Cara Pintar | Memahami Hukum Kirchoff

Kelas Pintar Indonesia
2 May 202213:00

Summary

TLDRIn this educational video, Nurul, an expert in physics, introduces viewers to the smart class and shares a quick method for solving Kirchhoff's Law problems. She explains the two laws: Kirchhoff's Current Law and Kirchhoff's Voltage Law, which describe the relationships between current and voltage in electrical circuits. Nurul demonstrates how to apply these laws to analyze a circuit with given voltage sources and resistances, guiding through the process of setting up equations and solving for the unknown currents. The video concludes with a clever shortcut for solving such problems efficiently, encouraging viewers to share, subscribe, and stay tuned for more informative content.

Takeaways

  • ๐Ÿ˜€ The script is a tutorial on Kirchhoff's Laws, presented by Nurul, a physics expert.
  • ๐Ÿ”ฌ Kirchhoff's Laws were first stated by German physicist Gustav Robert Kirchhoff.
  • ๐Ÿ“š There are two laws: Kirchhoff's Current Law (KCL) and Kirchhoff's Voltage Law (KVL).
  • ๐Ÿ’ก KCL states that the sum of currents entering a junction equals the sum of currents leaving the junction.
  • ๐Ÿ”‹ KVL states that the sum of electromotive forces (EMFs) and voltage drops around a closed loop equals zero.
  • ๐Ÿ“ An example circuit is used to demonstrate how to apply KCL and KVL to solve for currents in a network.
  • ๐Ÿ”„ The tutorial explains how to determine the direction of loops and currents to apply the laws correctly.
  • ๐Ÿงฎ A step-by-step approach is provided to solve a sample problem using traditional methods.
  • ๐Ÿš€ A shortcut method is introduced to quickly solve Kirchhoff's Law problems using a single formula.
  • ๐Ÿ“‰ The shortcut involves calculating the current through a resistor by using the difference in EMF and voltage drops across resistors.
  • ๐Ÿ“ The tutorial concludes with a reminder to share, subscribe, and turn on notifications for more informative content.

Q & A

  • Who introduced Kirchhoff's laws?

    -Kirchhoff's laws were introduced by the German physicist Gustav Robert Kirchhoff.

  • What do Kirchhoff's laws explain?

    -Kirchhoff's laws explain how to analyze the relationship between current and voltage in an electrical circuit.

  • What is Kirchhoff's first law?

    -Kirchhoff's first law states that the sum of currents entering a junction is equal to the sum of currents leaving the junction.

  • How is Kirchhoff's first law mathematically represented?

    -Mathematically, Kirchhoff's first law can be represented as ฮฃI_in = ฮฃI_out, where I_in represents the currents entering a junction and I_out represents the currents leaving the junction.

  • What is Kirchhoff's second law?

    -Kirchhoff's second law states that the sum of the potential rises and drops around a closed loop in a network is zero.

  • How is Kirchhoff's second law mathematically expressed?

    -Mathematically, Kirchhoff's second law can be expressed as ฮฃE - ฮฃI*R = 0, where E represents the electromotive force (emf), I is the current, and R is the resistance.

  • What are the steps to solve a problem using Kirchhoff's laws?

    -The steps include determining the direction of loops and currents, applying Kirchhoff's first law at junctions to get equations, and applying Kirchhoff's second law around loops to get additional equations, then solving the system of equations.

  • Why is it recommended to choose the direction of loops in a consistent manner?

    -It is recommended to choose the direction of loops consistently, preferably in the same direction, to simplify the calculations and avoid confusion when applying Kirchhoff's laws.

  • What is the significance of the direction of current relative to the loop direction in Kirchhoff's laws?

    -The direction of current relative to the loop direction affects the sign of the voltage drops and rises in the equations. If they are in the same direction, the voltage is positive; if they are opposite, it is negative.

  • How can one quickly solve a problem involving Kirchhoff's laws as demonstrated in the script?

    -A quick method demonstrated in the script involves directly applying a formula derived from Kirchhoff's laws to find the current through a specific resistance without going through multiple steps.

  • What is the shortcut formula mentioned in the script for solving problems related to Kirchhoff's laws?

    -The shortcut formula mentioned in the script is I3 = (E3 - E2*R1 + E3*R2) / (R1 + R2 + R3), which is used to quickly find the current through a 5ฮฉ resistor in a given circuit.

