How to Divide Polynomials using Long Division - Polynomials

MATH TEACHER GON
17 Sept 202211:43

Summary

TLDRIn this educational video, Trigon demonstrates how to divide polynomials using long division. Starting with dividing 6x^2 - 2x - 28 by 2x + 4, Trigon explains the process step-by-step, emphasizing that it mirrors the long division method used for whole numbers. The video illustrates dividing the leading terms, multiplying, and subtracting to find the partial quotient, which in this case is 3x - 7. Trigon then solves another polynomial division problem, reinforcing the method with a new example. The video is designed to teach viewers the algebraic process in an accessible manner.

Takeaways

  • πŸ“š The video tutorial focuses on dividing polynomials using long division, a method similar to dividing whole numbers but applied to algebraic expressions.
  • πŸ”’ The first example involves dividing (6x^2 - 2x - 28) by (2x + 4), where the leading terms are divided first, followed by multiplication and subtraction steps.
  • πŸ‘¨β€πŸ« The instructor emphasizes the importance of dividing the leading coefficients or terms of the dividend and divisor to find the partial quotient.
  • πŸ“‰ After dividing, the instructor demonstrates how to multiply the entire divisor by the partial quotient and subtract this product from the original polynomial to find the remainder.
  • πŸ”„ The process is repeated with the new polynomial (result after subtraction) to find subsequent terms of the quotient until the remainder is zero or less than the divisor.
  • πŸ“ The quotient obtained from the division is (3x - 7), indicating that the division process has been correctly followed and the remainder is zero.
  • πŸ” In a second problem, the method is applied to (3x^3 - 4x^2 - 7x - 5) divided by (3x - 2), showing the consistency of the long division approach.
  • πŸ“ˆ The tutorial highlights the need to bring down terms from the dividend when the current degree of the remainder is less than the degree of the divisor.
  • πŸ“Œ The final quotient for the second problem is (x^2 + 2x - 1) with a remainder of (-7), which is expressed as -7/(3x - 2).
  • πŸ’‘ The video concludes with a reminder to like, subscribe, and enable notifications for updates, encouraging viewer engagement with the channel.

Q & A

  • What is the main topic discussed in the video?

    -The main topic discussed in the video is dividing polynomials using long division.

  • What is the first polynomial division problem presented in the video?

    -The first polynomial division problem is 6x^2 - 2x - 28 divided by 2x + 4.

  • How does the video explain the process of polynomial long division?

    -The video explains that polynomial long division is similar to the long division of whole numbers, but in algebraic form. It involves dividing the leading terms, multiplying, and then subtracting.

  • What is the partial quotient obtained after the first division step in the first problem?

    -The partial quotient obtained after the first division step in the first problem is 3x.

  • What is the result of the multiplication of the partial quotient 3x by the divisor 2x + 4?

    -The result of the multiplication of the partial quotient 3x by the divisor 2x + 4 is 6x^2 + 12x.

  • What is the remainder after the first subtraction step in the first problem?

    -The remainder after the first subtraction step in the first problem is -14x - 28.

  • What is the final quotient obtained after solving the first polynomial division problem?

    -The final quotient obtained after solving the first polynomial division problem is 3x - 7.

  • How does the video handle the remainder in the division process?

    -The video brings down the remainder and continues the division process by dividing the leading term of the new polynomial by the leading term of the divisor, then multiplying and subtracting as before.

  • What is the second polynomial division problem presented in the video?

    -The second polynomial division problem is 3x^3 - 4x^2 - 7x - 5 divided by 3x - 2.

  • What is the final quotient and remainder obtained after solving the second polynomial division problem?

    -The final quotient obtained after solving the second polynomial division problem is x^2 + 2x, and the remainder is -7/(3x - 2).

  • What is the advice given by the video for those who are new to the channel?

    -The video advises those who are new to the channel to like, subscribe, and hit the Bell button to be updated with the latest uploads.

