Average and Instantaneous Rates

Minerva Project Curriculum
27 Jul 202211:24

Summary

TLDRThis educational video explores the concepts of average and instantaneous rates of change, using the example of a marathon runner to illustrate the calculations. It explains how to compute average rates of change and then refines the method to find instantaneous rates using limits. The video demonstrates how to calculate the runner's speed at the finish line by taking the limit as the time interval approaches zero, resulting in a more precise measure of speed. The process highlights the transition from average to instantaneous rates, showing their applications in various contexts beyond just distance and time.

Takeaways

  • πŸ“ The video discusses the concepts of average and instantaneous rates of change, focusing on their computation and relationship.
  • πŸƒβ€β™€οΈ A practical example is used to illustrate the calculation of average rates of change, specifically estimating the speed of a marathon runner crossing the finish line.
  • ⏱️ The average speed is calculated by dividing the displacement (delta d) by the change in time (delta t).
  • πŸ” To improve the estimate of the runner's speed, the observer moves closer to the finish line, reducing the distance over which the average speed is calculated.
  • πŸ“‰ The video demonstrates that as the distance and time intervals are reduced, the average speed estimate approaches the instantaneous rate of change.
  • πŸ“ The formula for average speed is presented as \( \frac{\Delta d}{\Delta t} \), where \( \Delta d \) is the change in distance and \( \Delta t \) is the change in time.
  • πŸ”„ The concept of limits is introduced to find the instantaneous rate of change as \( \Delta t \) approaches zero.
  • πŸ’‘ The instantaneous rate of change is defined as the limit of the average speed as \( \Delta t \) approaches zero, representing the exact speed at a specific moment.
  • πŸ“˜ A specific function \( d(t) = at - \frac{t^2}{5} \) is used to calculate the instantaneous rate of change at \( t = 10 \) hours, representing the runner's speed at the finish line.
  • πŸ”’ The video concludes with a calculation that results in an instantaneous speed of 4 kilometers per hour at the finish line, showcasing the application of limits in real-world scenarios.

Q & A

  • What are the two main types of rates of change discussed in the video?

    -The video discusses average rates of change and instantaneous rates of change.

  • How is the average rate of change calculated?

    -The average rate of change is calculated by dividing the change in distance (delta d) by the change in time (delta t).

  • What is the significance of being closer to the finish line when measuring a marathon runner's speed?

    -Being closer to the finish line allows for a more accurate measurement of the runner's speed, as it reduces the distance over which the average speed is calculated, leading to a better approximation of their instantaneous speed.

  • What is the formula for average speed given in the video?

    -The formula for average speed is v_average = delta d / delta t, where delta d is the change in distance and delta t is the change in time.

  • How does the video illustrate the concept of instantaneous rate of change?

    -The video illustrates the concept of instantaneous rate of change by using a limit as delta t approaches zero of the average speed formula, which gives the exact speed at a specific point in time.

  • What is the formula for instantaneous rate of change as presented in the video?

    -The formula for instantaneous rate of change is given by the limit as delta t approaches 0 of (d(t0 + delta t) - d(t0)) / delta t.

  • Why is it important to take the limit as delta t approaches zero in calculating instantaneous rate of change?

    -Taking the limit as delta t approaches zero allows for the calculation of the exact rate of change at a specific instant, providing an infinitesimally precise measurement of the speed at that moment.

  • What is the distance function given for the marathon runner in the video?

    -The distance function given for the marathon runner is d(t) = at - t^2 / 5, where time is measured in hours and distance in kilometers.

  • How long did it take the marathon runner to cover the last meter according to the video?

    -It took the marathon runner 0.3 seconds to cover the last meter, as calculated when the observer was one meter away from the finish line.

  • What is the instantaneous speed of the marathon runner as they cross the finish line, according to the video?

    -The instantaneous speed of the marathon runner as they cross the finish line is 4 kilometers per hour.

  • How does the video demonstrate the transition from average to instantaneous rate of change?

