Partial Differential Equations|Solving first Order PDE|Clairaut's Form|Solve z= px + qy + p^2+pq+q^2
Summary
TLDRThe video script discusses a mathematical concept involving the complete solution of a function with independent variables x and y. It explains the process of deriving the solution by setting up and solving equations involving constants a and b. The script also covers the substitution of values into equations to find the general solution, which is expressed in terms of x, y, a, and b, ultimately relating to a constant Z.
Takeaways
- 📚 The script discusses a mathematical concept involving students, functions, and terms related to partial derivatives.
- 🔍 It introduces a function of the form 'px + qy' and its relation to the last terms of a given function.
- 📘 The script mentions a complete solution to a problem, which is expressed in terms of independent variables x and y.
- 📝 The number of independent variables is constant, and the solution is differentiated with respect to a constant variable.
- 🧩 The script describes a process of finding a solution by setting values for variables a and b, and then solving for Z.
- 📉 It explains the process of substituting values into equations to find relationships between variables.
- 📌 The script includes the formation of equations based on the given conditions and the solving of these equations.
- 📊 There is an emphasis on the importance of the right-hand side values in the equations for solving the variables.
- 🔢 The script outlines a method to find the general solution by assuming certain values and deriving relationships.
- 📐 It discusses the concept of complete solutions and how they are derived from the given equations.
- 📈 The final solution is presented in a form that combines variables x, y, and constants a and b, with their respective powers and products.
Q & A
What is the initial form of the equation mentioned in the transcript?
-The initial form of the equation mentioned is px + qy plus a function of P, followed by the last terms.
What is indicated by the complete solution in the transcript?
-The complete solution is indicated by the expression: solution = a x + b y + a², highlighting the independent variables and their corresponding constants.
How is the value of 'B' derived in the transcript?
-The value of 'B' is derived by substituting b = x - 2y by 3 into equation number 4.
What are the key equations referred to in the transcript?
-The key equations referred to are equation number 3 (x + 2A + B = 0) and equation number 4 (y + A + 2B = Z), among others.
How is the constant term separated from the variable terms in the solution?
-The constant term is separated by considering the complete solution in terms of a constant so variable and then dealing with the variable and conal values separately.
What process is used to simplify the given equations?
-The process involves substituting derived values of A and B back into the initial equations to simplify and reach the complete solution.
What is the significance of equation number 5 in the solution?
-Equation number 5 is significant as it combines and simplifies previous equations, allowing for further substitutions and simplifications.
How are the differential values treated in the solution process?
-The differential values are treated by considering their respective values with respect to constants and variables, and using them to simplify the terms.
What role do independent variables play in the final solution?
-Independent variables help define the structure of the final solution, allowing constants and variable terms to be clearly identified and separated.
How is the final general solution obtained?
-The final general solution is obtained by assuming equation B from equations A and B and simplifying to get the form: solution = a x + b y + a² + ab + b².
Outlines
📘 Overview of Solution Components
This paragraph discusses the components of a solution involving functions, constants, and independent variables. It explains the formulation of the complete solution using the equation a*x + b*y, involving differential values and their relationships with respect to constants and variables.
📊 Equation Derivation and Manipulation
This paragraph focuses on deriving and manipulating equations involving variables x, y, and z. It outlines the process of substituting values and solving equations to find relationships between variables, including detailed steps for solving and simplifying the equations.
🧮 Applying Substituted Values
This section details the substitution of specific values into equations to achieve a complete solution. It highlights the integration of A and B values into the primary equations, showcasing step-by-step manipulations and simplifications to arrive at a comprehensive solution.
📏 Final Solution Formulation
The final paragraph presents the complete formulation of the solution. It consolidates previous calculations and substitutions, arriving at the general solution involving constants a and b. The paragraph concludes with an overview of the derived equations and their implications.