Outlines

00:00

๐Ÿ”ฌ Introduction to Kirchhoff's Laws

The video introduces Nurul, a physics expert, who explains how to understand and solve problems related to Kirchhoff's Laws in electrical circuits. Nurul begins by outlining the two fundamental laws: Kirchhoff's Current Law (KCL) and Kirchhoff's Voltage Law (KVL). KCL states that the sum of currents entering a junction equals the sum of currents leaving the junction, mathematically expressed as ฮฃI_in = ฮฃI_out. KVL asserts that the sum of electromotive forces (emf) and voltage drops around a closed loop equals zero, represented as ฮฃE + ฮฃV_drop = 0. Nurul provides an example circuit and demonstrates how to apply these laws to find the currents and voltages within the circuit.

05:02

๐Ÿงฉ Applying Kirchhoff's Laws to a Circuit

Nurul proceeds to apply Kirchhoff's Laws to a specific circuit example involving two sources and three resistors. She assigns currents I1 and I2 to the branches and sets up equations using KCL at a junction point, resulting in the equation I1 - I2 = I3. Then, using KVL, she formulates equations for two loops in the circuit, incorporating the voltage drops across the resistors. The equations are simplified to find the net voltage changes around each loop, leading to a system of equations that can be solved to determine the currents I1, I2, and I3. The process involves substituting and eliminating variables to solve for the unknowns, ultimately calculating the current flowing through a 5-ohm resistor.

10:03

๐Ÿš€ Quick Method for Solving Kirchhoff's Problems

In the final part of the video, Nurul introduces a shortcut method for solving problems involving Kirchhoff's Laws. She presents a formula that simplifies the process: I3 = (E3 - (I2 * R1 + I1 * R2)) / (R1 + R2 + R3). This formula allows for quick calculation of the current through a resistor by considering the voltage sources and resistances in the circuit. Nurul demonstrates the application of this formula using the values from the example circuit, resulting in a current of 0.5 amperes through the 5-ohm resistor. She emphasizes the efficiency of this method and encourages viewers to share, subscribe, and stay updated with the smart class for more insightful information.

Mindmap

Keywords

๐Ÿ’กKirchhoff's Laws

Kirchhoff's Laws, also known as Kirchhoff's Rules, are fundamental principles in electrical circuit analysis. The video script refers to these laws as the basis for solving electrical circuit problems. The first law, Kirchhoff's Current Law (KCL), states that the total current entering a junction is equal to the total current leaving it. The second law, Kirchhoff's Voltage Law (KVL), asserts that the sum of the potential rises and drops in any closed loop of a network is zero. These laws are central to the video's theme of teaching how to solve electrical circuit problems efficiently.

๐Ÿ’กCircuit Analysis

Circuit analysis is the process of determining the voltages across and currents through the various components of an electrical circuit. The video script provides a tutorial on how to apply Kirchhoff's Laws to analyze electrical circuits. This is a key concept as the video aims to educate viewers on the practical application of these laws to solve real-world circuit problems.

๐Ÿ’กOhm's Law

Ohm's Law is a fundamental principle in electrical engineering that states the relationship between voltage (V), current (I), and resistance (R) in a conductor: V = IR. Although not explicitly mentioned in the script, Ohm's Law is implicitly used in conjunction with Kirchhoff's Laws to solve for unknowns in a circuit. The script's examples of applying Kirchhoff's Laws involve calculating currents and voltages, which would typically involve Ohm's Law.

๐Ÿ’กCurrent

Current is the flow of electric charge through a conductor. In the script, current is denoted by symbols such as I1, I2, and I3, representing different branches of the electrical circuit. The video explains how to calculate these currents using Kirchhoff's Laws, emphasizing the importance of understanding current in circuit analysis.

๐Ÿ’กVoltage

Voltage, often symbolized as V or E, is the electric potential difference between two points. The script discusses voltage sources (E1, E2, E3) and how they contribute to the overall voltage drops and rises within a circuit. Voltage is a critical concept in the video as it is used to apply Kirchhoff's Voltage Law.

๐Ÿ’กResistance

Resistance, symbolized as R, is the opposition to the flow of electric current in a circuit. The script mentions various resistances (R1, R2, R3, R4) and their roles in the circuit. Understanding resistance is essential for applying Ohm's Law and Kirchhoff's Laws to analyze circuits.

