Sex linked Genetic diagrams

Miss Angler
21 Apr 202120:11

Summary

TLDRThis educational video script delves into sex-linked disorders, focusing on how they are inherited and calculated using a Punnett square. It explains the role of sex chromosomes in determining biological sex and susceptibility to disorders. The script uses examples like red-green color blindness and hemophilia to illustrate X-linked recessive disorders, highlighting the difference in inheritance patterns between males and females. It also clarifies the distinction between genotype and phenotype, emphasizing the importance of understanding these concepts for grasping sex-linked inheritance.

Takeaways

  • 🧬 Sex-linked disorders are genetic conditions that are passed down through the sex chromosomes, specifically the X chromosome.
  • 🔍 Humans have 23 pairs of chromosomes, with the 23rd pair being the sex chromosomes, which include the X and Y chromosomes.
  • 🚺 Females have two X chromosomes (XX), making them less susceptible to sex-linked disorders, as one X chromosome can compensate for the other in case of damage.
  • 🚹 Males have one X and one Y chromosome (XY), which makes them more vulnerable to sex-linked disorders since they have only one X chromosome to carry disease alleles.
  • 🟥 Red-green color blindness is an example of a common sex-linked recessive disorder, affecting the ability to distinguish certain colors.
  • 🔄 Inheritance patterns of sex-linked disorders can be visualized using Punnett squares, which help predict the likelihood of offspring inheriting the condition.
  • 👨‍👩‍👧‍👦 A carrier mother can pass on a sex-linked disorder to her children, with sons being more likely to express the disorder due to having only one X chromosome.
  • 🩸 Hemophilia is another example of a sex-linked disorder, typically affecting males and being carried by females as they have two X chromosomes.
  • 🧬 The script explains how to calculate the probability of offspring inheriting sex-linked disorders using genetic crosses and Punnett squares.
  • 📝 When explaining sex-linked inheritance, it's important to describe the genotypes of the parents and how the inheritance of one allele from each parent affects the offspring.

Q & A

  • What are the two types of sex chromosomes in humans?

    -The two types of sex chromosomes in humans are the X chromosome and the Y chromosome.

  • How do females and males differ in their sex chromosome composition?

    -Females have two X chromosomes (XX), while males have one X and one Y chromosome (XY).

  • What is the significance of having two X chromosomes in females in terms of disease susceptibility?

    -Females are less susceptible to X-linked disorders because if one X chromosome is damaged, the other can compensate and help fix the problem.

  • Why are males more prone to X-linked disorders compared to females?

    -Males are more prone to X-linked disorders because they have only one X chromosome, and if it carries a recessive disease-causing allele, they will express the disorder since they have no second X chromosome to mask it.

  • What is the difference between autosomes and sex chromosomes?

    -Autosomes are the first 22 pairs of chromosomes that are not involved in sex determination, while sex chromosomes (gonosomes) are the 23rd pair, which include the X and Y chromosomes that determine biological sex.

  • What is a common example of an X-linked recessive disorder mentioned in the script?

    -A common example of an X-linked recessive disorder mentioned is red-green color blindness.

  • How is the inheritance of X-linked disorders represented in a Punnett square?

    -In a Punnett square for X-linked disorders, the alleles are represented as superscripts on the X chromosome, with a dominant allele (usually a capital letter) and a recessive allele (usually a lowercase letter).

  • What is the significance of the term 'carrier' in the context of X-linked disorders?

    -A 'carrier' refers to an individual, typically female, who has one normal allele and one allele for an X-linked recessive disorder. They do not express the disorder but can pass the disorder allele to their offspring.

  • How do you determine the probability of offspring inheriting an X-linked disorder from a Punnett square?

    -You determine the probability by looking at the genotypes resulting from the cross and calculating the percentage of offspring that receive the recessive allele on their single X chromosome (males) or both X chromosomes (females).

  • Why is it important to specify the sex when describing the phenotypes in a sex-linked inheritance scenario?

    -Specifying the sex is important because the phenotype of an individual with a sex-linked disorder can differ between males and females due to the different composition of their sex chromosomes.

  • What is the difference between genotype and phenotype in the context of sex-linked disorders?

