Limit of cosØ-1 over Ø as Ø approaches 0 is 0 I Special limit of Trigonometric Functions
Summary
TLDRThis video script delves into the process of finding the limit of a trigonometric function as Theta approaches zero. It explores the indeterminate form issue when directly substituting zero, then employs the conjugation method to rationalize the expression. The script explains the use of trigonometric identities, specifically the Pythagorean identity, to simplify the problem. It also covers the limit of a product involving sine and tangent functions, illustrating the transformation of tangent into sine and cosine, and the application of limit theorems to reach the conclusion that the limit is one. The detailed explanation aims to guide viewers through the intricacies of limit calculations in trigonometry.
Takeaways
- 📚 The focus of the lesson is to find the limit of a trigonometric function, specifically cosine Theta minus 1 divided by Theta as Theta approaches zero.
- 🚫 Direct substitution results in an indeterminate form (0/0), which indicates that the limit does not exist without further analysis.
- 🔍 The method of conjugation is introduced to rationalize the expression, which involves multiplying the numerator and denominator by the conjugate of the numerator.
- 🔢 The Pythagorean trigonometric identity is used, where sin squared Theta plus cosine squared Theta equals 1, to simplify the expression.
- 🔄 The process involves transmuting the expression to involve sine squared Theta, which is equivalent to 1 minus cosine squared Theta, to facilitate simplification.
- 📉 The limit of sine squared Theta over Theta as Theta approaches zero is used, which is a key step in solving the limit.
- 🔑 The limit of Theta over sine Theta as Theta approaches zero is identified as a crucial theorem, which states that this limit is equal to one.
- 📌 Factoring is used to simplify the expression, allowing for the separation of terms and the application of limits to each factor individually.
- 🎯 The final result of the limit is determined to be zero after applying the above methods and simplifications.
- 📝 The script also discusses another limit involving the product of Theta and sine Theta over the square of tangent Theta as Theta approaches zero, which is transformed into sine squared Theta over cosine squared Theta.
- 🧩 The final limit of the second problem is found to be one, after simplifying and applying the limit of the ratio of Theta to sine Theta as Theta approaches zero.
Q & A
What is the main topic discussed in the video script?
-The main topic discussed in the video script is finding the limit of a trigonometric function, specifically the limit of (cosine Theta - 1) / Theta as Theta approaches zero.
Why is direct substitution not applicable when Theta approaches zero in the given problem?
-Direct substitution is not applicable because it results in an indeterminate form of 0/0, which means the limit cannot be determined by simply substituting Theta with zero.
What method is suggested to resolve the indeterminate form of 0/0 in the problem?
-The method of conjugation or rationalization is suggested to resolve the indeterminate form. This involves multiplying the numerator and the denominator by the conjugate of the numerator.
What is the conjugate of the numerator in the given problem?
-The conjugate of the numerator, which is cosine Theta - 1, is cosine Theta + 1.
How does the Pythagorean trigonometric identity help in solving the problem?
-The Pythagorean trigonometric identity, which states that sin^2(Theta) + cos^2(Theta) = 1, helps in transforming the expression into a form that can be simplified and factored to find the limit.
What is the significance of the limit of sin(Theta)/Theta as Theta approaches zero in the script?
-The limit of sin(Theta)/Theta as Theta approaches zero is significant because it is equal to 1. This fact is used to simplify the expression and find the limit of the given trigonometric function.
What is the final result of the limit of (cosine Theta - 1) / Theta as Theta approaches zero?
-The final result of the limit of (cosine Theta - 1) / Theta as Theta approaches zero is zero.
What is the second problem discussed in the script related to the limit of a trigonometric function?
-The second problem discussed is finding the limit of (Theta * sin(Theta)) / (tangent(Theta)^2) as Theta approaches zero.
How is the tangent function in the second problem converted to sine and cosine functions?
-The tangent function is converted by expressing it as the sine function squared over the cosine function squared, i.e., sin^2(Theta) / cos^2(Theta).
