1st order modelling 8 - tank level system

John Rossiter
24 Jan 201307:06

Summary

TLDRThis video explores the modeling of tank level systems, which are common in the process industry. It covers the relationship between fluid depth, inflow, and outflow, using a simple tank example. The video explains how flow-out is determined by pressure differences, and how the rate of change in fluid volume is influenced by these flows. The tank's behavior is modeled using a first-order differential equation, with a focus on time constant and resistance. Key takeaways include how increasing cross-sectional area slows fluid changes and how resistance affects the time constant and steady-state depth.

Takeaways

  • 😀 Tank level systems are common in the process industry and important to model for understanding fluid behavior.
  • 😀 A simple tank model assumes flows in and out, and a specific fluid depth (H) in the tank.
  • 😀 The relationship between depth, flow in, and flow out is critical for understanding tank behavior.
  • 😀 Flow out depends on the pressure difference between the tank and the outlet pipe, which is governed by the fluid's depth (H).
  • 😀 The pressure at the bottom of a tank can be approximated as ρgh, where ρ is the fluid density, g is gravity, and h is the depth.
  • 😀 The flow through the restriction at the outlet pipe is dependent on the pressure difference, simplified to a constant R in the model.
  • 😀 For uniform cross-sectional area tanks, the rate of change of volume is related to the rate of change of depth (dh/dt).
  • 😀 The flow rate in and flow rate out balance to determine the rate of change in volume (dV/dt).
  • 😀 The final model for depth in the tank is derived as A * dh/dt + Rg * H = FN, where A is the cross-sectional area.
  • 😀 By dividing through by Rg, the model is converted into time constant form with time constant T = A / Rg and a steady-state gain of 1 / (Rρg).
  • 😀 Increasing the tank's cross-sectional area (A) increases the time constant, meaning the tank will fill/empty slower, while increasing Rρg slows the behavior and decreases the steady-state gain.

Q & A

  • What is the main focus of this video?

    -The video focuses on modeling tank level systems, specifically exploring how the depth of a tank depends on the flow in and out, and how the flow out depends on the tank's depth.

  • What is the key assumption made about the tank in this model?

    -The model assumes a simple tank with a flow coming in and a flow going out, and a specific depth of fluid denoted as H.

  • How does the flow out of the tank depend on the depth?

    -The flow out of the tank depends on the pressure difference between the bottom and top of the tank, which is related to the depth H of the fluid.

  • What is the relationship between the flow through a restriction and pressure difference?

    -The flow through a restriction is determined by the pressure difference (P1 - P2) between the two ends of the restriction. In this case, the pressure difference is approximated by the formula row * g * H, where row is the fluid density, g is acceleration due to gravity, and H is the depth of the fluid.

  • What is the role of the constant 'R' in the flow out equation?

    -The constant 'R' represents factors such as the cross-sectional area and material properties of the outlet pipe, influencing the flow rate out of the tank.

  • What does the equation A dh/dt represent in the context of the tank?

    -The equation A dh/dt represents the rate of change of the depth (dh/dt) in the tank, where A is the cross-sectional area of the tank.

  • What equation models the depth in the tank after considering the flow in and out?

    -The equation for the depth in the tank is A dh/dt + R row g * H = FN, where FN is the flow rate in, R is a constant, row is the fluid density, g is acceleration due to gravity, and H is the depth of the fluid.

  • How does the time constant form of the model look after transformation?

    -After transforming the model, it takes the time constant form: T dh/dt + H = k * FN, where the time constant T is A / (R * row * g), and the gain is 1 / (R * row * g).

  • How does the cross-sectional area (A) affect the time constant of the system?

    -If the cross-sectional area (A) is increased, the time constant increases, meaning the rate at which the tank fills or empties slows down.

  • What happens when the resistance to flow (R * row * g) is increased?

    -Increasing the resistance to flow (R * row * g) will also increase the time constant and the steady-state gain, making the system slower to fill or empty.

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Ähnliche Tags
Tank SystemsProcess ModelingFlow DynamicsFluid MechanicsTime ConstantsEngineeringCross-sectional AreaPressure DifferencesIndustry ApplicationsSystem Behavior
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