    -Genotype refers to the specific set of alleles an individual carries for a gene, while phenotype refers to the observable characteristics or traits that result from the interaction of those alleles with the individual's environment.

Outlines

00:00

🧬 Introduction to Sex-Linked Disorders

This paragraph introduces the topic of sex-linked disorders, focusing on how they are inherited and calculated using a Punnett square. It explains the role of sex chromosomes, the X and Y, in determining biological sex and how autosomes differ from them. The paragraph emphasizes the importance of understanding chromosome structure, particularly the X and Y chromosomes, and their combinations in males and females. It also touches on the concept of females being less susceptible to certain disorders due to having two X chromosomes, which can compensate for a damaged one, unlike males who have only one X chromosome and are thus more vulnerable to X-linked disorders.

05:00

👨‍👩‍👧‍👦 Inheritance Patterns and Examples

The second paragraph delves into the inheritance patterns of sex-linked disorders, using red-green color blindness as an example. It describes how this condition is a recessive disorder carried on the X chromosome and represented with a lowercase 'r' as a superscript. The paragraph explains the genetic cross of an unaffected father and a carrier mother, detailing the possible outcomes for their offspring. It clarifies that unaffected sons inherit a capital 'R' from their mother, while daughters can be either unaffected or carriers, depending on whether they inherit the small 'r' from their mother. The paragraph also discusses how to represent these genetic outcomes visually and emphasizes the importance of knowing the genotypes and phenotypes for understanding sex-linked inheritance.

10:02

🧵 Calculating Sex-Linked Inheritance: Hemophilia

This paragraph shifts the focus to another common sex-linked disorder, hemophilia, to demonstrate how to calculate sex-linked inheritance. It outlines three different genetic cross scenarios with varying outcomes. The first scenario involves a male with hemophilia and a non-carrier female, resulting in 50% of offspring being carriers or non-affected. The second scenario includes a male with hemophilia and a carrier female, leading to a 25% chance for each possible genotype and phenotype among the offspring. The third scenario features a normal male and a carrier female, resulting in a 25% chance for each genotype and phenotype. The paragraph stresses the importance of accurately recording and grouping genotypes and phenotypes when calculating sex-linked inheritance.

15:02

📊 Understanding and Explaining Sex-Linked Inheritance

The fourth paragraph discusses how to explain sex-linked inheritance, particularly focusing on the differences in susceptibility between males and females. It highlights that males are more affected due to having only one X chromosome, which lacks a second X to mask the presence of a recessive disorder allele. The paragraph also addresses how to answer questions about the percentage of children with a disorder, emphasizing the need to distinguish between males and females when calculating these percentages. It provides a structured approach to explaining sex-linked inheritance, including stating parents' genotypes, explaining allele inheritance from each parent, and discussing why males are more likely to express the disorder.

20:05

👋 Conclusion and Terminology Recap

The final paragraph concludes the video script with a recap of key terminology related to sex-linked inheritance. It differentiates between autosomes, which are not sex chromosomes and are associated with autosomal diseases, and gonosomes, which are the sex chromosomes (X and Y) and are relevant to sex-linked disorders. The paragraph also distinguishes between recessive and dominant traits in the context of sex-linked disorders and clarifies the difference between phenotype (observable characteristics) and genotype (alleles on sex chromosomes). It corrects a misconception about using 'carrier' as a phenotype and ends with a reminder of the importance of understanding these concepts for grasping sex-linked inheritance.

Mindmap

Keywords

💡Sex-linked disorders

Sex-linked disorders are genetic conditions that are linked to an individual's sex chromosomes. These disorders are predominantly associated with the X chromosome, as males have only one X chromosome and are thus more susceptible to inheriting these conditions. In the video, red-green color blindness and hemophilia are mentioned as examples of sex-linked disorders. The script explains how these disorders are inherited and how they manifest differently in males and females due to the presence of two X chromosomes in females, which can mask the effects of a recessive gene.

💡Gonosomes

Gonosomes, also known as sex chromosomes, are the chromosomes that determine an individual's biological sex. In humans, these are the 23rd pair of chromosomes, which include the X and Y chromosomes. The video script explains that females typically have two X chromosomes (XX), while males have one X and one Y chromosome (XY). Understanding gonosomes is crucial for comprehending how sex-linked disorders are inherited, as these disorders are directly related to the genes present on these chromosomes.