What is the final result of the limit of (Theta * sin(Theta)) / (tangent(Theta)^2) as Theta approaches zero?
-The final result of the limit of (Theta * sin(Theta)) / (tangent(Theta)^2) as Theta approaches zero is one.
Why is it important to rationalize the expression in the script?
-Rationalizing the expression is important to eliminate the complex or indeterminate forms, allowing for a clearer path to finding the limit of the given trigonometric function.
Outlines
🧭 Calculating Indeterminate Limits with Trigonometric Functions
The paragraph discusses the process of finding the limit of a trigonometric function as Theta approaches zero. The specific function is cosine Theta minus 1 divided by Theta. Direct substitution results in an indeterminate form of 0/0. To resolve this, the method of conjugation is introduced, multiplying the numerator and denominator by the conjugate of the numerator, which is cosine Theta plus 1. This leads to a rationalized form that utilizes the Pythagorean trigonometric identity, simplifying the expression and allowing for the determination of the limit as zero.
🔍 Applying Trigonometric Identities to Simplify Limits
This section delves into the use of trigonometric identities to simplify the limit of sine squared Theta plus cosine squared Theta, which equals 1. The process involves transmuting the expression to isolate terms that can be substituted with known limits, such as sine squared Theta over negative 1, which simplifies to cosine squared Theta. The limit of sine Theta over Theta as Theta approaches zero is then used to simplify the expression further, ultimately leading to the conclusion that the limit of the original function is zero.
📉 Factoring and Simplifying Limits of Trigonometric Functions
The paragraph describes the process of factoring and simplifying the limit of a function as Theta approaches zero. It involves recognizing the Pythagorean identity in the numerator and applying the limit of sine Theta over Theta, which is one, to factor out terms. The resulting expression is simplified by direct substitution, leading to the conclusion that the limit of the function is zero. The explanation emphasizes the importance of considering multiple steps and theorems in the process of finding the limit.
📚 Transforming Tangent to Sine and Cosine for Limit Calculation
This part of the script focuses on transforming the tangent function into sine and cosine to simplify the limit calculation as Theta approaches zero. The limit of the product of Theta and sine Theta over tangent squared Theta is converted into sine squared Theta over cosine squared Theta. The process involves recognizing patterns that can be simplified using known limits and trigonometric identities, ultimately leading to the conclusion that the limit of the given function is one.
🔄 Further Exploration of Limit Transformations and Simplifications
The final paragraph continues the exploration of limit transformations, specifically focusing on the limit of the product of Theta sine Theta over tangent squared Theta as Theta approaches zero. The paragraph discusses the cancellation of terms and the application of the limit of Theta over sine Theta, which is one, to simplify the expression. The limit of cosine squared Theta as Theta approaches zero is also used, leading to the final conclusion that the limit of the original function is one.
Mindmap
Keywords
💡Limit
💡Trigonometric Function
💡Direct Substitution
💡Indeterminate Form
💡Conjugation
💡Rationalization
💡Pythagorean Identity
💡Substitution Method
💡Factoring
💡Tangent Function
💡Reciprocal
Highlights
Finding the limit of the trigonometric function cos(Θ) - 1 / Θ as Θ approaches zero.
Direct substitution results in an indeterminate form, indicating the need for alternative methods.
Introduction of the conjugate method for rationalizing the expression.
The use of trigonometric identities to simplify the expression, specifically the Pythagorean identity for sine and cosine.
Transformation of the numerator into a difference of squares to facilitate further simplification.
Multiplication of the numerator and denominator by the conjugate of the numerator to rationalize the expression.
Application of the limit theorem that sin(Θ) / Θ approaches one as Θ approaches zero.
Factoring out constants and applying the limit theorem to simplify the expression.
Substitution method used to replace cos²(Θ) - 1 with -2sin²(Θ) for further simplification.
Division of both sides of the trigonometric identity by -1 to align with the expression's numerator.
