Kinetic vs Thermodynamic Product - 1,2 vs 1,4 Addition of HBr to 1,3- Butadiene
Summary
TLDRThis educational video explores the addition reactions of dienes with hydrobromic acid (HBr) under varying conditions. It explains the concepts of conjugated, isolated, and accumulated dienes, focusing on 1,3-butadiene as a key example. The video details how at low temperatures, the kinetic product forms rapidly, leading to a 1,2 addition, while at high temperatures, the thermodynamic product, a 1,4 addition, predominates due to stability. The summary also covers the stability of alkenes and the mechanism of the reaction, emphasizing the role of carbocation stability and the proximity effect in determining the major products.
Takeaways
- 🔬 Dienes are alkenes with two double bonds, and they can be conjugated, isolated, or accumulated based on the arrangement of these bonds.
- 🌟 Conjugated dienes are more stable due to resonance, which allows for the delocalization of electrons across the alternating double and single bonds.
- 🧪 1,3-Butadiene is an example of a conjugated diene, with double bonds on carbons 1 and 3, making it reactive in a unique way compared to isolated or accumulated dienes.
- ❄️ At low temperatures (e.g., -40°C), the kinetic product of the reaction between 1,3-butadiene and HBr is formed, which is the 1,2-addition product due to the faster reaction rate.
- 🔥 At high temperatures (e.g., 60°C), the thermodynamic product, the 1,4-addition product, is favored as it represents the most stable alkene configuration.
- 🏷️ The kinetic product forms faster at low temperatures and is represented by a single arrow in the reaction mechanism, indicating an irreversible process.
- ♻️ The thermodynamic product is formed at high temperatures through a reversible process, represented by two arrows with the rightward arrow being larger to show the favored direction.
- 📉 Alkene stability increases with the number of alkyl groups (R groups) attached to the carbons involved in the double bond, with tetrasubstituted being the most stable and monosubstituted the least.
- 🛠️ The mechanism of the reaction between 1,3-butadiene and HBr at low temperatures involves the diene acting as a nucleophile and HBr as an electrophile, leading to the formation of a secondary allylic carbocation.
- 🔑 The proximity effect and the stability of the carbocation intermediate are key factors in determining the major product at low temperatures, favoring the 1,2-addition (kinetic product).
- 🔄 At high temperatures, the reaction is reversible, and the most stable alkene product, the 1,4-addition (thermodynamic product), is formed due to considerations of alkene stability.
Q & A
What is a diene and how does it differ from a typical alkene?
-A diene is a type of hydrocarbon that has two double bonds, unlike a typical alkene which has only one. The presence of two double bonds in dienes allows for additional types of reactions and properties compared to alkenes.
What are the different types of dienes mentioned in the script?
-The script mentions three types of dienes: conjugated dienes, isolated dienes, and accumulated dienes. Conjugated dienes have alternating double and single bonds, isolated dienes have double bonds that are far apart, and accumulated dienes have double bonds that are very close to each other.
Why are conjugated dienes more stable than isolated or accumulated dienes?
-Conjugated dienes are more stable due to resonance, which allows for the delocalization of electrons across the double bonds, making the molecule more stable than isolated or accumulated dienes where the double bonds are either too far apart or too close to each other.
What is 1,3-butadiene and how is it named?
-1,3-butadiene is a specific type of diene with four carbons and double bonds located at the first and third carbon atoms. It is named based on the number of carbons and the positions of the double bonds, hence '1,3' indicates the positions of the double bonds in relation to the four carbon chain.
What are the two different products formed when 1,3-butadiene reacts with hydrobromic acid (HBr) under different conditions?
-When 1,3-butadiene reacts with HBr at low temperatures, the kinetic product, which is the 1,2 addition product, is formed. At high temperatures, the thermodynamic product, the 1,4 addition product, is formed due to its greater stability.
What is the significance of the kinetic product in the reaction of 1,3-butadiene with HBr at low temperatures?
-The kinetic product is significant because it forms faster at low temperatures. It is the product of an irreversible reaction and is represented by a single arrow in the reaction mechanism, indicating that it is the major product under kinetic control.
Why is the 1,4 addition product considered the thermodynamic product?
