Eigen values and Eigen Vectors in Tamil | Unit 1 | Matrices | Matrices and Calculus | MA3151
Summary
TLDRThe video script focuses on finding the eigenvalues and eigenvectors of a matrix. It explains the process of using the characteristic equation to determine these values, providing detailed steps for calculating the sum of the main diagonal elements, and the determinant of the matrix. The script includes solving the characteristic equation, applying synthetic division, and verifying eigenvalues. It concludes with finding corresponding eigenvectors by solving linear equations, offering a comprehensive guide to understanding and computing eigenvalues and eigenvectors in linear algebra.
Takeaways
- 🔢 The script discusses the process of finding eigenvalues and eigenvectors of a matrix.
- 📐 Emphasizes the use of the characteristic equation for determining eigenvalues.
- 📝 The characteristic equation formula provided is λ³ - s1λ² + s2λ - s3 = 0.
- ➕ Sum of the main diagonal elements (trace) of the matrix is calculated as 6.
- ➖ Sum of the products of the elements in the minor diagonal of the matrix is determined.
- 📊 The determinant of matrix A is calculated as part of the process.
- 🧩 The characteristic polynomial is λ³ - 6λ² + 11λ - 6 = 0, which needs to be solved.
- 🔍 Synthetic division is used to find the roots of the characteristic polynomial.
- 📉 Eigenvalues obtained from the polynomial are λ = 1, λ = 2, and λ = 3.
- 🧮 Corresponding eigenvectors are found by solving the system of linear equations derived from the matrix and eigenvalues.
Q & A
What is the primary topic of the transcript?
-The primary topic is finding the eigenvalues and eigenvectors of a given matrix using the characteristic equation.
What is the characteristic equation used to find eigenvalues?
-The characteristic equation is lambda^3 - s1*lambda^2 + s2*lambda - s3 = 0.
How is the sum of the main diagonal elements of a matrix related to the characteristic equation?
-The sum of the main diagonal elements of a matrix (s1) is used as a coefficient in the characteristic equation.
How is the determinant of the matrix used in this context?
-The determinant of the matrix is calculated as part of finding the characteristic equation and determining the eigenvalues.
What values are found for the eigenvalues in the transcript?
-The eigenvalues found are 1, 2, and 3.
What method is used to solve the characteristic equation?
-Synthetic division is used to solve the characteristic equation.
What does the transcript say about the eigenvectors corresponding to the eigenvalues?
-The eigenvectors are found by solving the system of equations derived from substituting the eigenvalues back into the matrix equation.
How are the eigenvectors for lambda = 1 calculated?
-For lambda = 1, the eigenvectors are calculated by solving the equation system derived from the matrix equation.
What is the eigenvector for lambda = 3?
-For lambda = 3, the eigenvector is calculated as (1, 0, -1).
What is the purpose of cross-multiplying elements in the matrix?
-Cross-multiplying elements in the matrix is part of the process to find the determinant and solve the characteristic equation.
Outlines
🔢 Understanding Eigenvalues and Eigenvectors
This paragraph introduces the concept of finding eigenvalues and eigenvectors of a matrix using the characteristic equation. It explains the characteristic equation's general form, lambda cube minus s1 lambda square plus s2 lambda minus s3 equals zero. The focus is on summing the main diagonal elements and calculating determinants for the matrix.
🔄 Solving the Characteristic Equation
Here, the process of solving the characteristic equation is detailed. The steps involve synthetic division, applying lambda values, and evaluating the equation to find solutions. It highlights the specific calculations for lambda values and the importance of the characteristic polynomial.
🔍 Finding Eigenvectors
This section focuses on finding eigenvectors corresponding to the eigenvalues. It explains the formation of equations involving lambda and the vector components x1, x2, and x3. The solutions to these equations provide the eigenvectors, with a detailed walkthrough of solving these equations.
🧩 Eigenvectors for Specific Lambda Values
The final paragraph deals with applying specific lambda values, like lambda equals 3, to find the corresponding eigenvectors. It discusses the transformation of equations under these lambda values and the resultant eigenvectors. The emphasis is on solving these transformed equations to determine the eigenvectors precisely.
Mindmap
Keywords
💡Eigenvalues
💡Eigenvectors
💡Matrix
💡Characteristic Equation
💡Main Diagonal Elements
💡Determinant
💡Synthetic Division
💡Lambda (λ)
💡Sum of Main Diagonal Elements (s1)
💡Cross Multiplication
Highlights
The process of finding eigenvalues and eigenvectors of a matrix is introduced, with emphasis on using the characteristic equation.
The characteristic equation is explained as lambda cubed minus S1 lambda squared plus S2 lambda minus S3 equals zero.
Sum of the main diagonal elements of a matrix is computed, demonstrating a step-by-step approach.
Details on finding S1, S2, and S3 from the matrix are provided, including practical examples.
A matrix's determinant is calculated using the cross-multiplication method for clarity.
Synthetic division is applied to solve the characteristic equation, showing how to find the roots (eigenvalues).
Specific values of lambda (eigenvalues) are substituted back into the matrix to find corresponding eigenvectors.
Discussion on the implications of each eigenvalue and how to validate them within the matrix.
The method for solving systems of linear equations to find eigenvectors is outlined, using the example matrix.
Explanation of how different eigenvalues correspond to different eigenvectors and their significance.
Step-by-step guide on multiplying matrices and solving for unknowns in eigenvector equations.
Exploring the application of eigenvectors and eigenvalues in various mathematical and practical contexts.