💡Autosomes

Autosomes are the first 22 pairs of chromosomes in humans, which are not involved in determining sex. They are responsible for various other traits and characteristics. The video script contrasts autosomes with gonosomes to emphasize that sex-linked disorders are specifically related to the sex chromosomes, while other genetic conditions can be linked to any of the autosomes.

💡Punnett square

A Punnett square is a diagram used to predict the genotypes of offspring in a genetic cross. It is named after Reginald C. Punnett, who introduced it in 1905. In the video, Punnett squares are used to demonstrate how sex-linked disorders are inherited. The script walks through examples of how to calculate the likelihood of offspring inheriting conditions like red-green color blindness and hemophilia by using Punnett squares to visualize the genetic combinations.

💡Recessive disorder

A recessive disorder is a genetic condition that is expressed only when an individual inherits two copies of the recessive gene, one from each parent. In the context of the video, red-green color blindness is described as a recessive disorder linked to the X chromosome. The script explains that males are more likely to exhibit the disorder because they have only one X chromosome, and if it carries the recessive gene, they will express the condition.

💡Carrier

A carrier is an individual who possesses a gene for a recessive disorder but does not exhibit symptoms of the disorder. In the video, the script discusses how females can be carriers of sex-linked disorders, such as hemophilia, because they have two X chromosomes. If only one X chromosome carries the recessive gene, the other normal X chromosome can mask the disorder. The video uses the term 'carrier' to describe a mother who can pass on the recessive gene to her offspring.

💡Phenotype

Phenotype refers to the observable physical or biochemical characteristics of an individual, which result from the interaction of its genotype with the environment. The video script explains that in the context of sex-linked disorders, phenotypes can vary between males and females. For example, females may be carriers of a disorder without exhibiting symptoms (phenotype of being a carrier is not used), while males with the same genetic condition may show clear symptoms due to having only one X chromosome.

💡Genotype

Genotype is the genetic composition of an individual, describing the specific set of genes inherited from the parents. In the video, genotypes are discussed in relation to sex-linked disorders, with examples of how different combinations of alleles on the X and Y chromosomes can result in different outcomes for males and females. The script uses genotypes to explain how traits are passed down and how the presence of a dominant or recessive allele on the sex chromosomes influences the expression of disorders.

💡Red-green color blindness

Red-green color blindness is a common sex-linked disorder discussed in the video. It is a condition where an individual has difficulty distinguishing between certain colors, particularly reds, oranges, and greens. The script uses this condition to illustrate how recessive genes on the X chromosome can affect males more frequently than females, as males have only one X chromosome and thus are more likely to express the trait if they inherit the gene.

💡Hemophilia

Hemophilia is a bleeding disorder mentioned in the video script as another example of a sex-linked disorder. It is caused by a deficiency of certain clotting factors in the blood and is typically inherited in an X-linked recessive pattern. The video explains how hemophilia is more common in males because they have only one X chromosome, and if it carries the gene for hemophilia, they will exhibit symptoms. Females, on the other hand, would have to inherit the gene on both of their X chromosomes to express the disorder, which is less likely.

Highlights

Introduction to sex-linked disorders and how they are inherited.

Explanation of the structure of chromosomes, specifically the sex chromosomes (X and Y).

Differentiation between autosomes and sex chromosomes in determining biological sex.

Description of the genetic makeup of males and females in terms of sex chromosomes.

Importance of understanding chromosome combinations for learning about sex-linked disorders.

Discussion on why females are less susceptible to certain disorders due to having two X chromosomes.

Explanation of how males, with one X and one Y chromosome, are more susceptible to X-linked disorders.

Introduction to X-linked disorders and their representation on the X chromosome.

Example of a sex-linked disease: red-green color blindness, its symptoms, and how it is inherited.

Demonstration of a red-green color blindness test and interpretation of results.

Genetic representation of sex-linked diseases using superscript letters on the X chromosome.

Illustration of genetic cross using a Punnett square to predict inheritance outcomes.

Explanation of the inheritance pattern in an example with an unaffected father and a carrier mother.

Discussion on how to determine the genotype and phenotype of offspring from a genetic cross.

Clarification on the difference between genotype and phenotype in the context of sex-linked disorders.

