Density Practice Problems
Summary
TLDRThis educational video script introduces the concept of density, defined as mass per unit volume. It guides viewers through three examples: calculating the density of a granite rock, determining the mass of a gold bar using its density, and finding the volume of isopropyl alcohol given its mass and density. The script emphasizes the importance of significant figures and unit consistency, highlighting the conversion between grams and cubic centimeters, and the interchangeable use of milliliters for liquids. The examples are practical, illustrating how density is used to solve real-world problems, and the script concludes with a teaser for upcoming videos on more complex density problems, including unit conversions and identifying unknown metals.
Takeaways
- π Density is defined as mass per unit volume.
- π The formula for calculating density is Density = Mass / Volume.
- π When calculating density, units must be consistent, such as grams and cubic centimeters.
- π’ Significant figures in both mass and volume should be considered when determining the final answer.
- π The units of density will be the units of mass divided by the units of volume, e.g., grams per cubic centimeter.
- π Density can be used as a conversion factor to find mass from volume or vice versa.
- π To find the mass of an object with given volume and density, multiply the volume by the density.
- π To find the volume of a substance with given mass and density, divide the mass by the density.
- π‘ Gold has a high density of 19.3 grams per cubic centimeter, indicating its heaviness.
- πΎ Isopropyl alcohol, a liquid, has a density of 0.785 grams per cubic centimeter, which can be used to calculate its volume given its mass.
- π₯€ The volume of liquids is often measured in milliliters, which is equivalent to cubic centimeters.
Q & A
What is the definition of density?
-Density is defined as mass per unit volume, mathematically expressed as Density = Mass / Volume.
What is the mass and volume of the granite rock mentioned in the script?
-The granite rock has a mass of 15.5 grams and a volume of 6.01 cubic centimeters.
How is the density of the granite rock calculated in the script?
-The density of the granite rock is calculated by dividing its mass (15.5 grams) by its volume (6.01 cubic centimeters), resulting in approximately 2.58 grams per cubic centimeter.
What is the significance of significant figures in the calculation of density in the script?
-Significant figures are important to ensure the precision of the result. In the script, the density is rounded to three significant figures, which is 2.58 grams per cubic centimeter.
What are the units for the density of the granite rock as calculated in the script?
-The units for the density of the granite rock are grams per cubic centimeter (g/cmΒ³).
What is the density of gold given in the script?
-The density of gold is given as 19.3 grams per cubic centimeter.
How is the mass of the gold bar calculated using its density and volume?
-The mass of the gold bar is calculated by multiplying its volume (44.9 cubic centimeters) by the density of gold (19.3 g/cmΒ³), resulting in approximately 867 grams.
What is the density of isopropyl alcohol, and how is it used to find its volume when given a mass?
-The density of isopropyl alcohol is 0.785 grams per cubic centimeter. It is used as a conversion factor to find the volume when the mass is given, by dividing the mass (50.0 grams) by the density (0.785 g/cmΒ³), resulting in approximately 63.7 cubic centimeters or milliliters.
Why might one choose to express the volume of a liquid in milliliters instead of cubic centimeters?
-While cubic centimeters and milliliters are equivalent in volume, milliliters are commonly used to express the volume of liquids for convenience and convention.
What is the concept of a conversion factor in the context of density calculations?
-A conversion factor in density calculations is a ratio that allows the conversion between two related quantities, such as mass and volume. It helps to cancel out units and isolate the desired unit in the calculation.
What are the next topics to be covered in the series on density problems according to the script?
-The next topics to be covered include unit conversions, determining the volume of an object by measurement or displacement in water, and identifying unknown metals by measuring their density.
Outlines
π Calculating Density and Mass from Volume
This paragraph explains the concept of density, defined as mass per unit volume, using the formula Density = Mass / Volume. It demonstrates the calculation of the density of a granite rock with a mass of 15.5 grams and a volume of 6.01 cubic centimeters, resulting in a density of 2.58 grams per cubic centimeter. The explanation includes the significance of rounding to three significant figures and the importance of units in the calculation. It also covers a problem involving the mass of a gold bar given its volume and density, illustrating the use of density as a conversion factor to find mass.
