Grade 10 SCIENCE | Gay-Lussac's Law

Ma'am Deah Elmundo
12 May 202215:43

Summary

TLDRThe video script discusses Gay-Lussac's Law, which describes the direct proportionality between pressure and temperature for a given amount of gas at constant volume. The presenter explains the law's formula, ( P1/T1 = P2/T2 ), where P stands for pressure and T for temperature in Kelvin. The importance of using consistent units and converting Celsius to Kelvin for temperature measurements is highlighted. Two problems are solved using the law: one involving a gas cylinder with varying pressures and temperatures, and another concerning the pressure change in a helium-filled balloon with an increase in temperature. The video aims to help viewers understand the relationship between pressure and temperature, emphasizing the need for step-by-step problem-solving and accurate unit conversion.

Takeaways

  • πŸ“š Gay-Lussac's Law is not part of the original video series but was requested by viewers, showing the relationship between pressure and temperature.
  • πŸ”— The law is similar to Charles' Law and is often discussed alongside Boyle's Law, with a link provided for further review.
  • πŸ“ The general form of Gay-Lussac's Law is p1/t1 = p2/t2, where p represents pressure and t represents temperature.
  • πŸ“‰ Subscripts 1 and 2 refer to the initial and final states of a system, which are crucial for problem-solving.
  • πŸ” Units for pressure can vary (e.g., atmospheres, mmHg, kPa), but temperature must be in Kelvin, converting from Celsius if necessary.
  • βš–οΈ Direct proportionality means that if temperature increases, pressure increases, and vice versa, assuming volume and the amount of substance are constant.
  • βœ… The importance of understanding the relationships between pressure and temperature is emphasized for accurate problem-solving.
  • πŸ”’ Problem-solving involves converting temperatures to Kelvin when given in Celsius, and using the correct formula for Gay-Lussac's Law.
  • 🌑️ Example problem: A gas cylinder with an initial pressure and temperature is used to find the new temperature at a different pressure, requiring unit conversion and equation manipulation.
  • 🎈 Another example involves a mylar balloon with helium gas, where the pressure change is calculated given a temperature increase from 22Β°C to 45Β°C.
  • πŸ“ˆ The expected outcome of the second problem is a pressure greater than the initial 107 kilopascals due to the direct relationship between temperature and pressure.
  • πŸ“ The final pressure for the helium balloon is calculated to be 115 kilopascals, demonstrating the application of Gay-Lussac's Law in real-world scenarios.

Q & A

  • What is Gay-Lussac's Law?

    -Gay-Lussac's Law relates the pressure and temperature of a gas when the volume and the amount of gas are held constant. It states that the pressure of a gas is directly proportional to its temperature in Kelvin, given by the formula p1/T1 = p2/T2, where p is pressure and T is temperature.

  • How is Gay-Lussac's Law similar to Charles's Law?

    -Both Gay-Lussac's Law and Charles's Law describe the relationship between pressure and temperature in a gas. However, Charles's Law specifically deals with the volume and temperature relationship at constant pressure, while Gay-Lussac's Law focuses on the pressure and temperature relationship at constant volume.

  • What are the units typically used for pressure in problems related to Gay-Lussac's Law?

    -Pressure can be expressed in various units such as atmospheres, millibars, torr (millimeter mercury), or kilopascals. The specific unit used is not critical as long as the problem and the answer use the same unit.

  • How do you convert Celsius to Kelvin?

    -To convert a temperature from Celsius to Kelvin, you add 273 to the Celsius temperature. For example, 25 degrees Celsius is equivalent to 298 Kelvin (25 + 273 = 298 K).

  • What does it mean for pressure and temperature to be directly proportional?

    -When pressure and temperature are directly proportional, it means that if the temperature increases, the pressure also increases, and if the temperature decreases, the pressure decreases as well. This relationship holds true as long as the volume and the amount of gas are constant.

  • What is the general form of the equation used in Gay-Lussac's Law?

    -The general form of the equation used in Gay-Lussac's Law is p1/T1 = p2/T2, where p1 and p2 are the initial and final pressures, and T1 and T2 are the initial and final temperatures in Kelvin.

  • How do you solve for the final temperature in the given problem with a gas cylinder?

    -To solve for the final temperature, you first convert the initial temperature from Celsius to Kelvin, then use the initial pressure and the final pressure in the Gay-Lussac's Law equation to find the final temperature in Kelvin. After that, you convert the final temperature back to Celsius.

  • What is the expected change in pressure when the temperature of a gas increases, according to the video?

    -When the temperature of a gas increases, the pressure of the gas is also expected to increase, as they are directly proportional to each other.

  • What is the relationship between the initial and final states in the given helium balloon problem?