Mindmap
Keywords
💡Independent Variables
💡Complete Solution
💡Equation
💡Constant
💡Differential
💡Substitution
💡Right-hand Side
💡Left-hand Side
💡Square
💡General Solution
Highlights
Students are introduced to the concept of a complete solution in the context of functions.
The function is defined in terms of 'pxy' with additional terms involving 'px' and 'qy'.
The complete solution is expressed as 'a x + b y + a²', indicating a quadratic form.
The number of independent variables is discussed, emphasizing their constant nature.
The concept of a constant number of independent variables is equated to the solution's constant nature.
Differentiation with respect to 'a' is discussed, highlighting the variable's role in the solution.
The term 'a²' is introduced as a differential value, adding complexity to the function.
The right-hand value 'Z' is defined in relation to 'x' and 'y', setting up an equation.
Equation number 3 is introduced, relating 'x', 'a', 'b', and 'Z'.
Equation number 4 is presented, further defining the relationship between 'y', 'a', 'b', and 'Z'.
Equation number 2 is discussed, providing a basis for the subsequent mathematical manipulations.
The process of solving for 'b' using equation number 3 is explained.
Substitution of 'b' into equation number 4 is detailed, advancing the solution.
The complete solution is revisited with the substitution of 'A' and 'B' values.
A complex equation involving 'a', 'b', 'x', and 'y' is derived, showcasing the solution's intricacy.
The solution is further simplified, revealing the relationship between 'x', 'y', and the constants.
The final solution is presented, integrating all variables and constants into a single equation.
An assumption is made to simplify the equation, leading to a general solution.
Transcripts
students
pxy
function
terms
ofal px+ qy plus function of P the
last
terms
and and also complete
solution
solution = a x + b y +
a²
independent variables so number ofit
constant number of independent variabl
equ solution okay so which is the
complete solution the complete
solution
equ parti with respect to
a constant so
variable and
conal Val Z because constant separate
andal value of
x into X nus so a 2 differential value 2
into a 2us 1 that is 2 into
a b constant but a variable so first con
that is B into AAL value respect
to then plus b²
conal value Z okay then right hand value
Z that is x + 2 A + B =
0 equation number
3 that is
nowal
imp
then but constant so constant and
variable so con then
then respect to
then so B power 2al value 2 into B power
2us 1 that is 2 b
equal to the right hand side value Z
that is y + a + 2 b = z equation number
four equation number three equation
number four and equation number two
equation number
two
2 a
= equ
number = minus 2 into y that is left
side and right
side
number and
number
is now equation number five minus
equation number three
imp 2
2us 2 then minus of in the right side of
the value so minus into minus plus
number
number okay that is now substitute b = x
- 2 y by 3 in equation number 4
so the four equation a + 2 into
b x-
2 x
2
the - 2+
4al then- 2x
3
number
sing
okay that is now substitute A and B
values in equation number two equation
number two complete solution that is in
the complete
solution therefore number implies = a
into x
a y - 2x by 3 into x + B into
y x - 2 y by
3 into
y+ a
s is y - 2x 3 whole Square then plus
a y - 2x 3 then into b b Val x - 2 y by
3 then plus b² value is x - 2 y 3
S
XY - 2x² / 3 then second
XY - 2 y² / 3 the third numerator and
denominator
and Aus
b a s - 2 a +
b² y² - 2 into Y into 2x that is 4 x y +
b² that is 4 x
Sid 3 Val 9
next
second and second so minus into minus
plus 2X into 2
4xy then divid
by okay
then minus 2 into X into 2 y that is 4 X
Y plus b² that is 4 into
y²
equ
and
so X
3y 3 *
XY
[Music]
and8 + 5 that isus so
3
that3 so nextus 3 y²
okay that
is
x
9
Ying con
and solution
okay
soltion is = to a x + b y + a² + a b +
b² = to a x + P of a into y + a² + a
into P of a +
b
equal to Z let us assume this is
equation number
B
minting a from equation number A and B
we get General solution
okay
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