    -The video demonstrates the transition by starting with calculating average rates of change over larger intervals and then refining the process by taking smaller and smaller intervals, culminating in the limit process to find the instantaneous rate of change.

Outlines

00:00

πŸƒβ€β™‚οΈ Understanding Average and Instantaneous Rates of Change

This paragraph introduces the concepts of average and instantaneous rates of change. It uses the example of a marathon runner to explain how to calculate the average rate of change by measuring the displacement and time it takes for the runner to cover a certain distance. The paragraph discusses how to improve the accuracy of this calculation by reducing the distance between the observer and the finish line, which in turn reduces the time interval considered. It concludes by setting up the mathematical framework for calculating average speed and hints at using limits to find instantaneous rates of change.

05:00

πŸ“ Calculating Instantaneous Rate of Change Using Limits

The second paragraph delves into the mathematical process of finding the instantaneous rate of change by taking the limit as the time interval approaches zero. It explains that as the observer gets closer to the finish line, the average speed calculation becomes a better approximation of the instantaneous speed. The paragraph provides a formula for calculating the instantaneous rate of change and applies it to a specific function representing the distance a marathon runner covers as a function of time. It walks through the steps of plugging in values, simplifying the expression, and taking the limit to find the exact speed at which the runner crosses the finish line.

10:01

🏁 Interpreting the Instantaneous Speed at the Finish Line

The final paragraph reflects on the result obtained from the previous calculations, interpreting the instantaneous speed of the marathon runner at the moment of crossing the finish line. It emphasizes the importance of taking an infinitesimally small interval to achieve an accurate instantaneous rate. The paragraph concludes by highlighting the universality of the concept of rate of change and its application in various contexts beyond just distance and time, setting the stage for future discussions on the topic.

Mindmap

Keywords

πŸ’‘Average Rate of Change

The 'Average Rate of Change' refers to the measure of how a quantity changes over a period of time. In the video, it is used to estimate the speed of a marathon runner by calculating the distance covered divided by the time taken. For instance, the script mentions calculating the average speed of the runner over a 10-meter distance after the finish line in 4 seconds, resulting in an average speed of 2.5 meters per second.

πŸ’‘Instantaneous Rate of Change

The 'Instantaneous Rate of Change' is a concept in calculus that describes the rate of change at a specific point, often represented by the derivative of a function at that point. The video explains this by using the limit process to find how fast the runner is moving at the exact moment they cross the finish line, which is the instantaneous speed.

πŸ’‘Limits

In the context of the video, 'Limits' are a fundamental concept in calculus used to define the behavior of a function as the input approaches a certain value. The script illustrates this by taking the limit as the time interval approaches zero to find the instantaneous rate of change, which is a more accurate measure of speed at a specific moment compared to the average rate.

πŸ’‘Displacement (Delta d)

Displacement, denoted as 'Delta d' in the script, is the change in position of an object. It is a vector quantity that refers to the shortest path from the initial to the final position. In the video, displacement is used to calculate the average speed of the runner by measuring the distance covered between two points in space.

πŸ’‘Time (Delta t)

Time, symbolized as 'Delta t' in the script, is the change in time during which a certain event occurs. The video uses this concept to calculate the average rate of change by dividing the displacement by the time it takes for the runner to cover that distance, which is essential for determining speed.

πŸ’‘Speed

Speed is a measure of how fast an object is moving. The video discusses calculating both average and instantaneous speed. Average speed is calculated over a distance, while instantaneous speed is the speed at a specific moment, which is derived using the concept of limits in calculus.

πŸ’‘Marathon Running

The video uses 'Marathon Running' as a practical example to explain the concepts of average and instantaneous rates of change. The scenario of a runner crossing the finish line is used to illustrate how to calculate the speed of the runner at different points, making the abstract mathematical concepts more relatable.

πŸ’‘Function (d(t))

In the video, a 'Function' is used to represent the distance traveled by the marathon runner as a function of time. The function d(t) = at - t^2/5 is given as an example to calculate the instantaneous rate of change at the finish line, showing how mathematical functions can model real-world scenarios.