Introduction to hemophilia as another common sex-linked disorder and its inheritance pattern.

Tutorial on calculating sex-linked inheritance using hemophilia as an example.

Emphasis on the importance of accurately writing genotypes and phenotypes in genetic crosses.

Explanation of how to group and calculate the percentages of different genotypes and phenotypes in a Punnett square.

Differentiation between writing about carriers in questions versus describing phenotypes.

Guidance on answering questions that ask for the percentage of children with a sex-linked disorder.

Instructions on explaining sex-linked inheritance, including stating parents' genotypes and inheritance patterns.

Terminology recap including autosomes, gonosomes, recessive and dominant traits, phenotype, and genotype.

Transcripts

play00:00

hi everybody and welcome back today

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we're going to be looking at sex

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linked disorders and we're going to go

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through exactly how you inherit these

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diseases

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how to calculate them in a punnett

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square and also we are going to look out

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how do you explain these in longer

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questions when you have to explain it

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perhaps in a paragraph

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so a fundamental aspect of this topic is

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understanding

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the structure of the chromosomes now in

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the photograph in front of you

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you have what we call our gonozomes

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or the sex chromosomes

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now when we speak about gronosomes we

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are talking about the

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x chromosome and the y

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chromosome essentially these are the

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23rd pair in humans that dictate our

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biological sex

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autosomes are the 22 other

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chromosomes that humans have and they

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are not linked to our sex determination

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now in this photograph

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the very large chromosome is represented

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by

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our x so that is the x chromosome the

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smaller chromosome in blue

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is the y chromosome now

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depending on whether you are male or

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female females will have

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two x chromosomes and

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males will have an x and

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a y it's important to know these

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combinations of by heart because it's

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going to help you learn about these sex

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link disorders a lot

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more easily now you will notice that

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especially and fundamentally females

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have two

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x chromosomes which makes them a lot

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less susceptible to disorders because

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if one of their x chromosomes is damaged

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the other one can help

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it out it can fix the problem in males

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on the other hand you will notice that

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they only have

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one x chromosome and because an x and a

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y

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are actually not homologs in other words

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they're not an actual homologous pair

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they're not perfectly identical to match

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um whatever is on the y actually can't

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help if there's something broken

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on the x now in this video i'm only

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going to talk about

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x linked disorders which means that

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these are sex

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links disorders but they're only found

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on the x chromosome you do also get ones

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on the y

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so a very common example of a sex link

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disease

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is red green color blindness

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now essentially red green color

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blindness means that you have the

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inability to see certain shades of color

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and alongside here i have included a

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very simple red green color blind test

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if you cannot see the number in the

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circle there's a possibility

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that perhaps you do have color blindness

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you might see the incorrect number or a

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partial number

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if you're hoping to know what the

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correct number is it's a 2

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that's hidden inside of there often

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people with red green color blindness

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confuse the reds the oranges and the

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yellows and greens with each other

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now this particular kind of sex-linked

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disease

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is carried on the x chromosome and it is

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a recessive

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disorder that means that we are going to

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use a small letter to represent it but

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this time we're actually going to write

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it

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as a superscript at the top of the x

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if you don't have the disorder then your

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x chromosome is going to carry a

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capital r on it and that means you don't

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have it

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in other words in order for us to see

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the variations of how this turns out

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let's have a look at this example

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along on the left so what we have here

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is an

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unaffected father and we have a

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carrier mother now let's talk about the

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unaffected father

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if the unaffected father doesn't have

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the disorder that then means that his x

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chromosome

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will have a capital r on it and he will

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have

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a y and there's nothing on the y because

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this is not a y

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linked disease it is an x chromosome

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disease

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the mother on the other hand is what we

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call a carrier

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what that means is that one of her

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chromosomes carries it and the other

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doesn't

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so if we were to do her genotype she

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would have one capital r

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on her x chromosome and one small case

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r or lowercase r that means she's

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carrying that disorder

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now what they've done lower is that

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they've done a genetic cross like a

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punnett square but with pictures this

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time

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and what we have is four possible

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outcomes of the offspring first of all

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we have an unaffected son and an

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unaffected daughter now the only way

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that that's possible for the unaffected

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son

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is that his x chromosome which he gets

