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In this physics demonstration, a step-by-step approach is taken to solve a problem involving work done by a force. Given a force of 15N at a 45-degree angle to the horizontal and a displacement of 49 meters, the video explains how to calculate the work done by finding the horizontal component of the force and applying the work formula. The result is 520.89 Joules, which is then converted to 0.1244 kilo calories, providing a clear and concise explanation of the physics concept.

Takeaways

• 🔍 A physics problem is being solved step-by-step.
• 📏 Given information includes a force of 15N, an angle of 45 degrees with the horizontal, and a distance of 49 meters.
• 🔧 The goal is to find the work done by the force.
• 📘 The formula for work done by a force is work = force x displacement x cos(angle).
• 📐 The force's horizontal component is found using trigonometry: 15N * cos(45 degrees) = 10.61N.
• ⚙️ Work is calculated using the horizontal component of the force and the displacement.
• 📉 The angle between the horizontal direction and displacement is 0 degrees.
• 📊 The calculated work is 520.89 Joules.
• 🔄 To convert Joules to kilo calories (KCAL), divide by 4184.
• 📈 The work done is equivalent to 0.1244 kilo calories.
• 🤔 The video offers help for any further physics questions.

Q & A

What is the given force in the physics problem presented?

The given force in the problem is 15 Newtons (15 N).

What is the angle between the force and the horizontal?

The angle between the force and the horizontal is 45 degrees.

What is the distance over which the force is applied?

The distance over which the force is applied is 49 meters.

What is the formula for work done by a force?

The formula for work done by a force is work = force × displacement × cos(angle), where angle is the angle between the force and the displacement.

How is the horizontal component of the force calculated?

The horizontal component of the force is calculated using the formula: horizontal component of force = force × cos(angle).

What is the calculated horizontal component of the force in the problem?

The calculated horizontal component of the force is 10.61 Newtons (10.61 N).

How is the work done by the force determined when the force is acting horizontally?

The work done by the force when it is acting horizontally is determined using the formula: work = horizontal component of force × displacement × cos(0 degrees).

What is the work done by the force in Joules?

The work done by the force in Joules is 520.89 Joules (520.89 J).

How can the work done in Joules be converted to kilo calories (KCAL)?

To convert the work done from Joules to kilo calories (KCAL), you divide the work in Joules by 4184.

What is the equivalent work done in kilo calories (KCAL)?

The equivalent work done in kilo calories (KCAL) is 0.1244 KCAL.

What additional information can be provided to further understand the physics problem?

To further understand the problem, one could explore the implications of different angles and distances on the work done, or the effect of varying the magnitude of the force.

Outlines

00:00

🔍 Calculating Work Done by a Force

The script begins by introducing a physics problem involving a force of 15 Newtons applied at a 45-degree angle to the horizontal, over a distance of 49 meters. The main objective is to calculate the work done by this force. The formula for work done is given as the product of force, displacement, and the cosine of the angle between them. Since the force is not aligned with the direction of displacement, the horizontal component of the force is determined using trigonometry: 15n * cos(45°) = 10.61n. The work done is then calculated using the horizontal component and the fact that the angle between the force and displacement is now 0 degrees (since it's horizontal), resulting in 10.61n * 49m * cos(0°) = 520.89J. The script also includes a conversion of work from Joules to kilo calories, using the conversion factor 1 kcal = 4184J, yielding 0.1244 kcal. The video concludes with an invitation for further questions.

Keywords

💡Work

Work in physics is defined as the product of the force applied to an object and the displacement of the object in the direction of the force. In the context of the video, work is calculated using the formula work = force x displacement x cos(angle), where the angle is between the force and the displacement. The script demonstrates this by calculating the work done by a force of 15 Newtons over a distance of 49 meters at a 45-degree angle to the horizontal.

💡Force

Force is a push or pull upon an object resulting from its interaction with another object. In the script, a force of 15 Newtons is given, which is the magnitude of the push or pull acting on the object. The force is a key component in calculating the work done on the object as it moves horizontally.

💡Displacement

Displacement refers to the change in position of an object. It is a vector quantity, meaning it has both magnitude and direction. In the video script, the displacement is given as 49 meters, which is the distance the object moves in the horizontal direction while work is being done on it.

💡Angle

The angle in this context is the angle between the direction of the force and the direction of the displacement. The script mentions an angle of 45 degrees, which is crucial for determining the component of the force that contributes to the work done in the direction of displacement.

💡Component of Force

A component of a force is a part of the force that acts in a specific direction. The script calculates the horizontal component of the force, which is necessary to find the work done in the horizontal direction. This is done using the formula: horizontal component of force = force x cos(angle).

💡Trigonometry

Trigonometry is a branch of mathematics that deals with the relationships between the sides and angles of triangles. In the script, trigonometry is used to find the horizontal component of the force by applying the cosine function to the given angle.

💡Cosine

The cosine function is a trigonometric function that relates the angle of a right triangle to the ratio of the lengths of its adjacent side to its hypotenuse. In the script, cosine is used to find the horizontal component of the force, which is essential for calculating the work done.

💡Joules

Joules (J) is the unit of measurement for work, energy, or amount of heat. The script calculates the work done as 520.89 Joules, which is the amount of work done by the force in moving the object over the given distance.

💡Kilo calories

A kilo calorie (KCAL) is a unit of energy often used in nutrition to measure the energy content of food. In the script, the work done in Joules is converted to kilo calories to provide an alternative measure of energy. The conversion factor used is 1 kilo calorie equals 4184 Joules.

💡Conversion

Conversion in this context refers to changing one unit of measurement into another. The script demonstrates the conversion of work from Joules to kilo calories, which helps in understanding the energy expended in more familiar terms.

Highlights

Solving a physics problem step by step.

Identifying given information: Force equals 15N, angle with horizontal equals 45 degrees, distance equals 49 meters.

Objective: Find the work done by the force.

Work formula: Work = Force x Displacement x cos(angle).

Force is not in the direction of displacement.

Finding the horizontal component of force using trigonometry.

Horizontal component formula: Horizontal component = Force x cos(angle).

Calculating the horizontal component: 15N x cos(45 degrees) = 10.61N.

Using the work formula with the horizontal component.

Work calculation: 10.61N x 49m x cos(0 degrees).

Result: Work done is 520.89 Joules.

Explanation of horizontal direction and displacement angle.

Converting work from Joules to kilo calories (KCAL).

Conversion factor: 1 KCAL equals 4184 Joules.

Calculating the equivalent in kilo calories: 520.89 J / 4184 = 0.1244 KCAL.

Final result: Work done is equivalent to 0.1244 kilo calories.

Offering help for any other physics questions.