๐Ÿ’กLoop

A loop in the context of the video refers to a closed path in an electrical circuit. The script instructs viewers on how to determine the direction of loops and currents, which is crucial for applying Kirchhoff's Voltage Law. Loops are used to create equations that help solve for unknowns in the circuit.

๐Ÿ’กJunction

A junction, as mentioned in the script, is a point where two or more circuit elements meet. Kirchhoff's Current Law is applied at junctions to ensure the conservation of charge, stating that the sum of currents entering a junction equals the sum of currents leaving it. This concept is fundamental to the video's explanation of circuit analysis.

๐Ÿ’กConductor

A conductor is a material that allows the flow of electric current. While not explicitly named in the script, conductors are implied when discussing the flow of current through wires or components in a circuit. The video's focus on circuit analysis inherently involves the behavior of current in conductors.

๐Ÿ’กElectrical Network

An electrical network is a collection of electrical components connected by conductors. The script provides examples of electrical networks, such as circuits with resistors, voltage sources, and current sources. The video's aim is to teach viewers how to analyze these networks using Kirchhoff's Laws.

Highlights

Introduction to Kirchhoff's Laws by Nurul, a physics expert.

Kirchhoff's Laws explained as a method to analyze the relationship between current and voltage in an electrical circuit.

Historical context of Kirchhoff's Laws, first stated by Gustav Robert Kirchhoff.

Explanation of Kirchhoff's First Law, which states the current conservation at a junction.

Mathematical formulation of Kirchhoff's First Law, \( \Sigma I_{\text{in}} = \Sigma I_{\text{out}} \).

Example of applying Kirchhoff's First Law to a simple electrical circuit.

Introduction to Kirchhoff's Second Law, which relates to the sum of electromotive forces and voltage drops in a closed circuit.

Mathematical expression of Kirchhoff's Second Law, \( \Sigma E - \Sigma I \cdot R = 0 \).

Practical approach to solving electrical circuit problems using Kirchhoff's Laws.

Step-by-step guide to determining the direction of loops and currents in a circuit.

How to assign positive or negative values to electromotive forces based on their direction relative to the current.

Application of Kirchhoff's Laws to a circuit with four sources and four resistors.

Solving a specific problem involving a circuit with two voltage sources and a 5ฮฉ resistor.

Using conventional methods to find the current through a 5ฮฉ resistor.

Setting up and solving the equations using Kirchhoff's Laws for two loops in the circuit.

Substitution and elimination method to find the current through the 5ฮฉ resistor using the equations derived.

Final calculation revealing the current through the 5ฮฉ resistor is 0.5 amperes using the conventional method.

Introduction to a quick method to solve Kirchhoff's Law problems with a single formula.

The quick formula for solving the problem, simplifying the process significantly.

Final result using the quick method confirms the current through the 5ฮฉ resistor is 0.5 amperes, matching the conventional method.

Encouragement to share, subscribe, and ring the bell for more informative content from the Smart Class.

Transcripts

play00:00

Halo

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Halo

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[Musik]

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sahabat pintar Apakah kalian masih

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terkendala dalam mengerjakan soal Hukum

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Kirchoff

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perkenalkan saya Nurul buru ahli fisika

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dari kelas pintar Disini saya akan

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berbagi cara pintar untuk memahami

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konsep materi fisika dan menyelesaikan

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berbagai persoalan yang terkait dengan

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mata pelajaran ini dan kali ini saya

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akan berbagi cara cepat untuk

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menyelesaikan persoalan hukum Kirchoff

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Hukum Kirchoff pertama kali dikemukakan

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oleh ahli fisika Jerman yang bernama

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Gustav Robert kirchhoff pada tahun 1824

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sampai 1887 Hukum Kirchoff ini merupakan

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hukum yang menjelaskan Bagaimana cara

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menganalisis hubungan antara arus dan

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tegangan Dalam suatu rangkaian listrik

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Ucok ini ada dua ya sahabat kelas

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tingkat yang pertama hukum 1 Kirchoff

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dan yang kedua hukum 2 Kirchoff i

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Hai

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hukum 1 Kirchoff mengatakan bahwa jumlah

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arus yang masuk ke titik cabang

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sama dengan jumlah arus yang keluar dari

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titik cabang

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Hai secara matematis dapat dituliskan