Final simplification leading to the conclusion that the limit of the original expression is zero.
Transition to solving the limit of the product of Θsin(Θ) over tan²(Θ) as Θ approaches zero.
Conversion of tangent to sine and cosine to simplify the problem.
Use of reciprocal properties to rewrite the expression and simplify the limit calculation.
Cancellation of terms and factoring to isolate the limit of Θ / sin(Θ) as Θ approaches zero.
Application of the limit theorem for Θ / sin(Θ), concluding the limit of the expression is one.
Summary of the process and the importance of considering multiple methods for finding limits in trigonometric functions.
Transcripts
our focus in here is again finding the
limit of trigonometric function okay now
one of our problem is it says in here
find the limit of cosine Theta minus
1 over Theta as your Theta is
approaching zero now so that you will
notice when we make use of the direct
substitution shall we say we're going to
use the direct substitution in here here
we have now the
cosine cosine Theta which is the same as
zero which is the same as 0 -
one and of course that is the same as
Theta is zero now it will give you now a
result of 1 - 1 so cosine 0 is 1 - 1
over Z so it will give you a result
which is the same as 0 over zero which
is an
indeterminate okay indeterminate number
meaning to say if it is in determinate
there will always be the there will
always be the uh limit but of course we
need to look into other processes in
looking for the limit of this problem
okay so if that is undefine then the
limit does not exist but because it is
indeterminate there is the limit okay
okay so how is that now in here we make
use of the method of conjugation or the
rationalization method so we think of a
number uh that is to multiply in here
but it will never change the problem
definitely that is one okay so let's try
to
have the
limit the limit of uh we have in here
con
sign
cine Theta
-1/
Theta as your Theta is
approaching approaching zero now what
would be our
multiplier again as I said one okay our
multiplier is one but remember remember
our one must be defined okay must be
defined so what is the uh definition of
our one here the definition of our one
in here will be the conjugate of the
numerator what is the conjugate that is
the same as uh
cosine okay cosine Theta + 1
over
cine Theta + 1 so that is our definition
for the one so meaning to say uh because
our multiplier is one we change that one
to the this uh this one using uh by
using it as our by using this one to
rationalize this problem so what how is
that that is the same as
saying uh multiplied by
cosine cosine Theta + 1 over
cosine Theta + 1 so actually we are
having the idea of of rationalization
method using the conjugate of the uh
numerator now having said that one we
are now uh going to multiply so multiply
numerator to numerator denominator to
denominator but
notice notice that in our
numerator in our numerator that is
actually the difference of two perfect
square which is the same as cosine squar
okay
cine s Theta - 1 s or
minus-1 well of course the denominator
well let's try first to maintain uh in
their uh product form okay so Theta
multiplied by the
denominator that is the same as
cosine theta plus
+ 1 definitely your limit is uh the
limit your
Theta is
approaching zero okay it is approaching
zero but uh notice that uh in our
numerator the resulting statement for
our numerator is actually a result of
Pythagorean theorem or trigonometric
pythagorean identities which is uh you
have to remember that in our Pythagorean
theorem of the trigonometric
identities the uh uh Sin
squ Sin squ theta
plus
cine squ Theta results to 1 okay again
remember this equations so so remember
note okay let's try to write it
Note and Note again another note or
remember okay so notice that in here
when we are going to uh when we are
going to bring out the numerator in here
we have we have sign okay we have we
have to make ramification of this sin s
Theta is equal
to co
cosine cosine s theta plus + 1 trans uh
that is we have in here the
transmutation okay
or uh transpose the cosine so it will
become negative now but notice that uh
our cosine in here is negative but in
here that is positive same true with the
uh one in here positive that is negative
so what are we going to do what are we
going to do with this resulting uh
resulting statement for sin squ Theta we
have to divide both sides okay divide
both sides by what
by-1 now what is our purpose so that we
will make this one be the same as in our
numerator so if we going to divide this