π§ͺ Determining Volume from Mass Using Density
The second paragraph delves into using density to calculate the volume of a substance when its mass is known. It uses the example of isopropyl alcohol with a density of 0.785 grams per cubic centimeter and a mass of 50.0 grams to find the volume. The explanation highlights the selection of the appropriate conversion factor to cancel out the mass units and leave the volume in cubic centimeters. The result is rounded to three significant figures, yielding a volume of 63.7 cubic centimeters, which is also equivalent to milliliters due to the 1:1 relationship between the two units for liquids.
Mindmap
Keywords
π‘Density
π‘Granite Rock
π‘Significant Figures
π‘Gold
π‘Conversion Factor
π‘Isopropyl Alcohol
π‘Cubic Centimeter
π‘Milliliter
π‘Unit Conversion
π‘Graduated Cylinder
π‘Unknown Metal
Highlights
A granite rock with a mass of 15.5 grams and a volume of 6.01 cubic centimeters has a density of 2.58 grams per cubic centimeter.
Density is calculated by dividing mass by volume.
Significant figures are important in scientific calculations, and the result should match the number of significant figures in the original data.
The units of density are determined by the units of mass and volume and should be reported as such.
Gold has a high density of 19.3 grams per cubic centimeter, indicating its heaviness.
A gold bar with a volume of 44.9 cubic centimeters has a mass of 867 grams, calculated using the density as a conversion factor.
Density can be used as a conversion factor to move between mass and volume.
Choosing the correct conversion factor is crucial for canceling out the correct units to obtain the desired result.
Isopropyl alcohol has a density of 0.785 grams per cubic centimeter, which is lower than that of gold.
50.0 grams of isopropyl alcohol occupies a volume of 63.7 cubic centimeters, calculated using the density as a conversion factor.
The volume of liquids is often measured in milliliters, which is equivalent to cubic centimeters.
The concept of density is fundamental in understanding the mass and volume relationship of substances.
Practical applications of density include identifying unknown metals by measuring their density.
Density problems can involve unit conversions and measuring volumes by submersion in a graduated cylinder.
The video introduces more complex density problems in the next installment.
Transcripts
a piece of granite rock has a mass of
15.5 G and a volume of
6.01 cubic cm what is its density so
density is defined as mass ID volume in
this problem I have a mass in GRS and I
have a volume in cubic centimet so all I
got to do is take this Mass
15.5 G and divide it here by the volume
which which is
6.01 cm cubed or cubic cenm and that
gives me 2.5 7
903 what do I round this to well I have
three significant figures in the top
three significant figures in the bottom
so I'm going to keep this keep this and
keep this and look to the nine to see
whether I keep the seven the same or if
I round up it's higher than five so I'll
round up and I'll get two
2.58 for my rounded answer now what are
the units here what are the units for
density in this division problem here I
haven't canceled out any units I have my
gr and my cubic centim and nothing's
happened to them they're still both
there so that means that the units of my
answer have to have both these in them
so I'll report this as
G
divided cubic cm just like this
and this is my final answer for the
density of the rock let's do another one
gold has a density of
19.3 G per cubic centimeter that's
really high gold is very heavy if you
have a gold bar with a volume of 44.9
cubic cm what is its mass okay so in
this example all we have is a volume and
we have to take the density to figure
out what the mass is going to be so
let's start out with this volume here
okay
44.9 cubic
cm now how are we going to get from
cubic cenm to GRS which is the
mass I like to think of density here as
a conversion factor that lets me move
between mass like how much something
weighs and lets me convert between that
and volume how much space something
takes up
so the density here I can write this as
a conversion factor I can kind of expand
this gr per cubic cenm like this okay
it's like
19.3 G is the top and then we have the
slash here and on the bottom I have one
cubic cm right I have this cm cubed but
if there's no number in front of it it
can always be one okay so I can take
this number here the density I can turn
it into a conversion factor kind of
pulling this this cubic cenm down and
putting it on the bottom of the fraction
