Calculating Molecular Formula from Empirical Formula

Tyler DeWitt
28 Jun 201409:09

Summary

TLDRThis video explains how to determine a compound's molecular formula when given its empirical formula and molar mass. It outlines the steps to calculate the empirical formula's molar mass and find the multiplying factor by dividing the compound's molar mass by this value. The multiplying factor helps to scale the empirical formula to the molecular formula. Several examples are provided, demonstrating how this method eliminates the need for complex charts and simplifies the process to a few straightforward steps. This approach is efficient for solving similar problems in chemistry.

Takeaways

  • ๐Ÿ˜€ Understand the empirical formula: It's the simplest whole-number ratio of atoms in a compound, like CF2 or C2H2O.
  • ๐Ÿ˜€ Find the molar mass of the empirical formula: Add up the atomic masses of all atoms in the formula using the periodic table.
  • ๐Ÿ˜€ Use the given molecular mass: This is the molar mass of the compound you're solving for, e.g., 200.4 g/mol.
  • ๐Ÿ˜€ Calculate the ratio: Divide the molecular mass by the molar mass of the empirical formula to find the multiplication factor.
  • ๐Ÿ˜€ Multiply the empirical formula by the factor: This gives you the molecular formula.
  • ๐Ÿ˜€ Example: For CF2 with a molar mass of 200.4 g/mol, the multiplying factor is 4, resulting in the molecular formula C4F8.
  • ๐Ÿ˜€ You can have different molecular formulas from the same empirical formula: For instance, C2F4, C3F6, C4F8 all have CF2 as the empirical formula.
  • ๐Ÿ˜€ A formula chart can help visualize the relationship between empirical and molecular formulas, but it isn't always necessary.
  • ๐Ÿ˜€ Using the equation (molecular mass / empirical formula molar mass), you can directly determine the multiplication factor.
  • ๐Ÿ˜€ Practice with different examples: For example, C2H2O with a molar mass of 126.12 g/mol gives the molecular formula C6H6O3.
  • ๐Ÿ˜€ The key concept: Multiply the empirical formula by a factor to match the molecular mass, and you'll get the molecular formula.

Q & A

  • What is the first step in determining the molecular formula from the empirical formula and molar mass?

    -The first step is to calculate the molar mass of the empirical formula by adding the molar masses of each element in the formula.

  • Why is the empirical formula considered to be a simplified version of the molecular formula?

    -The empirical formula represents the simplest whole number ratio of the elements in the compound, whereas the molecular formula shows the actual number of atoms of each element in a molecule.

  • How do you calculate the molar mass of an empirical formula?

    -To calculate the molar mass of an empirical formula, multiply the atomic mass of each element by the number of atoms of that element in the formula, and then sum these values.

  • What does it mean when you find a multiplying factor greater than one while dividing the molar mass of the molecular formula by the empirical formula's molar mass?

    -The multiplying factor indicates how many times the empirical formula must be scaled to match the molar mass of the compound's molecular formula.

  • How do you determine the molecular formula from the empirical formula after finding the multiplying factor?

    -Multiply the subscripts of the elements in the empirical formula by the multiplying factor to obtain the molecular formula.

  • What is the significance of the number four when determining the molecular formula from the empirical formula CF2 with a molar mass of 200.4 g/mol?

    -The number four is the multiplying factor, which shows that the empirical formula CF2 needs to be multiplied by four to match the molecular formula with a molar mass of 200.4 g/mol.

  • In the example with C2H2O and a molar mass of 126.12 g/mol, how do you calculate the factor to multiply the empirical formula by?

    -To calculate the multiplying factor, divide the molar mass of the molecular formula (126.12 g/mol) by the molar mass of the empirical formula (42.4 g/mol), which gives a factor of three.

  • Why do you need to use the empirical formula's molar mass when solving for the molecular formula?

    -The empirical formula's molar mass is used to determine the multiplying factor, which indicates how many times the empirical formula should be expanded to match the actual molar mass of the compound.

  • What is the relationship between the empirical formula and molecular formula when the compound is made of multiples of the empirical formula?

    -The molecular formula is a multiple of the empirical formula, and the multiple corresponds to the ratio of the molar mass of the molecular formula to the molar mass of the empirical formula.

  • How does the equation Molar Mass of Molecular Formula / Molar Mass of Empirical Formula help in finding the molecular formula?

    -The equation helps by calculating the factor needed to scale the empirical formula to match the molecular formula's molar mass, which is then used to multiply the empirical formula's subscripts.

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Related Tags
Molecular FormulaEmpirical FormulaChemistryStoichiometryMolar MassScientific MethodEducationalFormulasProblem SolvingChemical CalculationsScience Tutorial