F519-Gerak Parabola ,Memahami dengan mudah ,teori plus contoh soal
Summary
TLDRThis video explains the concept of parabolic motion, covering both theoretical aspects and practical examples. It breaks down the motion into two components: horizontal (uniform motion) and vertical (accelerated motion due to gravity). Key formulas for velocity, time of flight, range, and maximum height are introduced and demonstrated with examples. The video also explains how to calculate horizontal distance, height, and velocity at different times. By providing a comprehensive overview, viewers are guided through understanding projectile motion using clear explanations and real-life problem-solving techniques.
Takeaways
- 😀 Gerak parabola is the motion of an object following a parabolic trajectory, combining uniform linear motion (GLB) and accelerated motion (GLBB).
- 😀 The motion involves both horizontal (GLB) and vertical (GLBB) components, with gravity affecting the vertical motion.
- 😀 The initial velocity (vo) can be broken down into horizontal (vox) and vertical (voy) components based on the angle of elevation (α).
- 😀 In projectile motion, the horizontal component of velocity (vx) remains constant throughout the motion due to GLB, while the vertical component changes due to gravity.
- 😀 The maximum height (y_max) is reached when the vertical velocity component (v_y) becomes zero at the peak of the parabola.
- 😀 The range of the projectile (x_max) and maximum height (y_max) can be calculated using specific formulas based on the initial velocity and angle of elevation.
- 😀 Time to reach the peak of the trajectory (t_peak) can be calculated using the formula t_peak = vo * sin(α) / g.
- 😀 The total time of flight (t_total) is twice the time to reach the peak, as the motion is symmetric.
- 😀 The horizontal distance at any moment can be calculated using x = vo * cos(α) * t, while the vertical position is given by y = vo * sin(α) * t - 1/2 * g * t².
- 😀 For non-symmetric parabolic trajectories (e.g., when an object is thrown from a height), the general formula for horizontal distance is used: x = vo * √(2h/g), where h is the initial height.
Q & A
What is 'Gerak Parabola' or projectile motion?
-Gerak Parabola refers to the motion of an object that follows a parabolic trajectory, resulting from the combination of two types of motion: uniform linear motion (GLB) and uniformly accelerated motion (GLBB). The path of the object forms a parabola due to the influence of gravity.
How is the initial velocity of the object described in the context of projectile motion?
-The initial velocity (Vo) is the velocity at which the object is launched. It can be broken down into two components: horizontal (Vox) and vertical (Voy). The angle of elevation (Alfa) is the angle between the initial velocity vector and the horizontal ground.
What is the role of gravity in projectile motion?
-Gravity affects the vertical motion of the object, causing a uniformly accelerated motion (GLBB). It influences the object’s vertical velocity, making it increase as the object descends and decelerate as the object ascends.
Why is the horizontal velocity constant in projectile motion?
-The horizontal velocity remains constant throughout the motion because there is no acceleration in the horizontal direction. This is a characteristic of uniform linear motion (GLB), where no forces are acting horizontally.
What happens to the velocity components at the peak of the trajectory?
-At the peak of the trajectory, the vertical velocity (Vy) becomes zero. However, the horizontal velocity (Vx) remains constant throughout the flight, since there is no horizontal acceleration.
How do you calculate the time it takes for the projectile to reach the peak of its motion?
-The time to reach the peak (TP) can be calculated by using the formula TP = (Vo * Sin Alfa) / g, where Vo is the initial velocity, Alfa is the angle of elevation, and g is the acceleration due to gravity.
What formula is used to determine the maximum range or horizontal distance covered by the projectile?
-The maximum range (Xmax) or horizontal distance is given by the formula: Xmax = (Vo² * Sin 2Alfa) / g. This formula assumes that the projectile follows a symmetric path, where the time to ascend equals the time to descend.
How do you calculate the maximum height (Ymax) reached by the projectile?
-The maximum height (Ymax) is calculated using the formula Ymax = (Vo² * Sin² Alfa) / (2 * g), where Vo is the initial velocity, Alfa is the angle of elevation, and g is the acceleration due to gravity.
What is the significance of the equation Y = Vo * Sin Alfa * t - (1/2) * g * t² in projectile motion?
-This equation describes the vertical position (Y) of the projectile as a function of time (t). It accounts for both the initial vertical velocity (Vo * Sin Alfa) and the effect of gravity, which causes the vertical velocity to change over time.
In the example where a bomb is dropped from a plane flying horizontally, how is the horizontal distance calculated?
-For a bomb dropped from a horizontal plane, the horizontal distance is calculated using the formula X = Vo * √(2h/g), where Vo is the horizontal velocity of the plane, h is the height from which the bomb is dropped, and g is the acceleration due to gravity. This formula assumes the bomb follows a parabolic trajectory influenced only by gravity.
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