one
we can have now the
statement uh sin 2 Theta / -1 we
have
sin s Theta okay is equal
to cosine 2 Theta /1 it will become now
cosine squ Theta now what about this one
pos 1 /1 it will give you
-1 notice that upon the upon the
division of -1 this statement
now is the same as our
numerator so meaning to say by
substitution
method okay by substitution method we
can now have a new statement
saying the limit of by
substitution what are we going to use
sin 2 Theta the limit of by substitution
method we can have now the limit of
netive
sin squ Theta so we replace this one uh
with its uh definition what is the
definition of this one negative sin squ
Theta as you can see it is but the same
okay this statement
is the same
[Music]
with this okay let's try to make an
arrow so that you can uh identify so by
substitution we can have now new
statement the limit of sin s Theta over
the same okay
over uh Theta the product of theta
multiplied by
cosine cosine Theta
+ 1 okay cosine Theta + 1
definitely as your
Theta as your Theta is approaching zero
still we cannot uh still
uh uh have the direct substitution in
here so that you will notice again in
this statement we have to remember again
that
uh in one of the theorem the limit
of
s Theta
over
Theta as your Theta is
approaching zero is the same as one so
with this we can we can make
ramification of this one again to at
least bring out this theorem so as you
can see the numerator is in a product
form the denominator is in a product
form and so that we with that we can
have now the factoring okay we can
factor that one so the
limit as your Theta is
approaching zero now what are the factor
the factor now is
NE -1 multiplied by
S
sin
Theta multiplied by sin
Theta okay multipli by sin Theta
definitely
over uh
Theta uh multiplied by that is the same
as that is the same as
cosine uh Theta
+ 1 okay so those are the factor of the
numerator now with that we can separate
again them by
factoring okay so we can have we can
factor out this one by
saying -1 how about in here we have the
limit times the
limit okay we have the limit of we have
the limit of uh s and we have the limit
of sin Theta we Factor out1 so limit of
s
Theta over Theta over Theta as it
approaches as approach as your Theta is
approaching zero now multiplied by
multiplied by another one
s
Theta
over
cosine Theta + 1 okay so we have in here
the equation now notice that
uh we have this
statement this statement now says
that this is the same
as this note so with that we can say now
that we have in here another statement
saying
-1 the result of this one is multiplied
by result is one okay and of course
we can have the direct substitution now
in here that is the same as uh that is
the same as sign s
uh
s sin 0 is the same
as 0 sin 0 is the same as zero
over uh substitute this one
cosine 0 is 1
+ 1 so notice the result is
what -1 M1 that is1 multiplied by 0 the
result is 0 over 2 now dividing that one
the result is zero so that is the that
is the uh limit of our problem so we can
say now we can say now that uh the limit
the limit yeah the limit of
cosine
cosine Theta -
1
over Theta - Theta as your Theta is
approaching zero is
what zero okay so meaning zero the
result will
be zero so notice that uh when we had
when we had the result which is zero
there are so many things that we need to
consider okay so there are so many thing
that we need to consider one uh think of
this that uh we need to uh we need to
think we need to
uh rationalize the problem by getting
the conjugate of our of our numerator
and so how are we going to rationalize
you use the uh the conjugate of this one
as our multiplier okay so meaning to say
why do we
multiply uh so that uh of course we can
reduce or we can change the uh problem
in terms of sign okay so our multiplier
is always the conjugate over the
conjugate or that is the same as one so
that it will not change the problem
now after that one notice that we have
now in here the uh numerator that is the
same as uh the result of
Pythagorean identities of trigonometric
function which is coming from this
statement okay so that with that with
that we make ramification of this
pythagorean identities and so bring out
this numerator cosine s Theta minus 1 by
having this statement okay sin 2 Theta
is the same as cosine 2 Theta minus 1
which is the same as in here with that
by uh by
substitution okay by sub
substitution we change we change the
cosine squ Theta minus 1 2 sin 2 Theta
but uh again notice that this is to be
uh to be factored okay why because if we
do not Factor this one it will result