    -The relationship between the initial and final states in the helium balloon problem is given by the Gay-Lussac's Law equation, where the initial pressure and temperature are known, and the final pressure is solved for after the temperature increases.

  • How do you calculate the final pressure of helium in the balloon when the temperature changes?

    -You use the initial pressure and temperature to find the final pressure using the Gay-Lussac's Law equation. After substituting the known values into the equation, you solve for the final pressure (p2) by cross-multiplying and simplifying the equation.

  • What is the final pressure of the helium in the balloon when the temperature changes from 22 degrees Celsius to 45 degrees Celsius?

    -The final pressure of the helium in the balloon is 115 kilopascals, calculated using the Gay-Lussac's Law equation with the given initial and final temperatures converted to Kelvin.

Outlines

00:00

πŸ”¬ Introduction to Gay-Lussac's Law

The first paragraph introduces the topic of Gay-Lussac's Law, which describes the relationship between pressure and temperature in a gas. The video aims to clarify this concept, noting its similarity to Charles' Law and its relevance alongside Boyle's Law. The general form of the law is presented as p1/t1 = p2/t2, where p represents pressure and t represents temperature. The importance of using the correct units for pressure and temperature is emphasized, with a reminder to convert Celsius temperatures to Kelvin by adding 273. The direct proportionality between pressure and temperature is highlighted, assuming the volume and the amount of gas remain constant.

05:02

πŸ“š Applying Gay-Lussac's Law to a Problem

The second paragraph delves into applying Gay-Lussac's Law to a specific problem. It involves a gas cylinder with an initial pressure and temperature that is subjected to a change in pressure, with the goal of finding the new temperature. The process includes converting the initial temperature from Celsius to Kelvin, setting up the equation according to the law, and solving for the final temperature. The paragraph emphasizes the need for careful unit conversion and equation manipulation, and it provides a step-by-step approach to ensure accuracy in the calculation.

10:03

🎈 Gay-Lussac's Law and Helium Balloon Pressure

The third paragraph presents a real-world scenario involving a mylar balloon filled with helium, where the pressure changes with an increase in temperature. The problem involves calculating the new pressure of the helium in the balloon when the temperature rises from 22 degrees Celsius to 45 degrees Celsius. The given initial pressure and temperature are converted to Kelvin, and the law's formula is applied to find the final pressure. The calculation process is detailed, leading to the conclusion that the pressure increases from 107 kilopascals to 115 kilopascals, demonstrating the direct relationship between temperature and pressure.

15:04

πŸ“‰ Conclusion and Engagement Invitation

The final paragraph wraps up the discussion by summarizing the key points covered in the video and encouraging viewers to apply the knowledge to understand their modules better. The presenter invites the audience to like, subscribe, and share the video with others. It ends with a friendly farewell, looking forward to the next interaction.

Mindmap

Keywords

πŸ’‘Gay-Lussac's Law

Gay-Lussac's Law, also known as the pressure-temperature law, describes the direct relationship between the pressure and temperature of a gas when the volume and the amount of gas are held constant. In the video, it is used to explain how the pressure of a gas increases with temperature and decreases when the temperature is lowered. It is a fundamental concept in the study of gases and is applied to solve problems related to changes in pressure and temperature.

πŸ’‘Pressure

Pressure is defined as the force exerted per unit area. In the context of the video, it is a key variable in Gay-Lussac's Law and is measured in units such as atmospheres, kilopascals, or millimeters of mercury. The script discusses how pressure changes in response to temperature changes, which is central to understanding the law.

πŸ’‘Temperature

Temperature is a measure of the average kinetic energy of the particles in a substance. The video emphasizes the importance of using the Kelvin scale when applying Gay-Lussac's Law, as it is an absolute temperature scale. The script provides a conversion factor from degrees Celsius to Kelvin, which is necessary for accurate calculations.

πŸ’‘Charles' Law

Charles' Law is mentioned in the video as being similar to Gay-Lussac's Law. It states that the volume of a gas is directly proportional to its temperature when the pressure is held constant. The video suggests reviewing Charles' Law for a deeper understanding of gas laws, indicating its relevance to the theme of the video.

πŸ’‘Boyle's Law

Boyle's Law is another fundamental gas law that is mentioned in the video. It states that the pressure of a gas is inversely proportional to its volume when the temperature is held constant. The video suggests that Boyle's Law, along with Charles' Law, is combined with Gay-Lussac's Law to form a more comprehensive understanding of the behavior of gases.

πŸ’‘Initial State

The initial state refers to the starting conditions of a system, which in the context of the video, includes the initial pressure (p1) and temperature (t1). These values are crucial for applying Gay-Lussac's Law to calculate the final state of the system after changes in temperature or pressure.

πŸ’‘Final State

The final state represents the conditions of a system after changes have occurred. In the video, the final state includes the final pressure (p2) and temperature (t2), which are determined using Gay-Lussac's Law once the initial state and the changes are known.

