be now pulled to
high voltage and clem this to ground and
then of course will start generating
hear a sinusoidal waveform going up like
here and again as you approach 0 will
change the situation and this is beyond
and this appeal so we need of course to
synchronize these two with the waveform
and we are going to have then
interleaving one side the other side etc
over the coil over the inductor we going
to have a sinusoidal waveform because we
have sinusoidal waveform half but they
have 180 degree to one side 100 nigiri
to the other side so we have a
sinusoidal waveform another
configuration is this one in here we
don't have a sensitive if it's not
convenient you don't want to have it we
have these two inductor which are
passing the DC current to this inverter
to power operation is very very similar
we have this sinusoidal waveform
generated as one side right Ron we have
it
other side etc so this is really a very
similar except for the fact that we
don't have this and the tab we paying
for it with two inductors instead now
it's interesting to realize that the
current that is passing through this
inductor hood through these inductor is
primarily DC current there's some ripple
depending on the size of that as large
as it will be the smaller larger will be
a less a smaller will be the ripple and
this this current times the voltage is
in fact just the read power coming off
the source so we have very little AC
current passing through the source and
which is a very desirable same thing
goes for these transistors these
transistors see only this current they
don't see this card this card is not
seen by this transistor arm in the
resonant current so you can build up a
fairly high resonant current without
this transistor passing it which is very
nice they are passing only this current
or this current okay this is the DC
current which are passed through the
transistor transistor do not see the AC
current which could be very high which
is very nice
finally let me say a few words about
ways to enhance our decoupling and to
increase the coupling coefficient and
one method that language has been shot
suggested is to end some ferrite
elements in the construction and this is
just one example there are many examples
that have been published practice here
we have the primary here we have the
secondary now we these are ferrite bars
okay a vector ferromagnetic bars ferrite
and what they do is actually the sort of
channel the flux to this direction
rather than the flux going all the way
to everywhere they are sort of
channeling it so if you place the
secondary coil the receiving coil sort
of around this of course they are bars
here too and just not showing it so
noise to confuse the picture so is this
secondary place over the primary it'll
capture these channel flux lines and
therefore it'll have a coupling
coefficient which is much larger than
you'd have without these apart okay so
this would be one way another way that
you need to put a plate of the
ferromagnetic material underneath and in
fact about okay so it'll lock the flux
in between that is that two different
weight and there of course the many
other ways to do this brings me to the
end of this presentation
hi thank you for your attention I hope
you have found it of interest and that
it will be useful to you in the future
thank you
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