πŸ’‘Derivative

Although not explicitly mentioned, the 'Derivative' is implied in the discussion of instantaneous rate of change. The derivative of a function at a point gives the instantaneous rate of change, which is the precise speed of the runner at the exact moment they cross the finish line, as discussed in the video.

πŸ’‘Indeterminate Form

The 'Indeterminate Form', specifically '0/0', is a concept mentioned in the script when discussing the need to simplify expressions before taking limits. It refers to a situation in calculus where a limit does not have a determinate value and further manipulation is required to find the limit, as seen when calculating the instantaneous speed at the finish line.

πŸ’‘Contextual Understanding

The video emphasizes the importance of 'Contextual Understanding' by considering the runner's fatigue after completing a marathon. This understanding is crucial for interpreting the calculated speeds and recognizing that the runner's speed would naturally decrease towards the end of the race.

Highlights

Discussing average and instantaneous rates of change.

Computing average rates of change and using limits to find instantaneous rates.

Using a marathon running example to illustrate the concept.

Estimating average rate of change by measuring distance and time.

Calculating average speed as distance divided by time.

Scenario: Calculating average speed with a 10-meter distance and 4-second time.

Contextualizing the result with the marathon runner's fatigue.

Improving the method by moving closer to the finish line.

Calculating average speed with a 1-meter distance and 0.3-second time.

The importance of proximity to the finish line for better approximation.

Introducing the distance function and its role in calculating average speed.

Formulating the average speed using the distance function.

Defining the instantaneous rate of change using limits.

Applying the formula for instantaneous rate of change at a specific time.

Using a specific function to find the instantaneous rate of change at the finish line.

Simplifying the expression to find the limit as delta t approaches zero.

Interpreting the result as the instantaneous speed at the finish line.

Reflecting on the universality of the rate concept beyond distance and time.

Transcripts

play00:00

in this video we'll discuss the topics

play00:01

of average and instantaneous rates of

play00:03

change so our goals are to compute

play00:06

average rates of change

play00:09

and then to use limits to find

play00:12

instantaneous rates of changes and see

play00:14

how these two relate

play00:17

so we're going to go back to one of our

play00:19

motivating examples

play00:21

your marathon running friend asks you to

play00:24

find how fast they're moving as they

play00:27

cross the finish line

play00:32

so one strategy to approach this problem

play00:35

is that perhaps

play00:36

you can stay a few meters after the

play00:39

finish line

play00:40

and estimate her average rate of change

play00:44

from when she crosses the finish line

play00:47

up to the point where you are

play00:53

draw the situation here your friend

play00:55

running in green and you're here in red

play00:58

and there's some distance between you so

play01:00

as your friend

play01:02

walks the distance or runs that distance

play01:05

you calculate her average speed

play01:08

which is given by distance divided by

play01:10

time

play01:11

so for that we need to know

play01:14

the displacement

play01:15

delta d

play01:17

where delta here indicates change so the

play01:20

change in distance

play01:22

we also need her time to cross that

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distance delta t the change in time

play01:28

so this quantity the average speed is

play01:31

given by the distance delta d

play01:34

divided by time delta t let's look at

play01:37

some concrete scenarios if you're 10

play01:40

meters away from the finish line

play01:42

and it takes your friend

play01:44

4 seconds to get there from the finish

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line

play01:48

we can calculate her average speed

play01:51

here delta d the distance is 10 meters

play01:55

and delta t the time was 4 seconds

play01:58

so

play01:59

this average speed which we'll denote

play02:02

here v average is equal to 10

play02:05

divided by 4 and it's in units of meters

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per second

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this is corresponding to almost 11

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minutes per mile which is a bit slow for

play02:15

a marathon runner we need to look at

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this result in context so your friend

play02:20

just finished a marathon that's a great

play02:22

accomplishment but she's tired so she's

play02:25

gonna slow down probably in those last

play02:27

10 meters that you were calculating

play02:29

maybe it would be better to be closer to

play02:31

the finish line next marathon you decide

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to improve your method moving closer to