πŸ’‘Directly Proportional

Directly proportional is a mathematical term used in the video to describe the relationship between pressure and temperature in Gay-Lussac's Law. It means that as one quantity increases, the other quantity increases at a constant rate. This relationship is graphically represented in the video by a graph showing a straight line passing through the origin.

πŸ’‘Kelvin

The Kelvin scale is an absolute temperature scale that is essential for calculations in thermodynamics. The video script emphasizes the need to convert temperatures from degrees Celsius to Kelvin when applying Gay-Lussac's Law. The conversion factor used in the video is 273, which is added to Celsius temperatures to obtain the Kelvin equivalent.

πŸ’‘Conversion Factor

A conversion factor is a number that is used to convert one unit of measurement to another. In the video, the conversion factor of 273 is used to convert Celsius temperatures to Kelvin. This is a critical step in the calculations as it ensures the use of consistent units across the application of Gay-Lussac's Law.

πŸ’‘Problem Solving

Problem solving is a process that involves identifying, analyzing, and solving problems. In the context of the video, problem-solving involves applying Gay-Lussac's Law to determine changes in pressure or temperature given certain initial conditions. The video provides a step-by-step approach to solving such problems, which is central to understanding the practical application of the law.

Highlights

Gay-Lussac's Law discusses the relationship between pressure and temperature in a gas.

The formula for Gay-Lussac's Law is p1/t1 = p2/t2, where p represents pressure and t represents temperature.

Subscripts 1 and 2 in the formula refer to the initial and final states of the gas.

Pressure must be expressed in units of pressure, and temperature must be in Kelvin.

Conversion from Celsius to Kelvin involves adding 273 to the Celsius temperature.

Pressure and temperature are directly proportional as long as the volume and the amount of substance are constant.

If temperature increases, pressure increases, and if temperature decreases, pressure decreases.

The video provides a step-by-step solution to a problem involving a gas cylinder with varying pressure and temperature.

For problems, it's essential to identify initial and final states and follow the given equation.

The video demonstrates converting temperatures from Celsius to Kelvin and back for calculations.

The second problem involves a mylar balloon filled with helium and its pressure change with temperature.

An increase in temperature from 22 to 45 degrees Celsius is expected to result in a higher pressure.

The final calculated pressure of helium in the balloon is 115 kilopascals after a temperature change.

The video emphasizes the importance of step-by-step calculations and understanding the relationships between variables.

Gay-Lussac's Law is similar to Charles's Law, and understanding one can facilitate understanding of the other.

The video includes a link to a discussion about Charles's Law for further understanding.

The video concludes with an encouragement to like, subscribe, and share the content for better comprehension.

Transcripts

play00:00

hello students for today's video i will

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be discussing

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a little about

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what we call gay lussac's law

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so by the way um this is not included in

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the videos that i have originally in my

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youtube account

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because this is not part of the

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milks

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young recent milk snack and judu

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pandemic

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but then there are some people who

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requested

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me to discuss gay losers law

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which as you can see now it shows

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pressure and temperature relationship so

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later on i will explain you manga manga

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about the massive pressure bottom as a

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temperature but then this law is very

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much similar to charles law so

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an audio discussion about charles law i

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have placed the link

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above so you can review it it is

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combined with boyle's laura say union

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so

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let's start so what is the general form

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for gay loose law

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it is very similar with charles law

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so

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it relates pressure and temperature

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using the formula

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p1

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over t1

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is equal to

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p2 over t2 where of course

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p would stand for pressure

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and t would stand for your temperature

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what are the subscripts what do they

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mean

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when we say number one usually this is

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referring

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to the initial state so you'll start

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all right and then

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final

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or you end we have to analyze the

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problem

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initial and final for you to be able to

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answer a problem successfully you need

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to be able to identify the correct given

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and make sure that you follow in the tao

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natin agresa given

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required equation solution answer unless

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you are very confident with your maths

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skills by the mushander

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but if you're not confident then you

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have to do it step by step so going back

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to our equation

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we have p1 over t1 is equal to p2 over

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t2

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pressure

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uh must be expressed in

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of course pressure units but then we are

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not really strict about the units

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because

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the problem uses atmospheres

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automatic atmospheres narinyon is

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pressure

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so my usual

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wedding atmospheres

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wedding

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tour wedding millimeter mercury

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wedding kilo pascals

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hindi time unless the problem states

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answer monarch express at a particular

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unit so temperature detail pet

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because

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your temperature must be in

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kelvin

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there are some cases when your

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temperature given is in degree celsius

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so you have to convert that into kelvin

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now what is our conversion factor

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kelvin temperature can be obtained by

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just adding

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273 to degrees celsius

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some college books they use 273.15

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pero right now in our discussion we will

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just be using 273.