Outlines

00:00

πŸ“˜ Polynomial Long Division Introduction

The video begins with the host, Trigon, introducing the topic of dividing polynomials using long division. The first problem presented is dividing \(6x^2 - 2x - 28\) by \(2x + 4\). The process involves dividing the leading terms of the dividend and divisor, which results in \(3x\) as the partial quotient. The host then demonstrates the steps of multiplying the divisor by the partial quotient and subtracting the result from the dividend. The process is repeated until the remainder is zero, yielding the quotient \(3x - 7\).

05:01

πŸ“— Detailed Polynomial Long Division Process

The second paragraph delves deeper into the long division process with a new problem: dividing \(3x^3 - 2x^2 - 7x - 5\) by \(3x - 2\). The host explains how to divide the leading terms, resulting in \(x^2\) as the partial quotient. The video shows the multiplication of the divisor by the partial quotient and the subsequent subtraction from the dividend. The process is repeated, leading to a remainder of \(-7\) over the divisor \(3x - 2\), and the quotient is \(x^2 + 2x - 1\).

10:04

πŸ“™ Conclusion and Call to Action

In the final paragraph, the host concludes the tutorial on polynomial long division by summarizing the steps and presenting the final answer for the second problem: \(x^2 + 2x - 1\) with a remainder of \(-7/(3x - 2)\). The host encourages viewers to like, subscribe, and turn on notifications for updates, and signs off as 'Teacher Trigon'.

Mindmap

Keywords

πŸ’‘Polynomials

Polynomials are algebraic expressions that consist of variables and coefficients, involving only the operations of addition, subtraction, and non-negative integer exponents. In the video, polynomials are the main objects of study, specifically for division using long division. The script mentions dividing '6X Square minus 2x minus 28' by '2x plus 4,' which are both polynomials.

πŸ’‘Long Division

Long division is a method used for dividing larger numbers or expressions, such as polynomials. In the video, the presenter explains how to divide polynomials using the long division technique, which is analogous to the method used for whole numbers but adapted for algebraic expressions. The script walks through the process of dividing '6X Square minus 2x minus 28' by '2x plus 4' using long division.

πŸ’‘Dividend

The dividend is the number or expression that is to be divided in a mathematical operation. In the context of the video, '6X Square minus 2x minus 28' is referred to as the dividend, which is the polynomial being divided by another polynomial, the divisor.

πŸ’‘Divisor

The divisor is the number or expression by which the dividend is divided. In the video script, '2x plus 4' is the divisor, which is used to divide the dividend '6X Square minus 2x minus 28'. The process involves dividing the leading terms and then performing multiplication and subtraction steps.

πŸ’‘Leading Coefficients

Leading coefficients are the numerical factors that multiply the highest power of the variable in a term of a polynomial. The video explains that the first step in dividing polynomials is to divide the leading coefficients of the dividend and divisor, which in the example is '6' divided by '2' from the terms '6X Square' and '2x', respectively.

πŸ’‘Partial Quotient

A partial quotient is the result of dividing the leading terms of the dividend by the divisor in a step of the long division process. In the video, after dividing the leading terms, '3x' is identified as the partial quotient, which is then used in subsequent multiplication and subtraction steps.

πŸ’‘Multiply and Subtract

This phrase describes two of the key steps in the long division process for polynomials. After obtaining the partial quotient, the video shows how to multiply it by the entire divisor and then subtract the result from the dividend to get a new expression to continue the division process.

πŸ’‘Remainder

The remainder is what is left over after the division process when the dividend cannot be divided evenly by the divisor. In the video, the presenter ensures that the remainder is zero, indicating that the division has been carried out correctly and completely for the given polynomials.

πŸ’‘Quotient

The quotient is the result of a division operation. In the context of the video, after performing the long division, the quotient is '3x minus seven' for the first polynomial division example. This represents the simplified form of the division of the two polynomials.