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the finish line this time you're just

play02:38

going to be one meter away from the

play02:40

finish line

play02:42

and you're going to calculate how long

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your friend takes to cover that one

play02:45

meter

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so you found out that your friend takes

play02:49

delta t equals 0.3 seconds from that you

play02:52

can get that the average speed is 1

play02:54

divided by 0.3 in meters per second

play02:58

which is about an 8 minute per mile now

play03:02

that's a much more reasonable time for a

play03:05

marathon runner but it's not quite what

play03:08

your friend wants yet

play03:09

so as we can see here in order to

play03:11

improve our approximation we want to be

play03:14

closer and closer to the finish line

play03:17

that way your measurement will be better

play03:20

and better

play03:23

you can draw the situation here so here

play03:26

is the finish line

play03:28

here is your position as the observer

play03:32

there is some time t 0 when your friend

play03:35

crosses the finish line and t1 when it

play03:37

reaches you if we know a distance

play03:40

function we know that the position of

play03:42

your friend will be d of t naught when

play03:45

they cross the finish line

play03:47

and d of t one

play03:49

when they reach you

play03:51

that we have that the distance covered

play03:54

is the distance at the point t one minus

play03:57

the distance at the time t zero

play04:00

the change in time

play04:02

is exactly that difference in time t 1

play04:04

minus t 0.

play04:07

in other words we can say that t 1

play04:09

is equal to t 0 the moment they cross

play04:11

the finish line plus some change in time

play04:14

delta t

play04:16

all of this framework we can write a

play04:17

formula for average speed

play04:20

that is again given by the change in

play04:22

distance delta d divided by the change

play04:25

in time so in most general terms

play04:28

delta d was given by g of t1 minus d of

play04:32

t0

play04:34

and delta t was just a change in time

play04:38

note that we can rewrite t1 as we did

play04:40

above as t 0 plus delta t

play04:43

and replace that in just so we eliminate

play04:46

t1 from this equation so in this formula

play04:49

delta t is the time between your friend

play04:51

passing the finish line and reaching you

play04:57

so for the most accurate instantaneous

play05:00

estimate

play05:01

we want that time to be as small as

play05:05

possible

play05:07

we now have a framework to do that and

play05:10

its limit so say if we take the limit as

play05:14

delta t approaches zero of this average

play05:17

speed d of t zero plus delta t

play05:20

minus d of t zero divided by delta t

play05:24

this would give us the exact

play05:26

instantaneous rate of change

play05:29

you would be infinitesimally close to

play05:32

your friend and the time would be

play05:34

infinitesimally small going towards zero

play05:37

if that limit exists then we have the

play05:40

instantaneous rate of change

play05:42

that's exactly what your friend wanted

play05:46

just to recap the formula for the

play05:48

instantaneous rate of change

play05:50

is given by the limit as delta t

play05:52

approaches 0

play05:54

of the function value

play05:56

at t 0 plus delta t

play05:59

minus the function value at t 0

play06:02

divided by delta t and this would give

play06:05

us the instantaneous rate of change at

play06:07

the time t 0.

play06:10

now say that we know your friend's

play06:12

distance as a function of time

play06:15

and it's given by the formula

play06:17

d of t

play06:19

is equal to a t

play06:21

minus t squared over five

play06:23

and that's in kilometers

play06:25

time here is measured in hours

play06:28

if your friend took 10 hours to run the

play06:30

marathon

play06:32

how fast were they running as they cross

play06:34

the finish line

play06:38

in other words what we want to compute

play06:40

is the instantaneous rate of change at t

play06:43

0 equal to 10 hours

play06:47

so strategy we're going to use exactly

play06:49

the definition that we have above we

play06:51

want to take this limit as delta t

play06:53

approaches 0.

