Hukum Dasar Kimia ( Latihan Soal Hukum Perbandingan Tetap/Hukum Proust) - Kimia

Siti Rohmah

30 May 202404:23

Summary

TLDRThis video script explains a chemical reaction where iron (Fe) reacts with oxygen (O2) to form iron oxide (FeO) with a mass ratio of 7:2 for Fe to O. The total mass of the product, FeO, is 27 grams, with 4 grams of oxygen left unreacted. The script breaks down the reaction process and shows how to calculate the mass of Fe and O2 that reacted by using the law of constant composition. It concludes that 21 grams of iron and 6 grams of oxygen participated in the reaction to form 27 grams of FeO.

Takeaways

😀 The problem involves a reaction between iron (Fe) and oxygen (O₂) to form iron oxide (FeO), with a stoichiometric ratio of 7:2 (7 parts Fe to 2 parts O₂).
😀 The total mass of the iron oxide (FeO) formed is given as 27 grams, with a remaining 4 grams of oxygen left unreacted.
😀 The goal is to determine the masses of iron and oxygen that actually reacted in the formation of FeO.
😀 The total mass of FeO (27 grams) is a sum of the masses of iron and oxygen that have reacted.
😀 From the given stoichiometric ratio, the mass of iron reacting is calculated using the ratio of 7 parts iron to 9 parts total (7 for Fe and 2 for O₂).
😀 By applying the ratio to the known mass of FeO (27 grams), the mass of iron that reacted is determined to be 21 grams.
😀 Oxygen reacts in the ratio of 2 parts to the total of 9 parts in the FeO formula. This yields a mass of 6 grams of oxygen that reacted.
😀 The remaining unreacted oxygen is explicitly given as 4 grams, which is added to the 6 grams of oxygen that reacted to make the total 10 grams of oxygen.
😀 Since no iron is mentioned as unreacted, it is assumed that all of the 21 grams of iron reacted with oxygen.
😀 The correct answer to the problem is 21 grams of iron and 6 grams of oxygen, both of which participated in the reaction to form 27 grams of FeO.

Q & A

What is the stoichiometric ratio of Fe to O in the formation of FeO?
-The stoichiometric ratio of Fe to O in the formation of FeO is 7:2.
How much mass of oxygen is left as excess in this reaction?
-The excess mass of oxygen left after the reaction is 4 grams.
What is the total mass of FeO that is formed in this reaction?
-The total mass of FeO formed in this reaction is 27 grams.
How is the mass of oxygen that reacts calculated?
-The mass of oxygen that reacts is calculated by subtracting the mass of excess oxygen (4 grams) from the total mass of FeO (27 grams), resulting in 23 grams of oxygen reacting.
What is the mass of iron that reacts in the formation of FeO?
-The mass of iron that reacts is 21 grams, which is calculated from the stoichiometric ratio of Fe to FeO.
How is the mass of iron calculated using the stoichiometric ratio?
-The mass of iron is calculated by using the ratio 7:9 (Fe:FeO) and multiplying it by the total mass of FeO. So, (7/9) * 27 = 21 grams of iron.
How is the mass of oxygen calculated in the formation of FeO?
-The mass of oxygen is calculated by using the ratio 2:9 (O:FeO) and multiplying it by the total mass of FeO. So, (2/9) * 27 = 6 grams of oxygen.
What is the total mass of oxygen that reacts in the reaction?
-The total mass of oxygen that reacts is 6 grams, based on the stoichiometric calculations.
What is the reason for using FeO as the reference point in this stoichiometric calculation?
-FeO is used as the reference point because its mass is already known (27 grams), making it easier to calculate the masses of the individual elements (Fe and O) that react.
How can the mass of oxygen in the reaction be verified with the given information?
-The mass of oxygen can be verified by noting that 6 grams of oxygen reacts with 21 grams of iron, and the excess oxygen is 4 grams, which confirms that the total mass of oxygen involved is 10 grams (6 grams reacting + 4 grams excess).