Speed of Sound Calculation in Air Physics

Physicshelp Canada
8 Dec 201202:43

Summary

TLDRThis educational script explains how the speed of sound varies with temperature, using a real-world scenario. On a cold day at 4°C, the narrator calculates the distance to a mountain by measuring the time it takes for their voice to echo back, 2.8 seconds. Using the formula V = 331 + 0.59 * T°C, they determine the sound speed as 333 m/s. By applying kinematic equations, they find the mountain is 466 meters away, illustrating the practical application of physics in everyday life.

Takeaways

  • 🌡️ The speed of sound varies with temperature; it travels faster in warmer air.
  • ❄️ On a cold day, sound travels slower, while on a warm day, it travels faster.
  • 📐 The formula to calculate the speed of sound in air is V = 331 + 0.59 * temperature in degrees Celsius.
  • 🔊 To determine the distance to an object, like a mountain, one can use the formula D = V * t, where V is the speed of sound and t is the time.
  • ⏱️ The time it takes for sound to travel to an object and back is twice the time it takes for sound to travel one way.
  • 🏔️ In the example, the temperature was 4°C, which made the speed of sound approximately 333 m/s.
  • 📏 The total distance the sound waves traveled to the mountain and back was calculated to be 933 meters.
  • 🔄 The actual one-way distance to the mountain was half of the total distance, which is 466 meters.
  • 🧮 The problem demonstrates the application of kinematic equations and the speed of sound formula to solve real-world scenarios.
  • 🤔 The script encourages critical thinking by combining physics concepts to solve a practical problem involving sound propagation.

Q & A

  • How does temperature affect the speed of sound in air?

    -The speed of sound in air increases as the temperature rises. On a cold day, sound travels slower, while on a warm day, it travels faster.

  • What is the formula used to calculate the speed of sound in air?

    -The formula used to calculate the speed of sound in air is V = 331 + 0.59 * (temperature in degrees Celsius).

  • If it's 4°C outside, how fast does sound travel according to the formula?

    -At 4°C, the speed of sound is approximately 333 m/s, calculated as 331 + 0.59 * 4.

  • What is the kinematic equation used to determine the distance sound waves travel?

    -The kinematic equation used is V = D/t, where V is the speed of sound, D is the distance, and t is the time.

  • How long did it take for the sound to travel to the mountain and back in the example?

    -In the example, it took 2.8 seconds for the sound to travel to the mountain and back.

  • What is the total distance the sound waves traveled in the example?

    -The sound waves traveled a total distance of 933 meters, calculated by multiplying the speed (333 m/s) by the time (2.8 seconds).

  • Why is the total distance calculated in the example twice the actual distance to the mountain?

    -The total distance is twice the actual distance to the mountain because the sound waves traveled to the mountain and then reflected back.

  • What is the actual distance to the mountain in the example?

    -The actual distance to the mountain is 466 meters, which is half of the total distance the sound waves traveled (933 meters).

  • How does the example demonstrate the use of both the speed of sound equation and the kinematic equation?

    -The example demonstrates the use of both equations by first calculating the speed of sound at a given temperature and then using that speed to determine the distance using the kinematic equation.

  • What is the significance of using both equations in the problem-solving process?

    -Using both equations allows for a comprehensive approach to solving problems involving the speed and distance of sound waves, particularly when environmental conditions like temperature are variable.

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Related Tags
Speed of SoundPhysics CalculationTemperature EffectSound WavesDistance MeasurementKinematicsAcousticsOutdoor ExperimentScience EducationPhysics Challenge