Clarification on the role of main diagonal elements in simplifying the process of finding eigenvalues.
Theoretical underpinning of the characteristic equation and its derivation from the matrix properties.
Insight into common mistakes and tips for accurately calculating eigenvalues and eigenvectors.
Transcripts
[Applause]
[Music]
find the eigen values under eigen
vectors
of the matrix a
or a matrix
in the matrix order eigen value zone on
the matrix or eigen vectors
square every continuous by using the
characteristic equation first of the
characteristic equation
characteristic
equation
adenosine characteristic equation now
the formula
lambda cube minus
s1 lambda square
plus s2
lambda
minus s3 equal to 0
either i want the characteristic
equation
the yes
yes
you know yesterday
yes sum of
main diagonal elements sum of main
diagonal
elements
of the matrix a
sum of main diagonal elements of the
matrix a or matrix a what are main
diagonal elements either the main
diagonal elements in two
two two either a diagonal element say
either on the main diagonal elements
two plus two plus two add all over the
six s one
so yes one again
next
yes to
yes
sum of minus of main diagonal elements
of the matrix
sum of
minus
sum of minus of
main
element sum of minus of main diagonal
elements of matrix
a okay
sum of minus sub the main diagonal
elements now if within a matrix
next
added under diagonal element marker two
upper in the two order row we did it in
the two order column
two zero zero two
two zero
zero two
cross multiply two 2's are 4 minus 0
into 0 0
plus 2 2's are 4 minus 1 ones are 1
plus 2 2's are 4 minus 0 into 0 0
center left minus number
determinant
determinant of
a
that means matrix is clear on the matrix
order determinant a contouring
matrix or a determinant in a
one
two zero one
zero two zero
one zero two either a matrix or a
determinant if a kind of particular
first thing in our kingdom
so two
into
up in the row with it in the column we
did it up and around two twos are four
minus zero into zero zero
next governing center element is zero
as an already solid the central element
is zero where the
as
zero into zero
zero minus one into two
[Music]
next in the one again our row in the row
here in the column it is zero into zero
zero one into two two
therefore two four less zero point now
four
plus one into zero to minus two minus
two two fours are eight one into minus
two minus two upon six
so yes three and a six so one okay
yes one and i got it today
six
lambda cube minus
s1 lambda square plus s2
lambda minus s3 equal to 0
lambda cube minus s1 or king is 6 lambda
in the equation lambda cube
minus 6 lambda square
plus 11 lambda minus 6 equal to 0
the equation if we solve online by
synthetic division first
first lambda one for the power
okay put lambda equal to one even the
lambda one put a one cube
minus six into lambda square now one
square
plus eleven into lambda again upon one
minus six if the zero of the pokemon one
cube in a one
minus six
one square and a one eleven ones are
eleven
minus six
whenever the one minus six and
five that means minus five minus six
plus eleven upon arrow minus eleven plus
eleven never the zero one
okay lambda one applies
in the equation
one
0 1
minus 6 1 position minus 5 next 1 into
minus 5
minus 5 lavan lava
lambda minus 2
next lambda minus 3 either
in the equation you're going to factor
therefore
total factors in a number of the
arithmetic
values are
one two three next number contouring for
the eigenvectors
next in american particular
vectors
in the eigenvectors under particular
lambda into
x
okay
two minus one one
zero 1
0 2 minus 1 1
0 1 0 2 1
1
into x 1 x 2
x 3 equal to zero
next in a minor parallelogram
one into x one
x one
zero into anything zero the one into x
three
x three equal to zero
next 0 into x 1
0 1 into x 2
x 2
0 into x 3 0 therefore x t equal to 0
next 1 into x 1
x 1
0 in x 2 0
therefore 1 into x 3 in our own x 3 1
into x 3
x 3 equal to 0 1 in the marina
moon equation 1
2
3 either i want to
first equations becomes the first
equation are king x one plus x three
equal to zero yeah
in the x three and the pokemon minus x
three upon x one again
minus x
minus x1 natural number one therefore x3
can answer minus one either in the end
therefore
lambda lambda equal
2 minus lambda
0 1
0 2 minus lambda 0
1 0
2 minus lambda
x one
x two
x three equal to
zero
only then equations
2 minus 2 0
2 minus 2 0
1
0 2 minus 2 0
x 1 x 2 x 3
equal to 0
0 into anything 0 0 into anything 0 1
into x 3
x 3 x 3 equal to 0 next
0 is full of a 0 up in full away 0 i
know 1 into x 1
foreign
next
lambda equal to 3 lambda equal to 3
applied upon lambda equation in
2 minus lambda
0
1
0
2 minus lambda
0
1 0 2 minus lambda
x 1
x 2
x 3 equal to
zero
people
lambda equal one three applies
a p equation now
two minus three minus one zero one
zero two minus three minus one
two minus three minus one
x one
x two
x three
equal to zero even allah gonna be
multiplying minus one into x one
minus x one zero and that which is one
into x three
x three equal to zero next
the zero is zero z double minus one into
x two
minus x two equal to zero one into x one
x one minus one into x three minus x
three
equal to zero
allah governing is the first equation
second equation
third equation
equation become the lambda equal to one
potential marx first equation
minus x one plus x three equal to zero
now
minus x one equal to the x three angle
minus x three
then under minus cancel therefore x 1
equal to
x 3
x 1
0
0 x 3 0 0
0
the eigenvectors are
an eigenvector over the lambda equal to
three k
one x one the first chosen operator x
two zero x three one
is
foreign
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