πŸ’‘Algebraic Form

Algebraic form refers to the way mathematical expressions are written using variables and operations. The video emphasizes that dividing polynomials using long division is similar to dividing whole numbers but is done in an algebraic form, involving variables and their exponents.

Highlights

Introduction to dividing polynomials using long division

Explanation of the first problem: 6x^2 - 2x - 28 divided by 2x + 4

Step-by-step guide on dividing the leading terms of the dividend and divisor

Calculation of the partial quotient: 6x^2 divided by 2x equals 3x

Multiplication of the partial quotient by the divisor

Subtraction step in the long division process

Continuation of the division process with the next term

Final quotient derivation: 3x - 7

Emphasis on the remainder being zero in the division

Introduction to the next problem involving 3x^3 divided by 3x

Division of the leading terms resulting in x^2

Multiplication and subtraction steps for the second problem

Derivation of the quotient for the second problem: x^2 + 2x

Explanation of the remainder over the divisor

Final expression of the quotient and remainder

Encouragement for viewers to like, subscribe, and hit the Bell button for updates

Conclusion and sign-off by the presenter

Transcripts

play00:02

hi guys it's me the Trigon in today's

play00:05

video we will talk about dividing

play00:07

polynomials using long division

play00:10

so without further ado

play00:12

let's do this topic so what we have here

play00:14

is the first problem in the later on we

play00:17

will continue solving another problem

play00:20

so this is the problem guys

play00:22

we have

play00:24

6X Square minus 2x minus 28 divided by

play00:28

2x plus 4. so this is your dividend

play00:32

and this is your divisor so basically

play00:35

guys

play00:36

um if you don't know how to divide

play00:39

polynomials using long division it is

play00:41

the same as the long division that you

play00:43

have learned from your Elementary days

play00:45

on how to divide whole numbers okay

play00:49

it's in algebraic form

play00:52

so let's start

play00:54

first thing you need to do is to divide

play00:55

the leading coefficients of your

play00:57

dividend and your device sorry

play01:01

leading terms

play01:05

okay

play01:06

the first thing you need to do is to

play01:08

divide the leading terms of your

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dividend and device or at your own

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leading terminal

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dividend

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and this is the leading term of your

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divisor so this will become 6X Square

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divided by 2x I will use this part

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Minima solution or side solution

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6 divided by 2

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is 3

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the next Square divided by X is simply X

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and this 3x will serve as the partial

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quotient so it will be placed here

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we have here 3x

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okay now this 3x will be distributed or

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multiplied one by one by one by two x

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and four so what will happen is that we

play01:54

have 3x times 2x

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that is equal to 6 x squared

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and this one at the Domain after 2x for

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the man 3x times 4 that is Plus

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12 X

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after multiplying

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we have to subtract so in launcher guys

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rotation

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we divide

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we divide the leading terms

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and then after dividing multiply and

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then lastly subtract 18 adding rotation

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now

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a multiple inclusion this is

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always enclosed by the parenthesis by

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parenthesis

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multiply okay so that is 6X squared

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minus six x Cooperative Omega 0n

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okay

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zero and then here you're adding

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negative 2x minus 12x it will become

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negative 14 x okay

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negative two x two x nothing

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plus minus

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12x

play03:12

negative 2X

play03:27

so you have negative 14x

play03:30

then after that you will bring down

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negative 28 so negative

play03:35

28. yeah what's next

play03:39

so same rotation

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divide dial divide nothing in background

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leading term which is negative 14x by

play03:47

the leading term of your divisor

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okay so we have negative 14 I will use

play03:52

this part

play03:54

negative 14

play03:56

x divided by

play03:59

2x so negative 14 divided by 2 is

play04:03

negative 7 and then X over X is zero I

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one so negative seven so this will

play04:09

become minus

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7.