play06:54

if your position which was given by d of

play06:58

10

play06:58

plus delta t that small time it took

play07:01

your friend to get there

play07:03

minus d of 10 the position of the finish

play07:06

line

play07:07

and we'll divide that by the time it

play07:08

took to cover that distance delta t

play07:11

the first thing that we need to do

play07:14

is to plug in this quantity 10 plus

play07:17

delta t

play07:19

into our function

play07:21

g

play07:22

which gives us the distance

play07:24

or the position that we are at

play07:26

after the finish line

play07:28

so that would be a times 10 plus delta t

play07:33

minus

play07:34

10 plus delta t

play07:35

quantity squared

play07:37

divided by 5.

play07:39

so that's plugging in 10 plus delta t

play07:42

into our function above

play07:44

then we need to subtract off the

play07:46

position of the finish line which is

play07:48

given by 8 times 10

play07:51

minus 10 squared over 5.

play07:55

so that's the numerator it gives us the

play07:57

distance covered between the finish line

play08:00

and your position

play08:03

we have to divide that quantity by delta

play08:05

t the time it took to do that and don't

play08:08

forget to take the limit as delta t goes

play08:11

to zero be as close as possible to the

play08:13

finish line

play08:15

so just simplifying out a few things we

play08:17

have limit as delta t goes to zero

play08:20

of eighty

play08:21

plus eight times delta t

play08:25

minus a hundred over five

play08:28

minus twenty delta t over five

play08:31

minus delta t

play08:34

squared

play08:35

over five

play08:36

so that's the first part

play08:38

and again we need to subtract off

play08:41

8 times 10 which is 80

play08:44

plus

play08:45

100 over 5. so that's two negatives

play08:49

making a positive

play08:50

and that's our numerator and we still

play08:52

have to divide everything by delta t

play08:56

simplifying out we see that the 80 here

play08:58

cancels with that negative 80.

play09:01

the negative 100 over 5 cancels with a

play09:03

positive 100 over 5.

play09:05

we're left with is still a limit as

play09:08

delta t approaches zero that doesn't go

play09:10

away

play09:11

and in our numerator we're left with

play09:13

eight times delta t

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minus 20 delta t over five

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minus delta t squared

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over five

play09:24

all right and we're still dividing by

play09:27

delta t

play09:29

now we know something interesting

play09:31

there's a delta t in every term cancel

play09:34

out one of each from the numerator with

play09:36

the delta t in the denominator

play09:38

and we're finally left with again the

play09:41

limit as delta t approaches 0

play09:43

of 8

play09:45

minus 20 over 5

play09:48

minus delta t over five

play09:51

so we've simplified this enough that

play09:54

it's easy to calculate the limit we can

play09:55

just plug in delta t equals zero and you

play09:58

see that the last term

play10:00

goes away

play10:02

we're just left with 8 minus 20 over 5

play10:05

which is the same thing as 4 kilometers

play10:07

per hour

play10:09

had you tried to plug in delta t at the

play10:11

very beginning which i encourage you to

play10:13

do

play10:14

you'd see you'd get an indeterminate

play10:16

form you would get zero over zero

play10:19

and that's why we had to carry out all

play10:21

these simplifications that we did here

play10:24

so as a quick moment of reflection let's

play10:27

interpret this result so four kilometers

play10:30

per hour was exactly the instantaneous

play10:34

speed that your friend was running

play10:37

the moment she crossed the finish line

play10:40

and that's amazing we combined the

play10:41

notion of an average but we took the

play10:45

interval to be infinitesimally small and

play10:48

that's why we obtained an instantaneous

play10:51

rate

play10:53

lots going on so lots of takeaways from

play10:55

today's video so we were able to

play10:57

calculate average rates of change

play11:00

but then we use these limiting processes

play11:02

so we used limits to define

play11:05

instantaneous rates

play11:07

so looking ahead

play11:09

although we worked with distance time

play11:11

and speed today this concept of rate is

play11:15

universal we will see instantaneous

play11:17

rates of change in many different

play11:20

settings

play11:21

that's all for now i'll see you next

play11:23

time

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Related Tags
CalculusMarathonSpeedLimitsAverage RateInstantaneous RateChangeMathematicsDistanceTime