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dengan persamaan berikut siknai masuk =

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Sigma yg keluar

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Berikut adalah contoh kasus rangkaian

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listrik ya di sini adalah titik

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cabangnya kemudian I1 dan I2 ini

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merupakan arus yang masuk ke titik

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cabang kemudian tiga q4 batin 5

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merupakan arus yang keluar dari titik

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cabang sehingga menurut hukum 1 Kirchoff

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bersamaan yang dihasilkan dari gambar

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ini adalah I1 ditambahi 2 = i3 ditambah

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T4 ditambah i5

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Kemudian yang kedua adalah hukum 2

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Kirchoff

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hukum 2 Kirchoff mengatakan bahwa hasil

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penjumlahan GGL dan penurunan tegangan

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sepanjang rangkaian tertutup sama dengan

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nol atau secara matematis dapat

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dituliskan dengan rumus Sigma eh

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ditambah sik tindikan di R = 0 di sini

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ada sebuah rangkaian yang memiliki empat

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GGL yaitu E1 E2 E3 dan ke-4 serta

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memiliki empat hambatan R1 R2 R3 dan R4

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dan mengalir Arus sebesar i pada

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rangkaian ini bagaimana cara

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menyelesaikan persoalan ini caranya ada

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tiga langkah pengerjaan yang pertama

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tentukan arah loop dan arah arus ini

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ditentukan bebas Tetapi lebih baik

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searah untuk memudahkan pekerjaan kita

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yang kedua Jika lupa bertemu dengan

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kutub positif maka eh akan bernilai

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positif jika lu bernilai bertemu dengan

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kutub negatif maka e akan bernilai

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negatif jika arah loop dan arus searah

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maka arus bernilai positif

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jika arah loop dan arus berlawanan maka

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arus menilai negatif

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Hai

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sehingga untuk penyelesaian kasus ini

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adalah S1 dikurangi E2 ditambah e3q

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tambah 4 ditambah Idi kali R1 ditambah

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R2 ditempuh Ertiga ditambah empat ini

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sama dengan nol

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Hai

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Nah langsung saja kita ke contoh soalnya

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perhatikan rangkaian listrik berikut

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di sini ada rangkaian listrik yang

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memiliki dua truk kemudian pertanyaannya

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adalah Berapa besar kuat arus pada

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hambatan

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5om berarti yang ditanyakan adalah harus

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yang ada di hambatan 5om Mari kita

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kerjakan dengan cara yang biasa terlebih

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dahulu

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pertama kita misalkan arus yang mengalir

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di sebelah kiri itu adalah I1

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kemudian arus yang mengalir di sebelah

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kanan itu adalah I2 dan arus arus yang

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mengalir di tengah-tengah ini adalah ih3

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Sehingga ini adalah eh satu ini adalah

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R1 ini adalah eh dua ini adalah R2 ini

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adalah eh tiga ini adalah R3 Hai

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kemudian kita tentukan arah loop dan

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juga arah arusnya

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arah lupa yang pertama ini kita pilih

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searah dengan arah jarum jam kemudian

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yang ini berlawanan dengan arah jarum

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jam

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kita pilih arus yang searah dengan arah

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Loop ya Sehingga I1 bergerak kekanan I2

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ini bergerak kekiri dan i3 nya bergerak

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ke bawah

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Hai kemudian kita bisa menerapkan hukum

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1 Kirchoff untuk mendapatkan persamaan

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yang pertama dengan titik cabangnya di

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titik p

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Sigma yg masuk

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= Sigma Ih yang keluar

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[Musik]

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di sini yang masuk ke titik cabang

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adalah I1 dan I2 berarti disinii Satu

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Ditambah I2 = i3 bisa dituliskan juga

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seperti ini Q1 = 3 dikurangi I2 kita

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dapatkan persamaan yang pertama kemudian

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kita menerapkan Hukum Kirchoff yang

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kedua untuk menganalisis Loop 1 dan 2

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untuk klub yang pertama

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Hai

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[Musik]

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singa eh ditambah Sigma ih dikali R = 0

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nanti disini Min S1 ditambah

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eh tiga ditambah I1 dikali R1 ditambah

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i3 dikali R3 = 0 langsung kita masukkan

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saja angkanya Min 10

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ditambah 5 ditambah i1d kali R1

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ditambahi 3

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R3 nya 5 = 0 tapi di sini Min 5 ditambah