putting a one in front of it as you know
anything that you can write as a
conversion factor you can also flip so I
could write density like this or I could
flip it and put one cubic cm on the top
and put
19.3 G on the bottom either way this
conversion factor lets me go between
mass and volume the question is which of
these do I want to use
I want to use the conversion factor
that's going to let me cancel out the
units of cubic cm and will leave me with
units in grams which is mass so what I'm
going to want to choose is the
conversion factor here that has centimet
Cubed on the bottom so that it will
cancel out and has grams on the top so
I'm going to choose this one I'm going
to write it in here and you'll see why
19.3 G up here on the top 1 cubic cm on
the bottom and now now I have cubic
centimet up here and I have cubic
centimet down here and I'm left with GRS
as my unit okay so I chose the right
version of the conversion factor okay
now I'm going to do
44.9 *
19.3 and I'm going get
86657 three sigfigs here three sigfigs
here and we have one which is a counting
number it's a definite number so we
don't worry about the significant figure
here so I'm going to round this number
to three significant figures I'm going
to keep the eight six look there to five
so that six is going to go up it's going
to be 8 6 7 and what are my units units
right here units are in grams
867 g is how much this piece of gold
would weigh one more isopropyl alcohol
is a liquid with a density of
0.785 G per Cub cm how much volume would
be taken out by 50.0 G of isopropyl
alcohol so here is our definition of
density and in this problem I get a
density I get this and I get a mass in
grams I'm going to have to use the
density to figure out what the volume is
so I'll start with
50.0 G and as I said I have to go
between mass and volume so I can use the
density as a conversion factor to do
that so let's write the density as a
conversion factor as I showed in the
previous example we're going to take
this centim cubed we're going to grab it
and we're going to pull it under the
fraction so we're going to get one
conversion factor that looks like this
0.785 G divided by 1 cm Cub that is one
of the conversion factors the other
valid conversion factor is to take this
and flip it so I'll do one cubic cm
divided by
0.785 G which of these do I want to use
I want to use the one that's going to
cancel out GRS from here and leave me
with cubic cenm so since GRS is going to
be on the top here I want to choose the
version that has grams on the bottom so
it's going to be this version of the
conversion factor that I'm going to use
so 50.0 G times this
1 cm cubed / 0
785 G Gams up here grams down there so
they cancel out so I know that I use the
right conversion factor I'm going to be
left with centime cubed and the mathod
I'll do is 50.0 * 1 the answer to that I
mean that's just going to be 50 but so
I'm 50 * 1 ided
0.785 and I get
63.
6943 three sigfigs here three sigfigs
here this is a counting number so it
doesn't matter so rounding the answer to
1 2 three significant figures look to
the nine SE the six goes up to 7even so
I get
63.7 the units are cubic cm now
isopropyl alcohol also known as rubbing
alcohol is a liquid and so for volume of
liquid we often measure it in
milliliters instead of cubic centimeters
now millimet milliliters and cubic cenm
are the same thing it's just that we
often use cubic centimet to talk about
the volume of like a solid object and we
often use milliliters to talk about the
volume of a liquid so if we wanted to be
super picky we might choose to say that
the volume of isopropyl alcohol because
it's a liquid is
63.7 ml milliliters and also because
isopropyl alcohol as a liquid if we
wanted to be super super picky we could
say that it had a density of
0.785 G per milliliter but it's the same
thing remember that 1 cubic cm equals 1
milliliter and you know if your teacher
is really picky or something and you're
talking about liquid you might want to
use milliliters instead of cubic
centimet but it's the exact same thing
anyway that finishes our introduction to
density in the next video we're going to
look at more difficult problems where
we've got to do unit conversions where
we've got to figure out what the volume
of something is by measuring it or by
dunking it into a graduated cylinder and
watching how much the water rises and
finally we'll look at problems where we
have to identify an unknown metal figure
out what kind of metal It Is by
measuring its density so that's all in
the next video on density problems
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