play04:13

okay so what we have here is the number

play04:15

one after dividing multiply

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negative seven times two x that is

play04:22

negative

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negative

play04:27

14 x

play04:30

negative 7

play04:33

times 4 that is negative

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Twenty Eight

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so multiplying that then I'll subtract

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nothing is

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so as you can see

play05:00

negative 14x plus 14x positive DNA so

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zero zero negative 28 plus positive 28

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that is zero so plug between zero then

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your remainder is zero again your

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remainder zero and the quotient

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is this

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the whole sent

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Ence the quotient

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is equal to 3x

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minus seven or

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is that we have 6X Square

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minus 2X

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minus 28

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divided by

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2x Plus 4. is equal to 3x

play05:44

minus seven and that's it guys so that's

play05:48

something new solving the next problem

play05:51

okay let's have another problem

play05:54

for the next problem same rotation

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divide the leading terms multiply and

play06:00

then subtract let's try

play06:02

okay so let's try this one

play06:06

eating term leading term 3x cubed

play06:09

divided by

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3x

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solution 3x cubed

play06:16

divided by 3x

play06:18

so 3 over 3 is 1 x squared over X cubed

play06:22

over X is x squared

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so is x squared

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so what's next sir Alexa

play06:34

multiply one by one

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okay so multiplying that then it will

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become this one

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x square times 3x that is 3

play06:47

x cubed

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x squared minus times negative 2x that

play06:52

is negative

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2x squared so subtract nothing

play06:58

and don't forget

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nah I'm not sure

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inclusions

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subtraction or negativity positive

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so what will happen

play07:12

is that we have not 3x cubed plus

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negative three x again zero negative

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zero zero

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don't mind 4x squared plus

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positive 2x squared that is equal to 6 x

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squared then bring down by this is

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negative 7X

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leading coefficient more 6X Square

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divided by 3x so 6 x squared

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divided by 3x

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so 6 divided by 3 is 2 x squared divided

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by X is X so Tanisha Plus

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2X

play07:53

multiply 2x times 3x is 6X squared

play08:02

2x times negative 2 is minus

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4 x again subtract then enclose by

play08:10

parenthesis

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change time operation Plus

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so what happened

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6X squared plus negative 6X squared

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again 0 again guys negative 7x plus

play08:27

positive 7x that is positive 4X that is

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negative 3x then bring down it on last

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one then which is negative five

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divided let you add in leading

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coefficient

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we have decimeters apart data

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we have

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negative

play08:47

three x over

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3x that is definitely

play08:52

negative one

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minus 1.

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okay so what will happen is this

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multiply that negative times negative 1

play09:01

times 3x that is

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negative 3x

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negative one

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times negative 2 that is positive 2.

play09:10

okay

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in close by parenthesis

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operation

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Plus

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negative

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so what will happen is this

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negative 3x plus 3x that is zero zero n

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is zero

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negative 5 plus

play09:37

okay plus

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negative that is negative seven it is

play09:49

quotient

play09:56

tapos

play10:03

positive negative remainder

play10:10

over

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divisor

play10:13

so to express our final answer guys

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okay

play10:18

uh divisor

play10:21

three

play10:23

x cubed

play10:25

plus 4 x squared

play10:28

minus 7X

play10:31

minus five

play10:33

divided by

play10:36

3x minus 2.

play10:38

is equal to it quotient

play10:42

in quotient is

play10:47

x square

play10:50

plus 2X because

play10:52

minus one

play10:54

is negative

play11:00

negative seven over your divisor

play11:05

that is 3x

play11:07

minus 2. so again

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quotient Theta

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since negative unit remainder

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minus seven over your device or which is

play11:18

3x minus 2. so I hope guys you learned

play11:21

something from this video on how to do

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the long division

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in dividing polynomials so if you're new

play11:29

to my channel don't forget to like And

play11:31

subscribe but hit the Bell button for

play11:34

you to be updated latest uploads again

play11:36

it's me teacher gone

play11:39

foreign

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