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from his mother

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because you can only get wise from

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fathers the x chromosome he got from his

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mother

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can only be the

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capital r he can't inherit the small r

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if he did

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he would have the disorder and so that

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then means

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that the only possible thing that is on

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his x chromosome

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is going to be a capital r

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and a y our daughter who's unaffected on

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the other hand

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she has two x chromosomes and now we

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need to know

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well what are her r's does she have two

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big r's little one

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what does she have well if we look at

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the fact that she is not a carrier

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it means that she is going to inherit

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one allele from each parent and she's

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going to inherit one capital letter from

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her father

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and she's going to inherit the other

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capital letter

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from her mother making her therefore

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have a genotype of

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a capital r on the one x and a capital r

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on the other

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then we look at the carrier daughter the

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carrier daughter just like her mother

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will have the same phenotype

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she will have an x with a capital r on

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it

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where did she get that capital r from

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she received

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that one from her father because that's

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all he can give to his daughters he

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can't give a y

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chromosome the other r on the other x

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however

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was inherited by and from the mother

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because that's the only other place she

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could have got this small r which she

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carries

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and so that's where her small r comes

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from finally we have the affected sun

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the affected sun is going to be x y

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and what do we find on his x chromosome

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well he inherited his y chromosome from

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his father so there's nothing that we

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can receive

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from the dad that will tell us if

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they're colorblind what's important is

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where did he get that affected allele

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from

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and he received it from his mother so

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that means the

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sun will have a small letter r on his

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x so to round this section off

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just to ensure that we know exactly how

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this works

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if you are two x's

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you're female you must have two small

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r's on both of your x's to have the

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disorder

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if you are a boy you only need

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one small letter r on your x

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and that's because you only have one

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x allele to work with on the other hand

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in our dominant or capital r you can

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have a girl

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who has two capital rs

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you can have a boy with a capital r

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which means he doesn't have the disorder

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and the final option oh i've made a

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mistake let's just quickly rub that out

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the final option is if you have

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a female who is a carrier

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and the female i'm just going to put it

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below here because i'm running out of

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space

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is going to be a capital r and a

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small or lower case r

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now we need to look at how do you

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actually calculate the sex linked

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inheritance and for this one i'm going

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to use hemophilia which is another very

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common kind of sex-linked disorder that

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we do in school

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and these are three different examples

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with three slightly different

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outcomes it's been a little bit

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challenging also to write these

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h's as superscript i know that they're

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written here lower

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remember when we write them we want to

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write the x and then we want to put it

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at the top

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like that uh just for reference when

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you're writing this

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in school so let's have a look at the

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first example so our first

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example is a male with hemophilia

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now you are going to set out your

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genetic cross like you normally do

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you're going to have your geno and

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phenotype of the parents

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meiosis gametes fertilization and then

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you're going to draw your punnett square

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like you normally would you you

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basically draw your normal

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genetic diagram except the lettering

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is just slightly altered and with this

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one the question would have said a male

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with hemophilia so here is our male with

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hemophilia there is his one allele and

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there is his other sex chromosome

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and then we have a female who is a

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non-carrier

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sometimes they call them non-carriers

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sometimes they can call a female without

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hemophilia

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sometimes they will also say it's just a

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normal

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female essentially what that means is

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that this female has

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two capital h's in other words she is

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not a carrier of the disease and

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she does not have it either

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now you would do your genetic cross like

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you normally would and these would be

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our

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outcomes now the way in which you write

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your answer is

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really important and so that's what i'm

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going to show you now in terms of

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calculating it

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now what we need to do is we need to

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group together our genome and phenotypes

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and so looking at our punnett square we

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can first of all group together our

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genotypes

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we're going to look at the females first

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and these two females carry the same

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genotypes we group them together so

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that's 50 percent and then these two

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male genotypes are also the same and so

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we group those together also

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50 the phenotype is

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a reflection of that where there are 50

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females without hemophilia it's

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important to write that they are without

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hemophilia

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and that they are females this is a

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sex-linked cross so you must give

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the sex of the individual and then 50

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males without

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hemophilia now let's have a look at the

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second example the second example will

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have something

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in the question along the lines of a

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male with hemophilia

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and so here are his alleles

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and they are always placed together

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let's not forget that

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and then the next important component is

