Relative Motion Review— Sine and Cosine Law Solution

HS Physics
16 Sept 202111:44

Summary

TLDRThe video explains how to determine the heading and airspeed of a plane navigating in windy conditions. The scenario involves a pilot flying to a city 600 km away in two hours, with wind blowing at 70 km/h at 10° west of south. Through vector analysis, diagrams, and calculations using trigonometric laws (cosine and sine laws), the airspeed of 278 km/h and a heading of 1.81° south of west are determined. The process includes understanding resultant vectors and correcting for wind direction to achieve the desired flight path.

Takeaways

  • 😀 The pilot's goal is to reach a city 600 km away in 2 hours, heading 15 degrees south of west.
  • 🌬️ There is a 70 km/h wind blowing at 10 degrees west of south, which affects the plane's trajectory.
  • 🛫 The plane's resultant velocity, considering the wind, is 300 km/h, calculated by dividing the distance by the time.
  • 🔍 The script uses vector addition to determine the plane's heading and airspeed, considering the wind's effect.
  • 📏 The cosine law is applied to find the plane's airspeed by using the known wind speed and resultant velocity.
  • 🧮 The calculated airspeed of the plane is approximately 278 km/h, accounting for the wind's influence.
  • 📐 The sine law is used to determine the angle between the wind vector and the plane's heading.
  • 🔄 The plane's heading is found by subtracting the angle calculated using the sine law from the desired direction.
  • 🏁 The final heading of the plane is approximately 1.81 degrees south of west, adjusted for the wind.
  • 📘 The script provides a detailed step-by-step approach to solving the problem using trigonometric laws and vector analysis.

Q & A

  • What is the distance the pilot needs to cover to reach the city?

    -The pilot needs to cover a distance of 600 kilometers to reach the city.

  • In which direction does the pilot need to fly to reach the city?

    -The pilot needs to fly in a direction 15 degrees south of west to reach the city.

  • What is the speed and direction of the wind?

    -The wind is blowing at a speed of 70 kilometers per hour at a direction of 10 degrees west of south.

  • How long does the pilot have to reach the city?

    -The pilot has two hours to reach the city.

  • What is the resultant speed of the plane required to reach the city in the given time?

    -The resultant speed of the plane is 300 kilometers per hour, calculated by dividing the distance by the time.

  • What is the angle between the wind direction and the desired direction?

    -The angle between the wind direction (10 degrees west of south) and the desired direction (15 degrees south of west) is 65 degrees.

  • What is the formula used to calculate the unknown side of the triangle in this scenario?

    -The cosine law is used to calculate the unknown side of the triangle, which is represented as 'b^2 = a^2 + c^2 - 2ac cos(B)'.

  • What is the calculated airspeed of the plane with respect to the air?

    -The calculated airspeed of the plane is 278 kilometers per hour.

  • How is the heading of the plane determined?

    -The heading of the plane is determined by subtracting the angle 'a' from the desired direction angle of 15 degrees south of west.

  • What is the final heading of the plane after accounting for the wind?

    -The final heading of the plane after accounting for the wind is 1.81 degrees south of west.

  • What trigonometric function is used to find the angle 'a' in the triangle?

    -The sine function is used to find the angle 'a' in the triangle, using the formula 'sin(a) = opposite side / hypotenuse'.

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Related Tags
Vector AnalysisPilot NavigationAirspeed CalculationWind CorrectionFlight PathMathematics ProblemPhysics of FlightAviation ScienceNavigation TechniquesTrigonometry Application