-The 1,4 addition product is considered the thermodynamic product because it is the most stable product and forms as the major product at high temperatures. It is the result of a reversible reaction and is represented by two arrows in the reaction mechanism, with the one pointing to the right being larger, indicating its stability.
What factors determine the stability of the alkene products in the reaction of 1,3-butadiene with HBr?
-The stability of the alkene products is determined by the number of alkyl groups (R groups) attached to the carbon atoms involved in the double bond. The more R groups, the more stable the alkene. Additionally, the position of the double bond and the type of substitution (cis or trans) also affect stability.
What is the role of the proximity effect in the formation of the 1,2 addition product?
-The proximity effect plays a crucial role in the formation of the 1,2 addition product. It refers to the tendency of the bromide ion to react with the carbocation that is closer to it, which in this case is the secondary carbocation formed when hydrogen adds to carbon 1.
How does the mechanism of the reaction between 1,3-butadiene and HBr differ at low and high temperatures?
-At low temperatures, the reaction is under kinetic control, favoring the formation of the kinetic product (1,2 addition product) because it forms faster. The reaction is irreversible. At high temperatures, the reaction is reversible and under thermodynamic control, leading to the formation of the thermodynamic product (1,4 addition product), which is the most stable alkene.
What is the significance of the carbocation stability in the reaction mechanism?
-Carbocation stability is significant in the reaction mechanism because a more stable carbocation intermediate forms faster and requires less energy. In the case of 1,3-butadiene reacting with HBr, the secondary allylic carbocation is more stable than the primary allylic carbocation, influencing the direction of the reaction.
Outlines
🧪 Chemistry of Dienes and Their Reactions
This paragraph introduces the concept of dienes, which are hydrocarbons with two double bonds. It distinguishes between conjugated, isolated, and accumulated dienes, highlighting the stability and reactivity differences due to their structure. The focus is on conjugated dienes, particularly 1,3-butadiene, and how it reacts with hydrobromic acid (HBr) under different temperature conditions. At low temperatures, the kinetic product, a 1,2 addition product, is formed due to the faster reaction at carbon 1. At high temperatures, the thermodynamic product, a 1,4 addition product, is favored due to its greater stability as a disubstituted alkene. The paragraph also explains the concepts of kinetic and thermodynamic control in reactions, and the stability of alkenes based on the number of substituent groups.
🔍 Mechanism of 1,3-Butadiene Reaction with HBr
This section delves into the detailed mechanism of the reaction between 1,3-butadiene and HBr at low temperatures, leading to the kinetic product. It describes the nucleophilic attack of the diene's double bond on the electrophilic hydrogen of HBr, resulting in the formation of a carbocation intermediate. The choice of hydrogen addition to carbon 1 over carbon 2 is justified by the stability of the secondary allylic carbocation formed, which is more stable than a primary carbocation. The proximity effect and the stability of the secondary carbocation intermediate are the driving forces for the formation of the 1,2 addition product. The paragraph also contrasts this with the reversible reaction at high temperatures, where the most stable alkene product, the thermodynamic product, is formed due to the greater stability of disubstituted alkenes.
🌡️ Temperature Effects on Dienes Reactions
The final paragraph discusses the effect of temperature on the reaction between 1,3-butadiene and HBr. At high temperatures, the reaction is reversible, and the thermodynamic product, which features the most stable alkene, becomes the major product. The mechanism for the formation of the 1,4 addition product is outlined, involving the movement of the double bond to create a primary allylic carbocation, which then reacts with the bromide ion. The stability of the resulting alkene, influenced by the number of substituent groups, is the key factor in determining the thermodynamic product. This paragraph reinforces the importance of alkene stability in product formation and the role of temperature in controlling reaction pathways.
Mindmap
Keywords
💡Dienes
💡Conjugated Diene
💡Isolated Diene
💡Accumulated Diene
💡1,3-Butadiene
💡Kinetic Product
💡Thermodynamic Product
💡Hydrobromic Acid (HBr)
💡Carbocation
💡Proximity Effect
💡Alkene Stability
Highlights
Dienes are alkenes with two double bonds.
Conjugated dienes have alternating double and single bonds.
Conjugated dienes are more stable due to resonance.
Isolated dienes react similarly to regular alkenes.