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that this cross now has a female

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carrier it's important to remember that

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the word carrier is actually not a

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descriptive word that you're allowed to

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use when you talk about

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the phenotype at the very end and i'll

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show you exactly what i mean by that

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they can use it in the question to

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describe the female

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but you can't use it to describe them

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later on when you write out the

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phenotype but i'll show you what i mean

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and here is our female carrier we know

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she's a carrier because she has one

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capital

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h on her x and one lower case h on the

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other

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now we are going to multiply this into

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the table and let's write out our pheno

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and genotype

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all right now this genome phenotype is a

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little bit longer because we've produced

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essentially four very different

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individuals and so let's have a look at

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the genotype

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so we're going to group all the same

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genotypes together now in this

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particular punnett square all the

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genotypes are different this female

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represents 25

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this female here represents 25 this male

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is 25 and this male is also 25

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the phenotypes follow a very similar

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distribution 25 percent of females

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without hemophilia

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we then have 25 females with

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hemophilia it's important to note that

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these 25 percent of the females with

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hemophilia

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won't actually be born but because a

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punnett square is working out

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probability

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you still need to provide the

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probability of a child

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inheriting the disorder don't get caught

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out on questions

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that are asking about hemophiliac

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females just because you know that

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they're not actually born

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but they will essentially be formed

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and often a mother goes through a

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miscarriage we then have 25

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males without hemophilia and then 25

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males with

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hemophilia now let's get to the third

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example

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in this final one we look at a normal

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male which as we can see here he has his

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dominant

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h on the x and the y chromosome

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and then we have very importantly now a

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female

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carrier you will now notice that

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whenever

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i'm going to write about female carriers

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we don't actually call them that when we

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write our phenotypes but you'll see now

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as i do the calculations and i write out

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our genome and phenotypes you multiply

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into the punnett square

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and you write down your pheno and

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genotype results

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now this final genome and phenotype

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reveals a very important way in which we

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need to group our results

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the genotype is very simple all we need

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to do

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is group them so we have 25 percent

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two x's with capital dominant h's we

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have an individual

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a female individual who has a capital h

play13:22

of a small h

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25 have a capital h a dominant allele

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and 25 percent of the males have a

play13:30

a recessive h on their x and that's how

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we record it

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what i want to bring your attention to

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is how you write the phenotype

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50 of the females are without

play13:42

hemophilia you do not write 25 percent

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without

play13:46

and then 25 female carrier technically

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being a carrier is not a phenotype

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you can't actually write that down

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because it's not a physical

play13:55

characteristic that can be observed

play13:57

it is only a genotype i know in

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questions that they will refer to them

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as carriers and they have to because

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that's how they're indicating that

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they're heterozygous that they have a

play14:07

big letter and a small letter or a

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dominant and a recessive allele present

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but you cannot write them that way we

play14:14

then still write however the males the

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same

play14:17

and that we have 25 percent males

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without hemophilia

play14:20

and 25 males with hemophilia the last

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thing that is really critical that goes

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with any sex linked inheritance is

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questions like the following

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let's say for example three they ask you

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to tell them

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of the children what percentage

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has hemophilia now of the four children

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in example number three how many

play14:46

have hemophilia now of all the children

play14:50

that's boys and girls

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and of all three only 25

play14:56

now that refers to all the children

play15:00

but what happens if the question was

play15:02

what percentage of the males

play15:05

have hemophilia now if we

play15:08

only look at the boys we only look at

play15:11

the males

play15:12

and there is only one of the two males

play15:15

that have it that then means that of the

play15:18

boy

play15:18

children 50 percent of the boy

play15:22

children have hemophilia it's really

play15:25

important

play15:26

to read the question carefully and to

play15:27

see are they asking about the children

play15:29

as a whole

play15:30

or are they asking about the boys or the

play15:32

girls only

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next we need to look at how are you

