FISIKA KELAS XII || GAYA LORENTZ PADA KAWAT SEJAJAR

Yusuf Ahmada
5 Oct 202008:17

Summary

TLDRIn this educational video, Yusuf Mada explains the concept of Lorentz force on parallel wires in physics. He demonstrates two types of problems: one where currents flow in the same direction, resulting in an attractive force between the wires, and another where currents flow in opposite directions, causing a repulsive force. The video walks through the formula to calculate the force and applies it in practical examples, highlighting the importance of current direction and distance between wires. The session concludes with a preview of the upcoming topic on Lorentz force on moving charges.

Takeaways

  • 😀 The Lorentz force is the force experienced by a charged particle moving in a magnetic field, and this concept also applies to parallel wires carrying electric currents.
  • 😀 When currents in two parallel wires flow in the same direction, the force between them is attractive (attracting the wires towards each other).
  • 😀 When the currents in two parallel wires flow in opposite directions, the force between them is repulsive (pushing the wires apart).
  • 😀 The formula to calculate the Lorentz force between two parallel wires is: F = (μ₀ × I₁ × I₂ × L) / (2π × r), where μ₀ is the permeability of free space.
  • 😀 In the formula, I₁ and I₂ represent the currents in the two wires, L is the length of the wires, and r is the distance between them.
  • 😀 An example is given where two wires with currents of 2 A and 3 A, separated by 1 meter, produce a magnetic force of 6 × 10⁻⁷ N, with the force attracting the wires towards each other.
  • 😀 The direction of the Lorentz force depends on the direction of the currents: if they are in the same direction, the force is attractive; if opposite, the force is repulsive.
  • 😀 In a more complex example with three wires, the force calculations show how the forces between each pair of wires are determined and how they combine.
  • 😀 For the three-wire example, the net force on wire 2 was calculated by adding the individual forces, resulting in a net force of 3.4 × 10⁻⁷ N to the left.
  • 😀 The concept of the Lorentz force on parallel wires is essential for understanding the interaction between electric currents and magnetic fields in physics.

Q & A

  • What is the topic of the video?

    -The video discusses the concept of Lorentz force, particularly focusing on its effect on parallel wires in physics.

  • What are the two types of problems related to Lorentz force on parallel wires?

    -The two types of problems are: 1) When the current in both wires is in the same direction, leading to an attractive force, and 2) When the currents are in opposite directions, resulting in a repulsive force.

  • How does the Lorentz force behave when the currents in the parallel wires are in the same direction?

    -When the currents are in the same direction, the Lorentz force is attractive, meaning the wires pull towards each other.

  • What happens when the currents in the parallel wires flow in opposite directions?

    -When the currents flow in opposite directions, the Lorentz force is repulsive, meaning the wires push away from each other.

  • What formula is used to calculate the Lorentz force between two parallel wires?

    -The formula for the Lorentz force between two parallel wires is F = (μ₀ * I₁ * I₂ * L) / (2 * π * r), where μ₀ is the permeability of free space, I₁ and I₂ are the currents, L is the length of the wire, and r is the distance between the wires.

  • What does μ₀ represent in the Lorentz force formula?

    -μ₀ represents the permeability of free space, which has a constant value of 4π × 10⁻⁷ T·m/A.

  • In the example with two wires, how is the force calculated?

    -The force between the two wires is calculated using the Lorentz force formula, and the given values are substituted into the equation to get a result of 6 × 10⁻⁷ N.

  • In the second example with three wires, how is the net force on wire 2 determined?

    -The net force on wire 2 is determined by calculating the individual forces from wire 1 (attractive) and wire 3 (repulsive), and then adding them since they both act in the same direction (to the left).

  • How is the force per unit length (F/L) calculated in the example with three wires?

    -The force per unit length is calculated by first finding the individual forces between wire 2 and wire 1 (F21) and between wire 2 and wire 3 (F23), and then summing them up. The result is 14 × 10⁻⁷ N/m.

  • What direction does the net force on wire 2 in the three-wire example act?

    -The net force on wire 2 acts to the left, as both forces from wire 1 and wire 3 push in that direction.

Outlines

plate

هذا القسم متوفر فقط للمشتركين. يرجى الترقية للوصول إلى هذه الميزة.

قم بالترقية الآن

Mindmap

plate

هذا القسم متوفر فقط للمشتركين. يرجى الترقية للوصول إلى هذه الميزة.

قم بالترقية الآن

Keywords

plate

هذا القسم متوفر فقط للمشتركين. يرجى الترقية للوصول إلى هذه الميزة.

قم بالترقية الآن

Highlights

plate

هذا القسم متوفر فقط للمشتركين. يرجى الترقية للوصول إلى هذه الميزة.

قم بالترقية الآن

Transcripts

plate

هذا القسم متوفر فقط للمشتركين. يرجى الترقية للوصول إلى هذه الميزة.

قم بالترقية الآن
Rate This

5.0 / 5 (0 votes)

الوسوم ذات الصلة
PhysicsLorentz ForceParallel WiresMagnetic ForceElectricityClass 12Magnetic FieldPhysics ExamplesElectromagnetismForce CalculationsScience Education
هل تحتاج إلى تلخيص باللغة الإنجليزية؟