1,3-Butadiene is a common diene with double bonds on carbons 1 and 3.
Reaction of 1,3-butadiene with HBr at low temperature yields the kinetic product.
Kinetic product forms faster and is a 1,2 addition product.
Reaction of 1,3-butadiene with HBr at high temperature yields the thermodynamic product.
Thermodynamic product is the most stable alkene product.
Alkene stability is determined by the number of R groups attached.
Tetrasubstituted alkenes are more stable than tri-, di-, or mono-substituted alkenes.
Trans alkenes are more stable than cis alkenes.
The kinetic product is formed under irreversible reaction conditions.
The thermodynamic product is formed under reversible reaction conditions.
Diene acts as a nucleophile and HBr as an electrophile in the reaction mechanism.
Hydrogen adds to carbon 1 to form a more stable secondary carbocation.
Proximity effect and carbocation stability drive the formation of the 1,2 kinetic product.
Resonance structures explain the formation of the 1,4 thermodynamic product.
Alkene stability is the driving force for the formation of the 1,4 thermodynamic product.
Transcripts
in this video we're going to talk about
the 1 2 and the 1 4 addition products
with dienes
but let's begin our discussion with
dienes
so here is a typical alkene
it has one double bond
a diene
is basically an alkene but with two
double bonds
now there's different types of dienes
this particular diene
is
known as a conjugated
diene
the reason why it's conjugated is you
have alternating double and single bonds
here it's a double bond this is a
carbon-carbon single bond and that's a
double bond
conjugated dienes have special
characteristics
now there are other type of dienes that
you need to be familiar with
so this
is an isolated diene
because the double bonds are
too far apart from each other
and then
you also have accumulated dienes
so that's where the double bonds are
very close to each other
of these three the most stable is the
conjugated ion
due to resonance
an isolated diene reacts in the same way
as a regular alkene because the double
bonds are far apart
but a conjugated diene it reacts in a
different way and we're going to focus
on that in our discussion today
so let's begin
so let's start with this common diene
this is called one three butadiene
if we count the number of carbons
we have a total of four carbons so think
of butane
and we have a double bond on carbon one
and three so it's called one three
buta diene
now what we're gonna do is we're gonna
react this dyeing
with hydrobromic acid
hbr
but we're going to react it under
two different conditions
we're going to react it at low
temperature let's say
negative 40 degrees celsius
and at high temperature which we'll say
at 60 degrees celsius
what will be the major product
for this reaction what would you say
well at low temperature
you're going to get something called the
kinetic product
the hydrogen is going to add on carbon
1.
this is let's call this carbon one two
three and four
by the way due to the symmetry of this
diene these two alkenes are equally
reactive
so the hydrogen is going to go on carbon
one
the bromine is going to go on carbon two
we're going to have a double bond
between three and four
so this is called the one two addition
product
because hbr added
to carbon to one and two
now this is also called the kinetic
product
because it forms faster
now at high temperatures
the thermodynamic product will be the
most stable product it's going to be the
major product
the hydrogen is going to add to carbon 1
but the bromine atom is going to add to
carbon 4. and we're going to have the
double bond between carbons 2 and three
so this is called
the one four
addition product
as you can see
on carbon one we have the hydrogen and
on the carbon four we have the bromine
atom
now this is also called the thermo
dynamic product
it is the product with the most stable
alkane
i mean the most stable alkene i take
that back
so this is the product that forms at
high temperature
now
the kinetic product
the reaction associated with the kinetic
product is an irreversible reaction so
we're going to use one arrow to
represent it
the reaction associated with the
thermodynamic product is reversible so
we're going to have two arrows but
typically the one pointing to the right
is going to be the bigger
arrow because
this product
is the most stable product
now let's talk about why this product is
the most stable product
the answer has to do with the alkene
stability
notice the number of r groups that are
attached to this alkene
this particular alkene has two r groups
so it's a disubstituted alkene
this alkene
only has one r group
that are attached to the two
carbon atoms that are double bonded so
this is a mono-substituted alkane
so it is the least stable of the two
so make sure you understand that
difference the kinetic product is the
product that forms faster ideally at low
temperatures the thermodynamic product
is the most stable alkene product that
forms as the major product at high
temperatures
now let's briefly review
alkene
stability so this is
a tetrasubstituted alkene
it has four