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going to explain this type of

play15:39

inheritance

play15:40

often they will ask you how do you

play15:41

explain the sex-linked inheritance

play15:43

you've just seen now in the hemophilia

play15:45

or

play15:45

perhaps in the red green color blindness

play15:47

and what you need to do

play15:49

in it's a very basic structure is you're

play15:51

always going to

play15:52

state the mother's genotype and that

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means that you need to give

play15:57

what her letterings are

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on her x's and her y's on her x's excuse

play16:04

me

play16:04

the same goes for then stating the

play16:07

father's

play16:08

genotype so you're going to state their

play16:10

genotypes

play16:12

for example let's say that our

play16:15

mother's genotype is a x

play16:19

with a capital h and a x

play16:23

with a lower case you need to state that

play16:25

and then for the father

play16:27

you need to do the same let's say for

play16:28

example he has a

play16:30

dominant allele on his x chromosome

play16:34

then what you need to do is you need to

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explain how

play16:40

this occurs through the following things

play16:44

you are going to then explain how you

play16:46

inherit one

play16:47

allele from each parent that's important

play16:51

males inherit only a y chromosome from

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their father

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and an x chromosome from their mother

play16:58

females on the other hand inherit an x

play17:00

chromosome from their mother

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and their father now depending how long

play17:06

the question is and what exactly it's

play17:07

asking

play17:08

they may also ask why are boys more

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affected by sex-linked disorders than

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girls

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this is where you will then include a

play17:17

section in your

play17:18

answer about the fact that males only

play17:20

have one x chromosome

play17:22

and because they only have one x

play17:24

chromosome they are more

play17:26

likely to inherit the disease

play17:29

why are they more likely to inherit the

play17:31

disease because they do not have another

play17:34

x chromosome to mask it in other words

play17:37

if we look back up at this father's

play17:38

genotype you'll see he only has one x

play17:40

chromosome with the capital h on it the

play17:42

dominant allele

play17:44

if he had a recessive allele there's no

play17:47

other allele that can protect him from

play17:49

that disorder

play17:50

the y chromosome is too small it doesn't

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have enough information on it

play17:54

and it can't mask anything on the x

play17:57

however on this mother's genotype you'll

play17:59

notice she has a dominant allele and she

play18:01

has a recessive allele

play18:02

which technically means she's carrying

play18:04

hemophilia

play18:05

but because she has two copies of the

play18:08

alleles

play18:08

one dominant and one recessive her

play18:11

dominant allele

play18:12

masks the recessive allele therefore she

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does not suffer from the disorder

play18:19

last but not least let's do a quick

play18:21

terminology recap

play18:23

we spoke about autosomes and gonozomes

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autosomes are the first 22 chromosomes

play18:29

and this is where you find autosomal

play18:31

diseases if you've come across an

play18:33

autosomal disease

play18:35

you are not going to use x's and y's

play18:38

you still use the standard a

play18:42

and small letter a or you can even use

play18:45

any other lettering depending on what

play18:46

they want you to use but essentially

play18:48

you only need to use your letters of the

play18:51

disease you do not need

play18:52

to use any other x's and y's

play18:55

gronosomes on the other hand are the sex

play18:58

chromosomes the x and the y and that's

play19:00

what we dealt with today

play19:02

you get recessive and dominant traits

play19:04

and this will then depend on whether or

play19:06

not the sex link disorder is a dominant

play19:09

or a recessive sex-linked disorder

play19:12

remember that for it to be recessive

play19:14

in females you're going to need two on

play19:18

each of her chromosomes so one on each

play19:20

in males however they only need one

play19:22

recessive allele because remember they

play19:23

only have one

play19:24

x in hemophilia we looked at a bleeding

play19:29

disorder

play19:30

that is found in males and carried by

play19:33

females no female hemophiliacs

play19:36

are born or exist red green color

play19:40

blindness

play19:41

is a type of sex lick disorder which

play19:43

both males and females experience

play19:45

although males are more commonly found

play19:46

to have red green color blindness

play19:49

and then we spoke about the phenotype

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which is the physical characteristics of

play19:52

the individual and what they look like

play19:54

remember we can't have a carrier as a

play19:57

phenotype

play19:58

and lastly the genotype essentially the

play20:00

alleles that we find

play20:01

on their sex chromosomes thank you

play20:04

everybody i hope this video

play20:06

has helped you and i will see you again

play20:07

soon bye

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الوسوم ذات الصلة
GeneticsSex-Linked DisordersInheritancePunnett SquareX ChromosomeY ChromosomeColor BlindnessHemophiliaCarrier StatusGenetic Traits
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