again to as I said as I said uh in
determinate result so we apply the one
of the theorem that state that the limit
of s Theta over Theta as your Theta is
equal to uh approaches zero is the same
as one so having said that one uh we
Factor this one so that we will bring
out okay we will bring out this the so
factoring sin 2 Theta is the same as -1
Sin Sin Theta * sin Theta definitely the
denominator will always be the same with
that we factor out separately so we
factor out one in here -1 as one of the
property of the uh limit we can factor
out so how about in here we can we can
have the statement limit of sin Theta
over Theta as your Theta is approaching
zero which is the same as that one so
that it will result to one how about the
other Factor we have the in here sin
Theta over cosine Theta + 1 we can have
the direct substitution now in here so
when we substitute this one sin Theta
into sin 0 it will give you zero how
about this one cosine Theta which is
Theta is zero that is that is one + 1 so
it will give you 0/ 2 so dividing it the
result will be zero and so we can
establish now that the limit of the
cosine Theta - 1 / Theta as your T is
approaching zero is the same as zero I
hope you understand the process and
thank you so much uh again please uh do
not uh forget to subscribe and click the
notification Bell so that uh he will
always be notified should there be any
problem or any video Lesson that is
being posted thank you and
more again we have in here the uh
problem uh that is the same as the limit
of the product of theta sin Theta over
tangent squ Theta as your Theta is
approaching zero now how are we going to
solve for the limit of this one now
notice that we have in here tangent and
sign now remember that uh in the
pre-calculus we stated that we always
try to convert or transform the tangent
in terms of cosine or sign okay so with
that we can have the equation by
saying the
limit as your Theta is
approaching
zero
of
theta s
[Music]
Theta
is the same
as is the same as we convert this one
into what uh s and cosine so this is the
same as this is the same
as Sin squ okay sin
s Theta over
cosine squ Theta so that is the
converted form of that one now having
said that one we are now uh we can
continue now our ramification of the
problem we can have now the next
statement saying the
limit as your Theta is approaching zero
will give you a result okay so get the
rece of this one and proceed to
multiplication so that is the same
as Theta
s Theta multiplied by the reciprocal of
this one that is the same as uh
cosine cine s
Theta
over
sin squar Theta okay our sin squ Theta
now now with this now we can have now
the uh multiplication or shall we say
the division we can have the division
okay by how we can have again the other
statement let's right we start here the
limit as your Theta is
approaching zero we can have this
statement by
saying
uh Theta
okay Thea
s
Theta
[Music]
over
over
[Music]
s
Theta multiplied
by
S
Thea we can have the
one okay so of course that is the same
as multiplied by
cosine
squar Theta now notice that uh one of
the statement
sign this one can canceled out can be
canceled out and so we can have now the
statement the
limit as Theta is
approaching zero
and have now the
statement
Theta okay over
s
Theta
[Music]
okay and of
course we have now in
here
cosine
cosine
squar
Theta now with that we can have another
factoring so we can Factor this one so
by
saying to uh bring out the
limit that states that uh the
limit
of theta
over
s over s Theta as your Theta is
approaching zero will always give you
one so because of this we can we have to
factor this things this one okay so we
can have now this statement
saying the limit of
theta over
s Theta as your Theta is
approaching zero okay or shall we say
cosine okay cosine squ Theta
Okay so with that notice that
uh uh if we are going
to yes yes notice that if we are going
to have now the result of this
one of this
one that would be the same as one and
the limit of cosine cosine squ
Theta okay the limit of cosine squ
Theta multiplied
by multiplied
by 1 okay so the limit of cosine squ
Theta by substitution cosine
squ uh Theta which is Theta is zero that
is the same as one so the result will
always be one 1 multip by 1 is one okay
so so we can say now we can say now that
uh the limit okay can say know that the
limit
of of theta sin Theta over tangent squ
Theta as your Theta is
approaching approaching zero will be one
so I hope you got the procedure of
having the result of this
problem thank
you and
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