alkyl groups attached
to the two carbon atoms that are double
bonded
this is a tri-substituted alkane
it has three r groups
a tri-substituted alkene is more stable
than
a di-substituted alkane
here we have a trans
dye substitute alkene
and that's usually more stable
than a cis disubstituted alkene
and here we have a mono substitute
alkane
which is more stable
than ethene which i'm just going to
write like that
so the more r groups that you have
around an alkene the more stable it is
and that's going to help you to identify
the thermodynamic product
but now let's go back to the reaction
of one three butadiene with hbr
and this time let's talk about the
mechanism
so let's react one three butadiene with
hbr at low temperature conditions
so as was mentioned before we're going
to get the kinetic product as the major
product even though both products can
form
this reaction is under kinetic control
so the one that forms faster is going to
be the major product when the
temperature is low
now in this reaction
the diene is going to behave as the
nucleophile
hbr the acid is going to be the
electrophile
so we're going to write up a mechanism
and to show the arrow
just remember
when when drawing the arrow it's going
to start from
a region of high electron density to a
region of low electron density
this double bond is electron rich
hydrogen being partially positive is
electron poor so the arrow
basically describes the direction of
electron
flow so to speak
so when the double bond
interacts with the hydrogen
the bond between hbr is going to break
those two electrons
is going to be pulled towards the more
electronegative bromine atom
now here's a question for you
why should we put the hydrogen on carbon
1 and not on carbon 2
notice what happens if we put the
hydrogen on carbon 2.
if we were to do that we would get a
primary
carbocation
but if we were to put the hydrogen on
carbon 1
the plus charge is going to be on carbon
2.
so we get a more stable secondary
carbocation but notice that it's
adjacent to a double bond
so what we get is a secondary allylic
carbocation and so that's the reason why
hydrogen is going to add on carbon 1.
it's because we get a more stable
carbocation intermediate
so that's the first thing you need to
consider
where will the hydrogen go
now what will the bromine atom do
or more specifically the bromide ion
now by the way
this structure has a resonance structure
we could move the alkene here if we take
those two pi electrons
and move it to the left
we can get another intermediate so this
is going to be
a less stable primary allylic
carbocation
so this is secondary
and this is primary
so just looking at the carbocation
stabilities
this particular resonance structure is
more favorable than this one
so because the secondary allylic
carbocation is more stable it's going to
form faster
because there's less energy that's
required
to generate this particular resonance
structure
now
which carbocation will the bromide ion
interact with
is it going to be the secondary
carbocation or the primary allylic
carbocation
well as was mentioned before the fact
that this is more stable
means that bromide is more likely to
interact with this secondary carbocation
but that is not the only reason there's
also something called
the proximity effect
because bromide is so much closer to the
secondary
carbocation it's easier for it to
interact with that particular
carbocation
this positive charge is further away
from the bromide ion so it's less likely
that the bromide ion is going to
interact with the primary
carbocation so therefore there are two
factors
that are favoring the one-two kinetic
product
the first most important factor is the
proximity effect
and for this specific example the second
thing is
we have a more stable carbocation
intermediate
so once the bromide ion
combined with the carbocation
we're going to get
the one two
addition product
so at low temperature conditions
this is going to be the major product
and the driving force is the proximity
effect and the fact that we get a more
stable carbocation intermediate
now let's draw the resonance structure
for the formation of the 1 4 product
so let's react 1 3 butadiene
with hydrobromic acid
at high temperature conditions so let's
use positive 80 degrees celsius
so at a high temperature this reaction
is reversible
so the most stable alkene product will
be the major product
so like before
we're going to react the alkene with hbr
and we're going to put the hydrogen on
the primary
carbon
so that we can put a positive charge on
the secondary carbon
now to get the 1 4 product we need to
draw the resonance structure
where this double bond is going to move
here
and now we have the plus charge
on the primary allylic carbocation
and then the bromide ion
is simply going to
interact with the carbocation
and so that's how we can get
the 1 4
thermodynamic product
so that's the mechanism
that you can write to show it
and so
for this one the driving force is alkene
stability
the thermodynamic product is the one
with the most stable alkene product
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