Physics 36 The Electric Field (4 of 18)

Summary

In this tutorial, the speaker demonstrates how to solve a complex 2D electric field problem involving multiple charges. The scenario includes three charges: a 12 µC positive charge at the origin, an -8 µC negative charge 1 meter to the right, and a 6 µC positive charge 1 meter above the first. The goal is to find the electric field at a specific location. The video covers the vector addition of electric fields, finding the magnitudes and components, and calculating the net electric field, including the direction and magnitude. This comprehensive approach provides a clear understanding of how to work with electric fields in two dimensions.

Takeaways

• 😀 The problem involves calculating the electric field due to three charges placed in a two-dimensional plane.
• 😀 There is a 12 microcoulomb charge at the origin, a -8 microcoulomb charge 1 meter to the right, and a 6 microcoulomb charge 1 meter above the first charge.
• 😀 The location of interest for calculating the electric field is at (1m, 1m) in the xy-plane.
• 😀 Electric fields due to positive charges point away from the charge, while electric fields due to negative charges point toward the charge.
• 😀 The electric field vectors for each charge are drawn to visualize their directions: E1 points away, E2 points towards, and E3 points away from its respective charge.
• 😀 To calculate the electric field, the magnitudes of the electric fields due to each charge are found using Coulomb's Law.
• 😀 The magnitude of the electric field for each charge is calculated using the formula E = k * q / r^2, where k is Coulomb's constant, q is the charge, and r is the distance from the charge.
• 😀 The electric field vectors are then broken into their x and y components to perform vector addition.
• 😀 For E1, the components are calculated using trigonometry with the angle θ being 45°, as the charge's position forms a right-angled triangle.
• 😀 The final electric field at the location is found by summing the x and y components of the individual electric fields, leading to a net electric field of 92,000 N/C in the x-direction and -34,000 N/C in the y-direction.
• 😀 The magnitude of the total electric field is found using the Pythagorean theorem, resulting in 98,000 N/C, and the direction of the field is calculated using the inverse tangent of the y and x components.

The video is abnormal, and we are working hard to fix it.
Please replace the link and try again.