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it's very important that you convert the

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temperature to kelvin

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kung hindi

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kelvin

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all right

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relationships

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according to

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gay

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pressure

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and temperature are

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directly proportional as long as your

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volume and your amount of substance

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they are

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constant

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so what do we mean by directly

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proportional

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pressure temperature you will be

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arriving at a graph

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like this

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it means that if you increase the

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temperature

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your pressure must increase

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similarly if temperature decreases your

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pressure also decreases

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so why am i emphasizing these

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relationships because if you are doing a

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quick calculation you can always go back

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to this

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relationships

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are pressure

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temperature

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that means there is something wrong with

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your

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solving so

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let's start with our problems i will be

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discussing here two problems only

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let me

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write the grace

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given

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required

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equation

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and then solution and answer

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in

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let's read the problem a cylinder of gas

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has a pressure of 4.40 atmospheres at 25

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degrees celsius

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at what temperature in degree celsius

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will it reach a pressure of 6.50

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atmospheres

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if we analyze the problem

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why to say you have the temperature in

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degree celsius

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so naturally if you are listening to

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what i have said a while ago you have to

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convert this to kelvin first

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and then

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kelvin and then you have to convert it

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back to

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degree celsius

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let's do it step by step

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given monetary

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a cylinder of gas has a pressure of 4.40

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atmospheres so

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that would be your p1

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at temperature of

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25 degrees celsius

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we add 270

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then what do we get

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we will be getting 298

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kelvin

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and then

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our final pressure is this

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6.50

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atmosphere

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we are looking for

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a temperature but make sure it must be

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in degree celsius

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let's write the equation here p1 over t1

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is equal to p2 over t2

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um actually

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young manga problems

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now related uh

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charles law and gaylo saxlow major three

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kisha kapagnawawwala

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temperature kasena babasha you have to

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do a lot of rearrangements now if you

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are not really used to deriving

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equations

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so

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for some of my students what i advise is

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to flip the equation

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numerator so in our case i'm missing

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nathan is t2

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okay so

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not in pueden

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equation

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t1 over p1 is equal to t2 over

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p2

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just don't forget that what you do on

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the left you must also do on the right

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para

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indicator

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and so nice nothing other equation let's

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write the solution what is t1 that would

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be 298

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kelvin

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over the p1 that's 440

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atmospheres over t2

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equals

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t2 over

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6.50

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atmospheres

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6.50

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atmospheres both sides

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therefore our t2 would be

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298 kelvin

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times 6.50

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atmospheres over

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4.40

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atmospheres

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atmospheres

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and let's use our

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calculator

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so t2 is equal to

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440

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point

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23

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kelvin

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but wait there's more sabinatin at what

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temperature in

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degree celsius

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the given current temperature in kelvin

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kela and malek some degree celsius to do

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that we subtract 273

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and we will be getting

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167 point

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[Music]

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degrees celsius

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and that would be our

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answer

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quick analysis la sabina

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directly proportional to pressure at sea

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temperature soda

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pressure

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temperature

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okay

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let's move to

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our

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next

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problem

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mylar balloon is filled with helium gas

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to a pressure of 107 kilopascals

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when the temperature is 22 degrees

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celsius

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if the temperature changes to 45 degree

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celsius what will be the pressure of the

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helium in the balloon

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so again the temperature increased from

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22 to 45 so we will be expecting our

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answer to

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be greater than 107 kilo

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pascals

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let me write the given parts of gresa

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pressure one

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is equal to 107

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kilopascals

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t1 is 22 degrees celsius

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if we add 273 there that is

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298 kelvin

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and t2 is 45 degrees celsius we do the

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same add 273

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that would be

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318

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kelvin

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oops 22

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plus 273 is

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i mistaken this is 295 kelvin

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and 45 plus 273 is still 318.

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so anohina hanap

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pressure of the helium

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in the balloon p2

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our formula for galux law is p1 over t1

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is equal to p

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2 over t2

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p2 is already in the numerator so we

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don't need to

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flip the equation we simply substitute

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so 107 kilopascals over

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295 kelvin

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is equal to

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p2

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times

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318

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kelvin

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to simplify we multiply both sides by

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318 kelvin

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so therefore our p2 is equal to 107

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kilopascals

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times

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318 kelvin

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divided by

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295

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kelvin

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so our answer is 115

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kilo

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pascals

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so there you go that's all for our short

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discussion today i hope this has helped

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you

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understand your modules better and

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please like and subscribe my videos if

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you have time or you can also share that

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to your classmates or friends

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so see you next time bye

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Related Tags
Gay-Lussac's LawPressure-TemperatureGas LawsPhysicsScience EducationProblem SolvingCharles LawKelvin ConversionAtmospheresKilopascalsEducational Content