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10 S1 ditambah lima i3 = 0 kita

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Sederhanakan agar mudah untuk

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menghitungnya menjadi minus 1 ditambah 2

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in 1 QNet tambah lima i3 = 0

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kita dapatkan persamaan yang kedua

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kemudian kita juga menganalisis klub

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yang kedua untuk mendapatkan persamaan

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Hai masih menggunakan hukum yang sama

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yaitu Hukum Kirchoff kedua Sigma eh

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ditambah Sigma ih dikali R = 0 nanti

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disini luknya berlawanan jarum jam ya

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ini berarti bernilai negatif

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ke-2

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plus ini negatif ya Dek tambah etika

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ditambah

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ih2 dikali R2 ditambah

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ih tiga dikali R3 = 0 kita masukkan

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semua angka yang diketahui Min 10

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ditambah 5 ditambah Ibu Adik Ali 10 buka

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Mbah i3 dikali 5 ditambah sama dengan

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nol Nah di sini kita kerjakan Min 5

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ditambah 10

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ih2 Rita Mbah 5 i3 = 0 kita Sederhanakan

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untuk mempermudah pengerjaan

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Hai min 1 hit + 2 e 2 ditambah

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i3 = 0

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ini kita dapatkan persamaan yang

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ke-3 kemudian kita subtitusikan

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persamaan pertama ke persamaan yang

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kedua

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21 juta Mbah

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2001 ditambah i3 = 0 kita subtitusikan

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dengan ini ya

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a bathing in 1 ditambah 2

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i3 dikurangi I2

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ditambah i3 = 0 min 1 ditambah 2 y 3 min

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2 I2 ditambah i3 = 0 menjadi min 1 min 2

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ini dua

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ditambah tiga i3 = 0 kita dapatkan

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persamaan yang keempat

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kemudian kita eliminasi persamaan yang

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ketiga dan keempat

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men1 ditambah

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22 ditambah i3 = 0 kita eliminasi dengan

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persamaan yang keempat yang satu minggu

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ai2 ditambah tiga itu juga sama dengan

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nol kita jumlahkan untuk mendapatkan

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arus i3 ini habis syahmin satu plus satu

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jadi mint dua ditambah empat i3 = 0

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kemudian disini tempat i3 = 2 karena

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tubuhnya pindah UAS sehingga i3 = 2 4

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MP3 = 0,5 ampere jadi arus yang mengalir

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pada Hambatan 5ons adalah 0,5 ampere

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Gimana sahabat pintar cukup panjang ya

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inilah cara pengerjaan dengan cara biasa

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Oke sahabat pintar sekarang kita masuk

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pada bagian terpenting dari video ini

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yaitu cara cepat untuk menyelesaikan

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persoalan hukum kirchhoff i

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Hai cara pintar untuk menyelesaikan soal

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ini hanya dengan satu rumah saja yaitu

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i3 =

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[Musik]

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E3 dikurangi ke-2 dikali R1

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ditambah

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e3000 orange eh 1B kali R2

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dibagi R1 dikali R2 ditambah R1 dikali

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Ertiga hitam + R2 dikali R3 kita

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masukkan semua nilai dari

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besaran-besaran ini lima dikurangi 10

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dikali dengan 10 ditambah lima dikurangi

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10 terjadi dengan 10 dibagi

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10 dikali 10 kita Mbah 10 dikali lima

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kita ubah link 10.000 ini

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55 dikurangi 10 Min 5 sekali dengan 10

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ditambah min 5 dikali dengan 10 dibagi

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100 ditambah 50 dutambah 50

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Min 50 ditambah min 50

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dibagi

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200 sehingga idenya adalah Neng 100

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dibagi

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203 = Min 0,5 ampere

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Hai jadi arus yang mengalir pada

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hambatan 5om ini adalah sebesar 0,5

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ampere Bagaimana sahabat pintar lebih

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cepat kan dan hasilnya sama dengan cara

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biasa tadi

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hai oke sahabat pintar itu tadi cara

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pintar untuk menyelesaikan persoalan

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hukum Kirchoff semoga bermanfaat dan

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jangan lupa share subscribe dan bunyikan

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loncengnya Agar kalian dapat informasi

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menarik lainnya dari kelas pintar saya

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Nurul undur diri salam pintar

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Hi Ho

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